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2:03 PM
@Qmechanic Pad or pat?
 
2:18 PM
This is the reason I love stack exchange
2
5
A: Orbital velocity of a planet - why is my calculation off by about 10%?

Rob JeffriesWell done you. I double checked the calculations and couldn't fault what you had done. So I contacted the lead author of the paper about it and here is the response: "After checking the numbers in our paper, I found an error: we actually used a mass of 1.0 MSun for J1407 in our simulations, inst...

It makes genuine contributions to science
 
http://zeroescape.wikia.com/wiki/Bootstrap_paradox
This is NOT your garden variety bootstrap paradox. It has a more complicated structure
For years all that progress in developing a time travel model is to be able to calculate this for any frames of reference
 
@0celo7 To prepare for the bullies
 
user228700
@SirCumference Oh my God! :-o
 
To prepare for you, you mean?
 
2:36 PM
@Kaumudi I know, right?
 
@BernardMeurer Maybe I should write an analysis book that ends with GR
 
@0celo7 : Ups. Thx.
 
Damn it SpringerLink, give me the paper, not unspecific errors. I could view the articles page just fine, but after I logged in to access it, it just throws "unhandled error occured".
 
Hi Bajoran
 
Aha, now it suddenly cooperates :P
 
2:45 PM
you broke its spirit
 
There's nothing worse than paying for a paper, and finding out it was in French
So you can't read it
 
@0celo7 I'd appreciate it if you'd finally quit this.
 
wtf why would you pay for an article?
 
why on earth is that link removed?
 
I'm tired...
 
2:46 PM
@Danu I mean you walked right into it
 
@DHMO Please do not post direct links to illegal (or questionably legal) download sources.
 
@ACuriousMind policies on different chatrooms lol
 
user228700
@SirCumference Aren't u supposed to have woken up just now? Ohh, u were up till 4 yesterday (well, at least u were here) I remember :-P
 
@0celo7 I don't really care.
I just think it's time to cut it out.
 
Say, if a relative of mine has published a paper in a journal, can I just bypass all the paywalls?
That sounds fair...
@Kaumudi Yep...
 
2:52 PM
Can't you just ask the relative to send you a copy?
 
@ACuriousMind I'm not looking for the paper he published, I just want to know if it grants us some kind of membership
So I could get any paper
 
Uh, no, you don't get any right to anything just because a relative of yours has some rights to it.
 
@ACuriousMind :(
Does he get a membership? Or a discount of some kind?
 
A "membership" where?
 
For the journal
 
2:56 PM
People who publish papers will typically be employed by a university and have access to a large range of journals through their university anyway
 
He's retired tho
Hell, if someone buys access to his paper, does he even get some of the money?
 
I have no idea what type of access retired academics retain, it probably varies a lot by case.
@SirCumference Of course not, researchers don't earn a single penny from their papers as such.
 
@Danu Yes, my liege.
 
@ACuriousMind Then...what's the point of publishing? That sounds like a horrible deal, considering how long it takes to write a paper
 
@ACuriousMind In Europe maybe.
 
2:59 PM
Dear lord, trying to find where exactly in this 111 page monster the inequality I want to see derived is stated is...annoying.
 
Many American universities that are not R1 don't have Springer or whatever.
 
@0celo7 Thanks.
 
@SirCumference For a reference for my statement that researchers don't earn anything directly from the paper and other publishing models, see e.g. this academia.SE question
 
@ACuriousMind I remember @dmckee complaining he didn't have access to some non-obscure journals.
 
@0celo7 I said "typically" and "large range", not "every academic can access every journal". What's your point?
 
3:05 PM
None apparently.
 
3:28 PM
@Danu Any idea what "The flat direction associated to the breaking has a corresponding massless scalar fluctuation from the broken vacuum, represented by a supergravity mode; as such, $b_3(X)$ necessarily increases" is supposed to mean? Why would the presence of a massless scalar tell me something about the third Betti number?
 
3:47 PM
 
@ACuriousMind is a scalar associated with a de Rham 3 form?
 
GR analogue: CTCs
Caption: No explanation needed on why things suddenly came out of thin air. They are just there
 
@ACuriousMind Ah
 
@0celo7 They appear to be implying that (maybe that's hidden in the "represented by a supergravity mode"), but I really don't know what exactly they mean.
 
