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OBE
1:22 AM
0celou7?
whaaa
 
 
2 hours later…
3:38 AM
0
Q: Posting questions with math symbols

LambdaI did a search and came up empty on how to use mathjax on this site. Do I need to use a third party or is a math symbols program built into the physics site?

 
 
2 hours later…
5:39 AM
@OBE I embraced the French in me
4
 
6:22 AM
Hello
 
 
2 hours later…
user228700
8:44 AM
@JohnR: Morning :-)
 
Morning :-)
 
user228700
Fancy lunch today?
 
I haven't decided.
 
user228700
Say, I never did find out what you did with those parathas...
 
Well, yes, it will be fancy, but what i mean is that I haven't decided what to have for dinner yet.
 
user228700
8:45 AM
Riight.
 
Some weekends I have everything planned, and others I find myself with no big ideas.
I'll wander along to the shops ina bit and just see what catches my eye.
 
user228700
Sounds good, seeing as u can buy whatever you want :-)
 
There's a posh supermarket in the UK called Waitrose.
 
user228700
OK..?
 
I don't normally shop there because their food is a lot more expensive and only a little bit better than the mainstream supermarkets.
But ... I recently fixed a computer for a friend and she gave me a Waitrose voucher as a present.
 
user228700
8:48 AM
Oh, cool!
 
user228700
How much stuff dyou reckon you could buy?
 
So the plan (only a vague plan) for today is to go to Waitrose and look for interesting stuff to spend my voucher on.
 
user228700
Lol, OK!! (:-P)
 
user228700
Haha, did u hit caps by mistake? x'D
 
Ah, you spotted that :-)
 
user228700
8:50 AM
I thought that u were just that excited about going to Waitrose :-P
 
:-)
I'm actually feeling a bit laid back this morning.
I have a bit of a cold and I'm not feeling my usual energetic self.
 
user228700
Ohh, OK :-|
 
user228700
Is it still cold over there?
 
But that's OK. I don't have anything special to do today so I'll just chill and take it easy.
 
user228700
:-) OK. I hope it goes away quickly.
 
8:52 AM
@Kaumudi.H We're well into spring now but we still get occasional cold nights when the sky is clear. Last night the temperature dropped below zero.
 
user228700
Sheesh, OK...
 
Try vitamin C?
 
When I got up there was frost everywhere, though the Sun is out now and the frost has melted.
 
user228700
Ah, frost :-)
 
user228700
It's late afternoon here; warm and sticky as always.
 
8:53 AM
@skillpatrol I'm currently eating some chocolate mints. They are just as effective as vitamin C at curing colds (i.e. completely ineffective) but much nicer to eat :-)
 
user228700
I'm waiting for my friend so we can have lunch but I'm starving because I haven't eaten any food in the past 16 hours.
 
Cool :-) Are you going out in Chennai for lunch?
 
user228700
Nope, I've ordered pizza :-P
 
Mmm, pizza :-)
Not chocolate pizaa?
 
user228700
Pizza, stuffed garlic bread, some tacos... :-P
 
user228700
8:55 AM
@JohnRennie NO.
 
@Kaumudi.H :-)
I find being hungry always makes food taste wonderful. It's almost worth putting up with the hunger for the extra spice it brings to the meal :-)
 
Me too.
 
user228700
But this is torture. The food has come, I'm waiting for the friend who's so late >.<
 
Ah, yes, I feel your pain!
 
user228700
...and everything's probably getting cold.
 
8:57 AM
I like cold food.
 
Put the oven on really hot. Then you can zap the pizzas for just a minute or two when your friend gets there.
 
user228700
I don't know how to work the oven :-/
 
????????
 
user228700
:-P It's true.
 
You got age 18 without knowing how to work an oven
 
user228700
8:58 AM
...because we bought an oven only two months ago and I haven't screwed around with it yet.
 
Wow, you really need to work on your survival skills :-)
3
 
user228700
Lol.
 
user228700
Oh, @Sir: The book?!
 
user228700
Today I am going to kill a human being.
 
user228700
...I don't plan on eating it but I do plan on enjoying the act of killing him.
 
user228700
9:02 AM
I mean, the food is literally right here >.<
 
@Kaumudi.H I guess a lot of Indian cooking is done on a hob rather than in an oven.
 
user228700
@JohnRennie Yep.
 
user228700
My friend is here! Ciao! :-)
 
Bye, enjoy the meal!
 
user228700
Thanks!
 
