« first day (4486 days earlier)      last day (539 days later) » 
01:00 - 20:0020:00 - 00:00

1:12 AM
I have a super simple question.
 
A superior question?
 
Nay, a super simple one.
 
Let’s see if your advertising is right.
 
I am asked to evaluate some triple integral over the solid $E$ which lies above $z=1$ and within $x^2+y^2+z^2=2z$.
I thought Spherical Coordinates gives $0<r<1, 0<\phi<\pi/2, 0<\theta<2\pi$
 
Either cylindrical or spherical coords, depending on what you’re integrating.
NOOOOO …
 
1:18 AM
My integrand makes the choice of coordinates rather obvious: $\iiint_E \frac{z}{\sqrt{x^2+y^2+z^2}} d V(x, y, z)$
No? Already?
 
$\theta$ limits fine, the others very not fine.
You have the hemisphere centered at the origin, not centered at $z=1$.
 
Well clearly, $x^2+y^2+(z-1)^2=1$, so $r=1$
Aha! That's what's been causing all this confusion!
 
Nooooooo … Pay attention
 
OK, paying attention.
 
$z-1$, not $z$. The spherical coordinate equation is easy from the original formula they gave you.
 
1:20 AM
 
Now you can see that above the plane $z=1$ constrains $\phi$.
 
What do you mean $z-1$? What term/equation are you referring to?
Oh!
That's genius!
No, worse. It's brilliant!
 
You probably can find an example almost identical to this in my videos ….
 
Something like this, perhaps:
 
Right.
 
1:23 AM
Mhmm, and I just have to figure out what $\phi$ restricts the sphere.
Like a pudding in an ice cream cone.
 
Moreover, what is $z=1$ in spherical?
 
$r\cos(\phi)=1$?
 
So $r=$?
 
Aha! $r=\sec(\phi)$. That makes so much sense.
 
Making progress. …
 
1:28 AM
But what does that mean? $z=1$ is just the origin of the sphere, no? So I'm trying to understand what this $r$ actually signifies.
 
No. It’s the plane!
 
Sure, I know that, it's the plane $z=1$, but I mean that the center of the sphere lies on that plane.
 
$r$, as usual, is distance from the origin. I use $\rho$ so as not to confuse with polar coord $r$.
 
Sure, so this is the minimum bound for the radius, I guess.
And the maximum bound would be $z=2$? $r\cos(\phi)=2$? Since that's where the top of the sphere is?
 
Draw (on paper) a ray coming out of the origin. Where does it enter the region? Where does it exit?
 
1:31 AM
OK.
 
Nooooo.
 
It enters at $z=0$ and exits at $z=2$.
 
Drawing a (vertical) cross-section is good enough to see.
It does not. Fix a ray in that cone you drew on computer.
 
That’s not the region.
 
1:33 AM
Oh, let me try again.
 
Remember how you figured limits in earlier problems. You fix $\theta$ and $\phi$ generally and study $r$.
 
Like this?
Ultimately, $1<z<2$, right? So then $1<r\cos(\phi)<2$?
That's it! I think that's it!
 
Aghhh. What is $r=2$?
 
A sphere of radius 2 centered at the origin
Oh whoops, I mean $z=2\sec{\theta}$?
 
No.
 
1:38 AM
Wait, let me see.
Oh of course, $\sqrt{x^2+y^2+z^2}=2$
 
Where is that in our problem?
 
Top of the sphere?
 
No. You just wrote down a sphere of radius 2 centered at origin. Nowhere in our problem.
 
We have a sphere of radius one pushed up a unit on the z-axis
Make that $x^2+y^2+(z-1)^2=1$
 
So you obviously need the eqn for that
 
1:42 AM
$(r\sin(\phi)\cos(\theta))^2+(r\sin(\phi)\sin(\theta))^2+(r\cos(\phi)-1)^2=1$
 
I want a simple equation.
 
$r^2\sin^2(\phi)+(r\cos(\phi)-1)^2=1$
Oh, let me expand
$r^2\sin^2(\phi)+r^2\cos^2(\phi)-2r\cos(\phi)+1=1$
$r^2-2r\cos(\phi)=0$
$r(r-2\cos(\phi))=0$
 
If you reread our conversation, you’ll see you ignored something important I said :)
 
$r=2\cos(\phi)$?
Hmm ...
 
