Mathematics

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Nov 7, 2016 05:28
What are you asking vrouvrou? Is the equation true? Yes it looks like it.
Nov 7, 2016 05:08
@Vrouvrou please, does your nickname mean anything ? Just curious.
Nov 7, 2016 04:58
Vrouvrou does your nickname mean anything? I remember some french player of a game I used to play using it.
Nov 7, 2016 02:54
Hey
Nov 7, 2016 02:50
Or if it is defined, it's still just $V$, not isomorphic to the external direct sum of $V$ and $V$.
Nov 7, 2016 02:49
But for example you can take the subspace $V= \{ (0,0), (0,1) \}$ of $\mathbb{Z}_2 \times \mathbb{Z}_2$, take the external direct sum of $V$ and $V$, and you get something isomorphic to $\mathbb{Z}_2 \times \mathbb{Z}_2$, but there's not an internal direct sum defined for $V$ and $V$. (I think... might be nice if someone who understands this stuff checked it out xD.. I think I'll just ask someone in school to make sure).
Nov 7, 2016 02:40
for $\mathbb{Z}_6$, it's an internal direct sum of those two sets.
Nov 7, 2016 02:39
There's one in [direct sum]en.wikipedia.org/wiki/Direct_sum
Nov 7, 2016 02:31
I think there might be some slight differences depending on the writer, but it looks to me like: Internal sum of two sub-structures is defined for two sub structures that are 'independent', and it's all their combinations. External sum are the actual tuples from the cartesian product of the sub-structures. If the internal sum of two sub-structures is defined, it's isomorphic to the external sum, hence naming it 'internal direct sum'.
Nov 7, 2016 01:55
Internal product is actually what it 'generates' in the given space.
Nov 7, 2016 01:54
[title]math.ncku.edu.tw/~fjmliou/advcal/sumvspace.pdf I think this explains it for me well enough.
Nov 7, 2016 01:50
This is mostly for a basic course in ring/module theory
Nov 7, 2016 01:47
Yeah I understand it like that, just not completely sure I get it precisely enough.
Nov 7, 2016 01:45
Thanks, yeah I looked at that already.. sadly not really.
Nov 7, 2016 01:41
It says they're isomorphic, but are they the same set? It seems to me like they are. If I take the direct sum of $V_1$ and $V_2$, and they are isomorphic to some $V$, is it true that if $V_1$ and $V_2$ are both submodules/substructures of $V$, then it's an internal direct sum? Is every internal direct sum an external direct sum?
Nov 7, 2016 01:39
guys would someone help me figure out the differnce between internal and external direct sum?
Nov 7, 2016 01:39
Nov 2, 2016 23:27
Either way, if I understand it right, it should be fine just to take $\langle H,H^a \rangle$, which is subnormal in $H_{(1)}$, and then since $H^b$ is subnormal and satisfies the inductive hypothesis, I can say that their union, which is $\langle H, H^a, H^b \rangle$ is also subnormal in $H_{(1)}$
Nov 2, 2016 23:22
Or more precisely, I think the claim halfway through about $\langle H, H^a, H^b \rangle$ is wrong - I don't see how it's equal to what it's claimed to be. Also, I think induction should start at s>0, not s>1.
Nov 2, 2016 23:21
would someone please help me out with the proof starting at page 133 ? The claim is that the derived subgroup of $G$ satisfies ACC (no infinite series of increasing subgroups), then union of two subnormal groups is subnormal.
Nov 2, 2016 23:19
Sep 12, 2016 12:33
@TobiasKildetoft Right, thank you Tobias.
Sep 12, 2016 12:29
Doesn't matter in what sense? That it's easy and it doesn't matter how you do it? (Just pick power set of arr(C), which is still small.? )
Sep 12, 2016 12:21
Hello, would someone please help me out with a small question - Saunders Mac Lane, Categories book, page 114, proposition 3, why is it said " If the small set J has cardinal larger than arrC" ? Couldn't it be equal to arr C?
Sep 9, 2016 22:30
Hey guys, has anyone ever heard of "maranda's theorem" in category theory? I'm can't really find what it is, though it does seem it might be this [maranda's completeness theorem]books.google.cz/…
Sep 5, 2016 19:26
Try to look at all the possible numbers between 1000 and 8999, that don't contain a 5.

