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7:06 PM
Would you guys have a fast way of writing matrices in latex ?
 
@Socrates Mathematicians problems
@Astyx I suppose you have a mouse
 
I do
 
Why don't you download software that gets image -> LaTeX?
 
@LucasHenrique that might not be the best way
 
Huh, I don't have an image of my matrix
 
7:08 PM
When I had Windows I downloaded that once. It was like "paint", but as you draw it creates LaTeX
 
a program (which can be coded by hand easily) that converts (a,b,c,d) to the appropriate matrix might be better
a script might be sufficient
 
you can probably create a latex command that does a b c d as a two-by-two
 
IKR, but that software is more general for any formatting
 
if you watch the latex command its nearly what you want
 
I don't have it anymore so I just write it down
 
7:09 PM
just seperated by "&"
 
If you guys are looking forward to a script I can code it
 
How does one write the plus minus sign in latex ?
 
IIRC \pm
$\pm$
 
Thanks
 
What matrix type do you need?
 
7:11 PM
@LucasHenrique I think the script would be too individual
$n\times m$
 
@Socrates eek
@Socrates What do you mean?
 
if you limit it by for example $2\times 2$ matrices, the script has a very limited use
 
Can somene teach me how do I create matrices on LaTeX? :|
 
but if you make nxm matrices, then the script might be not useful at all
"matrix latex" google
 
\begin{vmatrix} a & b \\ c & d \end{vmatrix}
 
7:14 PM
@Semiclassical isn't this the determinant symbol
 
yeah. that's what vmatrix does: vertical sides.
 
@Socrates the tex SE site has all that stuff that we don't need
 
bmatrix does bracket sides
 
@Semiclassical Ok, thanks
 
and pmatrix does parens.
 
7:15 PM
(in german, but seriously, doesn't matter)
 
@Semiclassical And plane matrix does no sides: $\begin{matrix}1&2\\3&4\end{matrix}$
 
Many of those can be solved by \left[ begin{matrix}blabla end{matrix} \right)
Only the border matrix needs a special command :)
$\left(\begin{matrix} a & b &c\\d&e&f\\g&h&i\end{matrix}\right\}$ for example
 
@s.harp interesting
 
hi all, i need to understand this formula used for combinatorics, (n+m-1)!/n!(m-1)! this was used to solve this situation of placing 9 indistinguishable marbles into 4 boxes. which formula is this referring to? thanks
 
Binomial coefficient @MubB
 
7:20 PM
@MugB: Are you asking why that is the right counting formula?
 
thanks @s.harp yes and why is this being used :) @TedShifrin
 
Let's say you have a collection of n different objects and you wish to pick out a subset of k of them (without regard for order). You can choose the first one n ways, the next one n-1 ways, and so on, down to n-k+1 for the kth. So you have n(n-1)...(n-k+1) possible ways of choosing them. Right?
 
okay @TedShifrin i got that part
 
To activate LaTeX rendering, use the link on the top-right. @MugB
 
BUT we don't care about the order. So each actual k-element subset has been counted k! times. So we divide by k!. But the first product I wrote down was n!/(n-k)!. So you're left with n!/(n-k)!k! ...
 
7:23 PM
That way, it'll turn things like $\binom ab$ into cool math notation
 
I forced myself to skip dollar signs this time, DogAteMy :)
 
Yeah, but they should know it exists
 
How did your Rudin test go, DogAteMy?
 
thanks will try that @AkivaWeinberger newbie here
 
@TedShifrin please what i can do to $\sum_{j=1}^n p_j\xi_j^2$ in relation with $|p|$ and $|\xi|$
 
7:26 PM
@Vrouvrou: All I can see is $\left|\sum p_j\xi_j^2\right|\le |p||\xi|^2$.
 
but how did we get to (n+m-1)! that part im not very clear. why are we doing (9+4-1)! @TedShifrin
 
@TedShifrin I haven't done that yet
 
@TedShifrin how to see this please
and what about $\sum_{i,j=1}^n p_j\xi_j\xi_i$
please
 
OK, @MugB. First, to clarify: Can you put 0 marbles in some box?
 
