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4:41 AM
@WhitePrime Do you mean cathedral of physicists?
 
 
2 hours later…
6:55 AM
Hi, everybody.
 
7:12 AM
@JohnRennie, hi John, division by zero has been determined as infinity, zero and then undefined or an operation not permitted, right? But in real world, in physics a lot of formulae are a ratio, can you describe what actually happens to such phenomena/functions when the denominator goes to zero?
 
@user157860 division by zero is always undefined. In physics a division by zero never happens. If you find you have a division by zero this is a sign that whatever you are considering is unphysical.
 
@JohnRennie, that is really surprising! please clarify why denominators of formule can never go to zero.Thanks
 
@user157860 why is it surprising?
Actually I suppose we can have 0/0 in the sense of a limit of infinitesimals, but that isn't really dividing zero by zero.
You don't have a finite number divided by zero in physics because there are no infinities in physics.
 
@JohnRennie, as I mentioned, most basic formulae contain a division, so , I thought, for all or most of them there must be a case when that denominator goes to zero.
 
@user157860 but there is no physically realistic situation where that would happen.
 
7:25 AM
actually, 0/0 should be the real undefined one 0/0 = n, since any number multiplied by zero is 0 0=0n, don't you think?
@JohnRennie , alright, I 'll reflect on that and if I find one case I'll submit it to you.
 
Where this happens in physics it's usually the result of taking limits e.g. v = s/t in the limit where both s and t go to zero.
So even though we end up with 0/0 we approach the limit in such a way that the ratio is well defined.
 
@JohnRennie, I was rather thinking of denominators which contain a subtraction, that surely must have a realistic instance
 
@user157860 if you can think of one let me know :-)
 
@JohnRennie, OK thanks
 
@user157860 even some mathematicians argue that infinity doesn't exist, though this is a minority view.
 
7:35 AM
@JohnRennie, the concept of infinity in actu has caused a lot o fallacies in physics. When Cantor advanced the idea in 1875 he was jeered and defined insane, I still can't understand how mathmen and physicist could later accept that
 
I don't think Cantor was "defined insane" as you put it. He had very real problems and committed himself. I agree that his work wasn't viewed positively by the establishment.
I don't see any problem with defining infinities in mathematics because mathematics isn't physics.
 
@JohnRennie, if you don't stick to reality, you get into trouble. Probably one can fool around in maths, but when you import such nonsense as Infinity+1 = infinity into physics you surely derail
 
I suspect most physicists would agree that actual infinity does not exist in the real world.
 
8:03 AM
@JohnRennie, I am glad to hear that, but in a discussion we had a while ago you did not agree that the forces of an electron never go to infinity. I maintained that there is no singularity and that blackholes are full of mythology and that any force (gravity etc) is considered at the centre of the mass/particle ant that that is its max value. Can you remember?
 
@user157860 I don't remember that. Do you have a link?
 
@JohnRennie, no, it was long ago, but if you wish we can go back on that sometime
 
Morgen
@JohnRennie It's certainly hard to justify in an instrumentalist manner
The dial doesn't go all the way to $\infty$
 
@user157860 I don't think anyone really believes there is a singularity at the centre of a black hole because we expect some theory of quantum gravity to eliminate the singularity.
 
@JohnRennie, glad to hear that
...you changed your mind
 
8:14 AM
@user157860 I doubt it, since I don't think I have ever believed there really was a singularity at the centre of a black hole.
Aug 12 '18 at 6:40, by user157860
@JohnRennie, and that, as you explained, because it is near the singularity, and that has infinite force, right?
This discussion?
 
Azathoth is at the center
 
In an ideal universe my NEW SUPERFAST CPU is arriving this morning.
 
@JohnRennie How much do you trust Leibniz
 
@JohnRennie, right-o
 
@user157860 We're talking about the event horizon there aren't we? Not the singularity at the centre of the black hole.
 
8:54 AM
Hm
If $f$ is unbounded on an interval of compact closure
 
I am reading "On the Electrodynamics of Moving Bodies" By A. Einstein (1905). On the 3rd page, after defining A time and B time, he talked about synchronization of two clocks. What does he mean by synchronizing clocks A & B by putting condition that tB-tA = tA'-tB ?
 
