« first day (2347 days earlier)      last day (2585 days later) » 

6:09 PM
0
Q: Time derivatives of time

trabladorrI have to preface this question by stating that I am a Physics enthusiast, and don't actually know enough for this question. Is there any circumstance where the second derivative of time is definable, (i.e. the rate of change of the rate of change of time) and what would its units of measuremen...

A very strange question
But I guess, for the relativistic case, you will be talking about about the 4-velocity
 
@ACuriousMind Since you've gone and took my words out from under me, can I ask you to put some strikethrough on that (now deleted)?
Also, if I retract a flag, is it shown on the post?
 
@EmilioPisanty Sure
 
@ACuriousMind didn't seem to take
shows explicit <s>s
 
Yeah, I can't seem to figure out a way to produce a strikethrough in comments
I just deleted the "now deleted", that fine?
@EmilioPisanty Depends on what you mean by "shown on the post". It is in the flag history, but won't be shown directly unless there's another pending flag on the post
 
@ACuriousMind (̶n̶o̶w̶ ̶d̶e̶l̶e̶t̶e̶d̶)̶
@ACuriousMind as in, did it show on the dashboard when you addressed the live one
 
6:22 PM
@Runlikehell So in summary, we groupthink too much and worried more about hits than selection criteria. Given that similar issues have been observed also in chemistry, I guess it is an important issue
 
@EmilioPisanty Yes - and it confused me for a bit until I had figured out you had retracted it yourself
 
@ACuriousMind I'm pretty sure it's new behaviour
 
The ability to retract a flag? Or that old flags are shown?
 
@ACuriousMind retracting flags, I think
but then I don't usually try to
I think I did at some point and it didn't look like this
 
86
A: Cancel misclicked flags

Michael StumThis is now completed and as of August 2016, live network-wide. Note that if you're a moderator (and thus your flags are authoritative), there's no retracting. Also, close flags get converted into close votes if you have enough rep, and can be retracted through the existing "retract close vote" ...

 
6:25 PM
but, really, I've got no idea at this point
 
^Been live for almost a year, apparently
 
Personally, my way to counter groupthink is I tend to look for articles very remote from the citation map, and I generally don't care much about whether the author is famous or not (unless I need to learn something and need some textbook like reputable source)

The thing I cared the most in a journal article is how relevant the results and the methods are, and whether they can be used and cross checked in our research
(NB I hate that edit timer, this should belong to the message above)
 
@ACuriousMind eight months sounds reasonable
 
Can you retract flags in chat?
Or is there some time limit.
 
@skullpetrol I don't think so
 
6:27 PM
Guys, could someone explain to me why the electric charge within a cylinder is zero? I tried to calculate the electric field, and I could apply Gauss' law, but I didn't understand why the enclosed charge was zero if we take a Gaussian surface within the hollow cylinder (with infinite height)
 
Flag me :-)
 
@ShaVuklia take a point charge, draw a cylinder around it, charge within the cylinder is not zero. Result is false, or rather, you should clarify exactly what you mean.
i.e. what do you mean by "hollow cylinder"?
 
@EmilioPisanty The hollow cylinder itself is uniformly charged
 
@ShaVuklia as in, you have a hollow cylinder that's uniformly charged, and there's no charge anywhere else in the universe?
 
I don't understand why the field lines go radially outward, but don't go radially inward or something similar
yes, we're only considering the infinitely long hollow cylinder
 
6:30 PM
@ShaVuklia so there you have it. There's no charge within the cylinder because you're thinking about a situation with no charge within the cylinder.
 
I don't understand. We do have a charge outside of the cylinder, then why not inside?
I've heard that some things cancel
 
@ShaVuklia you could have charge inside the cylinder
then you'd have charge inside the cylinder
 
oh right
electric field*
wait
I've confused a lot of terminology
Why is the electric field caused by the uniformly charged cylinder zero?
within the cylinder
oh
ah
I'm really confusing charge and electric field
 
it's obvious that the enclosed charge is zero
thanks @Emilio
 
7:14 PM
@Secret Can't this be damaging science and physics too much? What do you think?
 
@BernardoMeurer did you watch the Kodak Black review?
 
7:37 PM
@Secret In doing that you will inevitably encounter a higher than average level of poor papers. So you need a strong bullshit filter in the domain under consideration.
For myself I don't trust my bullshit filters outside a select group of sub-disciplines that I've studied in considerable depth.
In particular I don't trust my filters in any area of fundamental theory because I don't do those areas.
In other words: you have to become at least a little expert in those areas to be able to sort out the promising against-the-tide ideas from the not-so-promiing, outright-wrong, and not-even-wrong ones.
3
 
Good point.
 
@skullpetrol it's cold
what do I do
 
Put on a jacket.
 
I did
 
Try a sweater too.
 
7:47 PM
It's really my hands that are the issue
 
Once your core warms up you'll be fine.
Also, keep moving.
 
8:13 PM
@yuggib Are you around? I have a pseudodifferential operator question.
It might just be a series of typos, I'm not sure
 
8:28 PM
@skullpetrol The $\psi$do $P$ is given by the symbol $p(x,\xi,y)$ three or four times, then he switches to $p(x,\xi)$ in the same proof, which makes more sense.
 
Okay.
 
8:42 PM
@skullpetrol beeyumbole
 
Anyone here happen to know which system in-text citation references like [XYZ00a] follow? Can't figure out what it's called
 
Always @0celouvsky or at least try
 
@ACuriousMind relevant
 
@LegionMammal978 You get it from BibLaTeX as style=alphabetic, no idea if it has another name
 
thanks
 
8:47 PM
@ACuriousMind If $X$ is a Hilbert space, and I renorm it with an equivalent norm, does that norm also give/arise from an inner product?
I doubt it does.
 
