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11:11 AM
When I was in secondary school there was a nine-grade scheme: U for "ungraded" (fail), and (in increasing order) G, F, E, D, C, B, A, A*, where C and above meant "good pass".
I found it quite absurd, since anything less than C would basically be inadmissible for further study.
 
@ZhenLin How ever did they keep track? :o
...and was there a point in being able to tell how much of a failure you are? (i.e. the "underwater" grades)
 
Well, I suppose it must be a leftover from the old days when they merged two (or more...?) separate exam systems. Apparently there was one ("O-levels") for people who intended to continue past the age of 16 and one for people who did not.
I think the "O-level" grades got mapped to the E - A range.
Mind you, the G - D range are still considered pass... at least officially. In school comparison statistics I think it counts as a fail.
 
Yeesh. Grades are one of the things I don't miss seeing from school...
 
11:33 AM
@JM Meow?
 
@JonasTeuwen hi
 
@Ilya Hi! 8-).
 
@Jonas: it's broken only in the corner, but I have to change the whole glass of course :(
 
Hello Ilya and Jonas. Why does Jonas have whiskers today?
 
@Ilya What is broken? :-).
 
11:35 AM
@Jonas: here
 
@Ilya Oh how come?
 
dropped it on the floor at home, even the cover didn't save it
 
Sucks. What does that cost?
A little less than 200 EUR it seems...
 
@Ilya Is there an Apple Store you can get to?
 
@robjohn hi, 250 EUR there, and 5-10 working days
 
@Ilya Hmm. My son got his fixed for free, but we had AppleCare.
 
@RobJohn that's why I guess
@Jonas: yeah, there is a nodefix center in den Haag, 200 EUR there and 5 days. There is one repair center in Leiden, 150 EUR and 1 day
 
@Ilya You didn't buy AppleCare?
 
hey any moderator around?
 
@BenjaminLim JM is here
 
11:40 AM
I'm not a mod here... :P
 
@robjohn nope. I thought I'm old enough not to drop it on the floor. I was wrong :(
 
My friend just sold his iPad for £200+...
 
@JM Heh, I saw that. Tempted to reply: so is algebraic topology, simplicius
 
@tb the latter comment of him is also nice. Or maybe, the last one
 
11:42 AM
@tb "If I fail I will be deleted." - :D
 
@JM we have a new president now, you know
 
This Applecare is way too expensive. You will probably not break your next five iPads 8-))).
 
@Jonas: oh, you're playing with a fire :D
 
@Ilya Oh, not Medvedev anymore?
 
@JM nope, but he maybe will be a new prime-minister
@JonasTeuwen I don't remember how much was it, but it was about a half of price of an iPad
 
11:45 AM
@Ilya A new-old president.
 
Can I haz screwdriver?
 
@JonasTeuwen ?
 
Yes, I want to marinate something!
 
@JonasTeuwen ?
 
11:48 AM
??
 
Stop mocking my unicorn!
 
@Ilya: About half the price of new iPad. You might actually be able to get a second-hand one for the same price as fixing the screen.
 
@JonasTeuwen ?
@TaraB why do I need it? :)
 
@Ilya 8-). Do you know the Ornstein-Uhlenbeck semigroup?
 
@JonasTeuwen not much more that about any Markov semigroup. Why?
 
11:50 AM
Bunny will hunt you down and feast on your soul!
@Ilya Okay. I want to prove the contractivity.
 
@Ilya: Well, it might be quicker than getting yours fixed.
 
@JonasTeuwen weak one?
@TaraB how do I know that a new one is ok, ah?
 
@Ilya: Or are you not going to get the screen fixed?
 
@Ilya $\|e^{t L} f\| \leq \|f\|$.
 
@TaraB It's the funny thing nowadays: buying a new device is cheaper than having your old one fixed. Jeez.
 
11:52 AM
@JonasTeuwen which norm?
 
@JM: Yes. I dislike it. It's especially noticeable with mobile phones.
 
@JonasTeuwen Screwdrivers don't taste so good, even when marinated...
 
@Ilya $L^1(\gamma)$.
@JM Hmm... Then I must pick something else!
 
@JonasTeuwen pick pickles
 
Marinated pickles?
 
11:53 AM
@JonasTeuwen yes
@JonasTeuwen it is not done yet?
 
