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8:00 PM
I sould try harder to keep things in the correct vats, the balance in my brain is out of whack;
 
@anon
 
@Kevin, I am always scattering from the main project i have to complete :)
 
@PedroTamaroff breathe first, pedro
 
@Irina It happens to me too. It has happened to every grad student I've talked to. So I guess it happens to everyone.
 
@Kevin, you are also in 1st year ?
 
8:05 PM
@Irina this is my 3rd
 
@Kevin, how long takes PhD there ?
 
@Irina It always depends. 4 years is fast. 7 years is long. Everything in between is pretty average
 
@Kevin, generously reworded :)
we seems to be done with cubic calculator; now gotta rest;
I got a friends, it's nice to have common interests ;)
 
8:24 PM
@KevinDriscoll 3 years is cheating.
 
@N3buchadnezzar hi $\varnothing$instein
 
@N3buchadnezzar I agree. Though I know of someone who did it here. Work 7 days a week all day.
 
@KevinDriscoll That is my life now, although I can take a day off when needed.
 
@N3buchadnezzar That is rough. If I'm working hard I get up to around 60 hours a week with research and TA duties. But most weeks I'm not that diligent
 
Yeah, it is a lot of work. Although I do have a lot of extracurricular activites as well. So it is more fun that it sounds. Although I am more outside my door than inside :p
 
8:30 PM
@ted will you say hi?
 
I'll say hi if someone says hi to me :)
 
@KevinDriscoll Doing mathematics for the fun of it is... Suprisingly fun.
 
@Ted Hiiiiiiiiiiiii
 
I was just answering an email from one of our grad students who has been put in a totally awkward position by a professional who is abusing his position.
Hiiiii @Kevin and @Charles.
 
@Ted That's dispicable.
 
8:31 PM
@TedShifrin i always say hi
 
Yeah, I'm really pissed off at this guy ... at a different institution in our state.
 
@Ted There is a professor here who I constantly avoid because he has a reputation for doing similar things
 
He's taken helicopter parenting to all new levels. And I hope he hears I'm bitching about him here :D
 
Prepare the bitchcopter
 
I do not know anything about the guy, but he's emailed at least two faculty and one graduate student trying to line up tutoring for his child at UGA. Of all people, a faculty member somewhere else should know how fed up with helicopter parents we get and how inappropriate it is to be one!!! GROWL^5.
2
 
8:33 PM
@TedShifrin Heya.
 
Howdy @Pedro ... I thought you had purposely escaped once I showed up :D
LOL @N3
 
@TedShifrin Nah. Why would I do that ? =O
 
it's your new meme, @Pedro
 
Indeed. Gotta let the kids take care of themselves, or they'll never learn.
 
@TedShifrin Oh...?
 
8:34 PM
I am trying to find the expectancy value of the area of a triangle inscribed in a circle of radius R. Hmmm
 
So one of my students decided to name our "obligatory sentence" for linear independence proofs the Declaration of Linear Independence. :) I thought that was hysterical ... and then I found out some mathematician wrote such a thing in 1988
 
I don't understand. Is this a parent or a professional in the university, or both?
 
Ah, that's a cool problem, @N3buchadnezzar
Both, but professor at a different university, @Pedro. But then trying to use his position to coerce a favor from a grad student at our school.
 
@TedShifrin Ah, that is what I was guessing.
I have a question.
 
I am livid ... I was already upset that he was bothering faculty here to do favors for him and his child, who should be adult enough to take care of him/herself.
RANTS and signs retirement papers.
What is your question, @Pedro?
 
8:38 PM
@TedShifrin Well, I am reading the following property about algebraic integers.
Whenever $\alpha$ is an algebraic integer, then $\Bbb Q[\alpha]=\Bbb Q(\alpha)$.
 
Indeed. Quite related to the question someone was asking last night that @anon and I addressed.
 
But I am not sure where in the proof it is used that $\alpha$ is an algebraic integer.
 
Oh, no need for it to be an integer. Just an algebraic number.
 
@TedShifrin Ah, I see. Figured. So typo in Ireland and Rosen.
 
8:39 PM
That's an unfortunate typo :(
But I have plenty of errors in my own books, despite being o so careful, so I know it happens all too easily.
 