Yes.
 
1:44 AM
"That’s not the region."?
 
Way above
 
Hmm, "Now you can see that above the plane z=1 constrains ϕ."?
I'm not sure what I might be missing
 
Above your first picture.
 
:62375575
Whoops, I meant to copy that message.
I see, so $z-1$, instead of $z$
 
No.
Next sentence.
 
1:48 AM
The spherical coordinate equation is easy from the original formula they gave you.
 
Bingo.
 
But that's what I did, right? Converted from the cartesian to spherical using the given formula?
Oh wait, are you referring to the integrand itself?
 
The original equation of the sphere is something you can do in your head.
 
Sure
 
Not your algebraic version of it.
 
1:50 AM
Hmm
 
You see $r^2 = $ to start.
 
$r^2=2r\cos\phi$?
 
Easy, eh?
 
Huh
Wow
 
Anyhow, my lecture on spherical coords might help you …
 
1:52 AM
Well great, now I can extract the bounds from this!
 
You need $\phi$ but must know it from your second picture.
 
Oh I just plotted $z=\sqrt(x^2+y^2)$ lol to get a sense of the angle
 
What is the angle, then?
 
Let me see ...
Aha!
It's so simple!
 
I keep suggesting that you will get more intuition drawing sketches by hand.
 
1:55 AM
@TedShifrin I know, I'm just doing it by GeoGebra for the purposes of sharing the image here.
 
Fair.
 
what game is this, and why are you playing it on a potato
 
OK, we’re done :)
 
@leslietownes It's called "help a fledging undergrad figure out spherical coordinates for an hour!"
@TedShifrin So I have $\phi=45$ degrees!
Boom! I've got everything!
$0<\theta<2\pi, 0<\phi<\pi/4, \sec\phi<r<2\cos\phi$
I finally understand.
 
i'll wait until it's one of those free promotions on steam
 
1:59 AM
Thank you so much @TedShifrin for patiently walking me through the process. You deserve an award for the great teaching. I appreciate it.
 
Some people would disagree, but thanks. Don’t forget to check some of my videos :)
My iPad needs to charge.
 
you can also find him at "realTedShifrin (verified)" on twitter, he promotes a lot of cool investment opportunities over there
 
@anak yes but its tricky
2
Q: Proving an implication of two dimensional matrix.

BAYMAXIf $A = \begin{bmatrix} x & 1\\ y & 0\end{bmatrix}, B = \begin{bmatrix} z & 1\\ w & 0\end{bmatrix}$, for $x,y,z,w \in \Bbb{R}$. I have observed by considering many random values of $x,y,z,w$ that: If all the eigenvalues of $A^2B$ and $AB^2$ are less than one in absolute value $\implies$ $\det(AB...

Any idea of a proof for the above
 
Hatcher 2.C... should've not skipped that part.
 
2:31 AM
@TedShifrin I found that the cell complex construction I asked if you have ever seen before is described in Hatcher.
in 3.G titled transfer homomorphism
 
@leslietownes In all seriousness, I've never been to twitter, and certainly after Elon, I would not set foot (or other appendage) there.
@onepotatotwopotato I'm not surprised. Everything is in Hatcher. Never having taught out of it, I don't know it page by page.
 
Hatcher is indeed a long exact sequence.
 
Actually, what you asked about wasn't a cell complex construction. It was a chain map with singular/simplicial ... whatever chains.
 
Yes. I realized but too late to edit.
 
 
1 hour later…
4:05 AM
For vector fields on a smooth manifold, if $[V,X]=0$ for all $V$, must $X$ be the zero vector field?
I think I have a coordinate proof. Is there a noncoordinate proof?
 
That’s false, isn’t it?
Oh, no, it’s not. I was going to say the only vector field invariant under all flows is $0$ and then faked myself out.
 