But then that bastard Asaf will devour my pickles :-(.
@Ilya It is! But in infinite dimensional spaces 8-)).
(By my advisor)
 
@JonasTeuwen don't worry, he is far away from you
@JonasTeuwen so you want to prove the result proved for infinite-dimensional space for a finite-dimensional case? 0_o7
or it is an exercise?
who the hell has flagged that???
@Jonas: Dynkin has the theorem which gives necessary and sufficient conditions for a linear operator to be a generator of a contraction semigroup
everybody left...
everybody right
everybody, hands up
everybody fight
 
@Ilya No, I want an easier proof.
@Ilya I use Hille-Yosida!
 
@JonasTeuwen easier than your supervisor?
 
@Ilya Easier than his proof 8-).
 
11:59 AM
@JonasTeuwen the same as in Dynking: based on resolvents
 
@tb Do you actually know a strongly continuous semigroup with operator norm strictly smaller than $1$? I have some proof (thanks Markus!) which states this is not possible as you have something like if $M$ is the norm that $\|x\| \leq \frac{M}{\lambda} \|Ax\| + M\|x\|$.
 
render
 
So then you send $\lambda$ far far away on an eternal journey.
 
@JM I wanna delete a question
 
@Jonas: what about taking a strongly continuous $P_t$ and considering $\frac12 P_t$?
 
12:02 PM
@Ilya Hmm... There is something missing! 8-).
 
@JonasTeuwen what?
 
@BenjaminLim why can't you do it yourself?
 
I don't know.
 
@JM There are already answers on it
 
@JonasTeuwen Well, it has the legs for walking...
 
12:03 PM
@Ilya You get this from $A R(\lambda, A) + \text{stuff} = \text{stuff}$.
 
@BenjaminLim Then that wouldn't be fair to the answerers, no?
 
well um
@JM could I notify the rest?
 
@Jonas: I better call you - are you in the office?
 
@Ilya :-). Yes.
 
@BenjaminLim Yes, you could try asking the answerers...
 
12:06 PM
@JonasTeuwen You mean $\|P_t\| \lt 1$ for all $t \gt 0$?
 
render
 
@tb Yes, but I seem to be confused...
 
@JM Is there a way to hammer a CW into all my posts at once?
 
@KannappanSampath None that I know of. So that's why I was seeing those old questions suddenly...
 
@JM But, making it a CW bumps posts?
 
12:10 PM
Only temporarily, it seems. They disappear when I refresh the front page.
 
Good for me. only 300 posts. It should be over in an hour.
 
@KannappanSampath What the? Why would you do that? 8-).
 
For fun?
 
You're even more wacko than I am. Did one of those monkeys that devoured your biscuits bite you?
 
a strange way of doing fun
 
12:12 PM
I don't believe that's the kind of CW that can be reversed by mods. Be sure you know what you're doing...
 
@JonasTeuwen right now I can only think of boring examples.
 
I don't want to reverse that at all. Soon, I'll also write to the mods that my account be deleted. But before that, I'll delete all my comments.
 
@tb Yes, under some conditions you can show using the resolvent that $\|x\| \leq \frac{M}{\lambda} \|Ax\| + M\|x\|$ where $M$ is the operator norm?
@KannappanSampath Huh. Why?
Do you have rabies?
 
Because this place is full of so many good people. I guess I am not worthy to be a user on this site.
 
Hmm... That's a strange reason.
But there are many more idiots than there are many good people!
And you're one of the good people.
 
12:17 PM
@kahen hey
@KannappanSampath please don't freak out.
 
Hello again!
 
@Ben I am not freaking out. But, this time, I am sure about what I am doing.
 
@KannappanSampath why are you sure?
 
Ayhoy thare Landlubbers, ye oldie mate is back again =)
 
12:19 PM
@BenjaminLim I think he got bitten by one of them holy monkeys!
 
Anyone want to give me some hints about a flux integral ? Or calculating the flux out of a surface.
 
Hmm, the circumstances prevailing in this site lately clearly indicate to me that I am not a worthy user of this site. That I should quit at the earliest possible for the best functioning of this site. So, I'll oblige to the call of the community. I will quit, but I need my own time before I can settle this issue properly.
 
@Ilya hi. первый раз вижу :)
 
@N3buchadnezzar which one? Gauss formula, maybe?
 
I may not be able to hammer CW all at once. But i'd finish as quickly I can.
 
