@Tobias Let $G/\sim$ be the set of conjugacy classes, and let $\chi_1, \dots, \chi_c$ be the irreducible characters, then consider the map from $G/\sim \to \Bbb C^c$ via $[g] \mapsto (\chi_1(g), \dots, \chi_c(g))$, extend this linearly to an isomorphism $\Bbb C^{G/\sim} \to \Bbb C^c$ (as the $\chi_i$ are linearly independent).
Then because of $\chi_i(g^{-1})=\overline{\chi_i(g)}$, this is $\Bbb Z/2\Bbb Z$-equivariant, where the action on the LHS is by inversion and on the RHS is by complex conjugation