9:44 AM
a lot of apartments here don't come with ovens!
only hobs
I thought it was very strange
 
Yeah, that is strange.
Why no microwave ovens @BenNiehoff?
 
 
2 hours later…
11:32 AM
Hello @JohnRennie
 
 
1 hour later…
12:52 PM
I know roughly properties of spacetimes in 1 to 4 dimensions, but are there specific things above
I know that at $n > 4$ you get non-spherical black holes
Do you get weird shit for $n=279$ or something
 
people are having problems on my question which talks about sexual reproduction using $n$ human beings at biology SE :D
where n > 2
downvotes vs upvotes
 
1:23 PM
So, $E_8$, apparently, is the isometry group of the coset Spin(16)/SU(8)
that's a much easier definition than any other I've seen
@Slereah I know of one interesting thing that happens around 13 or 14 dimensions
for $5 \leq d \leq 13$, black strings are Gregory-Laflamme unstable, and they tend to break up into a fractal "string of beads" if you follow the time evolution
but for $d \geq 14$, the instability instead reaches an endpoint: a stable, non-uniform black string
also Roberto Emparan has a program where he takes the infinite-d limit of Einstein gravity and shows that a lot of calculations become simple
 
Black strings?
 
Hello guys, I have a quick fun question. So today, we had heavy rain in my area, which usually doesn't happen. There was a lot of water clogged on the roads, and getting to the point... no rare experience with rain is complete without driving your car over like 10-15cm of water. Long story short, our license plate got bent. Any idea why this could've happened?
 
@BenNiehoff what the hell?
 
There's also fold marks like the ones you see when you try to fold a really hard cardboard sheet.
 
@YashasSamaga do you have biology subject in 12th?
 
1:29 PM
Yes but I don't study biology.
 
@0celou7 the simplest black string in 5d is the Schwarzschild geometry times a circle
it's a black hole that is extended along one direction
 
so like a donut?
 
a black ring is like a donut
a black string is usually not contractible
 
@YashasSamaga you are from which board? You don't study because it's uninteresting or not in syllabus?
 
National Institute of Open Schooling
 
1:31 PM
but black rings are also unstable, as was shown last year I think!
to see a super sweet movie of a black string undergoing GL instability, look up Lehner and Pretorius
 
@Fawad I am not interested in high school biology but I'm interested in the stuff above high school :P
 
Good then,just keep the limit :D
 
@BenNiehoff Not trying to troll, what does contractible mean for a physicist?
I'm always curious when physicists use words
 
same thing it means for a mathematician, I think
 
Which is?
 
1:34 PM
a black ring is, say, a circle just sitting inside R^4, supported by its own angular momentum
whereas a black string is wrapping the S^1 in R^3 x S^1
 
@Meraj99 Some possibilities: It is possible there are strong currents in the water that push or pull the plate in an asymmetic manner result in the bending, or that the plate bump into something underwater
 
(I'm ignoring the time direction here)
 
Or aliens @Secret
Personally, I never rule them out.
 
Aliens seems pretty implausible for that scenario, but ok
@BenNiehoff I found a 2016 paper and a 2010 paper but no movie, any links to the movie?
 
1:49 PM
the top and bottom are periodically identified
 
hmm, it keeps forming beads
 
indeed
and you can show that something catastrophic has to happen in a finite amount of time
this paper is pretty famous
 
Naive intuition agree with me here: With so many black hole beads packing close together, they are just going to merge into one spherical black hole
 
ah, but it's a theorem in GR that you can't break horizons!
and since the black string is wrapping a non-contractible circle, you have a problem
 
Hmm, so that means the topology of the horizon cannot change, and thus we will expect the outcome will have something similar to the topology of a string?
 