12:21 PM
@Nimza говорят, Иван Иванович - распространенное русское имя
 
I learnt some Russian yesterday! - Itina hoeij!
But Ilya has explained that it is not a good thing 8-).
 
@Ilya I have $F = (x,y,z)$ and need to calculate the flux out of the triangle bound by the coordinate axis and (1,0,0) (0,2,0) and (0,0,3)
 
@JonasTeuwen ah, sorry - I had to escape and I hope it was not rude from my side just to write a translation
 
No :-)).
 
Pjalsta
 
12:23 PM
use the formula via projections:
$$
\iint x \mathrm dy\mathrm dz+ y\mathrm dz\mathrm dx + z \mathrm dx\mathrm dy
$$
render
 
Yeah, I was thinking about using stokes
And do a projection onto the xy plane, does that sound good?
 
Kannappan, I don't know what else to say, but: be sure; think long and hard and be sure that this is what you want.
 
@N3buchadnezzar it does. I mean, the surface suggests to do that, I think
don't forget to calculate the Jacobian - although it's just a determinant of a constant matrix in this case
 
There are only a few worse feelings than regretting something that was entirely done on whim and caprice.
 
@Ilya I know, but why the xy plane, I mean would it work if I did it on any other surface?
 
12:25 PM
@JM Can holy monkeys carry rabies?
 
@JonasTeuwen I do not think a rabbi, would be happy to be carried by anyone. Especially not a holy monkey.
 
@N3buchadnezzar sure, Jacobians would be different and that's it. When you do the projection, you parametrize the surface on another surface (usually on the plane, of course) and then do an integration of the original function on the another surface, paying for this the price of Jacobian
 
@JonasTeuwen Yes, monkeys can be rabid... any mammal can be rabid.
 
@Ilya This is all very new to me, thanks a lot for trying to explain it.
 
@N3buchadnezzar I like your trying :D
 
12:28 PM
So by stokes theorem I can do a path integral in the xy plane, so this would be a path for example (0,0,0) to (1,0,0) and to (0,2,0)
 
@N3buchadnezzar which stokes theorem do you refer to?
 
OH, sorry I forgot there were more..
 
@JM But is it common? Say with the ones that come into your kitchen to devour your biscuits! 8-).
 
$$ \oint_C F \cdot dr = \iint_R \text{curl} F \cdot \hat{N} ds $$
 
render
 
12:31 PM
@Ilya There is this Australian professor (used to be from the Sovjet-Union). He just passed me and said: "Now I know what you like to do in your spare time! Let's do this together one day"
 
@N3buchadnezzar which is in 3d?
 
So I was like... What the?
Apparently some guy told him I like to drink 8-).
 
@JonasTeuwen you can only hope for this :) isn't it a supervisor of @BenjaminLim?
 
@Ilya Is this not in 3d? In regard to the triangle we sort of have a 2d surface right?
 
@Ilya No, he is from Sydney.
 
12:32 PM
@N3buchadnezzar F is 3d or not?
 
F is 3d.
 
@Jonas: but who told you about иди на хуй? I guess, not a professor :)
@N3buchadnezzar well, ok. But in your case you don't know $F$, you know only $\operatorname{curl} F = (x,y,z)$, right?
 
Opposite
 
ah, so you need to find
$$
\oint\limits_{\partial T }F \mathrm dr
$$
where $T$ is the triangle?
why not to do it directly?
 
Yeah, or the problem only asks me to find the fluks out of the surface S.
Where S is the surface made by the triangle.
 
12:36 PM
@N3buchadnezzar ok, write me here an integral you think you're intended to find
 
$$ \iint_S F \cdot n = \iiint_T \text{div} F \, \mathrm{d}V $$
 
render
@N3buchadnezzar there are two integral. which of them do you need to find? what is $S$ and what is $T$?
 
My group theory tag is completely CW now. Tommorrow I have an exam in probability. So, I'll not be able to spend more time on this. But, atleast this should give the members of the community an indication that this fool is leaving the site, which would be a reason for them to be happy. I am sorry to put you to so much of inconvenience. I'll be done definitely in a few more days. Please bear with me.
2
 
@JonasTeuwen That I have no idea of...
@JonasTeuwen Weren't you bemoaning the lack of drinking buddies many moons ago? This seems like a nice development...
 
12:51 PM
@Kan: what's going on?
 
@JM Is there some recommended action that one should take with edit suggestions such as this one? I copied the comment and posted it to the answer but is this really what one should do? It happened a few times over the last week and I did similar things, but I'm not entirely sure.
 