@TedShifrin They also have non-standard nomenclature. Not that it bothers me, it is just curious.
 
Odd, since it's a relatively recent book.
 
@TedShifrin They call a subset of $\Bbb C$ a $\Bbb Q$-module if it is a finitely generated $\Bbb Q$-module.
Same for $\Bbb Z$.
 
well, that's probably a convention that others will make for convenience ...
 
@TedShifrin Ah, dunno.
Using those concepts they prove the algebraics are a field and the algebraic integers are a ring.
The proof is really cool.
 
8:45 PM
Right. Yes, I always am tempted to teach that proof when I do field theory for undergraduates and do not prove the primitive element theorem.
 
@TedShifrin What is the "primitive element theorem"?
 
It actually came up in the solution of a tricky problem I wrote for our high school math competition a few years ago. Here you go: When is $\cos(2\pi/n)$ or $\sin(2\pi/n)$ a rational number?
Primitive element theorem says any finite algebraic extension is given by a single element.
 
@TedShifrin Ah.
Well.
The lemma they use is the following.
Let $M=[\gamma_1,\ldots,\gamma_r]$ be the $\Bbb Q$ (resp. $\Bbb Z$)-module generated by $\gamma_1,\ldots,\gamma_r\in\Bbb C$.
If $\alpha$ is such that $\alpha\gamma\in M$ whenever $\gamma\in M$ then $\alpha$ is algebraic (resp. an algebraic integer).
 
@Pedro: The actual question I posed was: For how many $n\in\Bbb N$ can we pack circles of radius $1$ tightly between concentric circles of radius $n$ and $n+2$?
 
@TedShifrin Ponders.
 
8:51 PM
Edited. ... For your question, it's sort of interesting to try to bound the degree of $\alpha+\beta$ and $\alpha\beta$ when you know the degrees, or to find the minimal polynomial therefor if you know the minimal polynomials of $\alpha$ and $\beta$.
 
@TedShifrin I'd have to think about it.
 
About all of the above? :)
 
@TedShifrin The circles thing.
 
You hate it when I make you think :D
Yeah, it was one of two or three problems in a sequence of problems I wrote.
 
@TedShifrin Well, I need to look at a sum of arclengths.
 
8:54 PM
really?
 
@TedShifrin You want to pack circles of radius one perfectly between $n,n+2$, right?
 
Yes ...
 
hi
 
Hi @Twink
 
@TedShifrin Well, or look at some angles that give rise to tangent lines.
 
8:56 PM
Right.
 
@TedShifrin I will think about it.
 
Okey dokey. I'll check in later. :)
 
@TedShifrin Ted.
Is Lang's Algebra too advanced?
 
no
that's the book I use
 
hello guys
 
9:08 PM
and it's easy
hoffman is more difficult
 
@Twink What is the full title of your book?
 
Linear Algebra
I have it in PDF
do you want it?
 
@Twink I am not talking about that one. I am talking about "Algebra".
 
is there is a way to transport all the account informatons and to another one and then delete it?
 
@mohamez You can ask that in meta.stackexchange.com
 
9:16 PM
that's what I am doing right now thank you
is sharing ebooks illegal here in chat?
 
@mohamez It probably depends on your countries regulations. I don't know.
I wouldn't use MSE which is USA based for sharing ebooks that are not allowed to be shared.
 
I think is't not a problem here in my contry
$\epsilon$
$\in$
 
@mohamez $\in$
 
hi
 
Does 0.441725735696674 resemble any simple fraction or something involving $\pi$?
I did try Wolfram Alpha, but alas it did not bear any fruits.
 
9:31 PM
hello @mick
 
9:41 PM
@N3buchadnezzar Is that a rounded number or a truncated one?
 
Truncated
 
@N3buchadnezzar How many digits of accuracy?
 
Four so far, I am running some longer computations for higher accuracy now.
0.4417
 
Ah okay, then it'll be hard ot tell
if you can get 10+ digits of accuracy you can use the ISC, do you know about it?
@N3buchadnezzar
 
Yeah
It should be the expectency value of the area of a triangle inscribed in the unit circle
 
9:51 PM
@N3buchadnezzar ISC suggests theres a number of things it oculd be involving $\sqrt{\pi}$ based on what you have
 
will ponder a bit about it
Thanks for the help!
 