2:04 PM
well, the problem is the cascade keeps going, and in fact it is accelerating exponentially, so it must reach an end state in finite time
but we can't say what that could be!
actually, I think "theorem" was the wrong word to use
basically, this is the cosmic censorship hypothesis
 
btw, what number of dimensions will allow so called hollow black holes, that is a black hole with a spherical shell shaped horizon?
 
that isn't possible
you can have "ringoids" with horizon topology S^m x S^n
but you can't use S^0 as one of the factors
@ACuriousMind would be happy to know that Jose Figueroa-O'Farrill is in fact on MathOverflow, so maybe he can ask him about Majorana spinors!
21
Q: Isometry group of a homogeneous space

José Figueroa-O'FarrillBackground Let $(M,g)$ be a finite-dimensional riemannian (or more generally pseudoriemannian) manifold. Suppose that I know that a certain Lie group $G$ acts transitively and isometrically on $M$ and after a little bit more work I exhibit $M$ as a homogeneous space $G/H$. Let $$ \mathfrak{g} ...

 
 
1 hour later…
3:13 PM
@Kaumudi.H Well, it didn't come yesterday, and now it's not a business day D:
 
vzn
@bolbteppa garrett lisi is quite a character, collected a bunch of links on him once... amusing google fodder. made big waves in popsci press years ago... with lubos a case of hating someone rather similar to himself... o_O
 
3:34 PM
@BernardoMeurer I seem to be finding myself at a contemporary music festival
Help
 
Sweet
Make noises
get an award
 
It's so hipster I can't even
 
No I might get shot
 
3:39 PM
Hi everyone, I am trying to understand this formula: $\frac{\partial T}{\partial \dot r }$
Is this a double partial derivative?
idk if it can clearly be seen, but there is a dot above the 'r' ...
 
@trilolil dot upon $r$ or between $\partial$ and $r$ ?
 
It is not
 
@Fawad upon the 'r'
@Slereah in that case why add a dot on top of the 'r' if you already wrote the partial sign?
actually the entire formula is $ \frac{d}{dt} ( \frac{\partial T}{\partial \dot r } ) $
 
So am I going crazy, or is the uncertainty on energy for a coherent state of the harmonic oscillator zero?
 
Anybody?
@Fawad @Slereah
 
3:52 PM
@YashasSamaga are you Indian and preparing for iit
 
JEE discussions are banned in this chat
(By decree of R.U.)
 
4:16 PM
R.U. = Royaume-Uni?
 
[Philosophy] Bootstrapping oneself to perform an action: Belief
 
4:41 PM
@0celou7 really?
 
 
1 hour later…
6:01 PM
@0celou7 what is RU?
 
@Kaumudi.H It was good
how was yours
 
@KyleKanos I need some basic logic help
 
Oh noes, my wanna-be-adopted son is here, gotta scram!
3
:D
 
What's up?
 
6:10 PM
Have you played 2048, the game?
 
Twice. Beat it the second time, never played it again
 
Okay, keep this in a tab so you can observe what I'll ask
I have to write the game in C for my class
I'm having a little issue with getting the movements to work right
 
user228700
@Koolman I'm a dropper, don't u remember?
 
Would you agree that, given two functions, collapse (which moves all squares in a given direction) and join(which joins neighbouring squares in that direction), that a movement in the game is a collapse, a join, and another collapse?
 
sorry , forget about that @Kaumudi.H
 
6:13 PM
i.e. if you were to discretize a move it would be move all pieces one way, join the same-value pieces in that same way, and move them all again
 
I would probably do it merge then move
 
user228700
@Koolman That's nice :-)
 
That won't work @KyleKanos, look at the above example
if I tried merging there the 2 on the top has no neighbouring candidate
 
@Kaumudi.H so how is jee preparation going on
 
we must flush it down, then merge, and then flush it a second time (in the case the merged result is not at the bottom)
 
6:15 PM
@BernardoMeurer Sure will if you think for a moment more
 
user228700
@Koolman It's... going. What about u?
 
That is, check for an empty square
 
user228700
@SirCumference Oh, OK :-(
 
@Kaumudi.H same
 
something like if (cell[i][j+1] == BLANK_CELL) { compare(i,j,i,j+2) }
 
6:17 PM
Hmm
 
<-- smart :)
 
but don't I have to do that for cell[i][j+1],...[j+2],...[j+3]... ?
 
That would be one way
 
Hmm, I see
 
Another would be to make each number an object. Upon merger, one of the two is deleted
 
6:20 PM
Do you have a GH account?
 
But a 4x4 grid is terribly small
 
mine is 5x5
 
Even still, 25 total cells is nothing
Just remember that your computer can count to a million faster than you can count to 5
 
Hmm
I guess this is better than my double flush approach?
 
