In between reactant and product formation, a unstable substrate is formed and hence for an reaction to proceed, the minimum energy required is E(Subtrate)- E(Reactant) , NOT : E(Product)-E(Reactant)
Here you have to find the unstable substrate when the crate is overturned. Then Work required will be : E(Subtrated analogical position) - E(Reactant analogical position ie E(0.3) )
@Koolman Yeah, but it's just cool to see so many people that are around the same age, from the same country and taking the same engineering test, working on an SE chat
I'd never find someone on SE who I could've studied for the ACT with
I know the meanings but I forgot what they are called
@MadhuchhandaMandal What's P(E)? r(i)?
@SirCumference ACT cannot be compared with JEE. They are at difference scales. It's like comparing undergraduate studies with graduate studies. 10th grade students from India can score 2400/2400 in SAT and 36/36 in math and science section of ACT.
SAT = Indian 10th grade syllabus
AP = Indian regular high school syllabus
More than half the population will score 5/5 in Physics, Chem, Calc, etc. AP tests (in my opinion)
@YashasSamaga P(E) is probability that E (ie hitting of rod by stone) happens
r(i) was not intended it should be read as : Graph of P(E) vs r is marked as first (i) graph and Graph of P(E) vs w is marked as second (ii) graph , so that you can compare it with the options provided and find the correct option among ABC&D
