@thoughtforfood It's just showing the generalization of $kz$ in the one dimensional case where we have $\mathbf{\tilde{E}} = \tilde{E_0}e^{i(kz-\omega t)}\hat{x}$.
This question
asks whether a traveler looking through a telescope will see his earthbound twin moving in slow motion. It is closed as a duplicate of this question, which asks whether a traveler moving away from earth will hear earth-originated telephone conversations in "slow motion".
It woul...
Well the integral just gives the area under f(x). And $|v-u|$ is the base of the rectangle. So the area under the curve must be less than maxima*base of rectangle ( |v-u| ). I think they mean k is the maximum value of f(x).
$$\text{Let $f$ be an integrable function and limited on the non-degenerate interval $[a,b]$ and $\psi : [a,b]\mapsto \mathbb R$ be the function defined as} \\ \psi(t) = \int_a^t f(x) dx \\ \text{Show that there is a constant $k>0$ such that, for any $u,v\in[a,b]$ we have}\\ |\psi(u)-\psi(v)| \le k|u-v|$$
[Dream?, hallucination?, surreal weirdness?, whatever...] After having so many sleepless nights of chronic itch and scratching all over, it seems I might be arriving at a way to (temporary?) ease it.
Summarizing the many nights of imagery, it seems the itch and the scratching, are represented by the imagery as two set of things that can be exchanged into each other. For example, this night's the itch corresponds to whenever you have a water bucket and a headshot from some CS like game, it can be interchanged into a rifle of sort. Meanwhile for every 2 rifle shots plus a shot from a handhel…
As you close the switch the magnetic field started to build up as the DC current increases in the initial stages. Hence there is a change in magnetic field in the initial phase
@Secret Yeah, say the magnetic field changes from 0 to B in the upward direction. The lower face of the ring attains a South pole like configuration. So it should be attracted to the coil rather than be repelled by it ? Isn't it? @Secret
remember the ring is not attached to the coil. Thus when the coil gain a south pole like configuration, Lenz law will induce a current in the ring to produce a south pole to oppose it
@Secret Aha!I get it! Lenz law. Now suppose we keep a DC current on for a long time then will the ring remain attracted to the coil?
I mean the ring should eventually be magnetized by the magnetic field of the coil which is obviously larger than the induced magnetic field in the ring due to Lenz law
Nope, suppose, you do manage to prevent the ring form flying away in the initial phase, after the DC current stablises, the field also stablises. Hence the effect from Lenz law dies away and the ring will no longer felt anything from the coil
However, since aluminium is paramagnetic, then yes you will expect the ring will over time be magnetised to the same direction as the coil, thus when you let go of the ring, it might end up attracted to the coil and refuse to move up (until you switch off the field of course, which then the aluminium will demagnetise slowly afterwards as the spins rel…
I'm doing a calculation to find the formula for the resonance frequency and height of the building. I have the resonance frequency of buildings with different heights. I know wavelength, wavespeed etc If Resonance Frequency = k x Height and log(f) = xlog(H) x log(k)
In that case, your log equation is a linear equation (where log(f) is plotted against log(H)), thus x and log(k) can be obtained as the slope and the y intercept respectively)
In physics and chemistry, it is very common to linearise equations in order to plot them as straight lines since curve fitting is harder than line fitting. Of course, not all equations can be linearised hence in more advanced cases, nonlinear fitting is needed
That is not really true, my honours experience told me that fitting nonlinear curves are often more time consuming (as there are more optimisation steps going on in nonlinear least square fitting than linear ones) and at the same time the fitting itself is more error prone and you can end up with a range of nonlinear curves of the same base function all seemly fit the data
At least, I guarantee you that most physicists will understand a "linearized" equation as one where non-linear terms have been discarded by some sort of approximation, e.g. Taylor expansion to first order.
Doing e.g. a log-log plot to get a nice straight line as a graph instead of the power curve is not linearization of the equation, it's just changing the axes on your plot.
People said outside earth is a vacuum. But the air does not get sucked from the Earth's surface. Some said it is due to gravity and some said the speed of air molecules are not high enough to escape. We know vacuum will suck air like your vacuum cleaner and it has nothing to do with gravity. I...
C8:C19 should be your known y values, and D8:D19 should be your known x values. Is your cell for the intercept looks like mine when you highlight the equation?
the INTERCEPT function defaults to find the y intercept, so that is accounted for. To get the x intercept instead, after you fit your curve (hence getting the y intercept and slopes), set your y value to zero and find x
This question
asks whether a traveler looking through a telescope will see his earthbound twin moving in slow motion. It is closed as a duplicate of this question, which asks whether a traveler moving away from earth will hear earth-originated telephone conversations in "slow motion".
It woul...
I don't want to use this site anymore, so how do I delete it? If it's not possible to delete, can I just be permanently blocked from using it?
People said outside earth is a vacuum. But the air does not get sucked from the Earth's surface. Some said it is due to gravity and some said the speed of air molecules are not high enough to escape. We know vacuum will suck air like your vacuum cleaner and it has nothing to do with gravity. I...