 
1 hour later…
5:27 AM
too much excitement for me
 
6:14 AM
Can anyone please explain why in a T1 space X, X being countably compact implies X is limit point compact?
Given any infinite subset of X, one can get a sequence {a_n} out of it. Noting that X=$\cup_i (X-\{a_i\})$, we have finitely many indices $i_1, i_2,…,i_n$ such that $X= \cup_{k=1}^{k=n}(X-\{a_{i_k}\})$. So one of the sets on RHS ( say$ X-\{a_{i_j}\}$ contains infinitely many terms of the sequence. I want to now prove that $a_{i_j}$ is a limit point of the sequence.
But I am stuck here.
 
6:30 AM
This can’t work as an approach. Countably compact or not, two of these sets always cover.
Try taking $X-\{a_1, \dots, a_n\}$.
 
Yeah, then how should I proceed to prove the above statement?
Ok, I’ll try with this.
But this doesn’t cover the space X.
None of these sets contains $a_1$ for example.
 
6:46 AM
nvm, I got it now.
 
 
1 hour later…
7:51 AM
The idea is : every closed subset of X is countably compact.
 
8:32 AM
0
Q: mapping a distribution to it's parameter domain

geocalc33The K-distribution is a special case of the variance gamma distribution, which in turn is a special case of the generalised hyperbolic distribution. The generalised hyperbolic distribution is a superclass containing the student T's distribution, Laplace distribution, hyperbolic distribution, norm...

probably a lot is wrong in this post, but i'd welcome feedback!
 
9:15 AM
 
Rotating clockwise... is that intentional?
 
9:50 AM
@AkivaWeinberger If this holds, then for every smooth function $f$ and every smooth vector field $V$, we have $0=[X,fV]=(Xf)V+f[X,V]=(Xf)V$. This implies that, for every smooth function $f$, we have $Xf=0$, thus $X=0$.
 
10:01 AM
@onepotatotwopotato Yes. The default would rotate anticlockwise.
 
 
2 hours later…
11:58 AM
@PM2Ring oo, fancy
 
12:31 PM
@PM2Ring Okay, I can do that in Mathematica with the code I have...
 
12:58 PM
Unfortunately, SVG only stores the code (about 1K), whereas GIF needs 1M for a rougher animation.
 
3
Q: Proving an implication of two dimensional matrix.

BAYMAXIf $A = \begin{bmatrix} x & 1\\ y & 0\end{bmatrix}, B = \begin{bmatrix} z & 1\\ w & 0\end{bmatrix}$, for $x,y,z,w \in \Bbb{R}$. I have observed by considering many examples of $x,y,z,w$ that: If all the eigenvalues of $A^2B$ and $AB^2$ are less than one in absolute value $\implies$ $\det(AB+A+I)<...

 
1:14 PM
If $g_1 + g_2 = g_3 + g_4$, where $2\leq g_i\in\Bbb N$ for all $i$ and $g_1\neq g_3$ then $g_1 = g_4$ and $g_2 = g_3$ is the only case?
With $g_1g_2 = g_3g_4$
 
@robjohn Indeed. :) Sage can save static plots as SVG (using matplotlib), but the resulting code is fairly huge, especially if it contains text, since matplotlib embeds the fonts into the SVG file. I do use that for a lot of stuff, but for basic things I prefer to write directly in SVG, or generate the SVG by my own Python code, which is what I did for the stuff I've posted here recently.
 
Hrm... I really don't like embedded animaged gifs.
Just a few more comments, and it will be bumped up high enough that I don't have to look at it.
Almost there...
(It is a very nice image, I just don't want to have to watch it turn.)
(It is distracting.)
 
@XanderHenderson It's not a GIF! And I intentionally gave it a long period (15 seconds) so that it wouldn't be too disturbing for you. I suspect that the version with a 1 second period would probably be nauseating for you.
 
@PM2Ring I mean, a faster rotation would be worse.
And is it really necessary to be pedantic about the file format? I think that my communication about it was clear...
 
I could easily make it so that you could click it to stop it & start it. But Stack Exchange won't display SVG using such features.
Yes, your communication was clear. The pedanticism wasn't necessary... ;)
 
1:29 PM
No.
Just... no.
 
I fully intended to delete it after a couple of seconds, but you beat me to it.
 
Uh huh... Sure.... :P
 
1:45 PM
@PM2Ring thank you for posting this
 
@PM2Ring For a GIF with 360 images, it took 6.3 M, but it is as smooth as the SVG.
 
