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11:00 AM
@r9m I think the greatest professors are persons that inspire us, that make us to desire to reach their performance without forcing us to do that. You simply admire the person with his amazing abilities, you wanna be like that.
 
@DiscipleofBarney great!
@BalarkaSen im going to do some hatcher exercises after i ifnish probability theory
 
r9m
@Chris'ssis NIce :) having one or two professors like that really helps :)
 
homology ones or the fundamental group-covering spaces ones?
 
i think fundamental group ones
we still havent proved van kampen in the course
 
@BalarkaSen I like that I have a problem you consider crazy xD, I guess I am not doing super trivial stuff anymore
 
11:02 AM
those are harder.
 
(not saying you couldn't solve it easily if you had the will to)
 
F4z
For this equation: latex.codecogs.com/… I tried to make r the subject, and got latex.codecogs.com/… but the answer was supposed to be latex.codecogs.com/…
I'm wondering what happened to the 1 in the original answer?
 
@iwriteonbananas i've forgotten the geometric proof. just some general-nonsensical pushouts does the trick.
 
my prof loves abstract nonsense. we're going to prove van kampen via fundamental groupoid stuff and pushout stuff etc
 
i only recall the geometric proof of baby van kampen theorem (i.e., where $A \cap B$ is simply connected)
 
11:03 AM
@iwriteonbananas Are you guys using Hatcher or Topology and Groupoids (or something else)?
 
@iwriteonbananas ah, too bad.
there is a geometric proof in Hatcher, you may have a look if you want.
 
@DiscipleofBarney there's no official course book, but i assume my prof is taking a lot of stuff from tom dieck
 
@Incurrence no, no, i don't think it's trivial at all. i don't think i can do it very easily.
tom Dieck is a good book.
 
I'll post the proof up when I finish it and you can look or not depending on how you feel
 
@BalarkaSen i've looked at that prof but i forgot most of it
and yeah, i also like tom dieck
but hatcher is definitely more readable
 
11:05 AM
changed your opinion about it, didja? ;)
 
yes lol
and the exercises are amazing
one section has like 40+ exercises lol
 
indeed.
@iwriteonbananas 2.2, i think.
 
i have left out 3 or 4 problems from 2.2. hopefully i'll think about them when you start doing them. :)
 
cant believe you did 39-40 out of 43 problems in that section
 
11:08 AM
i was not sitting there eating grass all these 6 months. :P
 
FFT
 
@iwriteonbananas really, though, not all of the problems in 2.2. are hard. homology is an easy invariant once you get the hang of it.
very unlike $\pi_1$, but i like to think about it more than homology since your arguments tend to get more geometric.
 
ok cool, cant wait to do it in class
im procrastinating... im gonna finish probability theory now
 
i'm gonna go back thinking about $SP^n(X)$.
 
11:12 AM
@Incurrence A sort of fun way to calculate the inverse of $(I+N)$ is through a recursive process (and the recursion gives an intuition for the geometric series). Suppose that $X$ is the inverse, then we have $(I+N)X=I$, so $X+NX=I$ and that means $X=I-NX=I-N(I-NX)=I-N(I-N(I-NX))=...$ and because of the matrix is nilpotent, when you multiply this sequence out eventually the terms will be zero.
 
Oh that is a fun one, thanks xD
 
definitely let me know when you prove it, @Incurrence. i'm interested.
 
Hi @BalarkaSen again!!!
 
11:31 AM
@Incurrence Also the group you are studying (higher dimensional/generalized) Heisenberg group. As another exercise (as I saw you were doing some stuff with semidirect products), you can show the integer entry, 3 dimensional Heisenberg group $H$ is an extention of $\Bbb {Z}^2$ by $\Bbb Z$, so there is an exact sequence $1 \to \Bbb Z \to H \to \Bbb Z^2 \to 1$, and show that there is an exact sequence that does not split, so $H$ is not necessarily an indirect product, $\Bbb Z^2 \ltimes \Bbb Z$.
It should help get a grip on the idea of exact sequences, indirect product, and how they are connected.
 
