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12:00 AM
I frequent Imgur and I have seen that meme only a few times.
@ColdGolf I see you go to the school of Twisting Peoples' Words To Mean Something Else.
 
ignoring a user is sure a lot less effective when i still see people's responses to them
8
 
@ColdGolf only the stupid parts of reddit actually use that meme.
 
it just makes everyone look loony
 
@xnor Haha, I'll bet. There was someone who mentioned that yesterday...
 
Anonymous
12:01 AM
@El'endiaStarman Make it work, make it right, make it fast.
2
 
@EᴀsᴛᴇʀʟʏIʀᴋ Everytime I use a meme that SE doesn't know yet, I get flagged, and then probably kicked.
 
@ColdGolf no
it's not the new memes
 
@El'endiaStarman Aha, this.
 
it's you being obnoxious
 
12:02 AM
@EᴀsᴛᴇʀʟʏIʀᴋ Even the old memes, SE doesn't know them.
 
So I was bored and I found this: cafepress.co.uk/…
 
@EᴀsᴛᴇʀʟʏIʀᴋ Yep, this.
 
@ColdGolf no, we do
we don't use them though
 
You do , not we do.

Some people on SE just have not heard those memes.
 
12:03 AM
@Downgoat Found it, or made the design yourself? :P
 
everybody else doesn't use them because at the heart, SE is a learning site
 
@El'endiaStarman found it o_o
 
not r/circlejerk
@ColdGolf okay seirously stop editing that please
 
Anonymous
Also yes, no errors is clearly best, so Actually doesn't do anything if you tell it to do something dumb. It doesn't even tell you that you did something dumb.
 
@ColdGolf yes, and that's fine. Most of us have though, and jsut don't repeat it.
 
Anonymous
12:04 AM
(unless you pass the -d flag)
 
Most of you, from my experience, haven't.

You personally have, that's different.
 
@Mego actually "I'm"--dumb?
 
> from my experience
@xnor lel
 
12:04 AM
@EᴀsᴛᴇʀʟʏIʀᴋ A bad experience at that.
 
@ColdGolf i;long double a,b;main(){for(;;i++)for(;;b+=1e-18)for(;;a+=1e-18)if(pow(a,b)==i)printf("%LF ^ %LF == %d\n",a,b,i);} btw, it will take a while to finish.
 
@ColdGolf TL;DR: Those aren't welcome here. We are kindly asking you to stop.
 
@EᴀsᴛᴇʀʟʏIʀᴋ You mean aren't known, not just aren't welcome. I've stopped using them just because, while millions others know them, you guys don't.
@ReleasingHeliumNuclei How long is a while in this case?
 
@ReleasingHeliumNuclei -10/10 all of them are rational
 
12:08 AM
@ColdGolf print(sqrt(9)^(log(9,4)))
 
@ColdGolf Do we have to take an actual drill to your skull to get you to understand that we do know the memes? (Most of us anyway.) They aren't welcome when out of place and unconnected to any other conversation going on, or when posted repeatedly, or when in disregard of vulgarity, or when ignoring the requests of others to stop, etc...
 
@LeakyNun close enough :p
 
Julia, 27 bytes: print((2^.2)^(log(10,5)))
fixed
 
@ColdGolf up to 2147483647, increments 0.000000000000000001 at a time
 
@EᴀsᴛᴇʀʟʏIʀᴋ -10/10 sqrt(9) is 3
 
12:09 AM
...
 
@ReleasingHeliumNuclei Exceeds ideone's time limit.
 
i'm not fixing that one
@ColdGolf ... use gcc?
 
@EᴀsᴛᴇʀʟʏIʀᴋ you can use sqrt(2) to save 2 bytes
 
@ColdGolf How old are you?
 
12:11 AM
@LeakyNun also 2^.5
 
@EᴀsᴛᴇʀʟʏIʀᴋ I don't know Julia
 
@LeakyNun not without changing the exponent though
 
@Downgoat Seriously? So what?
 