Triangle inequality? @Vrouvrou
I assume $p$ means $\sum p_j$
 
7:29 PM
@ted
 
@Vrouvrou: $\left|\sum p_j\xi_j^2\right|\le |p|\sum\xi_j^2$, since $|p_j|\le |p|$.
 
@TedShifrin no
 
So $p$ means the vector of $p_j$'s, DogAteMy.
 
@AkivaWeinberger $p=\sqrt{\sum_i p_i^2}$
 
7:30 PM
$\vec p$ (or $\bf p$)
 
$\boldsymbol p$
 
OK, @MugB. So imagine putting 3 dividing lines between various of the 9 x's. What's to the left of the first goes in the first box, between the first and the second goes in the second, etc. Now can you count?
 
Or $\bf\vec p$
 
since $\bf\theta$ doesnt work but $\boldsymbol\theta$ does :D
 
@AkivaWeinberger $|p|=\sqrt{\sum_{j=1}^n p_j^2}$
 
7:31 PM
@s.harp Weird.
 
No, @s.harp, I really think he means the vector $p=(p_1,\dots,p_n)$. This is just Cauchy-Schwarz, but easier.
 
@s.harp Aw :(
 
@TedShifrin and what i can do to $\sum_{i,j=1}^n p_j\xi_j\xi_i$
 
Don't you need \boldsymbol for theta?
 
yes :D
$\boldsymbol\sum$ $\sum$
 
7:32 PM
hi does anyone here know a bit of stochastic calculus?
 
apparently bold symbol doesn't bold every symbol :/
 
I'm facing a problem
 
Same answer, @Vrouvrou. Think of this as the inner product of the vector $(p_1\xi_1,\dots, p_n\xi_n)$ and the vector $\xi$.
 
@TedShifrin yes that will equal to 9X8X7X6
 
No, @MugB. You need to have 9+4-1 slots, and the 3 dividing lines will go in some 3of them.
For example, @MugB, with 5 marbles and 2 boxes, you could have xx|xxx or xxx|xx or xxxx|x or ...
So this would be n=6, k=1 in my original notation.
 
7:36 PM
@TedShifrin okay i think i get it. although still quite foggy maybe ill need a bit more practice to see how it works
 
If you google "bars and stripes," you'll see this is a standard counting trick in combinatorics.
 
@TedShifrin thanks for the tip. will have a look.
 
You mean "stars and bars"?
 
Oh, maybe I messed up. Listen to Akiva. :P
 
Because otherwise I'm pretty sure "bars" and "stripes" mean the same thing
 
7:38 PM
haha yeah i think thats what Ted meant. got it
 
I discovered the counting technique myself in grad school and only learned the nickname recently when I taught probability. So I messed up. shrug
DogAteMy, I was looking forward to finding out some good problems you solved on your Rudin test. The PDE thing you asked me about is all about Mean Value Theorem not applying on disconnected domain to prove f'=0 -> constant.
Oh, I guess I can go back to math mode now :)
 
wow this technique is cool! @TedShifrin thanks a lot for pointing me to it. or else i think im gonna take another few mths to understand :D
 
What PDE thing? The one whose domain was the plane minus the positive real axis?
I mean, the positive x-axis
 
Right, DogAteMy. The question from section 3.6.
@AkivaWeinberger DogAteMy: How many matrices do you know that do not live in a plane? :)
 
@Akiva Okay, I posted my answer on the same question Daniel Fischer replied, if you're interrested
Or rather my answers
 
7:46 PM
@Astyx: I take it you're feeling 100% better.
 
Except for the fact I still dont know wether () or [] come first when sharing a link, much better yeah (although my stomach still hurts from time to time)
How are you by the way ?
 
Derp. Plain. @TedShifrin
 
I'm fine, thanks. Just came back from having a test to make sure my heart still works. Sadly for you all, it does.
LOL, I know, DogAteMy ... but I felt I owed you a carp.
 
So you are, at least technically, not heartless
 
What a shame indeed
 
7:48 PM
"Carp"?
 
The fish ?
 
To carp = to complain/whine.
 
Huh. Today I learned.
 
Ah, I should have said "to find fault in a picky way"
 
So you just carped your own definition.
 
7:49 PM
I suppose we could make gefilte fish out of our carps.
I did.
We need to carp diem, too.
 