Are all of its derivatives unbounded
@Paṇḍyā That is the Einstein convention of synchronization, by which mean you can assign a time value to faraway events
 
@Slereah is it a big deal if someone creates something that is GR locally but totally not GR globally?
 
it can be proven (Weyl proved it a while ago) that the Einstein synchronization means that any two events occuring at the same time are spacelike-separated
and therefore not causally linked
@MoreAnonymous Depends what you mean by that
 
You can tweak the parameters of this model extend and how big is local and how large is global
So essentially I can recover GR in as a initial value problem
one moment
 
9:00 AM
@Slereah I don't understand why suddenly light rays came into picture for synchronizing clocks?
 
@Paṇḍyā One of the assumption of special relativity is that the speed of light is invariant in all frames of reference
Therefore it can be used to measure quantities independently of the frame
This idea stems from the Michelson-Morley experiment which implies that the (two-way) speed of light is invariant
 
@Slereah back! let's say I use the ADM formalism's equation of motion. Then I can make this local GR versus global not GR game
 
How do you differentiate local v. global
 
Ah .. its like this if I essentially have a system descibed by $dy =dx$ then that holds in my version too it's the $y = x +c$ where I'll disagree
Where by dx I'm thinking of some version of $\delta x \sim \delta y$
Got a meeting in 20 minutes. Not sure I can explain it that quickly without compromising on quality of discussion. Is it interesting?
In $\delta x \sim \delta y$ I'm thinking of this in the sense of $\delta x$ and $\delta y$ is small. I'm not even sure which of the axioms I'm relaxing among: physics.stackexchange.com/questions/164598/…
Note: I can adjust the parameters back to give you the same thing again.
Maybe some notion subtle notion of topology?? Dunno
 
9:24 AM
Meeting postponed! got 1 hour 20 minutes
Okay I thought about it. It's this one I'm relaxing: "the idea is that General Relativity is successfully described by a Pseudo-Riemannian Manifold"
 
Do you mean pseudo-riemannian or lorentzian
 
9:43 AM
"A semi-Riemannian manifold, is a differentiable manifold with a metric tensor that is everywhere nondegenerate." - wiki.

I dont think my manifold is differentiable in the tradional sense of the word. But I can relax the parameters to make them both mean the same thing
When I do so I get my version = GR
 
10:00 AM
@JohnRennie, we had several conversations, you were explaining the relativistic formula for gravity. I'll try find it
I think it was in July
let me know
 
This?
Jul 26 '18 at 6:05, by user157860
@JohnRennie, Hi John, if you please, there are a couple of things I'd like to ask you.
 
10:39 AM
@DanielSank hypothetically, if any high-profile papers on quantum vs classical computing by the Google group were to come out in the reasonably near future, my guess is that you would be a coauthor
Is that guess crazy?
If it isn't, though, congratulations!
 
@EmilioPisanty the recent announcement of the big QC calculation?
 
TDIYGGHKOBMOCC
 
10:55 AM
LaTeX user shortcuts are a real find
 
11:07 AM
That girl Greta Thunberg, I still don't understand what exactly she wants
She complains how adults are ruining her future, blah, blah, blah, but in the end she doesn't explain what she wants from them
 
@EmilioPisanty I think we all know that such a guess would not be unreasonable. I am allowed to say that the work was inadvertently leaked, and has been accepted by a peer-reviewed journal.
@NovaliumCompany She wants the leaders of humanity to take our existential threat seriously.
It is not her job to propose a specific plan of action. She's a child.
 
@bolbteppa The ones I tend to do a lot are \h for $\frac{1}{2}$ and \i for $\int_{-\infty}^{\infty}$
 
How are the leaders supposed to fix those existential threats? All I can think of is replace internal combustion engine cars with electric.
 
Also a lot of shortcuts for like
Script-related things
ie \SU2 for $\text{SU}(2)$ or \su2 for $\mathfrak{su}(2)$
 
What examples of existential threats are there?
 