12:12 AM
@EᴀsᴛᴇʀʟʏIʀᴋ which is why I said two bytes
 
Julia, 22 bytes: print((3^.5)^log(3,4))
 
is (√2)^((√2)^(√2)) rational?
 
@ColdGolf can I do a lambda with a dummy argument?
 
@EᴀsᴛᴇʀʟʏIʀᴋ Nope. Has to have a number.
 
12:14 AM
Not a dummy one.
 
@ReleasingHeliumNuclei remove last sqrt and yes
 
@ColdGolf i mean it takes a number as input, but doesn't use it
 
@Downgoat ;_;
 
takes anything as input really
 
@EᴀsᴛᴇʀʟʏIʀᴋ Doesn't use it? Not allowed.
 
12:15 AM
okay
 
This made me actually laugh.
 
@ColdGolf it just has to state whether irrational^irrational can equal rational, correct?
Julia, 8 bytes: print(1)
FOG, 1 byte: 1
 
@EᴀsᴛᴇʀʟʏIʀᴋ Nope.
 
then closed as unclear
 
@EᴀsᴛᴇʀʟʏIʀᴋ "Prove that there exists two positive irrational numbers x and y, such that x^y is rational, in as few bytes as possible."
 
12:17 AM
> prove
 
@EᴀsᴛᴇʀʟʏIʀᴋ cite any one of his CMCs that isn't unclear
 
closed as unclear
@LeakyNun closed as impossible
(can i do that?)
 
@EᴀsᴛᴇʀʟʏIʀᴋ Use the number 2, and display the output.
 
output: 1
which is truthy
 
Where's your code?
Seriously?
 
12:18 AM
1 min ago, by Eᴀsᴛᴇʀʟʏ Iʀᴋ
FOG, 1 byte: 1
 
@EᴀsᴛᴇʀʟʏIʀᴋ That displays the output but does no calculation.
So it doesn't count.
 
you don't need calculation
@ColdGolf then downvoted and closed as unclear
what is it supposed to calculate?
prove != calculate
 
It's not particularly funny anyways.

I'd downvote you if you did it.
 
that's fine
downvotes are fine
 
Hear hear
 
12:19 AM
@Geobits would agree
damnit
 
CMC: chess or go bot
 
VTCd as unclear.
 
Google, 1M bytes: message too long
 
There are full challenges for both of those on main.
 
12:20 AM
@xnor Is it even possible...
 
Mini-epiphany: x = sqrt(2)^x has two solutions: 2 and 4. This means that an infinite tower of sqrt(2)^sqrt(2)^... could be either 2 or 4...?
 
@El'endiaStarman Nope.
 
1+1-1+1-1+1...=0.5, so √2^√2^√2...=3?
 
@El'endiaStarman That limit is the fix-point of f(x) = sqrt(2)^x, starting as x=sqrt(2)
@ReleasingHeliumNuclei the first statement is not true so the second statement is useless
 
@ReleasingHeliumNuclei Somebody already did it, an entire chess program in 1KB of javascript:

for(B=i=y=u=b=i=5-5,x=10,I=[],l=[];B++<304;I[B-1]=B%x?B/x%x<2|B%x<2?7:B/x&4?0:l[i++]="ECDFBDCEAAAAAAAAIIIIIIIIMKLNJLKM@G@TSb~?A6J57IKJT576,+-48HLSUmgukgg OJNMLK IDHGFE".charCodeAt(y++)-64:7);function X(c,h,e,s){c^=8;for(var o,S,C,A,R,T,G,d=e&&X(c,0)>1e4,n,N=-1e8,O=20,K=78-h<<9;++O<99;)if((o=I[T=O])&&(G=o^c)<7){A=G--&2?8:4;C=o-9?l[61+G]:49;do if(!(R=I[T+=l[C]])&&!!G|A<3||(R+1^c)>9&&G|A>2){if(!(R-2&7))return K;n=G|(c?T>29:T<91)?o:6^c;S=(R&&l[R&7|32]*2-h-G)+(n-o?110:!G&&(A<2)+1);if(e>h||1<e&e==h&&S>
 
@ColdGolf -1 needs an AI
 
@ΛεγίωνΜάμμαλϠΨΠʹ It has a basic AI.
 