12:26 PM
In measure theory, if $\nu$ is a measure on $Y$, then the notation $\int f d\nu (y)$ is only meant to signify that $\nu$ is a measure on $Y$, and one could just as well write $\int f d\nu$. Is that correct?
 
r9m
@Chris'ssis I must be ultra-dumb or sth :| .. no need for artillery :| .. The integral $\displaystyle \int_0^1\frac{\operatorname{Li}_2(x)\log^2 (1-x)}{x}\,dx$ can be computed easily enough with $\operatorname{Li}_2(x)+\operatorname{Li}_2(1-x) = \zeta(2) - \log x \log (1-x)$ :o and ofcourse knowing the value of $\sum\limits_{n=1}^{\infty} \frac{H_n^{(2)}}{n^3}$ .. :)
 
@AndrewThompson yea
 
Thanks, @iwriteonbananas.
 
@BalarkaSen u there?
 
12:56 PM
@Iwrite Can you verify a ultra short proof for me?
 
ADG
1:08 PM
@iwriteonbananas why are you writing on bananas please stop that immediately!
 
@DiscipleofBarney Thanks I'll give it a try tomorrow, I appreciate the help
 
@Incurrence sure, i will if i can
@ADG i live in a remote jungle region with no access to paper
 
ADG
@iwriteonbananas yet an access to a fast internet connection and a PC?
 
@Incurrence the proof looks okay to me....ur making me look up some linear algebra again
@ADG i hiked 4 hours through dense rainforrest to the nearest computer with internet access
 
@iwriteonbananas Haha, he said it was alright, and on second type up I feel it is good
 
1:23 PM
@Incurrence who said it was alright?
 
Hagen von Eitzen
 
@iwriteonbananas Oh did you not see his response :S
Well looking up some linear algebra again can only be a good thing I hope haha
 
@Incurrence no, hadnt refreshed the page, i was re-learning linear algebra lol
 
@iwriteonbananas xD
 
ADG
1:30 PM
@iwriteonbananas i have no Idea
 
2:05 PM
@iwriteonbananas now I am
 
2:19 PM
good
this exercise confused me
 
hi bananas, @Balarka
 
hey ted
 
hey @Ted
 
coolio
that's a fun exercise.
 
2:21 PM
okay, $X$ deformation retracts onto $S^1 \vee S^1 \vee S^2$, so the first part of the exercise is clear
 
right
 
i dont understand how $Y$ can have such a presentation though. it is obtained from $X$ by attaching a 2-cell, right? so we should have $\pi_1(X)/N \approx \pi_1(Y)$
 
why is it obtained from $X$ by attatching a 2-cell?
 
cant we re-attach a disk in the same place that we removed it to get X again?
 
i don't know what you're talking about
 
2:26 PM
ok
is $Y$ homotopy equivalent to some familar space?
meh i guess not
 
sorry, i was doing two things at once
 
Hi @TedShifrin. How was your final week of teaching?
 
@iwriteonbananas try to draw the fundamental polygon of $Y$
 
hi @MichaelA ... well, I've got one more review class and a office hours to go ... Sorta bittersweet. I taught a half-hour introduction to complex variables to the end of my multivariable course ... showed them $\partial$ and $\bar\partial$, proved Cauchy integral formula and power series expansions :)
 
2:31 PM
why is it not the klein bottle with a disk removed?
 
yes.
can you give it a cell structure?
 
sure, but the klein bottle with a disk removed is $S^1 \vee S^1$ (so it's not our space Y)
 
it's not a klein bottle minus disk.
 
i guess we glue the boundary of the disk we remove to something
 
the tube of the bottle is sticking to the boundary of the disk you chucked out.
 
2:36 PM
yes
so the fundamental polygon of Y is that of the klein bottle with a disk removed where the boundary of the removed disk is glued to...?
 
@TedShifrin Nice. Did they ask if it would be on the final?
 
it's a cylinder minus disk with the two ends of the cylinder pasted to the boundary of the removed disk, the first attachment by $x \mapsto x$ and the other by $x \mapsto -x$, @iwriteonbananas
it's 1-skeleton is the three-boquet.
see if you can determine how the 2-cell is attatched.
 
LOL, @MichaelA, I had already told them it wouldn't .... some of them were quite excited about it ... others, not.
@Balarka: it's bouquet :P
 
too much to write
 
that was a cool question you asked a few weeks ago, @MichaelA ... about the acyclic cover. As usual, Georges nailed it nicely.
glares @Balarka
 
2:45 PM
Both of the answers were helpful. I should have thought about Theorem B first. It clarified a few things for me actually.
 