11:13 AM
@NovaliumCompany False vacuum decay
Strangelets
Thunderbolt singularities
 
... these are not environmental problems lol
 
I would say the destruction of the universe is bad for the environment
4
 
and how the hell does she expect them to fix that
 
Well I'm guessing she is more interested in global warming
 
plus, aren't many leaders already working towarss environmental change? Elon Musk specially
 
11:16 AM
Elon Musk isn't the king of Mars yet
 
Maybe implanting chips in our brains will allow us to think of better solutions
 
I'm eating chips every day and so far nothing
 
Transcending humans cognitive abilities is the best investment in my opinion. Being smarter will allow us to solve problems faster and fix the holes in our sinking ship
@Slereah U must be pretty chubby
 
It's a joke
har dee har har
 
@Slereah mine too
maybe AI can tell us how to solve threat problems
 
11:20 AM
We already have intelligence and we know what must be done
We're just not doing it
 
@Slereah Our current intelligence is probably nothing to what the future holds
 
Intelligence tells you know to solve problems, it doesn't change your motivations
 
this is what your current intelligence tells u
 
Well, so does yours :p
 
yep
I wanna work at Neuralink (or similar) so baaaad
 
11:26 AM
I hope u like chemistry
i tried reading up on neurology but it's all potassium ion flow and whatever else
 
11:39 AM
This is the user tag thing:
16
A: Does TeXmaker have the ability to make custom user commands?

juliohmDefault shortcuts can be edited in Options -> Configure Texmaker -> Shortcuts. Texmaker also allows custom snippets of text to be inserted in the document with shortcuts, this functionality is known as User Tags in the User menu. Goto User -> User Tags -> Edit User Tags and define a tag with th...

Those \h etc shortcuts have the problem of not translating to other documents without the preamble redefinitions
 
well sure
but if you write a long ass document and reuse those all the time
It is quite useful
Oh also
\R for $\mathbb{R}$
 
12:19 PM
The danger is if you want to send the code to someone or re-use it without the shortcuts
Which has happened to me
You could use the tag shortcut with the @ to fast-track \mathbb and \text and \mathfrak! This is a massive efficiency find
 
I also use snarxiv to pre-generate papers
 
The last time I tried it I ended up below undergrad :\
'3 out of 4 (75%) — 1st year grad student' runs in victory
 
Let's see what I can do
Snarxiv's pretty hard because some of those really do sound like proper papers
21 Correct out of 25 Guesses (84%) — 2nd year grad student
Whew
 
12:36 PM
a) Of Bounces, Branes and Bounds
b) Firewalls
come on...
oh my god
Of course B was WRONG :\
An axriv vs vixra would be easier than this randomly-generated one
 
@bolbteppa and more hilarious
 
1:20 PM
@Slereah and sodium ions
@Slereah neurology I believe is much easier than qm and relativitiy
 
1:43 PM
@NovaliumCompany it is different certainly
 
@DanielSank nice :). Looking forward to reading the publication. It's a shame about the leak and the uninformed press.
and I know how frustrating it is to be under an "I'm allowed to say..." ;-)
 
I only heard about the publication via Scott Aaronson's blog, and he's being reasonably circumspect about the details
so I'm going to try to resist looking up the info on what was leaked
 
2:48 PM
Why can, t two graph cannot intersect in constant according to wein law, is there any reason related to thermal energy
 
3:06 PM
@yuvrajsingh Wien's displacement law?
 
@JohnRennie yes
@JohnRennie thank you, after posing it I search on stack exchange I found the answer.
@JohnRennie I have one more question regarding relativity
 
3:22 PM
@yuvrajsingh yes?
 
4:12 PM
Is it true that general relativity is applicable to all accelerated frames @JohnRennie
 
@yuvrajsingh you don't need GR to handle accelerating frames. Special relativity is fine for accelerating frames.
 
I mean some some say special relativity corrected the Newton law is it right
How
@JohnRennie
 
@yuvrajsingh You mean Newton's laws of mechanics? The first law, second law and third law?
 
No no Newton law of universal gravitation @JohnRennie
 
General relativity corrects Newton's law of gravity, not special relativity.
 
4:18 PM
@neeton law is a special case of general relativity when force is weak am I right sir
 
@yuvrajsingh yes. I have an answer that explains how we get Newton's law as the weak field limit, though it's a bit mathematical.
 
@JohnRennie So if one says that general relativity is an extension of special relativity it possibly means that the equations of motion of a testbody look like the equations of special relativity in the right limit. If you state that Newtons law of gravitation is a special case of general relativity, you are stretching the fact, that in the right limit the 'creation' part of general relativity looks like Newton's gravitational potential.