Beeyumbole, beethankful, beeyourself
The 3 bees
 
@0celouvsky No - consider endowing a finite-dimensional space with an equivalent p-norm for $p\neq 2$.
 
@ACuriousMind Is it obvious that those don't come from an inner product?
 
@0celouvsky Yes
 
I guess one would have to compute the parallelogram law.
 
8:50 PM
They don't satisfy the parallelogram law, exactly
 
@ACuriousMind So how are you supposed to detect if you can get an equivalent norm arising from an inner product?
 
I don't think you are supposed to detect that
 
ok
I didn't think so
 
Still cold?
 
yes
but I'm learning about $\psi$do's on manifolds so it's all good
it's really quite technical, not nice at all
no boundaries so that makes everything easier
 
9:00 PM
beeyumbole
 
I am very yumbole
this book is yumboling me
 
Who wrote it?
 
Looks like a yumbole guy
To rest on the blue of the day, like an eagle rests on the wind, over the cold range, confident on its wings and its breadth.
 
My plan is to give a good skim to figure out what I need to know, and pick that up from Hörmander and Grubb
Then come back later and really understand it
There's a nontrivial number of typos which is quite annoying
 
9:06 PM
No errata yet?
 
hmm
there appears to be a second edition
he has the first edition on his website
strange
and I got the first edition from the library
russian servers to the rescue
 
Dump the first edition.
 
yeah but if I'm reading a large part of the book I want to read a physical copy
the book is out of print, cheapest copy appears to be $211
 
Would you rather struggle with typos?
 
wow the second edition is completely restructured
@skullpetrol I found a used copy for $70
should I trust it?
damn, seller has one star
 
9:20 PM
Look around for awhile.
Buyer beware and all that.
Also ask around.
 
Ask?
 
Your profs
 
my advisor has an old copy
same one I got from the library
He didn't know there was a second edition
 
Ask him what he thinks.
ie advise ;)
 
@ACuriousMind When people say PD is a perfect pairing $P:H^q(M)\otimes H_c^{n-q}\to\Bbb R$ are they channeling their inner physicist and mixing up $\times$ and $\otimes$?
I thought it was just a typo when I saw it in Bott and Tu way back when
But now I'm seeing it again in the context of Sobolev spaces $H_s\otimes H_{-s}\to\Bbb C$
 
10:03 PM
@BalarkaSen Are you around?
 
i am
no they aren't mixing up $\times$ and $\otimes$. PD is billinear
 
@BalarkaSen What's a graded vector bundle?
 
@0celouvsky Whether you say that the pairing is a linear map on $\otimes$ or a bilinear map on $\times$ is equivalent.
 
I can guess but I don't know.
 
@ACuriousMind Yeah I just remembered the universal property.
 
10:09 PM
Glad to be of no help. I have too many chats open on my tab so I'm chickening out.
 
@ACuriousMind The question defaults to you.
 
@0celouvsky Well, I'd say it's just a bundle whose fibers graded vector spaces instead of ordinary vector spaces
 
10:35 PM
@ACuriousMind How about $V=\oplus_j V_j$?
 
What about it?
 
would you call that a graded vector bundle?
that might be the same thing you described assuming the fibers are all aligned "the same way"
 
@0celouvsky Well...yes, it's graded in the sense that you might call the elements of $V_j$ "elements of degree $j$"
I mean, a graded vector space is nothing but the direct sum of its degrees
 
" I've never taught anything as high level as matrices" wow — Rüdiger yesterday
@Rüdiger yeah, it's positively-definitely frightening... — Mehrdad 17 hours ago
↑ that's a fantastic pair of comments
 
@Danu Amazing: For $(P,V)$ a $d$-th order $\psi$do elliptic complex we always have $L^2(V_j)=N(\Delta_j)\oplus R(P_{j-1})\oplus R(P_j^*)$. Hodge's theorem is but a tiny sliver of what's out there!
 
10:46 PM
@0celouvsky wtf is a $\psi$do?
 
@EmilioPisanty It's a hair-do, but for your $\psi$
 
@ACuriousMind ah, figures
 
Jokes aside, I think it's his abbreviation for "pseudo"
 
@ACuriousMind surely not
that'd be stupid
it's not even an abbreviation
 
Something similar, at least, maybe for "pseudo-differential". I dunno
 
10:49 PM
$\psi$do, eight characters, `pseudo', six characters
unless its pseudo differential operator, in which case it's level-11 cringeworthy but I guess it does count as an abbreviation
speaking of which
In mathematical analysis a pseudo-differential operator is an extension of the concept of differential operator. Pseudo-differential operators are used extensively in the theory of partial differential equations and quantum field theory. In simpler terms, the definition of a pseudo-differential operator depends on the Fourier Transform. This topic is actually covered long after the introduction of the Fourier Transform. The Fourier Transform is covered at varying levels of rigor beginning with a cursory introduction in a standard second year differential equations course focusing on applications...
that's one of the weirder intro paragraphs in a Wikipedia article I've seen
>
In simpler terms, the definition of a pseudo-differential operator depends on the Fourier Transform. This topic is actually covered long after the introduction of the Fourier Transform. The Fourier Transform is covered at varying levels of rigor beginning with a cursory introduction in a standard second year differential equations course focusing on applications and progressing to a rigorous introduction often found in advanced undergraduate to beginning graduate courses in Fourier Analysis which relies on the use of mathematical analysis rather than exclusively univariate or multivariate
how about actually talking about PDOs rather than at what level and amount of rigour the FT gets taught?
 
That's...pretty weird
 
11:52 PM
@EmilioPisanty it is
 

« first day (2347 days earlier)      last day (2585 days later) »