Well, he misspelled "recommend" the second time... on the other hand, I don't know, it seems what you've done is making the best out of an unideal situation.
 
@KannappanSampath I really wonder how you come to have the idea that people think you are a fool. I'm sure they don't, and I for one certainly do not. You have one conflict with one user that spills over and over again and I find it more tiresome than anything else. I can understand that you're upset, sure, but I think I can also understand the other side.
2
@JM okay, thanks. That's what I thought. Just making sure if there's some ideas out there that one shouldn't do it.
@KannappanSampath In any case I will miss your contributions a lot if you decide to leave. Please take a deep breath and reconsider.
6
 
1:14 PM
@tbee Do you know what precipitated Kannappan's reaction?
 
Lack
of
maturity.
 
1:34 PM
Anyone here?
 
Are there any algebraists around?
 
I'm trying to find the term containing x^3 in the binomial expansion of (3x-2)^10.
I'm a teensy bit confused though.
If I multiply everything out, I end up with 1080x-128, which doesn't contain the power of three anymore.
Did I do it wrong?
 
@Moshe why don't you post a question
@Moshe let us work carefully
the coefficient of $x^3$ in the expansion is:
or rather let's look at the $x^3$ term
we have:
$\binom{10}{3}(3x)^3\times 2^{10 - 3}$
 
@BenjaminLim: Yes, why?
 
@TaraB Let $S$ be the following multiplicative set
$S = \{1,f,f^2, \ldots \}$
I want to consider the basis open sets of the Zariski topology so let's assume that $f$ is not nilpotent
Otherwise $S^{-1}A \cong 0$
Now
In Atiyah Macdonald
 
1:40 PM
@BenjaminLim: I was about to say before you started asking your question: although it might depend what sort of an algebraist you're looking for. I do groups and semigroups.
 
@TaraB Familiar with localisation and the zariski topology?
 
@BenjaminLim: Sadly not really.
 
ah ok
@TaraB are you postgrad or something?
 
I read a tiny bit of Atiyah Macdonald once, but only because I was using a theorem from it.
Postdoc.
 
@TaraB May I know where? I'm at ANU
 
1:41 PM
@BenjaminLim - Trying to, it's messing up the two digit exponent.
 
St Andrews (UK). But I'm from NZ and some of my friends did their masters' at ANU.
 
@TaraB Ah ok St. Andrews.
@TaraB I'm just next door! Although I got to say that in the Rugby world cup final last year many people here wanted france to win in the final :D :D :D
because you guys knocked us out!
 
I considered doing a summer scholarship at ANU myself, but then didn't really fancy spending the summer in Australia. Too hot for me.
 
@BenjaminLim Ok, I'll go back to studying. That Wolfram isn't all that helpful. It doesn't show steps and I'm kinda unsure what I'm doing wrong.
 
@TaraB It's not bad in Canberra. Besides this summer it was freezing. Raining and stuff in sydney, devo......
@Moshe that was computed exactly from what I told you above
 
1:43 PM
Yeah, it's always like that. I watched NZ v France in the world cup before that, and all the English people wanted France to win so that England wouldn't have to face NZ next.
 
@TaraB hahahahahaha
rugby rivalry, thank god not AFL......
 
France did win. =[
 
What do you call 'freezing'?
 
@TaraB Where are you from in NZ? I know several people from Hamilton, Wellington and Auckland. In fact one of my best friends at school is now living in Tauranga :D
 
1:44 PM
@Moshe Still there?
 
@TaraB Freezing was like $15^{\circ} c$
 
I'm from West Auckland.
 
@TaraB ah ok
 
@tb ya
 
well it was that cold you had to go into the surf in a wetti :(
 
1:45 PM
Yeah, that's certainly cold for Australian summer. Normal for Scottish summer, unfortunately.
 
@TaraB well you don't exactly do surfing there......
@TaraB I wanted to go for a surf a few times, had to go in a wetti
 
My friend's boyfriend has been surfing here this week, actually.
 
what???????????????????
 
@Moshe so, I guess you do know the binomial formula?
 
that's nuts!!!
 
1:46 PM
Yep.
 
@tb You mean n choose k a to the k b to the n minus k?
 
@TaraB Well in fact my friend asked to go for a surfing trip near byron bay
 
@Moshe yes. So what do you take as a and b in the present case?
 