So do you know this grouping into multiplets in the effective 4d theory stuff?
 
3:48 PM
@Danu Yes (sort of)
 
So there are these multiplets that have scalars. Perhaps if you have a new scalar (and force SUSY, I guess) you are forced to have another multiplet.
The multiplets count Hodge numbers IIRC.
 
Ahaa
 
It's in Luest's book.
The idea is that zero modes count cohomology
somethingsomething index theorem
 
Let me check my ST notes on that, I do recall something about multiplets/Hodge numbers
 
On the star board, in my post starting Although this has no really good answers..., the two exclamation marks in the brackets show in blue as if they were a hyperlink. Is this just me or does anyone else seem then in blue as well?
 
3:54 PM
Just you.
@JohnRennie what does one do about hemorrhoids, anyway?
 
user228700
@S007: U were totally right about forcing Hückel's rule BTW :-)
 
@JohnRennie I think that's just an optical illusion, they look a bit like that on my screen too, but when I go closer to the screen, the blue..."fades away".
 
rob
@JohnRennie Sounds like an anti-aliased font, perhaps, with the narrow ! leaking into the adjacent pixel.
 
Nope, they really are blue ...
 
rob
3:56 PM
@JohnRennie Note the extra colors in the A and g of "Although"
 
@Danu Hmmm, yes, thanks, I guess the reasoning about why the metric moduli count Hodge numbers applies here too, just for ordinary real cohomology
 
Hmm, yes, just a quirk of the way Chrome is rendering the text. I've just tried with IE11 and that shows the exclamation marks as black.
 
It's a bit cryptic though because I'm not actually varying a metric, but the $G_2$-3-form. Which nevertheless fulfills similar equations, so, the reasoning carries over
 
And if I increase the text size in Chrome the exclamation marks go black. Oh well, another searingly important issue solved.
 
@ACuriousMind Somethingsomething math :D
@ACuriousMind Forms also contribute to Hodge numbers
 
3:59 PM
@Danu I don't have Hodge numbers, I'm not on a complex manifold! But, yes, I get the point
 
@0celo7 nothing I'm afraid. There is no cure. They will disappear after a few days by themselves. The key point is not to get any more, which means eating lots of dietary fibre.
 
Right, sorry
No CY
 
@JohnRennie I don't have them btw. Just wondering.
 
Question: say I want the cosmic scale factor at a given time $t$. I'd need an object's distance from me now and at $t$. I know an object's distance from me now, but how could I mathematically determine its distance at $t$?
 
@0celo7 A couple of years back I got a, i.e. one, haemorrhoid. My doctor said I could either eat lots of fibre or have a sore bum. I elected for the fibre and so far I have not had a second one.
... continued on the John's medical tips for embarassing diseases Stack Exchange.
 
user228700
4:09 PM
Well :-P
 
user228700
@S007: To be clear tho, ur wording when u first explained it was a little weird...
 
4:28 PM
7 messages moved to Trash
 
Lol
 
user228700
Dude. 13 is not old enough.
 
@Kaumudi I understood it all by third grade
 
user228700
@0celo7 Damn. I'm sorry, man :/
 
Why are you sorry?
 
user228700
4:29 PM
@JohnRennie: Thank you :-)
 
user228700
@0celo7 Nvm.
 
14
Q: How does the Hubble parameter change with the age of the universe?

John RennieHow does the Hubble parameter change with the age of the universe? This question was posted recently, and I had almost finished writing an answer when the question was deleted. Since it's a shame to waste the effort here's the answer anyway. Maybe this can be one of the canonical answers sugges...

 
John, you should change your picture.
 
user228700
^No, don't.
 
@0celo7 No
0celo changes his every month. It's confusing
 
4:43 PM
No it's not. They all have a theme.
 
@Ocelo7 Moin, how are you ?
 
Ok
How are you?
 
I'm fine... Just studying topological string theory
@Ocelo7 I know it's been a long time, but what actually happened to your Ricci-flow problem ?
 
5:35 PM
@PhysicsGuy I somewhat solved it, not too convinced though.
 
5:53 PM
@Ocelo7 What do you get if you cross an elephant and a chicken ? The trivial elepant bundle over the chicken.
 