I'm very rusty on stuff I used to know very well, but I guess not using parts of math makes them atrophy, just like muscles ... :D
 
@BalarkaSen ok yeah
 
@TedShifrin i mean "t mch t wrt"
 
fuck i gotta run
 
@Balarka: You should learn Hebrew ... no written vowels.
 
2:48 PM
sry
 
bubye, bananas
 
catch u later
 
by
@TedShifrin meh
 
LOL
 
@TedShifrin why are symmetric products so interesting, btw?
 
2:54 PM
because lots of symmetric functions on products factor through them ... so they're a natural space to study such functions on.
 
i mean, sure, inspecting their topological properties are fun, but i am not sure why it's important. so far the only "very cool" property i have found till now is that it takes Moore spaces to Eilenberg-Maclane spaces.
@TedShifrin that leaves me kinda unsatisfied :P
 
3:06 PM
well, important in algebraic geometry because, for example, of the Abel-Jacobi map to the Jacobian variety
 
sounds complicated
 
Hi@TedShifrin @BalarkaSen
 
Can some one double check something for me
i calculated the gradient for these two points: (-2,1) and (4,-3) as -4/6 = -2/3
do you get the same result?
 
Yes you do @Dave
 
well i tested it on this image
but the points don't sit on the line
bit confused because i used those very points to calculate the gradient in the first place
 
3:16 PM
You find the gradient by dividing the change in y coordinates / change in x coordinates
 
yeah thats how i got -2/3
 
So you are right....
 
so why don't the points sit on the line =/
 
Where did you try them? Try with something else
 
do you know other websites with interactive graph tool?
 
3:25 PM
Sorry I don't
@TedShifrin you on your video showed linear transformations geometrically like reflection and revolution I was thinking are there any more?
 
@Remember loads
consider the linear transformation you get by first rotating and then reflecting :P
every linear transformation can be geometrically seen.
 
Like
 
i just gave you an example.
you can also visualize stretching
that every linear transformation can be "seen" is obvious, as every vector can be thought of as an arrow.
 
I mean something absolutely different like changing a figure to something else is that a linear transformation?
Stretching is just like scalar multiplication
 
that sounds nonsense to me. what do you mean by changing a figure?
 
3:33 PM
Like changing a circle into a square by functions.....I think so... :p
 
not a linear transformation.
of course every map between vector spaces is not a linear transformation, as otherwise the "linear" term would be pointless
 
I mean examples like those are those linear transformations?
 
you should study basis well enough before trying to study linear transformations, btw
@Rememberme what you said is not a linear transformation. i dunno what you mean by "examples like those"
 
Yes yes.....its just Ted's lectures....
They are amazing
 
have you studied matrices well, though?
row-reductions, etc?
 
3:37 PM
@BalarkaSen yes I have without them you can't do questions in Hoffman kunze
 
ok, do you think you can do a problem?
 
Let's see fire it at me...
 
@Remember prove that every invertible matrix can be row-reduced to the identity matrix.
in fact, prove that every matrix, after sufficiently many row-reductions, can be row-reduced to either to the identity matrix or to some matrix with a whole row zero.
 
That's a theorem in Hoffman kunze the second statement which you wrote
 
okay, i see.
this fact is useful because you can invert matrices by row-reducing the block-matrix $[A | I]$ to $[I | A^{-1}]$
 
4:04 PM
Hello, i have that $\theta_n\rightarrow \frac{N}{p}$ when $n\rightarrow\infty$ can i say that $$\lim_{n\rightarrow\infty}\int_{\Omega}(|x|^{\theta_n} |u_n(x)|)^q dx =\lim_{n\rightarrow\infty}\int_{\Omega} (|x|^{\frac{N}{p}} |u_n(x)|)^q dx$$
please tell me if it is right ?
 
4:55 PM
@r9m Sure. There are many things one can do to get that result. :-)
 
good morning guys
 
I see 6 stars for the message of Ted "Let him learn the rest of mathematics before you commit him to one small subject area, @Chris'ssis.", but if I ask those 6 that starred the message some simple question form that "small subject" and they don't know to answer, then how to interpret that?
 
hey @Rememberme what do you want to discuss about linear transformation?
 