@LeakyNun grandi's series, 0.5 is true
 
> It is a divergent series, meaning that it lacks a sum in the usual sense. On the other hand, its Cesàro sum is 1/2.
 
12:24 AM
@ReleasingHeliumNuclei
 
The Cesaro sum is not the normal sum
 
In mathematics, the infinite series 1 − 1 + 1 − 1 + ⋯, also written ∑ n = 0 ∞ ( − 1 ) n {\displaystyle \sum _{n=0}^{\infty }(-1)^{n}} is sometimes called Grandi's series, after Italian mathematician, philosopher, and priest Guido Grandi, who gave a memorable treatment of the series in 1703. It is a divergent series, meaning that it lacks a sum in the usual sense...
 
> It should be noted that the term summation can be misleading, as some statements and proofs regarding Cesàro summation can be said to implicate the Eilenberg–Mazur swindle. For example, it is commonly applied to Grandi's series with the conclusion that the sum of that series is 1/2, a result that can readily be disproven.
 
12:25 AM
@ΛεγίωνΜάμμαλϠΨΠʹ Your purposely messed with it?
 
It works for me.
 
@ColdGolf No, that's what I get when running it in the FF console on about:blank
 
@ΛεγίωνΜάμμαλϠΨΠʹ Weird, works for me.
 
@ColdGolf You sure it wasn't copied wrong?
Where's the original source?
 
12:27 AM
@ΛεγίωνΜάμμαλϠΨΠʹ js1k.com/2010-first/details/750
It works for me on Firefox 48.
 
@ColdGolf Works when I copy from there
 
@ΛεγίωνΜάμμαλϠΨΠʹ Maybe SE messed up the formatting.
 
!RemindMe 8 hours
Oops this is not reddit
2
 
code blocks exist for a reason,
you \`know\\\`
 
@ΛεγίωνΜάμμαλϠΨΠʹ You know chat markdown sucks in general, though.
@ReleasingHeliumNuclei LOL
 
12:32 AM
@ColdGolf ;_;
 
@ReleasingHeliumNuclei Did you know reddit has a copycapy subreddit of ppcg?
 
@ColdGolf which one
 
r/tinycode existed before us, iirc
 
Serious mini-challenge: Does T(n) = T(m) - T(n) with 0 < n < m (integers) have any solutions where T(n) is the nth triangular number (1, 3, 6, 10....). e.g. n = 4, m = 6 is close: T(4) = 10, T(6) = 21, T(6) - T(4) = 11. 11 ~ 10
 
@EᴀsᴛᴇʀʟʏIʀᴋ So you're the copycats?
 
Also, the subreddit I was talking about was different.
 
they were made inpendently
@ColdGolf oh, which one?
 
@EᴀsᴛᴇʀʟʏIʀᴋ reddit.com/r/programmingchallenges
It's not this one either.
 
@HelkaHomba you mean T(m) = 2 * T(n)?
 
12:35 AM
Wait, lemme google it.
 
@ReleasingHeliumNuclei Yes. Same equation.
 
whoa, my caret pathefinder script still works through ignored messages
 
woah
wait relink me?
 
12:37 AM
@HelkaHomba n = 2, m = 3 works
 
Aha! Good. But are there other solutions?
 
@HelkaHomba n = 14, m = 20 works
 
@HelkaHomba You mean, are there any triangular numbers X and Y where X = 2*Y?
Aw shoot ninja'd.
 
you're a little late to the party :P
 
12:39 AM
2n(n+1) = m(m+1)
2n^2 + 2n - (m^2+m) = 0
determinant = 4+8m+8m^2, so 2m^2+2m+1 = m^2+(m+1)^2 must be a square
 
Well, at least I can contribute further! We're looking for n(n+1) = m(m+1)/2.
 
so it is equivalent to finding pythagorean triples where the shorter legs are adjacent
 
........really now.
I give up. Anything further I add is just going to be ninja'd. :P
 
@LeakyNun Are you talking about squared triangular numbers? (oeis.org/A001110)
 
@ColdGolf No
 
12:40 AM
@LeakyNun Then?
 
