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12:00 PM
Closed geodesics should not be a problem unless it is null or timelike, (based on my half baked GR understanding)
But good rhyming at the 2nd 4th stansa
 
Closed geodesics are necessarily CTCs because they return to spacetime points they have already passed through
 
Ah I see
@JohnRennie btw are you good at wavefunctions of multiple variables, because I have a conceptual question in quantum arise when I am trying to study my DFT textbook?
 
@Secret no
 
uh ok, I guess I need to wait for the quantum guys to get on
 
user228700
@JohnRennie I don't get it at all ._.
 
user228700
12:11 PM
Also, I decided to ditch the "epic mail" plan. That e-mail id exists purely for questions, suggestions and corrections so I decided not to spam them with an elaborate "U have changed my life" letter.
 
user228700
This is what I wrote:
 
user228700
> I am not alone in feeling that of late there's been an acute shortage of poems at the beginning of the pod. Here I present to you one of my own poems (alright, it's not that short) in the hopes that you will consider it despite the fact that it's about friendship and love which are two topics about as far from the topic of death that one can get.
 
@JohnRennie you can have closed spacelike geodesics
 
@Kaumudi.H it's a general relativity joke. If you don't know GR you won't find it funny - actually if you do know GR you won't find it funny either.
 
$S^1 \times \Bbb R$ is all closed spacelike geodesics
 
user228700
12:12 PM
@JohnRennie :-P OK...
 
user228700
<insert poem>
 
user228700
> I'd be ever so grateful if you do choose to read it for I am an ardent fan of you both.
 
user228700
> Tuataras & Koalas, //both are inside jokes
 
user228700
> Kaumudi (cow-moothie)
 
@Slereah True. I was thinking of a geodesic as the path followed by a free falling observer so it would necessarily be timelike or null. But I concede your point.
 
user228700
12:14 PM
@JohnR: So yeah, that's what I wrote. Everything remains pretty much the same. Does it look OK?
 
Morning
 
user228700
@SirCumference Hey :-)
 
@Kaumudi.H Howdy. Ordered that book :)
No idea what to expect
 
user228700
@SirCumference Oh! That's great! I hope you like it :-) I ordered the T-shirt :-P
 
@Kaumudi.H I can't help feeling that of late there's been an acute shortage of poems at the beginning of your pod, so here I present to you a poem as a suggestion.

As for the author, well that's me. I can only hope that doesn't rule the poem out of consideration :-)
 
user228700
12:16 PM
Oh, u re-wrote everything .__. Was mine too weird?
 
u re-wrote everything - not really. It's your original post just tweaked.
 
user228700
And what about death? I gots to mention the thing about it being completely unrelated to death.
 
I wouldn't give reasons why they might choose not to consider the poem.
 
user228700
Hmm. OK, on second thoughts, I agree. He does tend to read other poems as well, from time to time.
 
user228700
@JohnRennie Why not tho?
 
12:20 PM
But your version is fine too. John Green probably gets deluged by stuff from budding young writers and since he'll be in a hurry he won't care too much about exactly what you write in the intro.
 
16
Q: How does one measure space-like geodesics? Or: What is the physical interpretation of space-like geodesics?

MarcIn general relativity, time-like geodesics are the trajectories of free-falling test particles, parametrized by proper time. Thus, they are easy to interpret in physical terms and are easy to measure (at least in principle). Is there a similar interpretation/measurement for space-like geodesics?...

 
Also you can have closed geodesics that are closed null curves :p
but no CTCs
 
user228700
@JohnRennie Yeah :-) Do I say "As for the author" after the poem?
 
Hmm, so I am guessing if I lay a hola loop on the floor that hola loop is a closed spacelike geodesic...?
because in my frame all points in the hola loop are spacelike separated from each other
 
user228700
Ooh, that'd be a great idea, to say that I was the one who wrote it after having made him read the poem first! :-P
 
12:22 PM
No
Spacelike geodesics are mostly gonna be straight lines
 
user228700
@JohnR: Thank God for the "Undo" option!! I accidentally hit "send" in the middle of editing! :-o
 
@Kaumudi.H I would say you're the author up front. You're asking John Green to devote his time to reading your poem, so be straightforward with him.
@Kaumudi.H Oops :-) Gmail?
 
user228700
@JohnRennie Sigh, OK. BTW, I doubt if John's gonna read it first. His asst, Rosiana (who's gonna get the inside joke at the end) will read it first.
 
user228700
@JohnRennie Yep!
 
