OK I am still struggling with the second sentence in the picture I gave above. I'll label my questions with (x). What I have so far: given any $p \in K_k[X]$ and choice of $x_0,h$ I know (Remark 8.19(c)) that $p = N_k[p;x_0;h]$, where the RHS is the newton interpolation polynomial for that function $p$ ((1): how do $x_0,h$ factor into the discussion here? Shouldn't any choice of $x_0,h$ give the same $N_k$ because this is a polynomial, so that if $N_k$ agrees...