3,4,5 (first solution:2,3)
20,21,29 (second solution:14,20)
Just as @ΛεγίωνΜάμμαλϠΨΠʹ found
 
@LeakyNun dandy :)
 
n = 2, m = 3
n = 14, m = 20
n = 84, m = 119
n = 492, m = 696
n = 2870, m = 4059
n = 16730, m = 23660
 
there are 4 equation systems that give ns and ms
 
n = 97512, m = 137903
 
12:41 AM
(If I still had homework I swear I could get you guys to do it all :P)
 
brb finding a piece of paper
 
@HelkaHomba good idea. i will use some months later :p
 
@HelkaHomba Your teachers might get suspicious of the golfed code though...
 
A serious mini-challenge (not code): Prove that there are infinitely many triangular numbers that are the sum of two other triangular numbers.
 
CMC: solve 3x^2 - 4x + 5 = 0.2x^5 - x(x - 4)^4 for x
 
12:44 AM
@ConorO'Brien Use desmos
 
@LeakyNun (1) I don't think desmos solves (2) shhh it's math
 
@ΛεγίωνΜάμμαλϠΨΠʹ 2,3,14,20,84,119 not on oeis strangely
 
@HelkaHomba
2m^2+2m+1-a^2=0
det = 4-8(1-a^2) = 8a^2-4, so 2a^2-1 must be a square
@HelkaHomba try searching for just n or just m
 
@ConorO'Brien WA?
 
@HelkaHomba oeis.org/A053141 for n
 
12:45 AM
@Dennis can you update cheddar on TIO? (npm install -g cheddar-lang)
 
@ConorO'Brien with WA or paper or code
 
@ConorO'Brien missing the 3
 
> for n
 
@ReleasingHeliumNuclei his teacher probably intended paper when she gave it to him, so use that
 
@HelkaHomba It becomes Pell's equation:
Pell's equation (also called the Pell–Fermat equation) is any Diophantine equation of the form x 2 − n y 2 = 1 {\displaystyle x^{2}-ny^{2}=1\,} where n is a given positive nonsquare integer and integer solutions are sought for x and y. In Cartesian coordinates, the equation has the form of a hyperbola; solutions occur wherever the curve passes through a point whose x and y coordinates are both integers...
 
12:46 AM
@ReleasingHeliumNuclei idk :P bad joke
 
> Solution to b(b+1) = 2a(a+1) in natural numbers including 0
 
@ConorO'Brien oops sorry
 
> Prove that there are infinitely many triangular numbers that are the sum of two other triangular numbers.
 
@HelkaHomba and oeis.org/A001652 for m
 
12:46 AM
@ColdGolf A053141 doesn't end
 
so it's zip(A053141, A001652)
 
@ΛεγίωνΜάμμαλϠΨΠʹ A053141 isn't what my challenge talks about, is it?
 
@ΛεγίωνΜάμμαλϠΨΠʹ I don't understand how an OEIS link is proof.
 
@ColdGolf Why, it gives infinitely many closed-form solutions
 
@ColdGolf because the OEIS link contains a method to generate an infinite amount of solutions
 
@LeakyNun How is that the case?
 
> a(0)=0, a(1)=2 then a(n) = a(n-2) + 2*sqrt(8*a(n-1)^2 + 8*a(n-1) + 1).
 
Ohh.
How I'd prove it, though, in latex: $t_{n(n+3)/2 + 1}=t_{n+1}+t_{n(n+3)/2}$
 
@ColdGolf put $ around it
chatjax will work, i know @El'endiaStarman also has it
 
12:51 AM
@EᴀsᴛᴇʀʟʏIʀᴋ $ doesn't work.
 
I don't have chatjax, but then again, I don't see hsi stuff :P
 
yeah, you need an extension for it
@ConorO'Brien lel
 
@ColdGolf You have to install the Chrome extension "SE ChatJax".
 
