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12:01 AM
@PedroTamaroff So how is it solved?
I tried $z\mapsto z^{-1}$
Which makes it very wierd.
 
Seen it, @DanielF. I'm hip.
But yes, I like it quite a lot.
 
@MikeMiller Like the group theory above?
@Alizter What are you talking about now?
 
@PedroTamaroff The log integral.
 
$$\int_{|z|=2}\log\frac{z+1}{z-1}dz?$$
Ah.
 
Yah
 
12:06 AM
If you let $w=\frac{z+1}{z-1}$, then $dw=\frac{-2dz}{(z-1)^2}$, and $(w-1)^2(z-1)^2=4$, so you end up with an integral $$-2\int_{\gamma}\frac{\log w}{(w-1)^2}dz$$
Here $\gamma$ is a circle that contains $1$ oriented clockwise.
By Cauchy, the integral equals $2\cdot 2\pi i (\log w)'_{w=1}=4\pi i$.
 
I had problems with making sense of the contour.
 
anyone here familiar with dijkstra's termination detection algorithm for parallel computing?
I'm trying to prove a concept of the algorithm & am having trouble
 
@Alizter Möbius transformations send circles to circles.
You can check that three points on this circle are $1/3,3,-3/5+4i/5$. This determines the circle completely.
 
Dijkstra has an awesome name. i, j and k are consecutively in his name.
 
12:12 AM
@PedroTamaroff Thank you. I shall now go read about Mobius transformations.
@PedroTamaroff Are mobius transformations related to modular forms?
 
@Alizter I am not sure what a modular form is, so I cannot answer that.
 
@PedroTamaroff I have a vague idea. :P
Awesome. Mobius transformation has a cool GL thingy
I can't wait to study this stuff in detail.
 
12:27 AM
Yes @Alizter
 
Hi @TedShifrin
Whats up
 
12:41 AM
Hi @Alizter
 
Hi @Alizter
 
1:06 AM
@MikeMiller know anything about periods?
I am wondering why a period integral with rational-function integrand can always be written with a polynomial integrand by "introducting more variables"
 
I dont
 
1:19 AM
Hello!!! Knowing that $I_1,I_2$ are ideals, can we conclude that $I_1 \cap I_2$ is an ideal?
 
verify
 
@anon as a rule of thumb, the only deep topics I know a lot of are topological or geometric in flavor
though I guess you could call periods = motives topological
 
just about to say that :)
I don't know any of the algebraic geometry necessary to understand at that level though
there is literally a proof method called just-do-it
as expected, you just-do-it
@evinda another useful thing for verifying the most basic of facts: unpackage definitions. What does it mean for $I\cap J$ to be an ideal? Well it means [blah] and [blah]. Just prove both [blah]s are true, using the hypotheses that $I$ and $J$ are ideals!
 
Let E be minimal splitting field of x^n-1 over K where K has char 0. How to show E|K is separable?
Any hints?
I know all elements in the basis E|K would be separable
 
1:35 AM
what does "basis E|K" mean?
also, any extension in char 0 is separable innit...
 
I mean basis of E over K
 
what is "the" basis of E over K? :-)
 
All the n^th roots of unity
 
those are not linearly independent, hence don't form a basis
for instance the sum of all the roots of unity = 0
there are n roots of unity, but the degree of the extension E|K is phi(n)
 
Oh wow! Yes. I slipped there.
 
1:38 AM
even the primitive roots of unity (of which there are phi(n), same as the degree of E|K) are not a basis, as the sum of them is an integer (specifically a coefficient of a cyclotomic polynomial, even more specifically equal to mu(n)) (which also means they cannot span the whole space either)
the only inseparable extensions exist in positive characteristic
 
Slow down! ;) Let me process all of this
What's mu(n)?
 
@anon I'd like to learn some of that, but probably not in my cards for the next few days
or months
 
@Anon yes, i understood that. :)
Thanks
 
2:04 AM
@anon Hey there.
How's your math doing?
@DanielFischer Are you there?
 
I'm here.
Am I not good enough for you? Huh??
 
@MikeMiller Oh, no. I broke your heart.
Shot to the heart.
And I'm to late.
 