@robjohn Hello
 
@XanderHenderson: don't worry, since it is 6.3 M, I can't even think of posting it.
 
@robjohn Oh, good. :D
 
We used to have so many GIFs posted in here.
 
1:49 PM
I want to show that compact subsets for a metric space X is also compact for another metric space Y
I think it is enough to show open sets in X are open in Y
is that sufficient?
 
I may be mistaken, but I think you need to show that open sets in Y are open in X.
 
Oh yes i think you are right , i have written it the other way
:D
 
for any open cover in Y, we can find a finite subcover in X, then that same subcover will work in Y.
 
thanks @robjohn
that was the idea ! :)
 
I was going to challenge @robjohn to come up with a mean rotating hyper cube...
...perhaps, after the pumpkin pie is done.
 
2:02 PM
I should make more pies this week... I have eaten all of the persimmon pudding; perhaps it is time for a pecan pie?
 
2:12 PM
The ingredients of humble pie are humble indeed.
TIL
 
2:28 PM
@user4539917 I don’t think animated GIFs work as avatars.
 
Jam
$\sum(\frac{1}{n})-log(n+1)$ converges why? I get it intuitevly both are slow functions going to infinity so they cancel each other
 
@Jam It converges because the sequence of partial sums converges. What kind of deeper "why?" are you looking for?
 
Jam
why the partial sum converges?
 
you can show the partial sums are bounded below and decreasing
 
Jam
i can show its decreaning for large n
cant find a a bound
0?
 
2:46 PM
No, that isn't quite the suggestion...
The sum is related to the logarithm (using the fact that $\log(x) = \int_{1}^{x} 1/t\,\mathrm{d}t$).
Compare $1/\lfloor x \rfloor$ to $1/x$. That should be more enlightening.
 
Jam
ohh that makes sense
 
How do you usually know when to use proof by contradiction, contrapositive, direct proof,... etc?
 
What is your favorite example of proof by contradiction?
 
My exam for real analysis is coming I haven't practice proof...
@Yai0Phah too many
for now i got squareroot of prime number is irrational in my mind
 
Strictly speaking, it is not a proof by contraction, but the definition of irrationality.
 
3:01 PM
or may be special case where square root of 2 is irrational
does this method come to you naturally after a lot of practice?
 
@user4539917 If you like rotating hypercubes, see mikelortega.github.io/tesseract (which I've linked here previously).
@robjohn They aren't permitted. There's an obscure bug that allows animated GIF avatars, but they tend to get removed fairly quickly, and I think the devs are working on fixing that bug.
 
if you are given implication then i can only think about direct proof ,counterexample, contrapositive or contradiction
do you exhaust all of this?
do you use your intuition?
 
If there's a direct proof and a proof by contradiction that are of similar complexity, it's generally preferable to give the direct proof. Unless you're specifically asked for a proof by contradiction. ;)
Sometimes, people get too focused on looking for a proof by contradiction and they overlook a more straightforward direct proof.
 
I see. Do you have any recommendation on exercise textbook where you can improve your proof skills?
I mostly end up cheating by looking at solution because of no patience due to lack of time.
 
3:18 PM
@NotTfue I don't think that any mathematician thinks this way.
 
@XanderHenderson why?
How do they think?
 
@NotTfue I don't think that anyone looks at a proposed result and says "I am going to try to prove this by contradiction!"
You try things.
Sometimes they work, sometimes they don't.
Experience will guide which kinds of things you try.
 
At school professors only teach us to use method they never mentioned this :(
 
In the "real world", I suspect that most mathematicians attempt to prove things by first building some toy examples, and trying to figure out what parts of those examples generalize. But you don't even know if a result is true or not until you get a proof (one way or the other).
2
@NotTfue Mathematics beyond high school is not just "plugging and chugging". It requires creativity. You build up a lot of tools, and you bring them to bear on problems. It is almost never obvious which tools are going to work until you try something.
 
In this case I wonder why do exam even test proving theorem. Most of the theorem I guess requires longer than an hour to come up. Verifying proof is already time consuming I can't think about coming up with one with fixed time interval.
 
math professors should be taught history of mathematics...
gotta save that to my collection :)
 
@PM2Ring I put that comic in my syllabi.
@NotTfue The history of mathematics is a distinct discipline from mathematics itself. It is actually a pretty difficult area to study, as one needs to be both a skilled historian and a skilled mathematician to do it well.
Hence most mathematicians don't know a ton of history (except, maybe, in their own area).
So who would teach that history to professors?
 