Yes
My method is sorta dynamic programming
(I'd assume that the check for empty squares is within the compare(i,j,i,j+1) function
But yes, I do have a github acct
 
6:23 PM
Would you mind taking a look at this thing? I just want to come up with a nice way to do moving robustly
 
Can't w/o links
 
One sec
I'm having an issue with my repo
@KyleKanos Who should I add to the repo?
I have to keep school stuff private during the semester
b/c policy
 
Well I'd just look at it, so can't you send me a link for it?
 
It will probably say you don't have permissions
b/c the repository is private
 
It says it doesn't exist
My account is kylekanos
(makes sense, no?)
Ooh, Euler Totient function
 
6:34 PM
I added you :)
 
I have a Baille PSW prime tester at work
 
Nice!
I wanted to try and implement that!
 
I used it for Project Euler stuff
If I remember, I can add it to my github page
 
I will poke you about it :)
I want to try AKS too
But BPSW is faster than AKS for very large numbers IIRC
 
So is it the SDL example to look at?
 
6:37 PM
No, it's on project01
that SDL example I can delete
Iff you have SDL on your system it should run flawlessly
CMake <3
 
while (quit == 0) sigh
 
hey hey
That's from the prof
not me
is (!quit) that much better?
 
Well you're expecting the user to quit, what about the case where they continue and have no more moves left?
 
To be implemented :P
They need to be able to move at all first
 
So I would do while (!quit && isValid())
 
6:41 PM
Outside that while it just ends the code though
that quit is there to handle the SDL sign-off thing
i.e. delete all the things before exit
 
Well you can add some clean up in isValid()
 
and close, lines 111 to 118
 
(probably would be better to do isValidBoard()
 
Oh, what language?
 
6:42 PM
Aw :(
Never learned that one
 
@KyleKanos I added a note to fix that :)
 
C++ would probably be better for this since you can do some OOP on this, but procedural can work too
 
But, back into moving
@KyleKanos I know, I much prefet C++ for this stuff, but it must be done in C
If you look at what I wrote for the move function it's shit
lel
 
Come on man. Postfix increments!?
 
What? is prefix that much better?
I thought it barely made a difference
 
6:45 PM
For integer types, probably little difference
But the difference is that the postfix creates a copy of the type (ints in this case) before doing incrementing
 
Ah
I did not know that
Okay, ignore all that crap in the move function, say I just want to make move UP work
So I iterate over the columns
 
So for simple types, it's not a big deal because the copy constructor is very cheap. But with derived types (okay, getting into C++ here), it can be more expensive
 
and then over the rows
but go from the bottom up with rows
if it's 0 move the next one up
if it's the same as what's before it then join
 
I think for UP, you should start at the bottom of _board[][] and iterate upwards
For DOWN, start at the top of _board[][] and iterate downwards
 
Exactly
 
6:48 PM
LEFT and RIGHT should start similarly
 
I see, always going from the opposing end
 
Id' call it going in the direction of motion
But I guess that depends on precedence
For example, suppose you have {2, 2, 2, 4}, does that become {0, 2, 4, 4} or does it become {0, 4, 2, 4} ?
 
    for (int i = 0; i<=4; ++i){
        for(int j=4; j>=0; --j){
            if(!_board[i][j-1]){
                _board[i][j-1] = _board[i][j];
                _board[i][j] = 0;
            }
        }
Something like this
Wait
I screwed up some index
* j>0
 
hold on, gotta prep the ribs for cooking
 
        for (int i = 0; i<=4; ++i){
            for(int j=4; j>0; --j){
                if(!_board[i][j-1]){
                    _board[i][j-1] = _board[i][j];
                    _board[i][j] = 0;
                }
                if(_board[i][j] == _board[i][j-1] && _board[i][j]){
                    ++_board[i][j-1];
                    _board[i][j]=0;
                }
            }
        }
Okay, then something like this
But now this happens
For obvious reasons
 
7:02 PM
Hmm. I guess at each index i,j, I would create a compare function that is recursive:
int compare(int i1, int j1, int i2, int j2)
{
    if (_board[i2][j2] == BLANK && i2 < 5)
        return compare(i1, j1, i2-1, j2);
    return (_board[i1][j1] == _board[i2][j2];
}
 
Ah, very smart!
I see
 
Then if this returns true, do a move function, but that's going to be tricky
For compare, you might have to return the location i2
 
When doing up or down I return the i2
but when doing left or right I return j2
 
that way, you can call a function move that moves i,j to i2,j2
 
I smell a TERNARY OPERATOR
WOOHOO
 
7:06 PM
Yeah, you probably could just pass the UP/DOWN/LEFT/RIGHT value to the function
But that is how I'd approach the problem
Of course, I'd do it all in Fortran 2003/2008, but that's just me
 
lol
How do you even do graphics in Fortran?
 