Hi, i got a question:
Suppose $f: U \to R$ , where $U $ is an open and convex set of $R \ ^ n $ s.t $ D_1 f(x) = 0$ for all $x \in U $.

Given $x,y \in U $ , s.t $x_i=y_i $ for $ i=2,\dots ,n$
i need to prove that $ f(x)=f(y)$

I defined $g : [0,1] \to U $ s.t $ g(t) = tx +(1-t)y$.

I want to say that f composition g has derivative zero using chain rule but i dont know that $f$ is differential.

So, how should I continue?
 
Not sure if I should laugh or cry
 
Ok, so I did that script
 
@Astyx: So perhaps I am heartless after all.
 
@Astyx Hi! :)
 
7:51 PM
@Liad Hi ! How are you ? :)
 
It's Python 3
 
@Astyx fine, and you?
 
@Liad: It's just a one-variable problem and you know that $D_1 f = 0$. Do you know $f$ is continuous?
 
@TedShifrin no
 
Oh, but you do know it's continuous on any closed line segment varying just $x_1$. Why?
 
7:52 PM
AFAIK it's idiot/typo proof so it's a nice and simple script
 
@Ted Technically if you don't have a heart, it's working. Your doctor might have been pedantic
 
but i see that f composition g is just $f(tx_1 +(1-t)y_1 ,x_2, \dots , x_n) $
 
@Astyx: Probably so. He was trying to get rid of me. This was my third time going to the office for this appointment (they kept screwing up), and this time he was a half hour late.
So why is that function of $t$ continuous, @Liad?
 
Hi @Ted
 
Actually, @Liad, to avoid saying the words "chain rule," you should just consider $g(t)=f(t,x_2,\dots,x_n)$, $t\in [x_1,y_1]$.
Hi @Balarka
 
7:55 PM
hi @TedShifrin
 
@Socrates done
 
Hi, Karim.
 
Is there a body of theory around using 'composite' fields aside from prime powers, such as (eg) the cartesian product GF(3) x GF(5)?
 
@TedShifrin alright, i thought of this function too.
 
@Extrarius: A product of fields isn't a field ?
 
7:56 PM
@TedShifrin is it correct that the derivative of this function is $ D_1f $ ?
 
I am just proving the following I + J is generated by gcd of n and m. Don't tell me answers though no spoilers. So I proved that I + J is the smallest ideal containing n and m. Then, now I will show that gcd is the smallest ideal containing n and m. Their was characterization of gcd in terms of their linear combination right ?
 
Of course, @Liad.
 
What differentiates a field from a ring?
 
But why does the Mean Value Theorem apply to tell you the function is constant? @Liad
 
that is ax + cy = d for integers x and y right ?
 
7:57 PM
Karim, unless $I=\langle n\rangle$ and $J=\langle m\rangle$, I don't know what you're talking about.
 
@TedShifrin
 
@Extrarius Existence of inverse.
 
Yeah I am talking about that @TedShifrin
 
@Extrarius Inverses and commutativity.
 
So you mean the gcd generates the ideal $\langle m,n\rangle$.
Language matters, Karim :)
 
7:58 PM
yeah right .. :) Yeah
 
But this is something you should have proved as an undergraduate.
 
@BalarkaSen Made any progress on the puzzle?
 
You can take composites of field in a different way though @Extrarius
 
It's OK to reprove it now.
 
Is there anything analogous to a composite field besides prime powers, such as a combination/mixture of two prime fields?
 
7:58 PM
no spoilers though @TedShifrin
 
The integers are not a field because they don't have inverses; the quaternions are not a field because they don't commute. But they're both rings. @Extrarius
 
@TobiasKildetoft I stopped thinking about it.
 
Do you guys often give downvotes ?
 
@BalarkaSen Probably a good idea :)
 
@Balarka: Did you stop thinking about moving frames too? I'm sure you're still sick :(
 
7:59 PM
@Astyx downvotes
 
ohh rightt
it is through bezout identity right
 
Sure.
 
Three of them are clearly godfather, miserable and education, but the middle one doesn't match up with the number of slots.
 