I'm dead. Thanks.
 
2:23 AM
@PedroTamaroff good
 
@MikeMiller
help me out here a sec
 
never mind, the lyrics were "shot through the heart" :/
 
hey everyone
 
let $\Delta$ be an abstract simplicial complex and take $M=max\{|S|:S\in \Delta\}
then take $m=\min\{|S|:S\notin \Delta\}$
(in the universe $\mathcal{P}(V(\Delta))$)
there seems like there ought to be some real easy relation between $m$ and $M$
like $m+M\leq |V(\Delta)|$, or something like that.
 
@anon may I nominate Pedro to be added to the list of room owners?
 
2:30 AM
$m$ is not defined (i guess) when $M=|V(\Delta)|$ and vice versa but i'm not sure what's going on there
 
@skullpatrol he's on the shortlist if rob or I ever feel like stepping down or expanding. I suppose I don't see any argument against expanding, either.
 
maybe it's $m+M\geq |V(\Delta)|$.
 
@anon Potato pohtato.
 
@anon thank you for the reply.
 
I think I should be owner before Pedro, for no reason but out of spite to Pedro
 
2:42 AM
you are on the shortlist of the shortlist, pal ;-)
 
@MikeMiller $M >= m - 1$
<-- genius over here
 
@AlexanderGruber Well, not so much a LaTeX genius.
 
:-)
 
@PedroTamaroff i don't need no dang fancy leq
 
@AlexanderGruber You certainly do.
 
2:49 AM
I'm watching you
 
<.<
>.>
me?
hi pal
 
no, you are the one
hi pal
I just working and the call all the time
we already report these calls to the police because they call me all the time
 
@Twink WAT
 
sometimes they say they wanna kill me and things like that
so what i do is just hung up because i don't know what they're doing :S
 
Where do you work?
If you don't mind saying.
 
2:55 AM
do you know where i am?
 
Why did you called me?
 
i am at work
i work for a few resorts
we do reservations, we have promotions for the resorts
you've been calling me alrady like 4 times and i already told it's not
i'm going to call the police
 
I'm going to call the police right now
so why did you told me that you wanna kill me?
can you please stop calling? because i am at work and you're disturbing a everybody here
 
I get this feeling like I'm being kept out of the loop on something
 
3:08 AM
I don't get it, @AlexanderGruber
 
the M thing I mwan
 
@MikeMiller M is the biggest dimension of a face of the complex
$m$ is the smallest dimension of a face missing from the complex
 
huh
 
Seems like those things should be related in some sort of way
 
3:13 AM
Does anyone have any recommendations for a textbook in a first undergrad course in number theory
 
@user130018 There are tons of good books, this site has a list somewhere in some questions, probably.
 
it is somebody with the name of john kimbo
 
Niven's book is primo
 
Thanks @MikeMiller
 
Hi @Alex @twink @mr eyeglasses
 
3:19 AM
@Ted I'm not happy about your cone answer
 
Hi @TedShifrin did you see that they use your book in this course? dms.umontreal.ca/~mat2300/plan/A14/planA14.pdf
 
Loops in the flat cone frequently don't bound a disc, but it has trivial holonomy, eh?
 
No, nontrivial
coming from $\pi_1$
 
Hi @TedShifrin
 
@Twink: most people ask for permission; he didn't ... But it's ok
 
3:21 AM
do you know him?
 
No, but
I know his adviser vaguely
 
does he teach it in French?
 
ouais
 
U Montreal is French-speaking
 
@TedShifrin But $\Bbb R^2$ has trivial parallel transport. When I say flat cone, I mean the punctured plane...
 
3:23 AM
btw how many languages have your books been translated into Professor @TedShifrin
 
You're wrong, @Mike.
 
@user130018 here
 
Linear Alg book in Portuguese is the only one I know,n@skull
 
Thanks @skullpatrol
 
$\Bbb R^2$ doesn't have trivial parallel transport?
I'm not claiming I'm right anymore. I'm just confused.
 