@TaraB In fact evans head, all of this is in NSW near the QLD border
 
I don't really see how there can be enough waves. (West Auckland has awesome surf beaches and I've never seen proper waves in the UK.)
 
1:47 PM
@TaraB UK is not exactly well known for surfing.....
@TaraB Tauranga has got like this massive long beach
 
Well actually, some parts of it are. Cornwall, for example.
 
@tb a = 3x, b = -2, n = 10, k = 3
 
Mt. Manganui
@TaraB You hear narrabeen in the lyrics of the beach boys song "surfin' usa"
or newport in california or something
no mention of the UK :(
 
@Moshe exactly and you get (10 choose 3) * (3x)^...
can you spell it out completely?
 
10 choose 3 is 120
@tb Spell what out?
 
1:48 PM
I've been to Byron Bay, but we couldn't go in the water because there were thousands of bluebottles.
 
@tb Come to australia and surf!!!! It'll be uber rad man......
@TaraB Those things are gnarly
I remember once in townsville
 
@Moshe Just the formula I started. Right 10 choose 3 is 120
 
I was visiting some guy we wanted to go into the water near magnetic island
and they were like no......
 
@BenjaminLim I'm not much of a surfer, but I sure like to hang out on the beach :)
 
@tb Let me show you the real australia :
 
 
sure.
 
@TaraB Avalon, Sydney
@tb there
 
I might see about learning to surf when I move back to NZ. I could barely swim when I last lived there, so it wasn't really a good idea.
@BenjaminLim: Lovely.
 
@TaraB Exactly, that's what I miss about being in Canberra
the closest place I believe for the beach is batemans bay
 
@BenjaminLim nice.
 
1:52 PM
that's like 2 hours away
 
Come to think of it: seeing as you constantly complain about the weather here, have you ever considered relocating to Australia?
 
@BenjaminLim: Yeah, I guess that's why else I didn't fancy Canberra in the summer. It's not even by the beach.
 
@JonasTeuwen If you want to know what australia culture is like, you can watch this video here: I believe it depicts quite well what the culture is like around the beaches and stuff of sydney. My friend plays in a band and this is their music video. youtube.com/watch?v=-DolfHRTKho
@MattN Was that at @tb?
 
@BenjaminLim Of course.
 
@TaraB yeah but if you do a postdoc at sydney
the beaches at sydney in summer are crowded as hell
oh btw
@TaraB and if you go to the smaller beaches there's a lot of localism which can be a problem
 
1:54 PM
@JM Haha, simplicity strikes again. : )
 
localism?
 
@TaraB and in the water you can only swim between the flags and usually it's very crowded. You go out a bit and it's the bodyboarders, out even more the surfers and it's very dangerous due to the risk of colliding with another surfer. I know some guy's dad who was knocked out cold and drowned
 
@Moshe ,I was wondering how did you embedd a button to your chat message, whats the code for that?
 
Well yeah, I'm used to only being able to swim between flags, because the West Auckland beaches are dangerous.
 
@TaraB yeah they don't like "outsiders" who are say not from around narrabeen to go and surf in the water, it's like they wanna reserve the best breaks for themselves
 
1:56 PM
Oh, that's not nice.
 
@TaraB yeah that's what you gotta do :D
 
@BenjaminLim: How did you put the photo in the chat?
 
I know some guy who got into a fight with someone else because apparently he took some guy's wave and it was actually a good one
to the right of the box where you type stuff is the "upload" button
 
user19161
@BenjaminLim Waves are free of charge.
 
@ClarkKent well there's surfing etiquette
@ClarkKent where are you from?
 
1:58 PM
@SauravTomar open square bracket, the word "tag", colon, the name of the tag, close square bracket
 
Sorry, gotta go do research now. Bye!
 
@SauravTomar [tag: a tag] (without spaces)
 
@BenjaminLim Crypton, no?
 
user19161
@BenjaminLim Oh dear, I think maybe I should not change my username in future. I am J.
 
1:59 PM
@BenjaminLim But he chooses to ignore. Maybe because if he did move there he'd have to find something new to complain about : )
 
@MattN oh tb?
 
user19161
@MattN Ding!
 
@ClarkKent waaaah????
 
@BenjaminLim Yes. : )
 
thanks @Moshe
 
1:59 PM
@tb You say you have never been to australia. Come here man I'll show you around.
 

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