Halp doesn't work on mobile
 
I'm on Firefox.
Is there a Firefox version of this extension?
 
12:52 AM
@HelkaHomba TL;DR: Yes.
 
@ColdGolf Perhaps. I don't know.
 
@El'endiaStarman Thanks anyways.
 
Where {x} is a non-integer part of x.

Prove the above image.
 
@SimonForsberg I actually returned and made a tiny levelset (under yet another alias) some time ago. ^^
 
12:54 AM
@ColdGolf WOAH dude calm down
 
@ColdGolf math? ;_; y u do dis
 
^^ warning, clickbait
 
@ColdGolf I'll just do k/n <= {x} < (k+1)/n:
 
> Ice.

So this one had to be cooked for various reasons. I boiled the rice and the ice, and I was left with rice.
10/10
 
12:55 AM
@EᴀsᴛᴇʀʟʏIʀᴋ most...2nd or 3rd upvoted?
 
@EᴀsᴛᴇʀʟʏIʀᴋ oatmeal >_>_>_>_>_>_
 
orange juice
 
@ColdGolf since we know floor(x)+k/n <= x < floor(x)+(k+1)/n
 
@ReleasingHeliumNuclei 3rd
the best part is that he tried them all
 
@ColdGolf So we have n floor(x) + k <= nx < n floor(x) + k + 1
 
12:56 AM
except beer + rice
 
which means floor(nx) = n floor(x) + k
 
@EᴀsᴛᴇʀʟʏIʀᴋ orange juice is not food
 
Neither is kimchi, but some people consider it to be.
 
@LeakyNun This is the proof.
Sorry for the bad latex formatting.
 
12:59 AM
@ReleasingHeliumNuclei does this have force awakening spoilers?
 
@Downgoat only the last sentence
 
@ColdGolf you should install chatjax (its latex for SE caht)
 
@Downgoat I'm on Firefox.
 
do u have greasemonkey?
 
Yes.
 
1:00 AM
@Downgoat Done.
 
@Dennis thanks!
 
@ColdGolf Protip: \text{} is great. I have no idea why one equation is way over on the right though.
 
@Downgoat Is there a ChatJax userscript?
@El'endiaStarman I tried using it, but I don't know how.
 
@ColdGolf yes lemme link
 
@Downgoat Thanks!
 
1:02 AM
brb waiting for Milkdromeda collision to occur
 
@Downgoat Thanks man!
@El'endiaStarman Do you know how do I type normal text in maths mode?
Along with latex in the middle of the text?
 
@ColdGolf What program are you using to render the LaTeX?
 
@El'endiaStarman An online one that converts it to png for those who don't have latex installed.
But I have installed ChatJax now.
 
@ColdGolf Like, CodeCogs or something?
 
1:05 AM
Nah, latex2png.com
$$[ \text{Let}\ x=\text{this is normal text} ]$$
Why is ChatJax not rendering this?
 
It renders for me.
 
It's between $
Weird.
Refreshed the page without cache, still doesn't render.
 
@ColdGolf you need to do $$ instead of $[
 
@Dennis I will be coding a patch to SILOS tonight. I'll ping you, but it might be late. Is it ok if I ping you and then you can take a look at it whenever you like, and have some time. Essentially the patch will require that lines of stdin be fed as command line arguments following the filename. (There will be some other features)
 
Ohh.
$$[ \text{Let}\ x=\text{this is normal text} ]$$
Still doesn't render for me, nor does it show any sign that it's loading.
 
1:09 AM
Weird. Feel free to keep testing in the Sandbox chat room, so that it doesn't get cluttered in here.
 
Now it works in the sandbox.
Weird.
 
@ColdGolf youd ont need [ and ]s
 
@RohanJhunjhunwala Sure, no problem.
 
@Dennis thanks
 
@LeakyNun Since it works now, lemme post the proof I tried post eariler:

> $$I_n=\Bigl[\frac{n}{\sqrt3},\frac{n+1}{\sqrt3}\Bigr]$$

> If $$I_n$$ has an integer, then we gonna do:

> $$n=\Bigl\lfloor\sqrt3\,\Bigl\lceil\frac{n}{\sqrt3}\Bigr\rceil\Bigr\rfloor$$
Doesn't work. What's going on?
 