5:21 PM
@r9m all day I thought of those integrals I mentioned. Indeed, it's some challenge to ask someone to do it completely without using CAS.
I cannot open the page of integralsandseries here integralsandseries.prophpbb.com
General Error
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Can't connect to local MySQL server through socket '/var/lib/mysql/mysql.sock' (2) [2002]

An sql error occurred while fetching this page. Please contact an administrator if this problem persists.
 
Hey!!! Could you take a look at the following?
1
Q: The graph has an Euler tour iff in-degree($v$)=out-degree($v$)

evindaI am looking at the proof that $G$ has an Euler tour iff in-degree($v$)=out-degree($v$), that I found at this site: www.cs.duke.edu/courses/fall09/cps230/hws/hw3/headsol.pdf (Problem 2) A simple cycle is a path in a graph that starts and ends at the same vertex without passing through the same ...

 
5:36 PM
Quick, silly question that I feel like should be obvious. If we have two finite dimensional vector spaces of the same dimension, and a series of invertable operators T_n going from one to the other that converges to a non invertable operator, we must have an eigenvalue of the T_n's going to 0, right?
(Convergance in operator norm, not that it really matters since it's its all finite dimensional and norms are equivalent)
 
6:01 PM
@Alan "Invertible", "convergence".
 
hi mr @Pedro
 
Hello.
 
Soggy day here ... how're you doing?
 
Not bad. Gave one class early in the morning, now solving some problem sheets.
 
Hi, I am trying to understand what this means. Would one mind having a look at it? math.stackexchange.com/questions/1250139/…
 
6:07 PM
problem sheets for ?
 
Hi @TedShifrin
 
@user96343: What do you not understand?
hi @Karim
 
@TedShifrin Homological algebra.
 
ah, cool ... Is that Mariano's course or another one?
 
@TedShifrin what do you think of my reading list this summer. Abstract algebra introduction thomas W.hungerford, David & dummit,Topology munkrees,analysis aboot,analysis rudin
what do you think ?
 
6:09 PM
No, Mariano's is Representation Theory of algebras.
 
ah, ok, I thought he was doing representation theory
any good problems, homologically speaking?
 
@TedShifrin, I am trying to understand what a curve is. I get the impression that ${z([a,b])|z(t):[a,b]→C,z,z′are continuous}$ is a curve from $a$ to $b$ but I am not sure.
 
@Karim: Wayyy too much. Learn analysis before topology. And maybe work on algebra first. Why not wait to learn stuff in courses?
@user96343: They're just trying to get you to think of a curve as the path you see, rather than as being given by a particular parametrization. $\gamma^-$ means you do the reverse path, going from $b$ to $a$, rather than from $a$ to $b$
 
@TedShifrin Hmm, some are nice. I will have to apply Künneth's formula for the next problem.
Not sure how that will go... =)
 
@TedShifrin, also I don't understand what this $\gamma^{-}$ really is.
 
6:11 PM
Künneth is nice ... sort of the homological version of wedge product in deRham cohomology, @Pedro.
 
I want to excell in these courses @TedShifrin next fall. I am taking topology,analysis,3rd algebra,pde
 
Too much, @Karim. Take analysis and learn it well before you do topology.
 
yeah I took measure theory before analysis which is weird I did really well, but yeah I should concentrate on analysis first before topology.
 
measure theory before analysis is totally nonsensical
 
@TedShifrin, I mean how do I properly define a curve? Also, they have mentioned one of the parametrizations for $\gamma^{-}$ but I would really like to hear the definition of an oppositely oriented curve.
 
6:13 PM
don't you have a reasonable faculty adviser there, @Karim?
I told you the definition, @user96343. The reverse path travels backwards along the same geometric path.
 
@TedShifrin Ah. OK.
 
no and when we make an appoitment they schedule us in like 1 month @TedShifrin
 
Sigh, @Karim. I just sent my advisees a farewell message. I figured I've advised close to 1000 students over my 30+ years.
@AlexW
 
@Ted!!!!!!!!!!
How's it going? :)
 
oh thats nice if I was your student then I would get you a farewell gift :)
 
6:15 PM
@TedShifrin, what I mean is like some sort of a set theoretic definition. Otherwise, wouldn't I have to define "geometric path" and such words?
 
