आर्यभट्ट

 Mathematics

Associated with Math.SE; for both general discussion & math qu...
Jan 25 13:25
It ends 40 then then 60 then 00
Jan 25 13:24
Sorry do not reply I got my answer a silly mistake
Jan 25 13:20
Number are multiplied
Jan 25 13:19
Help me in this I do not know where I goes wrong :


---

Question:

Consider the following sequence of numbers: 85, 87, 89, 91, 95, 96. We will explore the behavior of the last two digits when these numbers are multiplied.

1. Step 1: Multiply 95 and 96
Start by multiplying 95 and 96. Observe the last two digits of the result. The last two digits of the product are 20 (since 95 × 96 = 9120).


2. Step 2: Multiply the Result by 87
Now, multiply the product from Step 1 (which ends in 20) by 87. Notice how the units and tens digits of the product evolve. The units digit of the product will be
Jan 9 15:37
Who is cleo?
Oct 24, 2024 17:15
I am not a math major but read number theory in my high school and university
Oct 24, 2024 17:13
I everyone I was watching how Fabinnoci number and music is related but video took some new turn creating different mathematical expression from the same numbers can anyone help me in getting crux of the video?
Oct 24, 2024 17:11
Oct 5, 2024 10:08
@Jakobian it is आर्यभट्ट
Oct 5, 2024 10:07
Sir does minus explain that we are moving in counter clockwise direction
Oct 5, 2024 09:28
?
Oct 5, 2024 09:28
87 multiply by 89 multiply 90 multiply 91 multiply 93 multiply by 97 multiply by 98 multiply by 99 divided by 100 will give remainder
Oct 5, 2024 09:27
Sir i have similar question related to it
Oct 5, 2024 09:25
Last time when we had a talk u were complaining about back pain
Oct 5, 2024 09:24
@PM2Ring by the way how is ur back now?
Oct 5, 2024 09:24
Thanks sir
Oct 5, 2024 09:19
Oh ok
Oct 5, 2024 09:16
It is 8 after 3 squarings
Oct 5, 2024 09:15
Ok
Oct 5, 2024 09:13
Yes
Oct 5, 2024 09:11
Cycle repeat after 7 so after 64 cycle we would be at 2
Oct 5, 2024 09:11
(322 mod 10) ^128
Oct 5, 2024 09:09
2
Oct 5, 2024 09:06
@PM2Ring answer is 8?
Oct 5, 2024 08:51
@RyderisnotRude. No
Oct 5, 2024 08:51
But since it is not the multiple of 2 how do I approach it
Oct 5, 2024 08:51
And cycle of 2^n repeat itself after 4 so if it would have been 256 I could have easily says last digit would be 2
Oct 5, 2024 08:48
And since the last digit is 2 it should be 256
Oct 5, 2024 08:47
I looked for the nearest possible square to 322
Oct 5, 2024 08:47
Of it
Oct 5, 2024 08:47
322^128 I need to find last digit
Sep 26, 2024 16:52
Got it 👍
Sep 26, 2024 16:42
@robjohn can solve it using modular arithmetic?
Sep 26, 2024 16:41
Oops sorry for that it been a long time since I used the site
Sep 26, 2024 16:39
I tried to solve it using modular arithmetic
Sep 26, 2024 16:38
222^{333} mod2+333^222 mod 2$
Sep 26, 2024 16:37
It is not divisible by 2 and 3
Sep 26, 2024 16:36
This was the original question
Sep 26, 2024 16:35
$222^{333}+333^222$
Sep 26, 2024 16:35
Hey wait one minute I think my first question if incomplete
Sep 26, 2024 16:34
One thing how u predict something so divisible or not? Ima very bad at number theory
Sep 26, 2024 16:33
Remain 0
Sep 26, 2024 16:33
Yes
Sep 26, 2024 16:32
I could not read syntax here because I m on phone
Sep 26, 2024 16:31
Can u tell me is it divisible 37
Sep 26, 2024 16:31
Oh shit yes 0
Sep 26, 2024 16:30
It is same 1
Sep 26, 2024 16:28
It could be 1
Sep 26, 2024 16:27
Yes
 
Dec 24, 2024 12:05
Hi everyone actually I am very new to this I wish to grasp reasoning behind quantative aptitude and what is the history and it's logic are different from traditional math?