1:11 AM
Works for me
 
@ColdGolf works for me
is ChatJax enabled for you?
 
Not for me.
Weird.
Yes it is.
 
try restarting browser maybe idk
 
Lemme disable my reddit mathjax script.
maybe its the issue
$$I_n=\Bigl[\frac{n}{\sqrt3},\frac{n+1}{\sqrt3}\Bigr]$$
Doesn't work.
 
Ctrl+F5?
 
1:13 AM
I did that.
ChatJax doesn't work still.
I've now disabled all scripts except ChatJax:
$$n=\Bigl\lfloor\sqrt3\,\Bigl\lceil\frac{n}{\sqrt3}\Bigr\rceil\Bigr\rfloor$$
Doesn't work again.
I know it's not other extensions because it worked before.
 
If that doesn't help I always find a good old 'rm -rf \* --no preserve root' really helps out
PLEASE DO NOT UNDER ANY CIRCUMSTANCES ATTEMPT THE ABOVE
 
@RohanJhunjhunwala Well, what if somebody doesn't read your warning?
 
Its in all caps
 
Also, don't you need `no-preserve-root` with dashes in between?

NOTE: NEVER EVER UNDER ANY CIRCUMSTANCES AT ALL SHOULD YOU TRY THIS.
Or does your version also work?
 
idk, its a feature to prevent people from trying it
 
1:17 AM
You did it on purpose? Heh.
 
No, but I can claim I did.
 
Then you'd be lying, no?
 
Fun fact: this room has 12.5k messages posted per week.
3
 
@DJMcMayhem Is this from SEDE?
 
@DJMcMayhem that was an interesting fact so I "starred it as interesting"
 
1:20 AM
I think stars should add rep.
 
useful/interesting
so there are two reasons to star
 
Imagine if every star gave you 10 rep.
That would be cool.
 
Stars should never under any circumstances add rep
 
Why?

Because it's too easy to star things?

It's easy to upvote posts and comments too.
 
I've seen 10 stars given to a chat comment wich just said "Something clever and interesting worthy of being starred"
2
 
1:22 AM
Okay, what if one star was 1 rep, not 10 rep?
Can somebody link me the sandbox again?
Nevermind, found it.
 
@ColdGolf because its not contributing to the sight in any way. Stack Exchange aims to be a quality tepository of question seekers and answerers. It aims to be a collection of knowledge from experts in their field (for ppcg the field is code golf). Saaying humoruous things in comments should not be awarded?
 
@RohanJhunjhunwala I mean, technically, ppcg is more of fun than asking questions.
Don't tell that to the admins, though. Heh.
 
Something clever and interesting worthy of being starred
 
@RohanJhunjhunwala s/sight/site
 
@LeakyNun nice try.
 
1:25 AM
Posting latex in the sandbox displays normally with ChatJax.

Posting the exact same latex in here, doesn't work.
Weird.
 
@ConorO'Brien Outgolf our Python solutions
or submit a solution in J
 
fixed output?
 
Something useless and boring that isn't worthy of being starred.
 
@ConorO'Brien yes, my style
 
@El'endiaStarman sorry my bad.
 
1:26 AM
doing a J submission even though I should be doing notes
do I need an account
 
@ConorO'Brien no, that's the point of the website
 
oh, fun
 
@ConorO'Brien golfing code is a life skill. Everyone knows that programmers should be paid based on the number of semicolons they use. (Relevant Post)
47
A: Is fewer lines of code always better?

Craig GidneyCode with as few lines as possible is definitely the best code and every semi-colon you see is basically the developer admitting they weren't clever enough to use advanced constructions like the comma operator or short-circuiting operators to keep the line going as long as possible like you can s...