So to put it very short and colloquial, you are looking at different sites of an equation in these two statements.
 
Yes, I guess you can put it that way.
30
A: How does "curved space" explain gravitational attraction?

John RennieIf you have a look at my answer to When objects fall along geodesic paths of curved space-time, why is there no force acting on them? this explains how on a curved surface two moving observers will appear to exprience a force pulling them together. However two stationary observers will feel no fo...

 
Apparently Hilbert once said "Physics is too hard for physicists"
 
This is the answer where I show how you get Newton's law as the low field limit in GR.
 
4:24 PM
@JohnRennie a request if you are I can ask
 
@yuvrajsingh yes?
 
I have a lot of doubt on this topic can you assign a day where I can discuss my all doubt, @JohnRennie
 
@yuvrajsingh we can chat any time, but realistically you're not going to get much out of a conversation about general relativity without sitting down and learning it properly.
 
@JohnRennie I have no good content so from where should I read it
I already reading stack exchange answers
Is it right
 
You won't learn GR from Stack Exchange.
You need to sit down with a good book. But be warned it will take weeks to get even a basic knowledge of it.
 
4:32 PM
I am ready
@JohnRennie please suggest me a book
So that it worth my time
 
Sean Carroll's book seems to be popular, and I'm fairly certain he has a freely downloadable version.
Or his free notes are here:
 
OK, @JohnRennie please beer with me, for a weak, for some small doubts
 
By all means have fun reading through the book, but bear in mind you don't yet have the maths to understand large parts of it. So don't be too dismayed if you find it hard going.
 
@JohnRennie so is there any full pdf of book
 
@yuvrajsingh I can't comment, but I'm sure there will be copies floating around the Internet. I don't have an electronic copy.
 
4:48 PM
OK no issue thank you for your time @JohnRennie
 
shoop whoop
 
I don't understand, in the American revolution, Spain, France and Britain captured the major territories. After that France gave up all their territories and Spain gave up Florida. After that followed the war and conflicts between the native Americans and British, but where to these "Americans" came from? Everything in the east should be Britain?
 
wha
 
@NovaliumCompany They were. That was a while ago :-)
But you don't mean the American revolution. That normally refers to the war of independence against the British.
 
when the colonies rebelled
 
4:56 PM
They were revolting.
 
What's the technical difference between rebellion and revolution...success?
 
(Get your old jokes here. Form an orderly queue.)
2
 
revolutions succeed and rebellions are put down?
 
@JohnRennie If they were Brits, why did they fight the Brits in Europe? I mean, this is one country. Maybe the European Brits laid the taxes to the American Brits and the American Brits got pissed and so on? They kinda split?
 
US wanted independence from Britain mainly, at least on paper, due to taxation without representation
 
4:57 PM
@NovaliumCompany it's a long and complicated explanation. You need to read a history book. A few comments here aren't going to do the topic justice.
 
@JohnRennie I'm just getting over the most important historical events. I have no desire to know the details and the "long and complicated" story, just over the top.
 
@NovaliumCompany then you will not understand them.
 
Britain tried to tax the colonies in America, America and Britain got into some fistycuffs then America became it's own country.
babam
 
240 years later America got Donald Trump. There's progress for you.
 
John Rennie for president
 
5:02 PM
Mind you, we got Boris Johnson so it's far from clear who came out worst.
 
well I dunno if you can blame the American Revolution on DT...
but maybe
 
So the Brits owned that part of America but like, partially. The people there wanted to establish themselves seprately?
Simply said, they were brits, but they wanted to establish themselves as a seprate country and split from Britain?
@JohnRennie Cmon, how hard could it be?
 
The Brits owned the colonies fully, but the colonials started to see themselves as separate from the Brits. The colonials eventually wanted independence.
 
@JohnRennie What do you mean, its not American Revolution. I'm talking to the part where the declaration of independence was signed and when Washington was elected as first president
 
Of course not all colonials wanted independence, but enough did that there was a war fought over it
wat
 
5:11 PM
@enumaris thank u <3
 
The Declaration of Independence was signed in 1776, George Washington wasn't elected president until 1789
there's a lot of history that happened in the 13 years in between
like...the whole war itself and the whole confederation stuff...
 
