User V. Courtois | chat.stackexchange.com

V. Courtois

Aug 22, 2019 11:29

Thanks!

V. Courtois

Aug 22, 2019 11:22

@EriktheOutgolfer yes I did. I don't know if the channel is still alive, but if it is I'm interested.

V. Courtois

Aug 9, 2019 13:11

I see

V. Courtois

Aug 9, 2019 12:56

Isn't basically Jelly a fork of J ? because its syntax is handy.

V. Courtois

Aug 9, 2019 09:43

Oh, my bad. I saw your tio.

V. Courtois

Aug 9, 2019 09:43

aren't there multiple solutions?_?

V. Courtois

Aug 9, 2019 07:54

Haha yeah ok I see

V. Courtois

Aug 9, 2019 07:51

Ah, but many people that connect only at a certain time won't be able to even see it :o

V. Courtois

Aug 9, 2019 07:50

but though, starring the CMC was handy >_<

V. Courtois

Aug 9, 2019 07:49

e

V. Courtois

Aug 9, 2019 07:49

Okay, I take not

V. Courtois

Aug 9, 2019 07:48

I couldn't unstar when you said this, so my bad.

V. Courtois

Aug 9, 2019 07:47

@flawr I saw it done by some admins when they were here and there, so I did the same during their downtime.

V. Courtois

Aug 8, 2019 13:54

Would rather have been Blacken if it was about dyeing

V. Courtois

Aug 8, 2019 13:54

IMO

V. Courtois

Aug 8, 2019 13:54

Black and*

V. Courtois

Aug 8, 2019 11:18

ṗ3żþØ½ṗ2 produces babb instead of babab ><

V. Courtois

Aug 8, 2019 09:40

`ṗ5Œœ€` returns a set of pairs odd/even (works fine).
I need to check that even part contains only `Øỵ` chars, and the odd part only `ØỴ` chars, but neither `Ƈ` nor `Ðḟ` (associated with `e€` things ...) seem to work. Any ideas? I'm so close, it bothers me ._.
Then this will interleave the things that were not filtered out: `żƝ€Y` (works fine)

V. Courtois

Aug 8, 2019 09:00

:'(

V. Courtois

Aug 8, 2019 09:00

i'll go back to alphabet^5 strat I think

V. Courtois

Aug 8, 2019 08:58

can't I do both?

V. Courtois

Aug 8, 2019 08:58

€ maps to left arg and Ɱ to right arg

V. Courtois

Aug 8, 2019 08:56

does not work as it should at all

V. Courtois

Aug 8, 2019 08:56

I hate this ż€ link

V. Courtois

Aug 8, 2019 08:55

the worst is that Øỵṗ2Y works

V. Courtois

Aug 8, 2019 08:55

...

V. Courtois

Aug 8, 2019 08:43

no

V. Courtois

Aug 8, 2019 08:43

but that's not what I want lol

V. Courtois

Aug 8, 2019 08:43

anyway, I can resolve the double write by doing Ḋ€ after

V. Courtois

Aug 8, 2019 08:26

am I missing an underlying Jelly rule?

V. Courtois

Aug 8, 2019 08:25

instead of b1b1b

V. Courtois

Aug 8, 2019 08:25

output goes from b1b2b to b1b2bb1b2b

V. Courtois

Aug 8, 2019 08:25

as soon as we do ṗ3ż€Ø½ṗ2Y

V. Courtois

Aug 8, 2019 08:25

but

V. Courtois

Aug 8, 2019 08:25

returns exactly what we want, except there's no cartesian power on (1,2)

V. Courtois

Aug 8, 2019 08:24

works as intended

V. Courtois

Aug 8, 2019 08:24

this
z="bcd"; ṗ3ż€Ø½Y

V. Courtois

Aug 8, 2019 07:57

hey it's hard

V. Courtois

Aug 8, 2019 07:57

...

V. Courtois

Aug 8, 2019 07:56

begins with b1b2bb1b2bb1b2b

V. Courtois

Aug 8, 2019 07:56

even though it shouldn't

V. Courtois

Aug 8, 2019 07:56

message too long

V. Courtois

Aug 8, 2019 07:56

output of z=bc; ṗ3ż€Ø½ṗ2µṢ€:

V. Courtois

Aug 8, 2019 07:55

(cause I reread Q and it's not what I want lol)

V. Courtois

Aug 8, 2019 07:55

with Ṣ either

V. Courtois

Aug 8, 2019 07:55

it doesn't work

V. Courtois

Aug 8, 2019 07:55

I tried

V. Courtois

Aug 8, 2019 07:53

where should I put the Q so that it doesn't take Ø½ṗ2 as an argument?

V. Courtois

Aug 8, 2019 07:52

doesn't work :(

V. Courtois

Aug 8, 2019 07:51

should have b1b1b b1b1c b1b2b ... c2c2c

V. Courtois

The Nineteenth Byte