3:24 AM
That's not the connection/metric on my cone
 
@TedShifrin at least he put your name on the reference
 
Locally, sure; globally, no @Mike
 
I wasn't disagreeing about your cone. I was claiming that "has non-contractible curve" shouldn't mean "has nontrivial holonomy"
 
Well, sure @Twink ... It's fine. People use it all over the world cuz it's free :)
 
(To clarify my verbiage when I said I was unhappy with it, I meant it was confusing me.)
 
3:27 AM
@TedShifrin why don't you publush it so you can get money?
 
I said the holonomy around such a curve was nonzero @Mike
Nope, done that enough @Twink
 
What on earth is "Holonomy"?
 
what do you mean with "done that enough"?
 
So you meant for your cone, not that any non-null-homotopic curve has nontrivial holonomy (if it's clear what I'm trying to say)?
 
you have publushed enough books?
 
3:29 AM
Three published books is enough ...
 
you should publish ALL your books
no matter if it's 1 or 100
 
nah ...
If you have a simply connected flat surface, holonomy must be $0$, @Mike.
@Pedro: It's about parallel translating a vector around a curve and seeing through what rotation it has turned.
 
Right. I'm asking about non-simply connected surfaces, like the punctured plane with the metric it gets by sitting in the plane. It seems to me that the holonomy of this must be zero even though it's not simply connected.
 
@TedShifrin OK. What's "parellel translating"?
 
Yes, @Mike.
 
3:35 AM
Ok, thanks, that's what I was confused about - your wording made me think you were saying "the holonomy around any nontrivial curve is nonzero". Thanks for bearing with me!
 
You're an ant living in a surface, @Pedro, and you move a tangent vector along a curve, turning it as you go so that its derivative is only normal to the surface (so to the ant it is moving parallel, i.e., not turning)
 
He's calling you an ant, @Pedro
 
@TedShifrin OK. That can be done in several ways.
I can also be a human in a big surface!
 
@TedShifrin Why is he not living on the surface?
 
cuz the surface is intrinsic, not extrinsic
 
3:38 AM
OH HE GOTS YOU TED.
OH ANON GOTS YOU SKULL.
 
@Mike: To build my cone, you need a pacman, not the whole annulus.
 
@Pedro Not on a single curve it can't.
@Ted I understand your example. I just thought when I read it you were saying something about non-null curves on anything.
Oh, I suppose it can be done lots of ways in terms of how the ant moves. But if you only consider where the tangent vectors end up, rather than the path they take, it's unique.
 
I think I added an exercise on this to my notes (parallel transport on the cone was already there several times)
No, you need a particular path ...
 
Damn, I hate it when I forget about my tea and it cools off.
 
Microwave @Pedro
 
3:42 AM
You never said unit speed. Geometrically identical paths, distinct parameterizarions.
 
Oh, I misinterpreted your comment. Now we're even.
 
Hello everyone. I posted a question on meta, and I was wondering if anyone would like to answer it? meta.math.stackexchange.com/q/17395/173397
 
@TedShifrin Why do we still talk about numbers on a number line then?
 
I'm not saying I was right, @skull ... Typing on my iPad sucks, particularly in here
 
who is we
 
3:47 AM
Who are we? :D
Did @Pedro grok my explanation?
 
@TedShifrin I am not sure, that can be done in many ways right?
For example if you're on a sphere you can make the ant move in any direction and spin round and round.
And the tangent will be normal?
 
No, unique solution to the ODE once we specify a curve.
 
@PedroTamaroff The key is that we're specifying a curve first. Then we get unique parallel transport.
 
Oh, I mean the curves can vary.
 
Holonomy assigns different rotations to different closed paths.
 
3:51 AM
@MikeMiller Wait, how so? On a sphere, if I take say a great circle you can move while spinning and still get tangent normal stuff.
I might be missing he point here, probably because I suck at getting nonrigorous definitions.
 
So are you suggesting the ant can walk sideways?
 
It's actually a group homomorphism :)
 
Because no, what's wrong with you, the ant walks in the direction it's facing.
Ants can't walk sideways.
This is biology 101.
 
The vector pivots on the ant's back :)
 
I detect one of my fellow students on the new users list...
 
3:54 AM
Oh? How's Eric doing?
 