@Astyx That's a good answer, in the link you sent
 
Cause I've ever only given 2 while I gave 140-something upvotes, I don't know how to feel about that
 
yeah @TedShifrin my undergrad university sucked. My knowledge I guess mainly came from self-study.
 
@BalarkaSen you are on the right track at least
 
@Akiva Thanks, I thought it might be a bit long and ununderstandable at the end
 
That stuff was the main theme of the algebra course I taught, Karim.
 
@TedShifrin I computed curvature of the sphere and the pseudosphere with it by hand; it's extremely efficient at quickly computing stuff
 
8:01 PM
That is important @TedShifrin. Some profs just don't take teaching seriously.
 
Isn't it, though, @Balarka? You'll end up agreeing to be a fan, in the end :P
@Balarka: Not to mention proving Gauss-Bonnet :P
Karim: Research universities do not promote and give pay raises according to teaching.
 
@TedShifrin today I helped with help center here the experience was so amazing.
 
Yeah, it's pretty great. I still need to get used to doing the bookkeeping with those forms, but I am working on it.
 
@Akiva I really like Daniel Fischer's answer also
 
@TedShifrin this is why i wanted to look at f composition g, so that the function will be from R to R and then i know that if the derivative is zero then the function is constant
 
8:02 PM
@LucasHenrique congratulations
 
I like seeing people joy when I hear that they understand what I expalined @TedShifrin
I see @TedShifrin
 
@BalarkaSen I can give you a hint of the type the hunt had build in (one could pay for these with gold): A yes/no question about the puzzle.
 
@Socrates $\begin{bmatrix} \, & i & \, & t & \, \\ w & o & r & k & s \end{bmatrix}$, even tho it's weird to work in the first time for a programmer (usually get errors and bugs and meh).
 
@Liad: Well, you're still doing the same thing, without needing to look at the chain rule. As you pointed out, you can't officially apply the chain rule. But be careful. You need continuity on the closed interval.
Karim: That's good. Explaining things helps you get better at understanding and explaining!
 
I don't actually know how to prove G-B. I suppose one integrates $d\omega_2$... Stokes' says it's sufficient to integrate $\omega_2$ along the boundary of the surface.
 
8:03 PM
yeah
 
You mean $\omega_{12}$.
 
I apologize, yes.
 
I have the proof sketch at the end of the section. But you should figure it out :) The key thing is to figure out where $k_g$ comes from.
 
So that should be the geodesic curvature along the boundary.
 
Oh, and Euler characteristic :)
Depends how you choose the frame field, @Balarka.
Good luck with that. :)
 
8:04 PM
@Akiva However how do you easily show that all the mass have same parity ?
 
Hmm, right.
 
One hint is to start with a vector field with finitely many nondegenerate zeroes (which you certainly can prove exists).
 
@TedShifrin ok, in order to use the MVT , i need to have a differential function. and i dont have it :/
 
@Astyx Suppose not. If the total mass is even, choose an odd pebble; the masses of the remaining pebbles sum to an odd number, and so they can't be divided into two groups. Similarly, if the total mass is odd, choose an even pebble.
 
You do, @Liad. You need a continuous function on a closed interval that is differentiable on the open interval. Go back and be careful. But the function $g(t)$ I wrote down has both those properties. Make sure you can say why.
 
8:07 PM
Oh that was quite easy indeed .. :p
 
@TedShifrin So from an arbitrary frame you want me to get to one which is a Darboux frame along the boundary, right? And that's supposedly where the $\chi$ factor comes in.
 
@TedShifrin Sorry, but why $ g$ is continuous ? i dont know that $ f$ is.
 
The $\chi$ factor comes from what I wrote up there ^^^ ... but, yes, at some point, you'll need to relate different frames.
@Liad: But you do know (or can prove) that $g$ is continuous (i.e., $f$ is continuous along that closed line segment). Why?
@Liad: Hint: It's important to understand something about the set $U$ in the problem.
 
@TedShifrin huh, because $ D_1f(x) $ exists for each $x \in U $ ?
 
So why does that tell you $g$ is continuous?
 
8:12 PM
because g is differential
 
Hmm, trying to understand how such a vector field is relevant to the story (of course you want me to do some sort of Poincare-Hopf here).
 
@LucasHenrique was python your first experience?
 
