6:55 AM
2 hours later…
8:32 AM
They use $\tan^{-1}A=\cos^{-1}\frac1{\sqrt{1+A^2}}$. Which is derived from $\cos x=\frac1{\sqrt{1+\tan^2x}}$.
It is true that $|\cos x|=\left|\frac1{\sqrt{1+\tan^2x}}\right|$. But without absolute value this is not true for each $x$.
Possibly you might decide noty to worry about the signs and solve this with absolute values. And then throw away the solutions where the signs are opposite.
BTW this would be more suitable fro Mathematics - either the main chatroom or some of the other rooms. (Possibly Basic Mathematics.)
9:03 AM
Some related question on Mathematics: Simplifying a trigonometric expression: $\cos(\tan^{-1}x)$ and Simplify $\sin^3{\left(\cot^{-1}{\left(x\right)}\right)}$
The WolframAlpha links are simply to show that the functions we are talking about have different graphs. (They are equal only for some inputs.)
The syntax such as
\frac1{\sqrt{1+\sin^2x}
and similar is MathJax/LaTeX. If you plan to use Mathematics site, you'll need it.
ust a reminder - to read MathJax/LaTeX in chat you can use the bookmarklet mentioned in this post on meta or go directly to robjohn's website: math.ucla.edu/~robjohn/math/mathjax.html
2 hours later…
11:16 AM
Jun 25 '13 at 4:53, by Mariano Suárez-Alvarez
To get MathJax (LaTeX) working in this chatroom, follow these instructions.
BTW MO reached 50000 question in May 2014: chat.stackexchange.com/transcript/9369/2014/5/4 Now it is over 100k.
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