That's not the one I meant. But I think he's doing well! Our paths only cross rarely.
I wonder if he'll be a PDE Pal next quarter.
 
hi yall
 
I know... He's not a new user.
I said hi ages ago, @Alex
 
re-howdy
 
4:20 AM
@TedShifrin i'm a lil slow
As you can see. :p
 
4:37 AM
nice, my friend comes out of the gate running
 
Gah. I really like math but I tried to take too many courses in math this semester and I'm doing badly in all of them and I feel terrible :(
 
live and learn
learn from your mistakes as well as your successes
 
Unfortunately bad grades don't go away when I learn not to do that again :/
 
Is it too late to withdraw?
 
um, if I withdraw I get W
which I think looks pretty bad
 
4:43 AM
better than an F
 
talk to your professors rather than writing the idea off
 
good advice^
 
What do I tell them? I feel like given that I've turned in crappy problem sets and done badly on exams, they probably think I'm a terrible student and won't want to talk to me ...
 
That's not how professors work. :P Trust me, they're more than glad to talk to you, and they have your best interests in mind if you talk to them about how you're doing in the class, what you should do going forwards, whether you should keep taking or not, etc.
 
4:50 AM
@ZubinMukerjee Once you get an F, you'll need an A to just get a C+ average :(
 
back to being loyal, eh
 
we won :D
1-10
 
my eagles are doing pretty well this year... we won't talk about last sunday
 
that's a tough division
but playing dallas twice should be fun to watch
 
they don't stand a chance pal
 
5:01 AM
nah, on any given Sunday...
...look what happened to the perfect season
 
Sorry to bug you guys again, but we have thanksgiving break starting from next week, so my professors won't have classes or office hours during which I can meet them ... should I email them to ask if I can meet them tomorrow (last day before break)? Also should I mention it's because I'm considering dropping the courses?
 
yes
asap
 
lol okay, thanks
 
thanks for asking :-)
good luck
pal
 
 
2 hours later…
r9m
7:16 AM
@M.N.C.E. Hello :)
bbl (lunch)
 
7:34 AM
@r9m Hi.
 
r9m
@M.N.C.E. (sorry for the late reply .. I was afk) .. I wanted to ask you .. Asia is a very big place .. where are you from ? :-) (If you don't mind me asking)
 
@r9m Unfortunately, I do mind you asking, really sorry about that. :P
 
r9m
@M.N.C.E. haha :P no problem .. once I've seen you mention you are a high school student .. that just made me even more curious :P
 
@r9m May I know what you are curious about? :o
 
r9m
7:51 AM
@M.N.C.E. oh ! I've never seen a high-school student solve such incredible integrals like that !! .. I mean I've never seen anyone from high school so motivated with special integrals ..
 
@r9m Thanks... I solve these integrals only for fun, and I think I find users like Chris's sis much more impressive than myself.
 
r9m
@M.N.C.E. okay ! :-) .. might I ask how you got interested in integrals ? :) (I'm just curious .. )
THIS is Insane :P ROFL
@M.N.C.E. its okay if you don't answer my last question .. :) I have a habit of asking silly questions :P sorry 'bout that ..
 
@r9m I browsed around MSE a few months ago and saw a couple of difficult integrals along with their solutions. I guess that was how I start to take interest in solving integrals. There isn't much to it actually... :/
 
r9m
@M.N.C.E. I see ^^ .. okay :)
 
8:24 AM
Odd... I've lost 20 points, but I don't see anything about it on my reputation page.
 
r9m
@robjohn did it show [-20] on the rep tab ?
 
@r9m no... but I tracked it down to this question that was deleted an hour ago. >8(
 
r9m
@robjohn link says .. 'for reasons of moderation' .. ! does that mean it can't be restored ?
 
The question was a PSQ (I am still not convinced that they are all off topic, especially when the question is a good one), but it had many upvoted answers. Its votes were +3/-3, so the people who wanted it gone had enough downvotes to make it to 0 and then delete.
@r9m Nah... I could undelete it, but only people with 10K or more can see it and vote to undelete.
 
r9m
@robjohn oh ! okay
 
8:35 AM
Of the people who asked/answered that question, I am the only one with more than 10K, so none of the rest will know what happened.
 