3:46 PM
And you need to deal with old notation (or no notation) and obsolete ideas. Eg, historical treatments of the theory of quadratic equations are tedious because they don't use negative numbers, so you have a bunch of separate cases.
 
@PM2Ring Exactly.
 
@XanderHenderson No idea. (Pretty complicated than I thought)
 
4:21 PM
Yup.
 
4:36 PM
anyone here knows basic algebraic number theory?
never mind, figured it out
 
yes, but glad it's not needed
 
4:54 PM
@Thor @leslie This is something I've never seen before. I don't see anything obvious (since there isn't a projection from a Banach space to a finite-dimensional closed subspace, is there?).
 
@NotTfue What do you mean by "test proving theorem"? If you are referring to memorizing proofs of important theorems in your textbook, then they are basically important examples of some proving techniques, and you train by efforts of understanding these proofs.
 
@NotTfue Of course in real mathematics courses we're going to include proofs on exams. In some courses, all the questions will be proofs, although I always tested examples/counterexamples, as well. Some proofs may be regurgitations of proofs from the book/class. But some will be new things that are similar to what you've seen/done for homework. You learn only by practicing LOTS.
 
5:17 PM
is it correct to write the following? Suppose f(x,y) depends on x,y. I want to integrate its PARTIAL derivative w.r.t x, where the integration variable is x. Can I write the following? Here is screen shot.
 
@TedShifrin is there not?
doesn't, uh, Hahn-Banach say that one exists?
need to check the statement again
say $X$ is a Banach space and $A$ a finite-dimensional subspace. pick a basis $v_1,\dotsc,v_n$ of $A$. then, the maps $A\rightarrow\mathbb{R}$ mapping an element of $A$ to its $v_i$-coordinate are linear and trivially bounded, so they admit extensions $F_i\colon X\rightarrow\mathbb{R}$ by Hahn-Banach. then, $F(x)=\sum_{i=1}^nF_i(x)v_i$ is a bounded projection $X\rightarrow A$, I think.
but I never actually looked at a proof of Hahn-Banach, so take this with multiple grains of salt
 
Yes, I agree with that, and base fields are injective objects in the category of locally convex Hausdorff TVS's, thus so are their products (not necessarily finite).
 
opps, sorry, I meant can I write the following (I made latex typo)
 
5:34 PM
@Thorgott Ah, right. And, easier, I can split the projection to the cokernel.
 
Can non-compact spaces GH converge to compact spaces?
 
It is not clear to me how to split a projection. I think that there are non-split surjections of Banach spaces in general.
 
@Nasser Yes, this is correct.
 
@TedShifrin thanks. Just needed confirmation.
 
@Yai0Phah Yes, but this is a Fredholm map, so the cokernel is finite-dimensional :)
 
5:56 PM
ohh, yeah
 
6:07 PM
Oh, maybe I misunderstood what you said. I thought that you construct splits of injections $V'\to V$ where $V'$ is of finite dimension via constructing splits of projections $V\to V/V'$.
 
@Xander Gotta love repetition! Item 3 Item 2 Item 1
@Yai0Phah No, I was referring to the linked question. One needs to project the domain onto the finite-dimensional kernel and split the finite-dimensional cokernel back to the codomain.
 
6:38 PM
Suppose that X is locally compact Hausdorff. Then, what is the idea to one pt. compactify it?
I mean - the idea behind constructing a compact Hausdorff Y which contains $X$ as subspace such that Y-X is a singleton set.
Suppose that I add a point z (it's not in X) to X to form Y=X U {z}. Then, how to define topology on X?
 
well, you want every open cover to have a finite subcover
on the other hand, you want a space that's still hausdorff
so think about what neighborhoods of $z$ you could permit to attain both of these goals
 
@Koro Did you settle that countably compact implies limit point compact problem?
 
11 hours ago, by Koro
The idea is : every closed subset of X is countably compact.
@TedShifrin yes.
 