@Slereah hmm, that cannot be closed unless the universe wraps around back to itself like a cylinder or a torus?
 
user228700
12:25 PM
@JohnR: The subject is "Short Poem: A suggestion"
 
user228700
That OK?
 
Dunno
 
@Kaumudi.H Is it for their podcast? If so you might want to say so in the title.
 
user228700
@JohnRennie OK, so the thing is, the e-mail id is used only for the podcast.
 
remember that an overworked assistance is going to be filtering through hundreds of e-mails looking for a subject that stands out.
"A poem to start your podcast"
 
user228700
Yeah, I know :-/ I suck at this though, which is why I headed over here seeking much needed help.
 
user228700
@JohnRennie But "Short poem" refers to the one that they start their podcast with.
 
@Secret a closed FLRW universe has the topology of a 3-sphere and has closed spacelike geodesics.
 
user228700
OK, maybe I'll make it sound a little less pretentious. How about "Suggestion for the short poem"?
 
Sounds good to me :-)
 
user228700
12:29 PM
Does it really?
 
@JohnRennie so I guess they are all great circles in FRLW?
 
@Kaumudi.H Yes. If short poem is a term they use then that subject seems perfect. Informative but brief and to the point.
 
user228700
@JohnRennie :-) OK. Thanks so much. It all sounds much better now that u've edited it.
 
@Secret yes, subject to a 3D meaning of great circle
@Kaumudi.H let us know how you get on
 
user228700
@JohnRennie U can count on it! :-)
 
12:39 PM
NB, regarding that spacetime I read in the arxiv, it appears that all CTCs are geodesics. Not sure what that will mean other than naively I suspect divergences everywhere
 
0
Q: Physics Stack Exchange website's User Interface

MasoudIf someone has suggestions for Physics Stack Exchange website's UI where/how or to whom he should make his suggestions?

 
Jim
@Secret caustics perhaps?
 
how was your pi day?
 
nothing much. My molecules DFT calculation is still not converging and I spend most of the time reading my DFT book to better understand DFT
 
12:54 PM
DFT?
 
Density functional theory. It's a quantum chemistry model on modelling chemical reactions and molecules
 
\o @yuggib
 
Basically it tries to solve for the electron density distribution in the molecule to predict chemical reactions and geometries
 
@skillpatrol o/
pi seems a very stupid number to celebrate on a day
 
@yuggib hi
 
12:56 PM
@0celo7 hi
 
@yuggib What's the domain of f(A) when you use the spectral theorem functional calculus? When f is bounded I think it's the whole Hilbert space
 
@0celo7 If it is bounded it is the whole Hilbert space, yes. If else it is still densely defined, but it may not have an explicit characterization
(apart from being the set of vectors such that $\lVert f(A) \psi\rVert <\infty$)
 
@yuggib what other options are there? Celebrate it when it is found to be in yet another formula? :-)
 
@yuggib Ok, so in general we just don't know?
 
@skillpatrol then why don't you celebrate $0$?
@0celo7 We don't know it explicitly, yes. We just know it is a dense domain. For example, if the function admits a power series expansion then the analytic vectors of $A$ are in the domain of definition of $f(A)$
 
1:01 PM
I had a dream about Obama
 
@yuggib , if given the $n$ particle wavefunction $\psi (\vec{x}_1,\vec{x}_2,\cdots,\vec{x}_n)$, thus the probability of finding any particle in some infintesimal volume is given by $\int |\psi|^2 d\vec{x}_1d\vec{x}_2\cdots d\vec{x}_n$ how to write the expression that gives the probability of finding $m$ particles in the infintesimal volume where $m < n$?
 
@yuggib analytic vectors of $A$?
Hmm, how do we know it's densely defined?
 
@yuggib hmm...good point, also -pi for that matter.
 
what about e day?
 
@0celo7 what did he do?
 
1:02 PM
feb 7
 
@Secret I was working somewhere and he showed up
 
e day is too...exponential :P
pi day is nice and round
 
hmm, ok. Probably just daily US stuff get dragged into your memory
 
@0celo7 you can find it on e.g. Weidmann's book
 
What about the Euler–Mascheroni day
@0celo7 did he take your guns away
 
1:05 PM
@yuggib I take it that it's not trivial?
 
