Vyxal, 3 bytes
∑d∻
Compiles as:
stack.push(summate(stack.pop()))
stack.push(stack.pop() * 2)
lhs, rhs = stack.pop(2); stack.push(int((rhs % lhs) == 0))
Explained
∑d∻
∑ # Push the sum of the integers of the input
d # Double that sum
∻ # And push ((sum(input) * 2) % input) == 0