2
 
@LeakyNun I'd VTC this website as completely unclear what the challenge even is.
 
fucking hell
 
1:28 AM
Um...
Problem? @LeakyNun
 
@RohanJhunjhunwala Not saying to you
 
@LeakyNun ok, its a bit disconcerting to see something like that out of the blue
 
@RohanJhunjhunwala lol
@RohanJhunjhunwala I think it's a beer as well
 
@ConorO'Brien oh I've seen that joke in tnb too often lol
 
@ConorO'Brien Yes, a beer brewed in a particular German town, IIRC.
 
1:30 AM
ah, so I'm late
 
@El'endiaStarman I see you go to the school of Twisting Peoples' Words To Mean Something Else.
 
@ConorO'Brien @Others who liked my programmers.se post, you may be interested in this repo
 
@RohanJhunjhunwala GitHub looks awful without the wider github script...
 
Semicolons are completely optional in java
 
@ColdGolf Did you start your bot again? You're starting to slip into inanity again...
 
1:34 AM
I was just copypasting an earlier message of yours.

Isn't that a bit ironic?
 
@El'endiaStarman I thought it was always on.
:P
 
@ConorO'Brien Well, after this message, most of their messages were actually relevant.
 
I couldn't tell
thanks
 
@El'endiaStarman I mean, I told everybody I was gonna use a bot for a couple of minutes. Nobody could complain, but only if they had already knew this.
 
@ColdGolf Can you link me to the message where you said this?
 
1:37 AM
7 hours ago, by ColdGolf
@zyabin101 I'll switch it on, it's sloooow API tho
 
You know there is a unique feature, left click a profile and you get a few options which may interest you in using :)
 
@RohanJhunjhunwala I think it would be detrimental to my modly duties to ignore problematic users. :P
 
@El'endiaStarman Or to be problematic yourself.
 
@El'endiaStarman oh whoops, but perhaps it may interest Conor O Brien
 
@ColdGolf Certainly. I think, however, that community consensus is that the problematic one is not me. :P
 
1:42 AM
@El'endiaStarman Does your definition of community include only the mods? :D
 
@RohanJhunjhunwala How do you define "java"? They don't do anything to the byte code, but I've yet to find a standard java compiler that will allow you to leave them out completely (although there are some cases where they're optional).
 
@ColdGolf I was not aware that Conor, Leaky Nun, and Easterly Irk were mods.
 
His definition of community is the starred responses on the starboard @ColdGolf
 
Oh, and xnor too.
 
@Geobits I am unsure what you are talking about
 
1:43 AM
@El'endiaStarman When did I say that they were?

Also, are 5 users the entire community?

I don't want to start a long argument.
 
@Geobits did I send you a message I forgot about :( my bad
 
9 mins ago, by Rohan Jhunjhunwala
Semicolons are completely optional in java
 
@El'endiaStarman wait, are you able to see who has ignored a user?
 
@RohanJhunjhunwala what may interest me?
@El'endiaStarman of course I'm a mod!!! !drop table TNB_USERS
 
@DJMcMayhem It's not hard to list off a few people in this instance, even without knowing that.
 
1:44 AM
@ColdGolf I think it's pretty telling that there are at least five people in agreement versus one in disagreement. And I'm only counting those that I can remember have explicitly said something; this message of mine has 10 stars.
 
@Geobits I was talking about the above repo I linked. @ConorO'Brien left click a user ahem ahem, and some interesting options pop up
Also this repo is what I was talking about
https://github.com/elitheeli/stupid-machines
 
Imaginary internet stars at that.

Did you forget about https://chat.stackexchange.com/transcript/message/31891785#31891785 ?

The part I told you to read previously, when you asked me to link it.
 
@RohanJhunjhunwala yes, I saw the repo
 
you know, I'm quite glad I'm not a mod. I don't think I could ignore people if I was
2
 
@ConorO'Brien the options that interested you I was talking about was the ignore feature ...
 
1:46 AM
@RohanJhunjhunwala I already have ;)
 
@ColdGolf Please don't repeatedly edit messages with pings.
 
@El'endiaStarman Oh, it pings you again? I see.
 