My only source of this is OverSimplified yt channel, dont blame
"But you don't mean the American revolution. That normally refers to the war of independence against the British." That confuses me :P
 
I'm not sure what you were referring to
 
5:35 PM
nvm I think I got it
 
5:51 PM
Reading history is hard for me. Watching videos with visualization is much better. I have photographic memory
 
Like Sheldon?
 
vzn
6:37 PM
lol yep congratulations, an esteemed colleague made the bigtime... Research paper claims Google has achieved 'quantum supremacy' - a milestone in computing after their quantum processor performed a 'calculation in three minutes and 20 seconds that would take a state-of-the-art supercomputer 10,000 years' dailymail.co.uk/news/article-7490191/…
 
7:02 PM
@vzn I read that
 
I have achieved quantum supremacy
 
@Slereah No, Daniel Sank achieved quantum supremacy. Only, he's probably not allowed to talk to us about it or like, acknowledge it happened until whenever the big press conference is :D
 
@DanielSank Give us the quantum secrets
Although honestly I don't think I could stay awake talking about engineering :V
 
does anyone here like geometry
 
"geometry" is pretty broad
I like geometry fine
 
7:14 PM
welp i'll just ask, for a given inner product space, the conventional definition for the "angle" between $x$ and $y$ is $acos(\frac{x \cdot y }{|x| |y|})$, right?
 
If it's Riemannian, sure
 
welp i'll just use dot product notation
@Slereah ...ok
 
You can define angles for Lorentzian spaces but then it's more complicated
 
so my question is, is the "high school definition" of arclength over radius (for a given circle) equivalent to this definition, or is it specific to $R^n$?
 
This is a local definition
You can see that by considering the arc length of a circle on the sphere
The angle is $2\pi$ but the circumference isn't $2\pi R$
 
7:17 PM
ah, that's true
so it's only for Euclidean space right?
 
Yes
 
cool, thanks
 
Well you may remember that conformal transformations preserves angles
Although on the other hand
It doesn't preserve arc length
It's fairly easy to see for angles
 
What’s happening
 
$$\theta = \arccos(\frac{g_{ab} x^a y^b}{\sqrt{g_{ab} x^a x^b} \sqrt{g_{ab} y^a y^b}}) \to \arccos(\frac{\Omega^2 g_{ab} x^a y^b}{\sqrt{\Omega^2 g_{ab} x^a x^b} \sqrt{ \Omega^2 g_{ab} y^a y^b}}) = \arccos(\frac{g_{ab} x^a y^b}{\sqrt{g_{ab} x^a x^b} \sqrt{g_{ab} y^a y^b}})$$
I think the arc length is basically $\times \Omega^2$ for a conformal transformation, though
errr
more $\Omega$
Since $l = \int \sqrt{\Omega^2 g(\dot{x} \dot{x})} d\lambda$
 
7:39 PM
Found an incredible straightforward way to derive those infinitesimal conformal transformations, before this hadn't found one explanation which doesn't involve some trickery
 
doesn't Di Francesco have a nice one
 
Why does he do those random steps with applying the derivatives
'Lets take a random derivative of this insanely complicated equation as a way to solve it'
 
@bolbteppa is that not what physicists do with their spare time
 
I mean really
How else do you solve equations
 
They don't have spare time
 
7:54 PM
You just apply random transforms until something work
 
I think the good ones find the logic underneath the fluff runs
 
One idea I had once was just to make a brute force PDE solver
ie you start with a constant
And then you add more and more terms
In a tree-like fashion
 
Physicists like finding new equations not necessarily solving them :p
 
One tree branch is multiplying by a variable, another is applying elementary function, another is to sum with another branch
etc etc
 
Even applying that to ODE's is doomed
 
7:57 PM
It would be terrible at speed but I suppose that, unless it was a special function, it would eventually find it
 
this makes me think of differential galois theory (which I've never managed to actually learn)
it's basically supposed to be for ODEs what Galois theory is for polynomials
 
Yeah
I really wanted to learn it at one point too
 
I think I'd have to learn Galois theory first, though, and that's not altogether appealing to me
 