@user96343: That's why their definition is in terms of equivalence classes ... Two paths define the same curve if you can reparametrize one to give the other, provided you go from the beginning to the end, not vice-versa.
 
@TedShifrin
 
I am not really good at this.
 
You can't give a set theoretic definition. You have to define equivalent functions.
 
@TedShifrin, one sec, I'll think about this equivalence class definition.
 
6:17 PM
Doing ok, @AlexW ... working on getting my house ready to show in a few days. AGH.
You almost done with your work?
 
Ah, right! Your big move is coming soon. Excited?
 
Mostly ... a bit scared :) And you?
 
That's right! My last day is May 7th.
 
Ah, that's about the time I'll be done grading finals and assigning grades :)
 
I'd have to say mostly the same. Extremely excited. A little daunted by the math I'm shooting to cover. Grateful to be leaving here soon.
 
6:19 PM
Well, @AlexW, you can expect many ups and downs ... We all go through that, both in grad school and after.
But if it's your passion, you'll persist and succeed :)
Good night, @Mike.
No farewell gifts, @Karim. :P
 
so whats life as grad student like @AlexWertheim?
 
Ask him in a year, @Karim :D
 
okay :D
 
I hope so @Ted, I certainly hope so. :)
If anything, I think this year has been very helpful in confirming that.
 
Well, you have a big advantage, @AlexW, having had that year's experience as a motivator.
 
6:21 PM
Lol indeed @Karim, check back with me in August/September.
Right, @Ted? I know what the other side is like, haha. It'll be a good reminder that I'm in the right place.
 
I've told many an undergraduate student/advisee who wasn't working anywhere near up to his potential to drop out, get a job, and come back when the motivation was there.
 
There's nothing like it. And if that person ends up loving their job, then that's a win too.
I had to see that for myself, I think. I only wish I had learned this lesson over a summer instead of a year. But c'est la vie, n'est ce pas? =P
 
On apprend de plus en plus toujours, chaque jour ...
 
Mon dieu, c'est vrai!
 
LOL
 
6:27 PM
And there I go, having exhausted what little french I still remember. :)
It's high time I actually go back and relearn some.
 
morning
 
Il te reste beaucoup à apprendre :P
 
@TedShifrin Definition:Let $z:[a,b]\to \mathbb{C}$ and $w:[c,d]\to \mathbb{C}$,$a,b,c,d\in mathbb{R}$. We write $z~w$ iff $z$ and $w$ are equivalent(the notion of equivalence of two parametrizations is defined in the book I am reading). Let $S=\{f:[g,h]\to \mathbb{C}|g,h\in \mathbb{R}}$ . Then a curve from $a$ to $b$ is the equivalence class $[z]=\{w \in \mathbb{S}\|z~w}$. Is this better?
 
Hello, @MikeM
 
<--- already gave Mike the requisite greeting
If you insist on being that pedantic, yes, @user96343.
 
6:30 PM
I picked up one of your colleague's books the other day, @Ted.
 
which was that, @AlexW?
 
Lorenzini's "An Invitation to Arithmetic Geometry". Should be here any day now, I'm excited.
 
Ah, I don't know it, but he's a very clear lecturer, so I assume the book is good.
 
He apparently said of that book: "Never write a book as a junior faculty member"
 
@TedShifrin, sorry for being pedantic. I don't know math well and I am learning, so I am trying to understand this better. I will now try to understand $\gamma^{-}$.
 
6:31 PM
Literally turn the arrow backwards, @user96343.
 
It looks very beautiful, and from what I can see is a fairly gentle introduction.
 
In this publish-or-perish rat race, writing books isn't suggested until after tenure. A research monograph might be slightly different. But even I, less into the research game, waited until I was promoted before starting ...
 
Which, I suppose, is suggested by "invitation" in the title, as opposed to "A Brutally Difficult Introduction to Arithmetic Geometry".
 
I would never call a book an invitation, @AlexW ... I'd have to say "an invitational geometric approach" :D
 
"A Warning From Arithmetic Geometry"
 
6:34 PM
LOL. :) I'm waiting for your autobiography @Ted: "The Life of Ted Shifrin: A Geometric Approach".
 
I expect there will be a number of jokes at my expense at my retirement "celebration," @AlexW
 
the roast of ted shifrin
 
maybe it's time I turned vegetarian
@Mike: I suppose you can email your contribution.
 