@mohamez hi :)
@Irina hi
 
hi
does anyone understand this sentence from wikipedia?
"It has been proven that if a finite group is generated by a subset S, then each group element may be expressed as a word from the alphabet S of length less than or equal to the order of the group."
 
10:11 PM
euh yes
I have to go guys sorry
goodnight
check out my questions if you like :)
 
10:25 PM
@Pedro: it's very dry, and not enough good exercises. It's tough even for grad students, but you might like it. Dummit and Foote is verbose, but has excellent exercises. I woukd recommend Jacobson over Lang.
 
11:02 PM
@TedShifrin Well, I do have Jacobson's BAI.
 
Good :)
 
@TedShifrin Jacobson is also a baddie, though. =)
 
He's more concrete than lang. He also does decomposition of modules in terms of Euclidean alg, as I recall.
 
What is the charactieristic of $Z_4 X Z_6$? Is it just characteristic 4 multiplied by characteristic 6 = 24?
or is it just characteristic 6?
since the relations in Z_4 are redundant
 
@DonLarynx Don't guess.
Think.
Pick a usual element of $\Bbb Z_4\times \Bbb Z_6$.
It is of the form $(m,n)$.
Oh, Ted.
 
11:08 PM
I guess characteristic refers not only to fields ...
 
@TedShifrin He probably means order...?
 
Let's find out ...
Could be the smallest $k$ s.t. $ka=0$ for all $a\in R$?
 
So pick an $(m, n) \in \mathbb{Z_4} X \mathbb{Z_6}$. For example $(3, 5)$. Then $k = 12$.
I don't know
 
Do you have a definition, @Don?
 
where is a good source to read about this?
all of my sources suck atm
A characteristic p is such that p(1) = 0.
 
11:16 PM
@DonLarynx Note that $12={\rm lcm}(4,6)$
 
I'm not sure what "this" means ... But $p$ normally means prime. Are they talking about fields or general comm rings?
 
@PedroTamaroff What is a good source online to read about this?
 
@DonLarynx I don't know what "this" is.
 
characteristics of cartesian products of rings
 
11:26 PM
for $n*a$ they define it as $(n-1)a(a)$
so in $\mathbb{Z_6}$ we have $n = 6$ so we get $5a(a)$. I don't know how to make sense of this @PedroTamaroff
 
@DonLarynx Come again?
 
@DonLarynx You're misreading things. They define exponentiation recursively.
In fact they have a typo in the monoid part. It says $x$ when it should say $a$.
 
Okay, so....What do they mean by: $n∗a$ they define it as $(n−1)a(a)$. Can you please give me an example?
 
@DonLarynx Do you know what it means to define something recursively?
 
11:34 PM
Not how they defined it
 
@DonLarynx What do you mean?
 
Please show me an example where the equation $(n−1)a(a)$ is used
for $na$
 
@DonLarynx What they mean is this.
Consider the integers, for example.
Then, suppose you want to obtain $7\times 8$.
Here $n=7$, $a=8$.
Look at the integers additively, forget about multiplication.
Then to obtain $7\times 8$, you do $8+8$.
Then do $8+(8+8)$.
And so on.
Until you get $7\times 8$ which is defined here, as $8+8+8+\cdots+8$.
Seven times.
The recursion tells you how to obtain $na$ from $(n-1)a$.
Namely, $na=(n-1)a\cdot a$.
 
got it, thanks!
it makes so much sense now
so for $\mathbb{Z_3}$, we can say $((1 + 1) + 1) = 0$? @PedroTamaroff
 
@DonLarynx Yes.
 
11:49 PM
We need more people like you in this world
@PedroTamaroff But the question now is different. First, do you agree the $lcm(a, b)$ is the characteristic of $\mathbb{Z_a} \times \mathbb{Z_b}$
 
@DonLarynx Use \times
 
I don't understand how though]
Can you point me in the right direction?
 
@DonLarynx Well, first, do you agree that if $n={\rm lcm}(a,b)$ we have $n(m,q)=0$ for any $(m,q)\in\Bbb Z_a\times\Bbb Z_b$?
 

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