@0celo7 yes, it's not completely trivial
 
@yuggib Specifically, suppose I have the 5 particle wavefunction $\psi (x_1,x_2,x_3,x_4,x_5)$ how to write in terms of $\psi$ the probability of finding any 3 particles?
 
the one for power series and analytic functions is reasonably "easy"
 
@yuggib well for the most part I only care about $e^{iA}$, right?
 
@Secret I hate combinatorics...there should be some correlated indicator function to average
 
1:07 PM
ok sorry about that
 
@0celo7 Mostly, but not only. You often also care about the square root, and the alike
@Secret no problem, it is just that I don't like it ;-P
 
@yuggib I'm looking in Chap 11 of Yosida
what does he mean by l.i.m.
 
We celebrate 0 everyday @yuggib but it means nothing to most people :P
 
@0celo7 it is probably the limit in the sense of distributions, or something like that
 
> Proof. Easy.
 
1:11 PM
The actual question arise from my DFT reading where they mention this bizarre thing called the reduced electron density matrix, and I tried to dump the question down to physics level in order to work out whether that matrix means the probability of finding all but one electron. It seems I might have the wrong conception, I guess I need to read again. Anyway, thanks for helping me to realise that to calculate that probaility is not as simple as leaving out some integration variables
 
@yuggib What's a Baire function?
 
In mathematics, Baire functions are functions obtained from continuous functions by transfinite iteration of the operation of forming pointwise limits of sequences of functions. They were introduced by René-Louis Baire in 1899. A Baire set is a set whose characteristic function is a Baire function. == Classification of Baire functions == Baire functions of class α, for any countable ordinal number α, form a vector space of real-valued functions defined on a topological space, as follows. The Baire class 0 functions are the continuous functions. The Baire class 1 functions are those functions which...
 
Oh, does Yosida use that weird $\sigma$-algebra generated by $G_\delta$'s
 
the Baire algebra yes
 
@yuggib if $A$ is bounded, then is $f(A)$ defined everywhere, or are there problems when $f$ is unbounded?
 
1:23 PM
@0celo7 Well, it depends what do you mean by unbounded. If it is unbounded in the spectrum of $A$, then you have problems. If it diverges at infinity, then there is no problem (since the spectrum is a bounded interval of $\mathbb{R}$)
 
Yes, makes sense.
Hall only talks about bounded functions, so I was checking.
 
They are the mostly used, but not the only ones.
 
Well any continuous function gives a bounded operator, so that's nice.
 
Anyways, if you want a nice problem to think upon is the following: has every bounded operator on a Hilbert space an invariant subspace that is not trivial?
I.e., given $T\in \mathcal{B}(H)$, $H$ Hilbert, does there always exist a subspace $\{0\}\neq H_T\subset H$ such that $T H_T\subseteq H_T$?
 
Yeah, I'm thinking.
 
1:28 PM
take your time, it is open since at least a century... :-D
2
 
@yuggib Just throwing this out, but what about a $\pi/2$ rotation in 2 dimensions?
 
@0celo7 in finite dimensions greater than two it is always true
 
Huh? What's the invariant subspace for a 90 degree rotation
Oh :P
 
it is also true for non-separable Hilbert spaces
 
strange
 
1:31 PM
yep, in Banach spaces, it is false
 
@yuggib Yeah, I thought I saw that in Conway
@yuggib He says C.J. Read proved it's false for $\ell^1$
 
@0celo7 I think the first proof is due to Enflo
 
@yuggib What about the shift operator on $\ell^2$ that sends $a_i\mapsto a_{i+1}$ for a sequence $(a_n)$?
I have trouble seeing what its invariant subspace could be
Ah, nevermind
Writing that down sufficed to see I was being silly :P
 
I think we have enough information to not just close this question for unclear what you are asking, but in fact, off topicness (asking about a personal model)
"Temporal gradient lead to the implosion of the proton star, setting free huge amount of energy and generating the universe in 365 days, which is equivalent to the orbital period of earth around the sun (6 days). Gravity emerges with the orbital period of the electron around the proton in all 9 planets of the solar system, is such that the moment of all the stars in the universe is the number of multiverses which is 1697. And the distance to to the stars is a tunneling to other universes..." Uh, that does not seemed mainstream to me, I am afraid this question will be closed for off topic-ness — Secret 1 min ago
Kinda amazed how bored I am. But basically, this question is a mix of astrology, mutiversal esoterics and numerology
 
@ACuriousMind ;-P
 
1:35 PM
@ACuriousMind $a_1=0$, no?
 