What are the plans, @Ted? A departmental party? A small dinner?
 
It's an evening at the botanical garden, @AlexW ... a lot of people can't make it because it's a week after graduation and they are out of town. But some students from years and years ago are coming, so that makes me very happy.
 
6:36 PM
Publish or Perish
 
That's great, @Ted. I'm sure they're both very happy for you and remiss to see you retiring.
 
heya mr eyeglasses
 
@TedShifrin, which arrow should I turn backwards? [g,h] to C?
 
I polled lots more people about your situation. Many suggested you seek out the department head for assistance, interestingly.
 
I feel like that's a bit too far
It might not be, but I think it's over already
 
6:38 PM
@user96343 ... the arrow on the curve that says which direction you're moving as the parameter increases.
 
I'm not sure if it's worth pursuing
 
There was general agreement that professors make mistakes, but everyone said he should have been willing to explain what was wrong with your work, thereby discovering that he was wrong.
 
Hey @DanielFischer
I want to write an algorithm that finds an optimal vertex cover of a tree in linear time O(n), where n is the number of the vertices of the tree..

I have tried the following:

http://pastebin.com/8PUhynhd

Its time complexity is $T(n)=\sum_{i=1}^{|V|} O(|V_i|+|E_i|) \leq \sum_{i=1}^{|V|} O(|E_i|) \leq \sum O(|E|)=O(|V| \cdot |E|)$.

($|V_i|, |E_i|$ are the number of vertices and edges respectively of the subtrees at the root of which we call DFS )
Right? Or have I calulated the time complexity wrong?
 
well, it made all my colleagues sad that a university professor would act that way, mr eyeglasses, if that makes you feel better.
 
@evinda I'm not a computer scientist (nor graph theorist), I don't know what a vertex cover is. I'm sorry, but I can't help you with that.
 
6:42 PM
heya, @DanielF :)
 
I find it hard to believe it's not pursuing. Maybe it's not pursuing if the end goal is to get those points back. But if nothing is done, your professor will not change the way he acts.
 
Hi @Ted. Retirement already arrived, or still a week to go?
 
@TedShifrin Do you know who Olga Kharlampovich
 
No, mr eyeglasses
last class on Monday, @DanielF ... then two finals to go.
 
Hi @MikeMiller.
 
6:43 PM
morning daniel
 
@TedShifrin Finals? Written exams, or oral?
 
@TedShifrin, while defining the equivalence of parametrizations, they said $z$ and $w$ are equivalent when there is a continuously differentiable bijection $s\to t(s)$ from $[c,d]$ to $[a,b]$ so that $t'(s)>0$ and $w(s)=z(t(s))$. To define orientation, can we just change this to $t'(s)<0$, keeping everything else same and then define a new relation based on this "reverse-equivalence" or whatever name one gives it?
 
Written finals always, @DanielF ...
 
Then you'll have a last grading also looming :(
 
@user96343: Sure. Note that that means that you start at the endpoint and end at the startpoint.
yup, @DanielF ...
I'm pretty efficient at grading, though ...
Although I try not to mark students wrong when they're right :D
 
6:46 PM
@TedShifrin, you mean my attempt at understanding $\gamma^{-}$ is flawed?
 
Practice makes perfect.
 
No, @user96343, I was just adding oops a "note," not a "not." Darn.
Sorry about that.
Too much going on.
 
@TedShifrin, thank you very much! However, may I ask you a question I already asked Mike Miller once and tried to ask on academia but it was closed?(It is basically on how to deal with a professor )
 
LOL, based on my discussion with mr eyeglasses, I'm not sure I can be of much help, @user96343.
 
@TedShifrin, okay then, thanks. I would have still been glad to hear your opinion on this difficult situation.
 
6:51 PM
Sadly, professors are just like human beings. Some are excellent, most are average, and plenty are awful.
 
@DanielFischer Ok.. No problem :)
 
@robjohn how are you doing? You're pretty silent these days.
 
@TedShifrin, thanks then. It was kind of you to help. And happy retirement.
:)
 
@evinda @Ted Guten Abend :)
 
guten Abend, @Alessandro :)
@user96343: What was the problem, briefly?
 
6:54 PM
@Alessandro Guten Abend :) Wie geht es dir?
 
