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2:20 AM
 
 
8 hours later…
10:27 AM
Thanks for doing that!
Only now I noticed that I have mentioned the same thing to you before:
in MathOverflow, Dec 12 '19 at 8:55, by Martin Sleziak
As a side note, I think that might be a suitable tag for your question. And since you created a new tag, maybe filling in the tag-info might be useful. (Then there is smaller chance that the tag will be removed.)
in MathOverflow, Dec 12 '19 at 8:58, by Martin Sleziak
The tags used on only one question are automatically deleted after certain time unless they have tag-wiki.
I have forgotten about that since then.
Sorry for bothering you with the same thing twice! (Still, I think that it's useful that the tag-info for this new tag is no longer empty.)
 
 
3 hours later…
1:06 PM
I have removed a depreacated tag from this question: Show that the number of perfect matches in graph $G$ is equal to $\operatorname{Per}(A)$ All five spots are used, but there is no top-level tag. (Although the tagging of this specific question probably does not matter that much - there are already some close votes.)
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Q: Show that the number of perfect matches in graph $G$ is equal to $\operatorname{Per}(A)$

Maher BisanLet $G = (V_1, V_2, E)$ be a bipartite graph with $|V_1| = |V_2| = n$. Let $A=\{a_{ij}\}^{n}_{i,j=1}$ be the $n\times n$ matrix satisfying $$ a_{ij} =\begin{cases} 1 & \ if\ \{i,j\} \in E\\ 0 & if\ \{i,j\} \notin E \end{cases} $$Define the permanent of $A$ by: \begin{equation*} \operatorname{P...

0
Q: Show that the number of perfect matches in graph G is equal to Per(A).

Maher BisanLet $G = (V_1, V_2, E)$ be a bipartite graph with $|V_1| = |V_2| = n$. Let $A=\{a_{ij}\}^{n}_{i,j=1}$ be the $n\times n$ matrix satisfying $$a_{ij} =\begin{cases} 1 & \text{if }\{i,j\} \in E\\ 0 & \text{if }\{i,j\} \notin E \end{cases}$$ Define the permanent of $A$ by: \begin{equation*} \oper...

 
I don't know if this is the appropriate room for this question, but here goes.
I initially wrote an answer here which I believed would construct a counterexample to the claim. I have since learnt that this approach cannot work. I have updated the post with some text at the beginning, together with a couple of other comments regarding the question and the other answer.
Is what is there worth keeping or should I delete my answer entirely?
 
 
6 hours later…
7:25 PM
A new tag created by YCor. The tag-info is empty at the moment.
0
Q: On dissecting a triangle into another triangle

Nandakumar RThe Wallace-Bolyai-Gerwein theorem states that any polygon can be formed from another by cutting it into a finite number of pieces and recomposing these by translations and rotations if and only if the two polygons have the same area. It is easy to see this: An equilateral triangle can be cut i...

6
Q: Complexity of scissors congruence?

T.... Where is the complexity of the problem 'Given two bounded compact convex integral polyhedra in $\mathbb R^n$ presented by $O(poly(n))$ integer valued halfspaces given by linear inequalities with coefficients of size $O(poly(n))$ bits with promise that they are equal volume is there a scisso...

The third of Hilbert's list of mathematical problems, presented in 1900, was the first to be solved. The problem is related to the following question: given any two polyhedra of equal volume, is it always possible to cut the first into finitely many polyhedral pieces which can be reassembled to yield the second? Based on earlier writings by Gauss, Hilbert conjectured that this is not always possible. This was confirmed within the year by his student Max Dehn, who proved that the answer in general is "no" by producing a counterexample.The answer for the analogous question about polygons in 2...
 
 
2 hours later…
9:54 PM
@MichaelAlbanese It would be better to hear from somebody who knows the topic, but from you're description I'd guess that the answer could be still useful and it is better to keep it.
If the thing which is worrying you is "undeserved" reputation, I'll just point out that in this case your reputation won't change whether you delete the answer or not - since it has been around for a long time and it has score >=3.
Regarding the question whether this is on-topic in this room - if you get not response here, you can always try the main chatroom (or maybe even Homotopy theory chatroom).
 

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