@0celo7 If I didn't have classes during Thanksgiving I'd join
@rob That is some stellar piece of advice there, thanks for sharing that.
 
rob
@BernardMeurer My pleasure.
 
@rob I wish your profile was less cryptic sometimes, you seem like an interesting guy
@knzhou Sup dawg
 
rob
6:09 PM
@BernardMeurer As it says, "Get used to disappointment"
On the other hand, you know what my favorite movie is
 
@rob Ha, indeed, I do
@ManishEarth Hello fellow human
 
6:21 PM
@BernardMeurer What?
 
@0celo7 What what?
 
what are you talking about?
 
I'm saying I would go over there for Thanksgiving but I have classes
 
Ok, why are you assuming my parents would invite you?
 
Not your parent's, Bob would kill me
wherever Michelles is lol
 
6:24 PM
In Houston.
Although I don't think Jay would invite you either.
 
Of course he would, I'm exotic
They need me to meet their thanksgiving diversity quotas
 
Jay does not have diversity quotas.
Also you're white.
 
We'll see about that once Hillary wins
 
6:45 PM
$$\textrm{Cooking} \subset \textrm{Chemistry}\rightarrow\textrm{Chemistry}\sim\textrm{Cooking}$$
 
@BernardMeurer give me $100 and I will write the best analysis book
 
@0celo7 No thanks
I don't have anything close to 100 bucks
I'm saving to buy CIV VI
 
Get Michelle to give me then
 
@ACuriousMind You like Civ right?
@0celo7 Lol, You sister likes me, but we could be married for 20 years and I don't think there is anything I'd be able to do to make her give you 100 bucks
 
@BernardMeurer Yes, probably played IV the most though and likely won't get the new one until it's on sale
 
7:01 PM
@ACuriousMind I've heard it's so good though :/
i really need a game to decompress right now
 
@BernardMeurer There is so much wrong with that picture.
@ACuriousMind I've accepted that I'm a nerd. I'm sorry for making fun of you for being one.
 
@BernardMeurer Sure, but I'm not enough of a Civ fan to pay full price for that game if I already have the last two (also very good) iterations
 
@ACuriousMind Civ V was my favorite so far
Beyond Earth was a piece of shit
 
Ah, didn't play BE
@0celo7 Well, no need to apologize, but good to see you've accepted what you are ;)
 
@ACuriousMind Don't. It's really bad
@0celo7 You're friends with me, there was no possible way you weren't a nerd
 
user218912
7:10 PM
@0celo7 well I'm not a nerd.
 
@ACuriousMind What do I do now?
 
@0celo7 You...get on with your life?
 
@obe You only wear blue clothing, you're very much a nerd
 
user218912
@ACuriousMind can you help me do an integral which is $$\int d^3k \int d^3k' Ae^{B(k-k')^2}$$
 
user218912
just a hint pls
 
7:13 PM
@obe Only if you help me figure out how FreeBSD handles networking
 
user218912
@BernardMeurer idk what that is D:
 
user218912
@BernardMeurer I'm changing my ways, I wear black shoes now.
 
@obe It's okay, no one that expects to have sex someday should know what FreeBSD is
 
user218912
lol
 
@obe It's just a Gaussian integral. Forget that you're supposed to integrate over both $k,k'$ and first do the integral over one of them as you would usually.
 
7:14 PM
What happened to the Slovenian lady?
 
@0celo7 We're married now
 
No you're not. You would have invited me.
 
user218912
@ACuriousMind oh so that works
 
user218912
thanks
 
user218912
didn't realize i could do that :(
 
7:17 PM
How else are you going to do multiple integrals?
 
user218912
idk
 
user218912
proves i'm not a nerd
 
@0celo7 We are married
 
@BernardMeurer what?
 
@ACuriousMind I know your secrets
 
7:23 PM
1. He's quoting me, not pissing me off. 2. If you mean to imply I'm a Nazi, stop that.
 
Don't stop.
 
@0celo7 ...what?
 
user218912
this chat makes no sense
 
user218912
also I did the integral
 
What would Khaled do?
They want you to stop.
 
7:25 PM
@ACuriousMind I just like poking fun at you because you vote for AfD
::hides::
 
@obe I concur.
 
Your face makes no sense.
What is the longest acceptable finger nail length for males?
 