Super! Ich habe gestern die B1 Prüfung geschrieben @evinda
Ich muss 3-4 Wochen auf das Ergebnis warten, aber ich bin sicher dass ich die Prüfung bestanden habe
 
Prima!!! Herzlichen Glückwunsch!!!!!! :) @Alessandro
 
@TedShifrin, there is this professor X who clearly doesn't like professor Y. X perceives me close to Y and one day, when I absolutely had to visit X on some purpose(some committee meeting of students), X erupted suddenly and asked me why I was keen on such meetings(it is my responsibility to be there) and suddenly accused me of being close to Y and being shielded by him. Now, I have never taken X's course or done anything remotely impolite in the last few years.
 
whoa ... this sounds like very unprofessional and unstable behavior. One of my colleagues basically doesn't speak to me, but I don't believe he holds it against my students/advisees. That's just ridiculous.
 
Now, I need to speak to X at times because X is one of those people on the committee and is powerful(seniority wise, Y is still a more important person in the department(the head)).
 
7:00 PM
is this a small department, @user96343?
 
So, I was wondering what I should be doing. Till now, I have resorted to not talking to X unless absolutely required minus any small talk. This has 16 people.
 
X is behaving unprofessionally.
 
yeah
its like kids
 
He obviously has a problem with the department head.
I assume Y knows about this?
 
does this high school stuff happens usually between professors @TedShifrin ?
 
7:01 PM
@TedShifrin No, I did not really report this is to Y because I didn't know what to do. Also, whenever I need to speak to X, it is hard to: he keeps finding ways of erupting at me.
 
there are personality/professional conflicts that occur, @Karim, but most of us are adult enough not to let it affect our students.
 
I see
are you taking any class from him @user96343 ?
 
If you cannot manage to avoid X, @user96343, and you've done nothing personally to make him upset at you, I think you need to let Y know and I would suggest you remove yourself from that committee.
 
@KarimMansour, no. I am not.
 
I would say avoid him and not class from him but I wouldn't suggest reporting to Y though since later if you did take a class from him he wouldn't put you in his mind.
 
7:04 PM
@TedShifrin, I was just elected. It may be hard to quit so quickly from the committee without citing a very strong reason. It may beg the question as to why I ran for it(the place in the committee) in the first place.
 
just say I am busy with school or something
 
if faculty member X cannot deal with you professionally, that's a strong reason, unless the committee can avoid X.
what advice did you end up with on academia, @user96343?
 
@TedShifrin, okay. I shall try to communicate this to Y. They said it was offtopic on academia.
 
doesn't seem so off-topic to me ...
 
I framed the question a bit more vaguely and maybe that lacked enough details.
 
7:07 PM
Professional behavior and lack thereof is an issue all over academia.
 
that sucks
yeh I guess humans can't stop being humans afterall
 
@TedShifrin, well, thank you. I think I will speak to Y about this.
 
that's probably a fair conclusion, @Karim
 
@KarimMansour, thank you too.
 
np @user96343
 
7:53 PM
@AlexWertheim Looks like a good book.
 
8:26 PM
@r9m it's interesting that no one answered this question
(from there I'm only interested in unanswered questions - when I enter there - pretty rare though since I still have a lot of stuff from my research)
 
r9m
@Chris'ssis why is that interesting?
 
@r9m I was saying it's interesting that no one answered the question. Is it that difficult?
 
r9m
@Chris'ssis How am I supposed to know .. maybe they have other things to do :| .. in other words if you think it deserves an answer you can just join that site and put an answer
 
@r9m What do you think about that integral (as difficulty)?
 
The original founders of the forum are long gone.
 
r9m
8:39 PM
@Chris'ssis nothing .. does not interest me atm
 
@r9m OK
@BalarkaSen Who are they?
@r9m You don't seem in a great mood, no smile or anything like that. :-)
 
The admins and the mods, mostly. Shobhit became absent pretty abruptly, last time I heard.
 
@BalarkaSen Who is Shobhit?
 
The admin of the forum.
 
I see.
 
8:53 PM
where did he go @BalarkaSen ?
 
i don't know
hi, btw, @Karim
 
Hey @BalarkaSen I m reading hungerford btw atm
 
haven't seen it.
@Mike Eek.
these two guys sure had a crush on pathological spaces
 
who
 
the authors of the paper.
click on the ping :P
 

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