@0celo7 Yeah, every "space of sequences with first n entries zero" is invariant
 
@yuggib this is an exercise in Conway
Maybe I'll think about it
bye peeps
 
@heather did you figure out your problem?
 
If a question involves esoterics and astrology, I can still find out a way to suggest the OP to look for mainstream resources, but if it is numerology, than sorry its out
 
1:38 PM
Always remember that matrices are representations of a linear operation, and the matrix elements depend on the basis you're using.
You have to pick a basis and an order for that basis.
For example $$ \{ | 00 \rangle , | 01 \rangle, | 10 \rangle, | 11 \rangle \} $$
I'm on my phone so I don't know if I got the mathjax right.
 
Looks fine to me
 
^ thanks
So, Heather, once you have a basis you can construct matrices by thinking about how your operations (gates) act on each basis vector (state).
 
pardon my removed comment, i didn't know you were explaining it to her
 
For a density matrix of a pure state e.g. those density matrices which are projection operators $\lvert a\rangle\langle a\rvert$, if for the basis I choose such that the density matrix have off diagonal terms, are those off diagonal terms representing the coherence between the different basis elements as otherwise I don't know how one can make sense of "the state is coherent with itself"?
 
There's a formula for how to build two-qubit matrices from two one-qubit matrices. Note that you can only do this for operative which act on each qubit individually (I.e. not for entangling operations).
The formula is the kroner product.
 
1:48 PM
"A timelike path $f$ is said to have an interior corner at $t \in I$ if $t$ is a singular point of $f$, and if the corresponding tangent vectors to $f$ at $f(t)$ are oppositely directed"
 
@DanielSank You mean Kronecker product, right?
 
As an example suppose I have the following density matrix of the pure state:

$$\lvert a\rangle\langle a\rvert=\begin{pmatrix}0 & 0& 0 &0\\0 & \frac{1}{3}& \frac{\sqrt{2}}{3} &0\\0 & \frac{\sqrt{2}}{3}& \frac{2}{3} &0\\0 & 0& 0 &0\\\end{pmatrix}$$

Do $\frac{\sqrt{2}}{3}$ means the coherence between the 2nd and 3rd basis element is $\frac{\sqrt{2}}{3}$?
 
Hello
 
Did you know the brain is happy to trade pleasure with meaning and vice versa
 
1:49 PM
@Secret What do you mean by "coherence between", and what does it mean to assign a number to it?
 
what do you mean? @Kenshin
 
Well some people think the aim of life is to seek pleasure
while others say it is meaning
But in truth it is a combination
Ideally one has both
But if you have a painful event, you can still be happy enough if you see the event had meaning
so that is you traded pleasure for meaning and you remained happy
(not as happy as if you had both tho)
 
@ACuriousMind I read from this PSE that the off diagonal terms means the relative phase between basis vectors. However Lubos's example seemed to be a mixed state thus I am not sure if the same meaning applies to pure states, in particular the projection operators which is formed by the outer product of the state with itself
 
An example of both is (1) sports player enjoys sport while gaining skills to be a professional (he is enjoying the moment and has meaning)
If he doesn't end up succeeding he won't regret because he had fun
someone else however may be willing to undergo pain to become a professional, they too are likely to be happy enuf cos of their meaningful persuit
 
@Secret Trimok's answer to a different question shows much more clearly why we think of the off-diagonals as phases, and their vanishing as decoherence.
 
1:56 PM
but for people to pay to watch you play you have to go a lot further than that
your performance completely depends on how much you practice
 
Again, practicing is cheating
I've said it before.
 
right
but its necessary
without it there is no skill
 
Look, there's no fun in watching people who train a lot
anyone can do that
 
can you
 
that's why kids sports are so interesting, you see people in their natural states
 
2:07 PM
to you
 
I'm 100% correct always.
The best and smartest people tell me so.
It's 24 degrees and windy today :(
 
that's quite an acute angle
 
@0celo7 I cannot accept a measure of temperature that is based on the boiling point of horse's blood
 
fahrenheit is stupid
 
2:10 PM
> The next result appeared in Bernstein and Robinson [1966], where it is proved using nonstandard analysis. Halmos [1966] gave a proof using standard analysis.
@Slereah This is the first time I've heard of nonstandard analysis
 
lawl
it is fairly uncommon
 
@yuggib ??
@AccidentalFourierTransform proof?
 