8:10 PM
Yeah polynomials aren’t very interesting...they’re social constructs
There are no polynomials in the night sky
 
vzn
8:37 PM
in The Classical Channel, 24 hours ago, by Scott Aaronson
posted on September 23, 2019 by Scott

You’ve seen the stories—in the Financial Times, Technology Review, CNET, Facebook, Reddit, Twitter, or elsewhere—saying that a group at Google has now achieved quantum computational supremacy with a 53-qubit superconducting device. While these stories are easy to find, I’m not going to link to them here, for the simple reason that none of them were […]

 
Is there a quantum version of Norton's dome
I'm not sure if that would be self-adjoint
Potential would be... $V(r) = r^{\frac{3}{2}}$
So $$\hat{H} = \frac{\hat{p}^2}{2m} - \hat{r}^{\frac{2}{3}}$$
Better check Hall for properties on self-adjointness
Ah, the condition is that $A + B$ is self-adjoint if $\text{Dom}(A + B) = \text{Dom}(A ) + \text{Dom}(B)$
not sure that helps
Apparently $V$ needs to be a sum of some $L^2$ function, a bounded function and a non-negative locally square integrable function
I think it's not self-adjoint, though flipping the sign does make it so
I should check that tomorrow
 
9:04 PM
@Slereah that function is locally bounded so there’s literally no problem
 
But it's not bounded or non negative
Although maybe locally bounded is enough
I dunno
But since flipping the sign makes it fine, it's probably not a big deal
I don't think lack of determinism classically has terrible consequences quantumly
Though it may be interesting to solve it
It's probably doable rly
Not a hugely complex pde
 
@Slereah locally bounded implies locally L2
 
Alright
I'm guessing the "particles go off to infinity" type of bad classical systems aren't self adjoint though
I think they all have terribly unbounded potentials
 
@Slereah I'm not sure what you're on about here - the $x^2$ oscillator potential is certainly unbounded but a perfectly fine quantum system
 
@ACuriousMind not locally tho
I mean I guess that neither is 1/x for Coulomb
I dunno
I would guess that a system that pathological wouldn't be self adjoint though?
Since the whole "particle going off to infinity" would probably be ~ a loss of unitarity in QM
 
9:15 PM
@ACuriousMind this German physicist keeps saying “irgendwie” in English
 
@Slereah Why? The reason classical determinism fails is that Norton's force isn't Lipschitz, but there's no such requirement in quantum mechanics
 
@ACuriousMind different system here
Thinking of the space invader
Ie $F = \tan(t)$ for instance
The non collision Painlevé singularity would be a better example but not quite as tractable
 
Classical reality is Lipschitz, take that math people with your monsters
 
Hm
I wonder if $F = \tan(x)$ would also be such a system
It also has unbounded acceleration and is easier to quanticize
Harder to solve though
 
Ok it’s a vocal tic
 
9:25 PM
hi guys
nvm my question got solved
 
Hm
$x'(t) = \tan(x(t))$ does seem solvable, but I don't know about $x''(t)$
 
o actually, I do have a question
normally, when we talk about measurements, we usually have some observable (hermitian operator) that we're working with
and then the measurable outcomes are its eigenvalues
however, sometimes physicists talk about "measuring in a basis"
and then they mean that they project onto the basis vectors
of course when we talk about an observable, we are also projecting (onto an eigenstate)
however, in the case of "measuring in a basis", is there anything to say about eigenvalues?
or could you talk about the expectation value, whatever that would be?
I guess my question is, if we could assign some observable to the act of measuring in a basis
 
9:45 PM
@Slereah Any measureable function of $x$ is itself a (densely defined) self-adjoint operator. So $\tan(x)$ certainly exists and has a well-defined, unique time-evolution by Stone's theorem.
 
Hm
I wonder what happens to particles in such systems
 
@ShaVuklia When you're "measuring in a basis", you're measuring any observable that has the basis vectors as its eigenvectors with distinct eigenvalues.
 
whoop, was just writing what ACM wrote...
ninja'd
 
omg!
that makes so much sense
 
@ACuriousMind Wait a moment
$V = -x^4$ isn't self adjoint
Actually
There is a QM system with a non-self-adjoint Hamiltonian I remember
Electron around the Schwarzschild metric!
though that is hardly classical
As classical as QM can be, of course
 
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