@0celo7 Do you play guitar?
 
@ACuriousMind Changing topics.
@BernardMeurer I'm tone deaf.
 
@0celo7 Yes, that was evident by your non-sequitur question. Why did you feel the need to clarify that for me?
 
7:31 PM
@0celo7 Then very short
I'd say about 1.2mm longer than your fingertips
 
Wtf that's horrifying
Longer than fingertips?
@ACuriousMind Just letting you know, chill.
 
@0celo7 You asked for the longest
 
8:17 PM
@BernardMeurer do you need analysis help
 
8:54 PM
GRAAAHHHHH
Can anyone explain the tons of things I don't understand about degenerate gases to me?
We're going over it in class, but since the professor talks at a ridiculous speed and the info is new to me, I'm getting confused
 
9:22 PM
...anyone?
 
rob
@SirCumference I'm not prepared to type out a lecture on degenerate gases over chat, but I can possibly clarify some things if you have specific questions.
 
@rob First of all, why does the degenerate radius increase with mass for a while, but decrease after we reach the necessary pressure to compress an atom?
 
rob
@SirCumference Hmmm, I only remembered the second case. The thermal contraction (or negative thermal expansion coefficient, or however you parameterize it) arises because heating the gas increases $\left< p^2 \right>$ and thereby $\sigma_p^2 = \left< p^2 \right> - \left<p\right>$; $\sigma_x^2 is allowed to decrease according the uncertainty principle.
But you're talking about radius of a degenerate-matter star, yes?
In that case, it's probably that the relationship between density and pressure is nonlinear in a different way than the relationship between mass and pressure, so that there's a mass region where they compete.
Consider that $e^{-x}$ (positive x) has a maximum at zero, and $x^2$ has a maximum at infinity, so $x^2 e^{-x}$ has a maximum "in the middle somewhere."
 
 
1 hour later…
user218912
11:03 PM
hey
 
@obe whats up
 
Hey
 
how can the absorption spectrum of a blackbody (e.g. the Sun) be used to determine its composition? by definition, doesn't it absorb every frequency?
 
rob
@dm__ Blackbody emission, line absorption.
In physics and optics, the Fraunhofer lines are a set of spectral lines named after the German physicist Joseph von Fraunhofer (1787–1826). The lines were originally observed as dark features (absorption lines) in the optical spectrum of the Sun. == Discovery == In 1802, the English chemist William Hyde Wollaston was the first person to note the appearance of a number of dark features in the solar spectrum. In 1814, Fraunhofer independently rediscovered the lines and began a systematic study and careful measurement of the wavelength of these features. In all, he mapped over 570 lines, and...
 
awesome, thanks!
 
11:22 PM
@heather Young one
 
@0celo7, nice, just as I was on the computer. I am present.
 
Today I will each you what a sequence of real numbers is.
And what it means for such a thing to have a "limit"
 
You're going to discuss sequences ?
 
yes.
 
Ah, yes, coincidentally, I was reading a bit about limits.
(got the cartoon guide to calculus by larry gonick; it's pretty good)
 
11:24 PM
Do you know what the absolute value is?
 
closer, and closer, and closer, and far away!
 
sure, it's the distance from zero; distance can't be negative, so it turns negative numbers into positive numbers. I can write out the function if you want.
 
Yes, write it out
Because that's a bad definition
Oh the second part is good
Write it out
 
$f(x)$ $x\geq 0, x$ $x<0, -x$ (don't know how to do stacked thing right of the tall curly brace)
 
@heather Are you an autodidactic learner ?
 
11:28 PM
uh
 
@PhysicsGuy, what's that mean?
 
That you teach the things yourself.
 
@0celo7, is that wrong?
 
I mean without a professor or teacher
 
@heather use f(x) = \begin{cases} x & x \geq 0 \\ -x & x <0 \end{cases}
 
11:29 PM
@PhysicsGuy, I guess, yeah
one moment, be back soon
 
@ACuriousMind how the hell do you remember such things?
 
@ACuriousMind What happened to MathJax ?
 
