morning

@jippie Mornin

I think I just finished troubleshooting a ultrasonic cleaner... it's supposed to have 100W output to a 2.8L tank, and the circuit is so exciting - the only thing that's isolated is the actual output.

but it looks like one of the output IGBTs was shorted out, so maybe it'll only be a $2.50 fix to a $600 piece of equipment.

@W5VO $2.50 plus your hourly rate

@jippie Yeah, it's not so cool when you factor what I should be charging

but I offered to help someone take it to the dumpster

that being said, I usually don't get paid for messing around with electronics at home

I never do the little jobs around the house; I always think about what I should be charging for my hourly rate and I just can't make the business case for the job.

It is cheaper to order new dishes than to spend half an hour washing them

anyways, time to leave for the office

sonicsonline.com/b2510dth.html

enjoy your (remainder of the) day @W5VO

@jippie Well, I'm late to bed. See you in the morning

@W5VO My physio course is tailored to engineers. Very little rote memorization, most physiological systems are mapped to models explaining aspects of behavior.

@ScottSeidman It's funny - my rote memorization is pretty bad, but I can just about memorize a datasheet for a part without trying.

@W5VO Your internal underlying model for the product on the datasheet is probably just better than for some other stuff

@ScottSeidman probably

@W5VO Ever read "The Design of Everyday Things"? Its a great read, and talks about how the model a person automatically constructs should match up with how the device works, or things will go wrong

morning

heyhey

@jippie Aloha

Stupid simulator. Doesn't know how to take the log of a negative number.

@ThePhoton Gives up too easily, huh... You need a better simulator ;)

@W5VO For what these things cost, they should be able to do stuff like that.

@ThePhoton Just define log( -1 ) as k(ph) and if memory serves me right log( -a ) would then equal log( a ) + k(ph). Et voila you can do math with a constant.

or call it exp(j^2) ...