First digit can be either 1,2,3,4,6,7,8,9 - that's 8 numbers. The second digit can 0,1,2,3,4,6,7,8,9 - 9 numbers, same for 3rd and 4th digit. So all the possibilities are 8*9*9*9
Sep 5, 2016 19:18
Yeah that's how I understand it.
Sep 5, 2016 19:18
If we asked the same question for numbers from 10 to 19, including 19, we would have a set {10, ... , 19} (10 elements), and 1 of them would contain a 5 - 15. So there's 10 numbers, 9 don't contain 5, 1 does.
Sep 5, 2016 19:16
I don't know what you're saying. You have all those numbers, {1000, .... , 8999} and you're asking how many there are of those, that have no 5 in any of their digits.
Sep 5, 2016 19:13
@TobiasKildetoft Hah that's good advice, I don't understand why I didn't look in some book first...
Sep 5, 2016 19:12
@MATHASKER I understand it as "a number between 1000 and 9999, such that non of the digits are 5" - the possibilities are - 1st digit 8 (9 possible numbers on the first digit, you can't choose 0), then 9 on 2nd-4th digits. So you have 8*9^3 ?
Sep 5, 2016 19:09
The universal morphisms one
Sep 5, 2016 19:08
yes I realize that, but I don't see how it follows from the definition.
Sep 5, 2016 19:07
[adjoint functor]https://en.wikipedia.org/wiki/Adjoint_functors

hey guys, would someone please help me understand the universal morphism definition? If I take the "left adjoint functor" , and I do the construction, obtaining some functor $G$, does that $G$ satisfy the definition of a "right adjoint functor", I would have thought so, but I don't see how I would show that.
Aug 29, 2016 21:47
@BalarkaSen
Aug 29, 2016 21:46
Hey, just reading some of the stuff you wrote earlier.


What exactly about the fact that F isn't a set made you say Nat(h^A, id) is not really a set ?
Aug 29, 2016 21:05
I feel like I just shouldn't bother thinking about these questions at this point in time xD
Aug 29, 2016 21:04
Thanks a lot for the help guys.
Aug 29, 2016 20:45
But I'm just not sure whether it makes enough sense from a rigorous perspective - it shows there's some sort of thing like a bijection, but I don't know it's a set in the first place, so I'm not sure how it would make sense... it seems like you still need to presume that it's a set. I'm just ranting now.. I'll read the thing you wrote higher up though.
Aug 29, 2016 20:43
@BalarkaSen Well see that's what I was sort of hoping it says.
Aug 29, 2016 20:37
I'm not sure what theorem you mean at all.
Aug 29, 2016 20:34
Were it not directly said it's isomorphic, I'd be fine with just thinking "ok there's some sort of weird bijection between this set/class-thingy and a set"
Aug 29, 2016 20:34
Well it's said that they're isomorphic, not just in bijection.
Aug 29, 2016 20:31
@mercio I generally try to avoid these questions given my problems with set theory, and me being unable to tell whether it's worth thinking about too much... but this one time I wanted to understand this a bit rigorously, and I got stuck lol.
Aug 29, 2016 20:29
@BalarkaSen Sorry, I don't really see how that follows. Would you be willing to please try and fill in a bit more of the reasoning?
Aug 29, 2016 20:28
Yeah sorry to hear that.
Aug 29, 2016 20:23
Well if it's possible at all, then that's not so surprising.
Aug 29, 2016 20:21
Ok, so the elements of that set themselves aren't sets, but it's a still a set hm. I didn't even know that's possible.
Aug 29, 2016 20:17
@BalarkaSen If it's locally small, but the domain category's objects arent' a set, how can I tell that a specific natural transformations between the two functors is a set?
Aug 29, 2016 20:14
That would make sense, but I don't see that the domain category is small - there's written it's locally small.