2 hours ago, by
Bubbler @AidenChow Pop n, pop m, grab the next m values on the stack, and rotate it n times. So if you pushed 1..5 and then push 3, push 1, then roll, what you get is: [1, 2, 3, 4, 5] -> [1, 2, [3, 4, 5]] -> [1, 2, [5, 3, 4]] -> [1, 2, 5, 3, 4]