Oh lord
 
I made an implementation of Boggle using Fortran.
The board was only on the terminal (so it was tiny as hell) because I was too lazy to try figuring out how to use gtk-fortran
 
Oh, one more thing, can you check the way I'm passing the array to the move function on the code?
I feel like I'm doing something wrong
 
7:15 PM
I'd probably just make the board global and not worry about passing it anywhere
Kinda lazy, but it's how I roll
 
Can't do that
prof will take me point
 
Hmm
How long before this needs to be turned in?
 
April 15 ot 17
 
Okay, so like 3 weeks
Plenty of time to work out a struct for the board
 
Yes, I think getting a more robust type for the board would be nice
I don't know how to use structs well though
 
7:18 PM
That was really a joke
 
There's no sense in doing a struct here because all you need is a 2D array
 
So?
I can always overkill
 
But anyway, since the dimensions of _board are set in stone, just pass it as int _board[MAX_BOARD_POS][MAX_BOARD_POS]
Well the baby's waking up, gotta scram for reals this time
 
7:35 PM
@KyleKanos Thanks for the help!
 
7:50 PM
@KyleKanos I think that's his initials.
 
@BenNiehoff I know he's there, maybe I will eventually bug him about that
 
@ACuriousMind Howdy
 
heyhey
 
What's going on?
 
Ignore that.
 
7:57 PM
Ignored.
 
8:23 PM
@ACuriousMind Can I have a homomorphism of a finite group into $\Bbb Z$? Don't say yes :p
 
@0celou7 I think you can figure out that for yourself - consider what it would have to do with $g^{\mathrm{ord}(g)}$ for some element of the finite group.
 
@ACuriousMind So the answer is no unless the first group is trivial?
 
@0celou7 indeed
 
9:12 PM
@ACuriousMind well, or it's the trivial homomorphism
luckily that's all I need
 
9:34 PM
Why the change of name @0celou7
 
see the star board
 
which one
It's not french at all
 
9:55 PM
yesterday, by ACuriousMind
@0celo7 So why aren't you 0celou7?
 
frikken cutting and pasting of surface presentations
talk about the worst kind of math
 
10:18 PM
@ACuriousMind I've heard a rumor that one can prove the Riemann-Lebesgue lemma using the fact that translation in real space becomes multiplication in Fourier space. Is that something you'd know about?
 
odd rumor
rumors are usually more celebrity gossip
 
indeed, very strange rumor
 
@0celou7 nope
 
I mean, taking absolute values just gives $|\hat f(k)|=|\hat{f_h}(k)|$, where $f_h(x)=f(x-h)$
So there's not even any information contained in that statement that's useful for limits
 
@BernardoMeurer Forgive me father for I have sinned
I was trying to configure Arch for a local test server, but it was taking too long, so I instead booted Windows and installed IIS
Worst decision of my life
Now I have to delete all this BS manually because Microsoft
 
10:40 PM
One can prove it for compactly supported functions using the dilation operator I do believe
I do believe incorrectly...
Bah
 
10:59 PM
@ACuriousMind what surface is $$\langle a,b,c,d,e,f,g,h,i,j,k,l,m,n,o|abc,bde,dfg,fhi,haj,c^{-1}kl,e^{-1}mn,g^{-1}ok^{-1‌​},i^{-1}l^{-1}m^{-1},j^{-1}n^{-1}o^{-1}\rangle?$$
 
11:33 PM
Riemann-Lebesgue is probably used to prove the existence of Fourier series in your understanding of Fourier series, so potentially circular no?
 
11:52 PM
@bolbteppa No?
Riemann Lebesgue is for transforms, not for series
there might be one for series
probably that $a_k\to 0$?
I think that follows from absolute convergence of the series.
 
hey @0celou7
 

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