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10:00 PM
It's a big theorem that homotopy groups of iterated suspensions ($\pi_{n+i}(\Sigma^i X)$) stabilize eventually
and the beginning of stable homotopy theory
 
What are some good books covering it?
 
I dunno, never read a lot about stable homotopy theory
I think there's a book by Adams
 
goes to smash into a 15-holed torus
Hi @Ali @Balarka ... just dropping by for a few moments
 
Hi @ted :)
 
10:08 PM
Hi @Alessandro
 
Heya Ted $:)$
 
Hi @Mahmoud
 
@TedShifrin techinically you are an algebraic geometer
can I ask a geometry question
 
Not an algebraic one, though
 
What about from the second chapter of Hartshorne
 
10:09 PM
Probably dubious. What's the question?
 
I get that stalks are nice when talking about properties of sheaves
 
@TedShifrin hi
 
Salut, @Dodo :)
 
but what happens if we take the inverse limit instead of the direct one
is it still a useful object?
 
Yikes.
You want to localize more and more, not make things bigger.
 
10:11 PM
It's an interesting object but I have no idea what it means. Look up completion of a ring.
 
That doesn't seem right, @Balarka.
I mean, the completion of the polynomial ring is the ring of formal power series.
 
That's true.
Well, depending on whether you choose the obvious ideal to complete at
 
Anyhow, @Ali, I have no clue.
 
@DanielFischer it is $\geq 0$. Is there a straightforward proof for this ? Given $e$ a normal unit vector, all we know is $\langle p_H(x),e\rangle=0$, $\langle x,e\rangle\geq 0$ and $\langle y,e\rangle\leq 0$
 
How does that work for multivariate rings?
I am fairly sure R[[X]][[Y]] =/= R[[X, Y]]
or does it just not
 
10:15 PM
Why is $k[[X]][[Y]]$ different from $k[[X,Y]]$?
I've forgotten how completion works in the multivariate setting, though.
Probably tern knows this.
I need to get going ... going to a concert. Talk later.
 
You can make completion work for any ring. Take inverse limit of R/I^n
I is the ideal you complete at
 
I was confusing things
That doesn't hold true for laurent series
but for formal power series its fine
So R((x,y))=/=R((x))((y))
 
@DHMO Trump's resort is a good tongue twister
La-mar-al-lado-de-un-lago-o-algo
 
Thats tremendously hard to say
 
@TedShifrin $k[[X]][[Y]]$ and $k[[X,Y]]$ are isomorphic as $k$-algebras, but not as topological rings. In the first, $X^n$ (as $n\to\infty$) does not tend to $0$ (since you need higher and higher powers of $Y$ to do that), whereas in the second it does (since you only need higher and higher total degree there).
 
10:35 PM
@AliCaglayan can you give an example of an element in Q((x))((y)) that is not in Q((x,y))? :P
(you are right that they are not the same)
 
@arctictern Its difficult to come up with one
Literally all the ones I try end up being in Q((x, y))
but some smart people on MO said so
 
yes, the false beliefs in mathematics question
 
I found this cryptic line of reasoning, lol.
Earth.
We use the word Earth as another word for the soil.
Soil is dirt.
We use the word Dirty to describe the contaminated state of a human being or other object or life form.
The opposite of Dirty is clean.
We use soap to get clean.
Soap rhymes with boat.
Boats are used to ride in water.
Humans drink water.
The average adult human body is 65% water.
6-5= 1
Lets go back to the topic of Dirt.
The word dirt has four letters in it.
Subtract 4 by our product (1)
4-1=3
What shape has three sides?
A triangle.
 
What's up, friends?
 
@PhysicsGuy Hi there.
 
10:46 PM
@Mahmoud Where did you find this reasoning?
 
On a Youtube comment, under a video about Earth.
 
Hah, that's funny.
 
11:11 PM
hey @Danu
 
Hi
 
11:44 PM
hi
 
11:56 PM
hello for two simultaneous linear equations such as 2x-6=0 and 3x+6y=15 when using a matrix why does it become:
[2, 0] and not [2, -6]
[3, 6]_______[3, 6]
ah damn that messed up my layout
 
because -6 isn't the coefficient of a variable.
Hence it should be on the other side of the equation, i.e. 2x=6.
 
oh so i should just aim to put all vairables on the left and all constants on the right
 
Right.
 
i was assuming the book just forgot to include the y as a typo
ok thanks :)
 
now that we're talking about linear systems
 

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