To be consistent with data protection laws, we’re asking you to take a moment to review key points of Google’s Privacy Policy. This isn’t about a change that we’ve made – it’s just a chance to review some key points.
@JohnRennie It turns out I wasn't logged in to any of my google accounts. I have three (soon to be four, hopefully): one for work, another for stuff peripherally related to work / my nerdishness (cough physics.SE), and another just for fun. As far as I can tell, there's no way to delete my google account that was specific to my previous job. I just can't access it (which is a good thing). I'm trying to convince my new employer that my previous employer had a good idea.
@Ocelo7 -- Be careful, you might get what you asked for. While PSE's moderation is light, it does not let me tell you that you must be a moron since your left arm is much longer than is your right arm. PO has no qualms about that.
Note: I have yet to retake the harassment training at my new job. I do know however that making jokes about one's gender, one's age, one's religion, one's heritage is completely out of bounds. But if your left arm is much longer than your right arm, I can joke about it. That does not fall into the category of "protected", anywhere. The last harassment training I took used that as an explicit example.
I love the audacity of some of the homework askers. This chap isn't even giving the usual pleas of I tried but can't do it. He's just come straight out and told us to do the problem and post the answer :-)
@JohnRennie -- No,that's probably protected. I was being quite literal when I wrote about having one arm longer than the other. On the other hand, at my previous job, my supervisor (a VP) and the office manager were both females. After grilling me before they made the job offer official, they asked me what I liked to do for fun. I knew what they meant, so I answered "I love taking my three lady friends on romantic walks through the woods and down to the beach!"
My three lady friends? Check my icon. They are real dogs. Quite literally.
@JohnRennie -- Regarding my so-called romantic walks through the woods: My wife has joined me twice on those walks in the last seven years. Both times she has said "never again!" These so-called woods are infested with swamps, mud, briars, spiders as big as one's hands, and poisonous snakes. My arms are a complete mess under UV light. My three "lady friends" (my three female dogs) love it when I let them loose in that mess.
The reason we don't answer homework questions is to discourage people from asking them. It's not that we're unhelpful bastards, we just don't want to be swamped by people trying to get us to do their homework.
I'm a mentor at a potentially competing site that does answer homework questions. There's a big caveat: The person asking the question has to have done some homework. Asking "Do my homework for me!" doesn't work.
@DavidHammen most of us would regard the effort put in by the OP as an important factor. Where the OP has made a genuine attempt to tackle the problem themselves we'd probably stretch a point and answer, or at least give a hint.
So ask at that competing site. You should be able to find it if you have a decent amount of google-fu. Since it is a potentially competing site, I am not going to mention it by name. @JohnRennie, you can let me mention it by name.
Hi guys, I have a wavefunction collapse question that does not involve entanglement:
Suppose I have a set up containing one electron. 8 light minutes away I placed a detector B that can read the spin of the electron (and can flash red if spin up, green in spin down).
Suppose I have a friend Ann standing next to detector B.
Now I use another detector A next to the electron unit to measure my electron spin. Suppose my measurement collapse it to spin up. will I expect 8 minutes later, Ann will inform me her detector flashes red?
Physics Forums have very strong reasons for that format. This site (physics.SE) is not intended to be a homework help forum. We generally close questions related to homework, for good reason. Physics forums does not do that. Helping students to learn is their primary reason for being. That means lots of what would be duplicate questions here get posed, over and over again.
My guess is that when the electron get projected to e.g. spin down eigenstate, that information will need to travel with an upper bound of the speed of light to reach Ann, thus she will see the detector B flashes red. However I am not really sure if there is any chance the information becomes distorted somehow during the travel and causes the detector B to flashes green instead
Well similarly to Fadeev Popov spooky ghosts, I'm trying to remove all field configurations where the field isn't of the same value at the boundary of the wormhole
Why is a field "leaving" or "entering" the wormhole to being with - a field is just some assignment of values to spacetime points, what do you mean by "entering"?
You might need to describe the setup in more detail before I can say anything about this
Q) If v is the velocity of a body moving along x-axis, then acceleration of body is:
(1) dv/dx
(2) v dv/dx
(3) x du/dx
(4) v dx/dv
Please provide the explaination of
the correct option to me as well.
* sorry mistake, that's not a conlinder, because the base of the cone (e.g. in $S_z$) is held fixed as it glue around $S_w$*
So I am guessing, all sets of points indicated by the blue dots and line (since the previous line said the identification is an equivalence class, it is kinda implying I basically have many such pairs of blue points and lines on figure 3, except not drawn for clarity?) are the points being identified in lens space?
and that the two blue points substends an angle of $e^{\frac{2\pi i}{p}}$ relative to the xx' line?
I have a quick question regarding an equation in my textbook. It's about calculating the probability transition amplitude of a quantum oscillator.
Why is this true? The difference between the first and the second row seems to be small. There is a minus sign before $\dfrac{i}{\hbar}$. In the to...
> Since your interests are GR and Quantum Field Theory, with maybe some insight into Quantum Gravity (QG), could you summarize with some technical reasonings, what is known and what key findings are still needed for Hawking et al's conjecture that the BMS super translation symmetries and conserved charges are the basis for doing away with the information paradox?
Q) If v is the velocity of a body moving along x-axis, then acceleration of body is:
(1) dv/dx
(2) v dv/dx
(3) x du/dx
(4) v dx/dv
Please provide the explaination of
the correct option to me as well.
I have a quick question regarding an equation in my textbook. It's about calculating the probability transition amplitude of a quantum oscillator.
Why is this true? The difference between the first and the second row seems to be small. There is a minus sign before $\dfrac{i}{\hbar}$. In the to...
