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11:37 PM
@N3buchadnezzar Oh noes you sad.
 
11:48 PM
Hey guys
@Pedro: Are you there?
 
He's not, I will be his representative.
 
Ok Mike
 
yo can anybody help me solve a riddle
 
The teacher of the class I'm TAing just sent me the exercise list she will be assigning as homework
I spotted a mistake and I just wanted to check it with you
 
Ook
What class is this?
 
11:50 PM
Linear algebra
 
Oh, shoot.
 
It's terribly silly but I really don't want to email a prof if it's not 100% correct
It says "extract a basis from the following generating sets"
 
Nice, I got it right.
 
b) isn't a generating set since $\mathbb{R}[x]$ is infinite dimensional
and there are just 3 vectors
 
You misread, it's asking for a basis for the vector space it generates.
 
11:53 PM
Nah, 17
 
Right, I read the $\subset$ symbol as saying "This may not be the full space"
 
ahhh, you're right
 
Can't correct your teacher then
anyone up for a riddle?
I gotta solve this urgently
5 # 2 = 11; 2 # 4 = 14; 3 # 2 = 7; 4 # 5 = 30; What is 8 # 4.
 
Hi everyone, How can I say with words that $P(X)=C(X−\alpha_1)\cdots(x−\alpha_n)$, can I say P is divided into simple roots ? thanks
 
The problem statement could be clearer though
Thanks for your help @Mike
 
11:54 PM
No prob
 
wtf LaTex doesn't work here
oh nvm saw the guidline
 
@FernandoMartin OK.
 
Nevermind, @Mike helped me out
Thanks anyway!
 
@Nico don't know but bump
Welcome back Graduate
haven't talked in 17 days
 
If I multiply g(a) by 0. And g(a) is not defined, will the product be zero?
 
11:57 PM
yes
 
how come
 
anything * 0 is 0
 
interesting that you can operate with not defined values
 
@PedroTamaroff I'm replacing you!
 
Hm
If you have 0x
if that's your function
 
11:59 PM
@Shahar "$g(a) \cdot 0$" is nonsense if $g(a)$ is not defined.
 
and you want to find the value at inifinity
 
@Mike *Hand to mouth and backstab. Shh... it's all over now.$
 
then it will be 0
 
@Shahar "Value at infinity" is not a well-defined concept.
 
if g(x) = x/0
 
11:59 PM
and infinity is not defined I thonk
think*
 
sorry g(x) = 1/x
 
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