I learned about different religions today
Fun fact: People who follow the Zoroastrianism have fire temples. In those fire temples they have 16 types of flames, they perform 1128 rituals on every flame.
 
6:55 PM
Interesting?
 
I also learned about the Bahá’í Faith.
Very interesting.
They have very interesting ideas about World unity.
They believe that humanity is connected as one, and that every religious figure is simply a manifestation of god.
After all, god is unknowable.
If interestd, you could read more here: bahai.org
 
@Koro Yeah, my suggestion wasn't any better than your original try.
 
The Baha'i temple in Chicago is beautiful
 
You should also take a look at the Tabernacle of Unity and the seven questions.
 
I highly recommend checking it out if you're ever in that city
 
6:57 PM
@AkivaWeinberger you;ve been there! lucky
I only got to see photos.
 
I'm not that interested, all sorts of religious beliefs are a bit like a fairy tale for me
 
I believe that anything can be a religion.
We do not need to place our faith into some higher being.
 
I also got to see the Baha'i gardens in Haifa but I was very young
I would like to go again some day
 
My friends and I had some interesting debates about whether or not yoga is a religion.
@AkivaWeinberger when you do go, take loads of pictures and share pls
 
@TedShifrin I also realized that it doesn't require the underlying space to be $T_1$.
However, the converse of the statement holds in case the space is $T_1$.
 
7:00 PM
Anyways, it's 3 in the morning in Singapore. I need sleep! Night yall
 
I think for the Chicago one at least they don't like photography there
I do have photos of two of my friends licking the Bean sculpture though (in downtown Chicago)
They both got COVID shortly after
Probably unrelated
 
@Koro I haven't thought about such things since I last taught point set topology, and that was literally decades ago.
 
:-).
 
@AkivaWeinberger uh
 
@AkivaWeinberger Um ...
 
7:04 PM
@AkivaWeinberger Devious lick
This is the most recent image in my camera role
We recreated Gollum!
 
In a compact Hausdorff space, can we have isolated points?
I think -yes, why not.
 
OF course.
 
stream of consciousness
 
copper: have you ever tried this food ministryofcurry.com/wp-content/uploads/2022/07/…?
in one of its versions that I've had, they also add raw mango toppings on it and the taste is so amazing :-).
 
7:23 PM
@Koro not yet :-) i don't really have a sweet tooth
 
Pomegranate isn't exactly sweet :)
 
Oh I see.
I miss some of the foods I used to take almost daily before I came to college for Masters. One of them is this https://en.wikipedia.org/wiki/Dabeli apart from the one whose image I shared above.
My friend and I used to have this after coming from office.
 
Ah, potatoes in sweet snacks.
 
yay! There were many such food shops near where we lived. Almost all of them selling this same thing. But the taste from each shop was different.
I liked how some of them served it with sauce made from tamarind.
(sometimes I talk too much about food. I should not. 😅)
 
@Koro but not in a continuum
 
7:50 PM
@TedShifrin Sigh...
@Ajay I mean, not if the word "religion" is going to remain a useful word.
 
i like to eat food
 
It has been 20 years since I took any anthropology, but my recollection is that anthropologists typically define a religion to be a set of practices and beliefs pertaining to the supernatural.
 
You're definitely a gourmand as opposed to a gourmet :D
@Koro Had I not been a mathematician, I would have been a chef. I probably would have worn out pretty quickly, though.
 
i think the reality of being a chef is management skills...
 
@copper.hat Depending on what, precisely, you mean by "chef," yes, very much so.
CIA teaches a lot of food prep skills, but also a ton of business and restaurant management stuff.
 
7:57 PM
@Thorgott Do you happen to know a book that treats number rings, as opposed to just considering rings of integers? (number ring being a subring of a number field)
 
@copper Those skills I actually do have to a reasonable extent. But my love of cooking probably would have worn out having to do it, rather than enjoying doing it for friends.
 
my son is very interested in cooking, i was pointing out to him that a career in the food industry may not be quite what he had imagined.
 
It's sort of like musicians. Very few make it as soloists, chamber musicians, or good orchestral players. But the super-talented ones tend to do well (albeit work their butts off).
 
01:00 - 20:0020:00 - 00:00

« first day (4486 days earlier)      last day (539 days later) »