@NathanMerrill I concur. Mostly because it's hard to align carrots with ignored messages inbetwixt
 
Actually, ignores are a really good reason to stop using carets
 
1:47 AM
@NathanMerrill Every now and then I wouldn't mind having room-owner powers though. Just occasionally >_>
 
Update: My web-knife is still running
 
Sorry, But I have to nitpick your drop table usage.

The format is `DROP INDEX name_of_table.name_of_index`
 
4
Q: Should we have additional room owners?

trichoplaxCurrently our main chatroom, The Nineteenth Byte, has only the 4 PPCG moderators as room owners. Since the chatiquette is not applicable to other Stack Exchange sites, using chat flags for breaches of chatiquette which are not also network-wide offenses is problematic - wasting the time of 10k us...

Maybe you could
 
@Geobits yeah, we just need sudo for the chat room
 
@DJMcMayhem Haha, well I wouldn't volunteer myself for the job, but I'd probably take it if offered.
 
1:48 AM
The community is divided on this.

I personally both agree and disagree at the same time about it.
 
0
Q: Evaluate expressions with significant figures

soktinpkGiven an expression, your task is to evaluate it. However, your answer cannot show more digits than necessary, as this gives the impression of having more precise measurements than reality. The number of significant figures that a number has is how many digits it has when written in scientific n...

 
@Geobits I'm more just curious if you agree with my answer on it, haha
 
Oh, I upvoted it just now. I hadn't seen that you answered before that.
 
yeah, I upvoted it as well. I actually agree with Alex A as well (in that it isn't necessary, as our chat is pretty well moderated), but that I don't really see any harm in having extra owners, but I definitely see potential benefit
 
wait is ColfGolf disliked mainly because of behavior in chat or the site or both?
 
1:53 AM
@NathanMerrill yeah, I suppose users like quill, trichoplax abs elendia (non ppcg mods) does help a lot.
 
@MitchSchwartz Mostly chat, so far as I know.
 
@MitchSchwartz I'm disliked by people who either hate specific memes, or just don't know them.
 
Question: Is there an online tool that can show if a given chess position has a checkmate/stalemate?
 
i thought people around these parts liked memes
 
Although I'm still shocked by some of those statistics I posted. I honestly think this might be the most active chat room
 
1:54 AM
@MitchSchwartz I've stopped using them. Evidently, nobody likes them.
Except maybe a few.
 
Guys I just figured out something amazing
 
@Syxer ??
 
You can embed Skype calls in webpages
 
@MitchSchwartz Not really obnoxious, all screaming caps ones for sure.
 
@Syxer You mean call recordings?
Or the Skype web app?
 
1:55 AM
If an end user has Skype open and you use the following HTML, you can make them call a target whenever they click the link:
<a href="skype:8:<username>">link</a>
 
@Geobits You were actually the first that came to mind when the idea of appointing room owners was brought up.
 
Just be sure to not parse the html with regex @Syxer
 
@RohanJhunjhunwala Of course
 
@El'endiaStarman was it brought up recently? (Other than meta)
 
@Syxer What???
 
1:57 AM
@ColdGolf yeeeesss
Tested on Mac OSX El Capitan, newest Skype update.
 
That could potentially be a huge security issue. Tell that to the Skype team and pssibly get a bug bounty!
 
@El'endiaStarman It came up a couple times during mod talks, too, IIRC. And there was a room owner strawpoll once, but in jest (I think). People seem to think I'm mature for some reason. Or at least some people.
 
That isn't a security issue by any stretch of the imagination.
 
@ColdGolf Not really - IP harvesting is already done by the user when they connect to the page, as long as there's no further exploitation through Skype, it's fine.
 
@DJMcMayhem Starting around here.
 
1:58 AM
question: do we have a challenge to output the permiter given coordinates?
 
I thought Skype resolved its leaking IP issues a while ago?

Or was that only for non-contacts?
 
@Geobits that strawpoll is surprisingly even
 
@Downgoat no, I love it. Sandbox it!
 
@NathanMerrill 6 yes and 5 no isn't even, is it?
 
Or just post to main
 
1:59 AM
(though you did say it was in jest)
 

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