@0celo7 You like it.
 
The logic of a temperature system has nothing to do with its usefulness
 
I wonder how early non-standard analysis could have been done
 
2:15 PM
@AccidentalFourierTransform Sick burn
 
Probably not too ancient, since it requires the axiom of choice
 
@0celo7 100ºF=boiling point of horse's blood
 
@yuggib I extremely doubt that.
Water boils at 212F.
 
Well either the axiom of choice or that weird extended logic system
 
A hot day is 100F.
Don't tell me horses boil on hot days.
 
2:17 PM
they do
 
@0celo7 By definition of the good ol' Fahrenheit himself (that was a veterinarian or something like that)
 
@yuggib That's ridiculous.
100F is a hot day
Besides, doesn't adding stuff to water raise the boiling point?
 
adding fire does not
 
Horse blood's regular temperature is 100F
 
2:19 PM
@0celo7 so it was not the boiling but the body blood temperature
 
yes
 
anyways, it remains stupid
 
I still want to know how you can think blood boils at 100F
 
what is the boiling point of spacetime
 
@0celo7 doesn't it?
 
2:20 PM
@0celo7 basically because I don't give a damn about how many Celsius 100F are
 
@yuggib it's around 40
 
@yuggib 37 or 36 I think
 
nobody knows exactly because nobody cares about fahrenheit
 
$\frac{C}{5} = \frac{F-32}{9}$
 
except for all of America
 
2:21 PM
@0celo7 And belize. you are in good company
 
I care about Fahrenheit, it's a shitty unit, like all the other American units. but it's important anyway because of widespread useage
 
American units are awesome
 
it's not even widespread
 
they're actually normally sized unlike European ones
European units are so awkward
 
Why can't you use kelvins
the proper SI unit
Or even better
Measure temperature in Joules
 
2:23 PM
Because most people cannot count past 200
 
So we can dispose of the concept of temperature altogether
 
I measure temperature in terms of $\hbar\omega$, where $\omega$ is the average frequency of photons from the sun
 
Also why are "moles" a unit
Avogadro's number is literally just a number
It's like making a new unit for $2$
 
yeah, but the concept behind avogadro's number isn't a number. it's what it's counting that has a unit
 
So we return to the original question: why on earth should there be a pi day??
 
2:26 PM
when I count coins I make little stacks of 10
should I make it a unit
 
because a. pi is cool and b. you now have an excuse to eat pizza and pie.
 
@yuggib To measure the circumference of days
 
I want the $\aleph_{\omega^\omega}$ day
 
Americans don't need more excuses to get gat
 
2:28 PM
$\aleph_{\omega^\omega}$ isn't a number >:|
 
I can't see $\aleph_{\omega^\omega}$ being less interesting than $\pi$
@Slereah of course it is
 
It's a cardinality
 
it is a (cardinal) number
 
@yuggib So what date would you propose to have that day?
 
i want $\phi$ day
 
2:30 PM
The $\aleph_{\omega^\omega}$th day of the year
 
@ACuriousMind January 31st of course
 
it may take a while
 
or $e$ day, $e$ is cool
 
@Slereah if you have particularly long years
 
Actually, I don't think we can have $0$ day because there is no date zero
Unless, we pick that date to be when the number $0$ is first discovered
(which I forgot what that is)
 
2:33 PM
the day when 0 was first discovered?
a loooooooooooooooooong time ago.
 
Probably some Iranian on heroine who discovered it.
 
IIRC it was in India
Also I think the Mayas discovered it independantly
Also it depends what you mean by "zero"
 
oh, i thought it was discovered in Persia
 
@0celo7 Heroin was only invented in 1874, so that's unlikely.
 