@0celo7 I just have a rather good memory
 
:/
life isn't fair
 
@PhysicsGuy I escaped it so that I could tell heather the commands she needs to use for the "stacked thing right of the tall curly brace".
(One escapes it by enclosing it in backticks)
 
11:31 PM
Okay
 
@0celo7 Yep, it most assuredly isn't :/
 
Do y'all know which questions I really hate ?
"Is the universe infinite ?"
"Do you believe in parallel universes ?"
 
In mathematics, the notion of being compactly embedded expresses the idea that one set or space is "well contained" inside another. There are versions of this concept appropriate to general topology and functional analysis. == Definition (topological spaces) == Let (X, T) be a topological space, and let V and W be subsets of X. We say that V is compactly embedded in W, and write V ⊂⊂ W, if V ⊆ Cl(V) ⊆ Int(W), where Cl(V) denotes the closure of V, and Int(W) denotes the interior of W; and Cl(V) is compact. == Definition (normed spaces) == Let X and Y be two normed vector spaces with norms ||•||X...
@ACuriousMind Re the two bullets for normed spaces: doesn't the second imply the first?
Compact maps are automatically continuous, no?
 
@0celo7 The text below the bullets seems to say that that's only for Banach spaces.
 
What is yellow and curved ?
A Bananach space
 
11:41 PM
Note that if $Y$ is not Banach, then the sequence being Cauchy does not imply it converges, i.e. you can't conclude that the image of the bounded set is precompact.
 
@ACuriousMind Did you take a formal course on measure theory (Borel stuff)?
 
@0celo7 never
 
You didn't need it for FA?
 
What little I know of measure theory is from a very rushed "review" in FA
 
I might have to know what a Radon measure is.
 
11:42 PM
And another rushed review in that course on the unitary representations of the Poincaré group
 
So you know what a Radon measure is?
 
In mathematics (specifically in measure theory), a Radon measure, named after Johann Radon, is a measure on the σ-algebra of Borel sets of a Hausdorff topological space X that is locally finite and inner regular. (Intuitively, it is useful in mathematical finance particularly for working with Lévy processes because it has the properties of both Lebesgue and Dirac measures, as unlike the Lebesgue, a Radon measure on a single point is not necessarily of measure 0.) == Motivation == A common problem is to find a good notion of a measure on a topological space that is compatible with the topology in...
 
Yes I can google too.
 
What's your ptoblem with Radon measure ?
Image not found....
 
There's too much to remember without taking a class on it.
 
11:44 PM
@0celo7 I only ever used it in the form as a functional on continuous compactly supported functions, not in the actual measure-theoretic form
 
@ACuriousMind There's a way of viewing submanifolds of $\Bbb R^n$ as Radon measures, apparently.
 
@Ocelo7 How ?
 
If I knew what a fucking Radon measure was, I could tell you.
 
Probably for $X\subset\mathbb{R}^n$ as $f\mapsto \int_X f$, hm?
 
Yeah.
 
11:48 PM
@0celo7 I think that saying "Radon measure = linear functional on continuous functions" is pretty much all you generally need to understand under a Radon measure
 
Well, they write $\mu(A)=\mathrm{vol}(A\cap \Sigma)$ for $A\subset\Bbb R^n$ a borel set.
For $\Sigma$ the submanifold.
 
Its main use is "something you can integrate against", so you might as well cut out the middle man and directly think of the integration rule as the "measure"
 
Well, they're going to treat you like Seargant Hartman.
When is your test ?
 
@ACuriousMind What is the "weight" of the measure?
 
@0celo7 no idea
 
11:52 PM
"weight" ?
 
> A $k$-varifold on $\Bbb R^n$ is a Radon measure on $\Bbb R^n\times G(k,n)$.
wtf
 
Oh man, Varifolds.....
 
@ACuriousMind Did you ever talk about compactness of Radon measures (?)
 
@0celo7 Possibly? We only taked about these measures to use them, and forgot about them as quickly as we could after we didn't need them anymore
Basically all I can do off the top of my head is the Lebesgue process on a measure to get a proper integral out of it.
 
Maybe I should just take these results for granted.
 
11:58 PM
Can someone explain the difference between the cosmic microwave background and cosmic background radiation?
 
Yes.
 
@ACuriousMind You can remember all that semicontinuity crap?
 
@SirCumference The former is a specific type of radiation left over from the recombination phase, the latter is the entirety of all radiation filling the cosmos approximately homogeneously.
 

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