Right now, I feel that studying analysis has become more of a painstaking chore than something I enjoy. I assume this is what it feels like to be overworked
@Dave The whole idea behind simplifying square roots is to break your number, 1536, up into a "perfect square" part, and a "square-free" part. So $1536 = 16^2 * 6$
@BalarkaSen Do you know what I studied in the past? You talk like you have the whole my file with all I studied so far. The things that annoys me at most is that you do the clever with me you knowing almost nothing about mathematics. Like you there are many others.
And you're not only just expressing your personal argument, you're also trying to drag other peoples to do analysis by making false universal arguments.
I don't think I need to excel in any branch of mathematics to stop @Chris'ssis making not only completely false universal statements, but also making others believe her philosophy.
@Chris'ssis Dont mind but i think you should not just talk into something which you dont know about.... I might be wrong but i think you should not force people to do what you want its their wish completely
@BalarkaSen well, I saw the passion with which this person talked about subjects in analysis, and from there I got the conclusion that he has an incilnation toward analysis.
Hi so I am solving problems in dummit and foote, however this problem I am not able to do it
Show that if $n = 3k$, then $X_{2n}$ has order 6, and it has same generators and relations as $D_6$ when x is replaced by r and y is replaced by s.
where $X_{2n} = <x,y | x^n = y^2 = 1, xy = yx^2>$
So ...
but yea then I would have to prove then that ord(G) = 6 then as @TobiasKildetoft pointed out I didn't realize this before we have to show they commute which they don't !
Let $\Omega$ a bounded space. Let $u_1$ the solution of the problem $$-\Delta u_1(x)=f(x), x \in \Omega \\ u_1(x)=g_1(x), x \in \partial{\Omega}$$ and $u_2$ is the solution of the problem $$-\Delta u_2(x)=f(x), x \in \Omega \\ u_2(x)=g_2(x), x \in \partial{\Omega}$$ Using the maximum principle I...
@teadawg1337 Maybe I wasn't clear enough: no need to have discussions, bridges with you @BalarkaSena @Rememberme (at least). First you respect me if you wanna discuss with me (to say it clear once and for all).
I have under research different variants of this one, but far more advanced. They are not hard, but some specific technique is required (once you get that you're almost done).
"Von Neumann's ability to instantaneously perform complex operations in his head stunned other mathematicians.[84] Eugene Wigner wrote that, seeing von Neumann's mind at work, "one had the impression of a perfect instrument whose gears were machined to mesh accurately to a thousandth of an inch."[85] Paul Halmos states that "von Neumann's speed was awe-inspiring."[13] Israel Halperin said: "Keeping up with him was ... impossible. The feeling was you were on a tricycle chasing a racing car."
@Chris'ssis Well, sorry to disappoint you, but that was a test. I don't think I need to explain how you did on it. I will not engage in conversation with you again until you begin to show remorse for this unwarranted hostility towards me and several others.
Hi so I am solving problems in dummit and foote, however this problem I am not able to do it
Show that if $n = 3k$, then $X_{2n}$ has order 6, and it has same generators and relations as $D_6$ when x is replaced by r and y is replaced by s.
where $X_{2n} = <x,y | x^n = y^2 = 1, xy = yx^2>$
So ...