Hello!!! Could you explain me how we conclude that if $I(V)$ is a prime ideal and $I(V)=I(V_1) \cap I(V_2)$, then $I(V)=I(V_1)$ or $I(V)=I(V_2)$?
 
r9m
@robjohn ^ that is the problem of being the lonely Superman on planet Earth ! =P
 
@evinda Isn't that by definition?
 
@robjohn. I haven t got taught this... :/ What definition do you use?
 
r9m
I have chili powder .. but that's definitely not smoking material .. BBL :P
 
8:44 AM
@evinda pretty much what you've said. It corresponds to $p\mid ab\implies p\mid a\text{ or }p\mid b$
 
@robjohn A OK!! also, how do we conclude that $I(V)=I(V_1) \Rightarrow V= V_1$ ?
 
@evinda Is $I(V)$ again a prime? what exactly are $V$ and $V_1$?
 
Yes, it it is a prime ideal. V is an algebraic set...
 
@evinda is it a minimal generating set? Otherwise the ideal generated by $2$ and $4$ is the same as that generated by $2$, but $\{2,4\}\ne\{2\}$
 
@Pedro there's just one issue, how do you show that there is morphism by the set of cosets? Moreso, if that morphism is between $G/H$ and $S_5$, than we already assume $G/H$ is a group which is true iff $H$ is normal
Also, I don't see how to show that $S_5$ doesn't have element of order 15 anymore.. but that's solveable
 
9:11 AM
hi @robjohn
 
@LucioD hey there
 
@robjohn how's it going?
 
pretty good, and you?
 
@robjohn Not bad. Feeling a bit stoned from tiredness but okay otherwise.
 
9:16 AM
What I am suggesting here is a form of self-government. Since, the system records and graphs the activity of all the users in the room, why not choose the room owner based on that data, rather than the current system? If you want to be a room owner it is only fair that you should actively participate in that room.
 
@robjohn Are you aware of an application of Holder's inequality which allows $\int |f|^{\frac{1}{p}'}g$ can be stated to be $\leq \int |f|^{\frac{1}{p'}}|g|^{\frac{1}{p}}$, where $p'$ is the conjugate of $p$?
 
@LucioD so $\frac1p'=\frac1{1-p}$?
I know that $\frac1{p'}+\frac1p=1$
 
@robjohn Yeah usual definition of conjugate
 
@LucioD but then, one of $p'$ or $\frac1p'$ is going to be negative or infinity
 
@robjohn :) Yeah its where I'm getting stuck, something strange going on in this paper, anyway g2g c yer
 
9:41 AM
How is one supposed to expand (XD)^2 in matrix algebra? What about (X+D)^2?
 
10:10 AM
Morning @skullpatrol. Good to see that you have a real avatar again.
 
@DanielFischer Thanks pal, my team finally stopped playing like a bunch of girls and got a win last night :D
1-10
 
@skullpatrol Congrats.
 
:D)
 
Whom did they win against?
 
The Kansas City Chiefs.
 
10:20 AM
How is everyone?
 
Fine thanks, how are you?
 
I am good. I like your picture now
I still prefer the old text face
 
Back to my true colors.
Silver & Black
 
Was the pink your actual identicon?
Or did you modify the colours/steal anothers?
 
I found it in the system somewhere...
 
10:27 AM
What music do you listen to @Skull?
 
all kinds
you?
 
Bands/musicians though?
My genre is not main stream in the slightest, so I would probably be judged here
 
@Committingtoachallenge people who judge others by the kind of music they listen to, are not my kind of people :-)
they are not apart of raider nation
we don't judge
 
10:44 AM
@MikeMiller I got a naive question. I learnt what groups are, I learnt what dihedral groups, symmetric groups, permutation groups and matrix groups are, abelian, non-abelian etc and that they're abstract. Though I haven't seen anything proven with group theory, I only see a handful of definitions. All I see is more abstract restatements of definitions... What can we do with group theory? What's a classic example?
 
10:54 AM
@UserX studying symmetry in geometry is the most simple example
Cryptography is another (less simple)
Coding Theory uses tons of Group Theory
(And ring..)
It's probably one of the most important undergraduate subjects, standing side by side with analysis
 

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