BlizzardWalker

 Math Mods' Office

For informal chat with the site moderators about moderation, s...
Apr 2, 2024 15:25
Anyway, if you think to keep it, then let it be in accordance with your regulations. I have nothing to say about that! Thanks in advance for your fast comments on the requests, appreciate all the hard work you guys do!
Apr 2, 2024 15:23
I did not say I cheated, I did not know it was a publicly lively contest. My apologies in advance but all I asked was to delete it, I didn't intend to receive such harsh criticism
Apr 2, 2024 15:20
@XanderHenderson Thank you for the fast response. The reason is this question was posted from a lively math contest which still ongoing so deleting this question would be a very valid reason imo.
Apr 2, 2024 15:17
There has been pretty a lot of downvotes for this problem, if any of users could delete this question, it would be super appreciated!
Apr 2, 2024 15:17
Hello, can any of moderators please delete the following question:

https://math.stackexchange.com/questions/4889437/roots-of-complex-derivative
 

 CURED

For feedback/discussion/requests of Close/Undelete/Reopen/Edit...
Apr 2, 2024 15:22
There have been pretty a lot of downvotes for this problem and this problem is from the ongoing live contest, so if any of the moderators could delete this question, it would be super appreciated!
Apr 2, 2024 15:21
Hello, can any of the moderators please delete the following question:

https://math.stackexchange.com/questions/4889437/roots-of-complex-derivative
 
Sep 12, 2023 08:11
@MartinR Do you think the solution for the original problem is correct?
 
Nov 14, 2021 16:23
Who will be the next president of the United Mathematics Stack Exchange
Nov 14, 2021 16:22
How is going on everybody?
 
Jun 10, 2021 12:26
it is just more mathematical rigor that is lacking
Jun 10, 2021 12:25
t
Jun 10, 2021 12:25
I am pretty sure that your logic is correc
Jun 10, 2021 12:25
thank you so much!
Jun 10, 2021 12:16
I agree with the well-definition of $x_{\epsilon}$. But, how do you get that $x_{\epsilon}$ approaches to $a$ whenever $\epsilon$ approaches to zero?!
Jun 10, 2021 12:16
Honestly, the last part really lacks the mathematical rigor: how $f(a) = 0$ and continuity of $f$ directly implies that limit of $x_{\epsilon}$ approaches to $a$ whenever $\epsilon$ approaches to zero: This really requires mathematical formalism, intuitively this seems okay though (however, I am still confused on how you choose these $\epsilon$ values, as this is not correct to assume that you have the control of the choices of these $\epsilon$ values.
Jun 10, 2021 12:16
Oh, now I see the point. But now arises another question: how continuity of $f$ will guarantee that for any small values of $\epsilon$, you can find that the function values near the neighbourhood will be larger than $\epsilon$? I guess there should be another point $y_0$ if we are dealing with continuity
Jun 10, 2021 12:16
Moreover, you obtained that $x_{\epsilon}$ is larger than one quantity. How can you take the limits for each $\epsilon$ where you do not have control over the choices of $\epsilon$
Jun 10, 2021 12:16
Can you please exemplify more on the set of $x_{\epsilon}$?! I still can not figure out the meaning of this set. (pretty sure this comes from continuity of $f$, but I would be really appreciated if you could provide a little more details if possible)
Jun 10, 2021 12:16
So it means that $x_{\epsilon}$ is the smallest ("infimum") number for which $x_{\epsilon} > a$ and $|f(x_{\epsilon})| >= \epsilon$? Meaning that for all numbers $y$ less than $x_{\epsilon}$, we will know that $|f(y)|$ is less than $\epsilon$?
Jun 10, 2021 12:16
I guess the equality of $f(a) = 0$ could be derived by just plugging $x=a$ in the given inequality
Jun 10, 2021 12:16
$$ |f(x_\varepsilon)| \le K\int_{a}^{x_\varepsilon}|f(t)|dt \le K(x_\varepsilon-a)\varepsilon $$ How do you derive the left-hand-side inequality?!
Jun 10, 2021 12:16
How do you know that the maximum of function $g$ will be epsilon?! Instead of epsilon, there should be the supremum of the function $g$ on that interval (i.e. absolute value of $f$)
Jun 10, 2021 12:16
I do not understand exactly why $1 <= K(x - a)$ implied that $x = a$
 

 Martin Hopf's prime numbers

primes of the form (b^n^2-1)/(b^n-1)
Jun 10, 2021 12:16
how is going on?!
Jun 10, 2021 12:16
well hello!
 

 Mathematics

Associated with Math.SE; for both general discussion & math qu...
May 7, 2021 07:21
Which cruel evil has chopped me off from the chat
May 7, 2021 07:17
@porridgemathematics How is going in your neighbourhood?
Apr 6, 2021 17:42
Hello
Oct 26, 2020 19:03
hey
 
Oct 20, 2020 19:52
What
Oct 20, 2020 19:51
@matt NOOOOO
Oct 20, 2020 19:50
hahaha
Oct 20, 2020 19:50
who is deusovi
Oct 20, 2020 19:50
yeo
Oct 20, 2020 19:50
I am winner
 
Oct 20, 2020 19:42
I will see when moderators will move you out of this forum
Oct 20, 2020 19:42
"Always provide proper attribution for all copied material." Aha, so you basically wanna rule me out, I see
Oct 20, 2020 19:41
really be ashamed of yourself
Oct 20, 2020 19:41
@D.W. I am not as proficient as you, but I know ALL THE RULES IN THIS FORUM, and IF I DID NOT MENTION SOURCE, THEN THERE IS SOME REASON THAT I DID NOT DO IT!!
Oct 20, 2020 19:41
@D.W. Next time be more careful when you pick words
Oct 20, 2020 19:41
@D.W. He told me not to mention his name here!!!
Oct 20, 2020 19:41
@D.W. And also, downvoting gives you nothing but hatred feelings towards you! Really sad that this forum has such unfriendly users, who are very eager to downvote any amateur's posts.
Oct 20, 2020 19:41
@D.W. I have every right to ask a question in this forum, providing in the statement all my findings and progress. What else do you want from me?
Oct 20, 2020 19:41
@D.W. This is original problem created by my professor.
Oct 20, 2020 19:41
@D.W. And he allowed me to post this question in this forum
Oct 20, 2020 19:41
@D.W. What is problem with posting this question?