Jun 2, 2016 20:42
I don't know if I am a developer or a programmer...I love to code a lot in Java/C++ but I haven't had time to learn any of the frameworks like Spring, or any C++ frameworks.
Jun 2, 2016 20:41
hi everyone
May 31, 2016 22:14
I do
May 31, 2016 22:10
It doesn't?
May 31, 2016 22:08
People keep comparing programming to corporate slavery for lack of a better name
May 31, 2016 22:07
I want to be a developer but there's too much negativity and it stops me
May 31, 2016 21:31
hi is anyone here?
 

 Geometry & Topology: Dank Ass Ganja

Discussion in informal spirit
May 24, 2016 07:33
You have 7k reputation
May 24, 2016 07:14
Yo Balarka, there's 39 questions that have close votes. Check it out.
 
May 24, 2016 07:29
Handwavy? How? Sequence is bounded by zero line, and the fact that it's concave down (at worst) or a straight line headed down (at best) means that it eventually hits zero. This is all due to the monotone convergence theorem.

You don't explain why my argument is handwavy. Similarly, I can conclude yours is handwavy, but it's not in my best interests.

What is your counterexample?
May 24, 2016 07:26
You've stopped commenting because you know I'm right. I've invited you to a chat room where we can discuss this and hopefully sort out some of your legally blind issues.
May 24, 2016 07:26
Recall that at $n = 0$, $a_{n+1} = 0$ because $(1-1)a_0 = 0$. Subsequent terms also equal zero (can you see why)? Your equation wouldn't hold because the ratio is undefined.
May 24, 2016 07:26
Clearly, just take the harmonic series. But I never base my answer on that. Can't you see that I've included the ratio in my inequality? Are you legally blind?
May 24, 2016 07:26
Recall $a_{n+1}$ will never be equal to $a_n$ because the ratio $\frac{a_{n+1}}{a_n}$ is less than 1.
May 24, 2016 07:26
Because I need help, I'm a student.
May 24, 2016 07:26
What does $(a_n)_n$ mean? Did you mean $a_n$? $(a_1)_1$, $(a_2)_2$, $(a_n)_n$ does not make sense.
May 24, 2016 07:26
Connecting the dots of the sequence, the graph looks like a concave down curve and therefore converges due to the monotone convergence theorem (bounded below by zero). Agree?
May 24, 2016 07:26
What is wrong with my answer?
 

 Mathematics

Associated with Math.SE; for both general discussion & math qu...
May 22, 2015 15:14
If you're learning linear algebra, check out my app play.google.com/store/apps/details?id=com.joc.matrixfree its meant to serve as a double-checker
May 22, 2015 15:13
Hey guys
May 17, 2015 22:00
but since bRa and aRb and bRb isn't in there it can't be anti-symmetric.
May 17, 2015 22:00
@TedShifrin anti-symmetric: if aRb and bRa then aRa
May 17, 2015 21:57
@TedShifrin Because if aRb and bRa, then a = b
May 17, 2015 21:54
Is $\{(a, b), (b, a), (b, b)\}$ anti-symmetric? I thought it wasn't because $(a, a)$ isn't in the set, but $(b, b) = (a, a)$
May 10, 2015 19:16
@SpawnKilleR don't worry, im drunk too
May 10, 2015 19:16
[3^x*c_1 + 3^(-x)c_2]/[(3^x)*(c_3) + (3^(-x))*(c_4)] = y
May 10, 2015 19:15
didnt see denominator
May 10, 2015 19:15
oh wait
May 10, 2015 19:14
Yes, it's very possible. You're basically dealing with $(3^x)*(constant_1) + (3^(-x))*(constant_two) = y.
May 10, 2015 19:12
@TedShifrin You should be a mod. You're always in here
May 10, 2015 19:11
Just ask.
May 10, 2015 19:11
@SpawnKilleR Don't ask to ask please
May 10, 2015 19:11
Believe it or not, this problem can be solved numerically (using C++): "Find $h, k$ such that the system is consistent. $$2x - y = h; -6x + 3y = k;$$
May 3, 2015 22:59
@Ted: Ignore that. My proof is correct.
May 3, 2015 22:51
@TedShifrin My proof was wrong. plus the 4x5 augmented, row-reduced matrix with all zeros except for the 1st row [0, 0, 1, 1, 1] is consistent.
May 3, 2015 22:49
@AlexClark skipping
May 3, 2015 22:06
@columbus8myhw That's because calculus was re-written to satisfy that issue. See here: math.stackexchange.com/questions/21199/…
May 3, 2015 22:04
@columbus8myhw I'll try again.
May 3, 2015 22:02
@columbus8myhw I can't answer your question. Anyways, thanks @Ted
May 3, 2015 22:00
@columbus8myhw Using epsilon-delta it's correct.
May 3, 2015 21:59
@columbus8myhw Why is it technically incorrect? It's geometrically correct. (Define technically.)
May 3, 2015 21:58
@TedShifrin Continuation of proof: Since addition of reals takes place in 1-dimension, it can be safe to assume we're adding up linearly-dependent lines with zero slope. In the end, we end up with a line that will never equal the b-vector. But this is impossible because our linear dependency covers all of $\Bbb{R}$. Thus the coefficients must equal zero. QED
May 3, 2015 21:56
@columbus8myhw Too general, will not waste time.
May 3, 2015 21:55
Perhaps you can elaborate on how you define "abuse of notation": is it when notation is introduced, but not explained or defined (i.e., assumed to be understood)? or do you mean when unconventional notation is used in place of what is standard? Or both. Examples would help. — amWhy Dec 24 '12 at 15:11
May 3, 2015 21:51
@TedShifrin That's pretty easy to prove. Suppose that it was a pivot in the column. Impossible for any x to equal it because 0(c) = 0 where c is any number. Now, suppose that it was inconsistent. That means there's no solution, which means for any x-vector it will never equal the b-vector. (Kind of stuck here?)
May 3, 2015 21:48
@TedShifrin My Linear Algebra 1 professor sucked. The TA was better.
May 3, 2015 21:48
@TedShifrin I thought that for an augmented matrix to have a free variable you need to have the entire row equal to zero.
 

 English Language & Usage: Multi-Layer

Not for the faint of heart or those easily triggered by Englis...
May 10, 2015 20:37
something that performs the action of sewing.
May 10, 2015 20:37
@crl sewer: sows all pipelines together.
May 10, 2015 20:37
drowning in conformity sounds just as appealing as drowning in isolation. Perhaps it is the use of the word drowning that is awful, and should be eliminated from vocabulary, Then, for example, indulging in conformity and indulging in isolation sound just as great.