Can someone help me with a question? If it's not that easy I'll post in the site.

(Mathematical Circles) Eleven students formed five study groups. Prove that we can find two students, say A and B, that every study group that includes student A also includes student B
 
Right, differentiable implies continuous. (You need to know that $x$ and $y$ are interior points of $U$. Which they are.)
 
Hey everyone, hope you're all keeping well!
 
8:13 PM
yes because U is convex.
 
@Liad: AND open.
@Balarka: You need to play the game we've played in complex analysis and differential topology all the time.
 
@Socrates Nope. Java (ugh) was my first experience, then I started to program in C, learn OOP (C++) and then Python
 
Caml 4 life
 
In the definition of the subbasis for the product topology above, in the collection $\mathcal{S}_{\beta}$ are we taking only one open set $U_{\beta}$ from every $X_{\beta}$?
 
8:15 PM
No, all possible open sets.
(or basis elements for the topology of $X_\beta$)
 
@krijn: On that page, it sounds like composite fields must have the same characteristic. Am I incorrect in that understanding? I'd like to "mix" two fields with different characteristic
 
@Extrarius You are correct in that understanding and you'll have a hard time to mix two field with different characteristic into a proper field
 
@TedShifrin Hmmm, I thought that the use of the same indexing set for $U$ and $X$, meant that we would only be taking one open set from every $X$, because if we change $\beta$, then we are taking an open set $U$ from a different $X$ (I hope what I said makes sense, it's a bit difficult to convey my reasoning here)
 
quantifiers, @Perturbative: Set-builder notation means you consider a collection formed by taking all possible open sets $U_\beta\subset X_\beta$ ($\beta$ fixed).
 
Hello!! I want to find the maximum of $f(x_1, x_2)=-(x_1+3)^2-(x_2-2)^2$ with the constraints $x_1, x_2\geq 0$. I thought to calculate the extrema as we would not have constraints and we pink only the positive $x_i$'s. Is this correct?
 
8:22 PM
Must the additive and multiplicative identity elements in a field be unique?
 
@Extrarius You can easily prove that for a group already
 
@MaryStar: You must also restrict the function to the boundary and use single-variable calculus to see what happens there.
OK, I'll be back later. Have fun finishing that, @Balarka.
 
@TedShifrin What do you mean?
 
@TedShifrin Ah so $\beta$ is fixed for $X_{\beta}$, but not for $U_{\beta}$
@TedShifrin Thanks for all the help!
 
@TedShifrin Yeah, will think about it.
 
8:24 PM
@Krijn: You seem to be knowledge about group theory. Are there any comprehensive introductions to group theory that you would suggest?
 
@Extrarius Sorry to say that I learned it from a Dutch source, but I'm not that knowledgeable on group theory
 
@Extrarius comprehensive and introduction do not really go together here
 
@TobiasKildetoft: Well, I'll take one or more of each if you have suggestions =-)
 
For introduction there are tons out there. Most of them will be for algebra in general rather than only group theory, but that is probably a better place to start anyway
I have heard good things about Artin's book, though I have not read it myself
 
@Astyx (insert puke emoji)
 
8:27 PM
Caml is better than it seems !
Even Facebook is starting to use Caml nowadays
 
I'm a computer programmer (with a basic computer science education) that is trying to learn areas with heavy mathematical underpinnings. (I recently posted about working to understand the building blocks behind elliptic curves)
 
Can u guys tell me what i did wrong
I tried to do this with synthetic division
 
@MATHASKER It's right
3 isn't a root (test it)
 
But the answer in my review sheet shows that it's different
Its x^2+2x^2+6x+30+17/(x-3)
 
That might be wrong
 
8:53 PM
the answer @Astyx?
 
Yes
 
like my answer or the the one the teacher gave?
 
Yours
 
oh could you tell me what i did wrong
 
I meant I like your answer :p
 
8:57 PM
so am i correct?
 
Hi @Semi
I think so
 
hi @Astyx
 
Ok thanks ya cuz i went over it a lot of times and was really confused
 
@AkivaWeinberger didn't know that, actually, but it makes sense.
 
And matrixmatrix makes a matrix whose sides are matrices.
 
8:59 PM
wait what
 
You heard me
 

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