Opium has been used for a while, tho
 
2:35 PM
@ACuriousMind a ball of poppy seeds then
@heather Persia = Iran
@Slereah additive identity in the ring of integers
 
Joke: The only time when $\infty < 0$ is that $\infty$ is discovered way later than $0$
 
then it wasn't discovered until like the 19th century :p
People have been talking about infinity for quite a long time
going back to the 6th century BCE, at least
 
@0celo7 i know, I meant I didn't think it was in India
 
@0celo7 Set theory and abstract algebra are pretty recent disciplines
the idea of identity in a ring (or if you want of the identity in an abelian group) is not very old
 
no George Cantor, no cardinals
 
2:49 PM
@0celo7 How to do this kind of crap?
 
@ACuriousMind what does Z[1/2] mean?
@BernardoMeurer trivial application of chain rule
 
@0celo7 Show me, I have no clue how to do this
 
@0celo7 The ring you get when you extend the integers by an element that is the inverse of 2. Equivalently the localization of $\mathbb{Z}$ at $2\mathbb{Z} - \{0\}$.
@BernardoMeurer Apply the chain rule, compute the derivatives. There's no particular trick to that exercise as far as I can see
 
@ACuriousMind I don't know how to do the chain rule
I keep getting fucked up matrices and bullshit
 
$D(f\circ g)(1,1) ) = Df(g(1,1))\cdot Dg(1,1) = Df(1,0) \cdot Dg(1,1)$. Really, all that you can fail at is computing $Df$ and $Dg$ correctly and I can't help you with that unless you show us what you've done.
 
3:04 PM
@ACuriousMind localization?
 
@ACuriousMind Bah, I just needed to transpose something because I'm a moron
Analysis managed to ruin Linear Algebra
Fuck you Analysis
 
What?
 
@0celo7 If you don't know what it is you may just ignore it. It's a way of adding inverses to arbitrary rings, see the Wiki article if you're interested
 
@ACuriousMind the author says it's the dyadic integers
I know what those are
 
@0celo7 Yeah, that's another name for it
 
3:09 PM
Er, dyadic rationals
 
I give up
Analysis II is too hard
 
@ACuriousMind hmm, he mods out Z
 
Fuck it
 
@BernardoMeurer don't be a baby. This is just calculus
 
This is bullshit
 
3:10 PM
Look up the multi variable chain rule
@ACuriousMind what is Z[1/2]/Z?
 
@0celo7 What do you think?
Think about what $\mathbb{R}/\mathbb{Z}$ is - your thingy is a subset of it, after all
 
A circle
So dyadic circle points
 
Yeah, so your thing is the points on this circle that correspond to rationals with a denominator that's a power of two
 
Makes sense.
@BernardoMeurer I can't help you now but did you not do the chain rule in class?
 
> ATTENTION SUBMITTERS: due to a temporary, unforeseen technical issue earlier today, we will be combining tonight's mailing with tomorrow night's mailing. We apologize for the inconvenience.
And here I sat wondering why I didn't get the usual arXiv mail
 
3:38 PM
@ACuriousMind what's arXiv mail?
@BernardoMeurer hello?
 
@0celo7 You can subscribe to get a daily list of papers submitted to the ArXiv that day in a certain category
 
:o how
 
@Slereah Are there people who measure circles with a normalized degree system
So that 2pi = 1
 
$2\pi = 1$ is called a "turn"
Or a rotation
 
3:41 PM
Not that
 
see for instance rpm
 
If you do S=R/Z, then a circle is [0,1)
So neither degrees nor radians make sense
@ACuriousMind what are you subscribed to?
 
What about gradients
 
@0celo7 hep-th and math-ph
 
@ACuriousMind isn't math ph filled with analysis :P
 
@0celo7 It is; so what? hep-th is also filled with lots of stuff I don't particularly care for
Alas, the stuff I do care for also appears there, so I watch out for it
 
hep-th sounds like it would be filled with papers about cross sections
 
@Slereah Actually, not that much. It's rather diverse in the topics that appear there
 
Where are the cross sections?
 
This paper has very strange numbering. The first theorem that appears is 2.4, followed by 2.7, and the next thing that appears numbered is proposition 3.9
 
3:56 PM
Do people still calculate those?
 
It appears that both equations and theorems/propositions are numbered with the same counter oO
Why would you ever do that?
 
Have you ever read the Principia Mathematica, @ACuriousMind
 
That seems like an interesting paper
 
It has the worst chapter numbering
 
@ACuriousMind what?
 
3:57 PM
It goes from chapter 5 to chapter 9
 
@Slereah My desire to suffer is not that strong, no
@0celo7 My thoughts exactly
 

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