Find the closed form of
$$\prod_{n=1}^{\infty}\frac{\sqrt[\Large 2^{2n}]{\tanh(2^{\Large2^n}})}{\sqrt[\Large 2^{2n-1}]{\displaystyle \tanh (2^{\Large2n-1}})}$$ It's newly created.
$$\prod_{n=1}^{\infty}\frac{\sqrt[\Large 2^{2n}]{\tanh(2^{\Large2^n}})}{\sqrt[\Large 2^{2n-1}]{\displaystyle \tanh (2^{\Large2n-1}})}$$ It's newly created.