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12:43 AM
Why is that civil engineering courses for example concrete structure less intuitive than economics, finance, statistics and mathematics?
 
1:23 AM
Who says it is? Or to put it another way, what kind of intuitometer are you using here? No one else's seems to agree with mine on the fine details.
 
1:34 AM
I just saw a children's play (5-11th grade) rendition of To Kill a Mockingbird, and they left all the n-words in. As a Northerner, I was quite shocked.
 
1:50 AM
@HariPrasad The whole blog thing has kind of died down network-wide, and no official per-site Stack Exchange blogs will be started. Most per-site blogs (if they exist) are stagnating, as @ACuriousMind alluded to. This would make starting an official blog affiliated and integrated with Stack Exchange impossible.
You could use a third-party host - as we've done on Worldbuilding using Medium, thanks to a suggestion by a CM - but our blog was supposed to build our community and get our name out there, where we can help worldbuilders online. Physics Stack Exchange has a different culture, and while some users do have their own blogs, the community doesn't have much of a vested interest in creating one, especially given that it will have to be done elsewhere.
I'd trust the assessments of ACuriousMind and DavidZ more than mine on this, as they know the Physics Stack Exchange community better than I, but I concur with them here. Those on Physics who would be best-suited to write for the blog might not have a vested interest in doing so, and I don't think the community would gain a lot from it.
It's still worth raising the issue on meta for a third-party host - I don't want to discourage you from doing that - but I highly doubt that it will be successful.
 
@ACuriousMind Just said "huh" to my parents
I'm ruined
I can't stop saying it
 
@0celo7 Surely it would have been more shocking had they taken them out.
::gets angry at the thought of what was done to George Carlin's memory at the Mark Twain award ceremony, again::
 
@dmckee I would not have missed it.
As in, I was surprised that they said it, I would not have known that it was taken out.
 
vzn
@0celo7 spking of your family, whats new w your sister
 
@vzn Don't be a creep.
Next time you bring her up, I'll just block you.
I've told you to not do that.
 
vzn
2:02 AM
@0celo7 ok. why dont you stop talking about her in here then?
 
I don't talk about her with you.
 
vzn
oh. right.
currently guilty of some kind of unidentifiable cyber and/ or chat crime
 
Correct.
 
vzn
unforgivable
also had a sibling... over ~½ decade ago
 
@0celo7 Well, you'll either have to live with it or make a conscious effort to untrain that
 
2:09 AM
@vzn Are you saying your sibling passed away?
 
@HDE226868 I actually think writing more self-answered Q&A would be a good substitute for most things one might want on the technical side from a physics.SE blog, and chat sessions such as for the LIGO announcement can substitute for the "physics news" one might also expect from such a blog.
Alas, as I had to find out, if you don't actually have an answer sitting around waiting for a question, finding nice questions for a Q&A where you also give the answer is kinda hard
 
@dmckee you wouldn't happen to be in the market for scary looking infinite sums that allegedly model the membrane of a drum
 
vzn
@0celo7 something to talk about w my psychotherapist, eh? at least in some "safe" context. (among those who care.)
 
@vzn Ok, good luck with that?
Sorry to hear he/she passed.
 
vzn
@0celo7 thx?
@0celo7 wow! so you do exhibit empathy on occasion :)
 
2:17 AM
Contrary to your beliefs, I'm a nice person.
 
vzn
@0celo7 contrary to your statement, never asserted otherwise.
 
@0celo7 Nawh. I'm busy trying to make Lagrangian Mechanics suitable for my students who are struggling.
 
@dmckee I'm a student. Need any ideas?
 
I don't think your struggles are representative of the typical student
 
I can't do integrals, @ACuriousMind.
Currently battling with orthogonality relations on $[-\pi,\pi]$.
 
vzn
2:21 AM
@0celo7 ahem ok. will try this. sincerely sorry for being too facetious about your sister. will try to avoid that. in my defense did not think it all that different than your mocking tone wrt the SJW in here (and rather mocking in general it would seem... yet funny nonetheless). and maybe other incidents. found your ref to your family interesting. also thought you said she had something to do with economics iirc. etc...
 
@vzn Ok, forgiven. She works finance at a major tech company. No economics in the academic sense.
 
vzn
@0celo7 wow. that was easier than thought. ok. so can you say what state? finance as in accounting or something other? (eg stock market etc...)
 
GitHub.
I don't actually know what she does, TBH her work doesn't interest me.
 
vzn
she works at github?
 
@vzn Yes.
 
vzn
2:26 AM
interesting. work at a fortune 250 company and we just did a big company-wide migration to git from clearcase. it was pretty tough at times. due to variety of factors wrt both packages... git is very impressive architecture... originally built by torvalds linux creator. have been using their new "gist" codesharing site quite a bit last yr or so (on my blog, math research).
 
I should get he to send me some swag from the gift shop. I need some new clothes anyway.
 
vzn
lol. luv the swag myself. maybe next time ask her what she does in more detail. possibly only for your own & sisters sake :)
 
@vzn Oh, and "luv" did come up with my gf :)
 
vzn
@0celo7 really? congratulations! how so? that is if the details are G rated :D
 
We were alone and it slipped out, I dunno. Nothing non-G rated yet.
 
2:31 AM
@ACuriousMind That could work. I'd be concerned, though, that the posts would miss a substantial portion of the userbase. If the posts are continuously technical, that's 1) A fantastic thing, from the side of the person seriously studying physics, and 2) A fantastic way to go over the heads of most people. That poses a conundrum, in my view, because you should still go ahead and write the technical articles.
There are other arguments to be made about this - one of which being that I worry too much about minor things - but I still think that the community may not fully get many of the posts. Is that a bad thing? Maybe not.
 
vzn
@0celo7 ↑ lol too ambiguous to interpret/ comment. except that "it slipped out" doesnt sound G rated :P
 
@HDE226868 Yeah, they'll go over the heads of the "casuals". But I don't think we should cater any more to that portion of the userbase than we already do, to be honest.
 
@vzn lol
the words you perv
 
vzn
@0celo7 oh! ok! congratulations! (presuming its mutual) :D
 
@0celo7 That phrase screams "euphemism" to me, too. :P
 
2:35 AM
@ACuriousMind I agree with that - and I'm not suggesting that articles be written to a lower level, for lack of a better phrase. But it might hurt community support a bit.
 
@vzn Weeeeeelll, it's not not mutual, but one of us isn't quite there yet :/
 
vzn
@ACuriousMind lol aka double entendre etc... (lol thought you were giving me cold shoulder after danu incident.)
 
@vzn Vulcans do not hold grudges.
 
vzn
@0celo7 ?!? (making small assumption here.) think you maybe will have to use your brilliant persuasive skills. know a few tricks myself :D
 
@ACuriousMind in some cases that might actually get better answers...
 
vzn
2:38 AM
@ACuriousMind ah shew! lucky for me! but there does seem to be some kind of deep kirk-spock rivalry going on, exploited to big/ unprecedented level/ effect by eg Abrams. (ps have you seen his movies? also, did you know Shatner just wrote a new book/ memoir on Nimoy? some wild stuff in that...)
 
@HDE226868 Well, another advantage of the self-written Q&A is that you don't need community support to write them because they're not supposed to represent the community
 
@vzn She was willing to read my proof about the orientation of normal vectors. I think she's there but just needs to say it :)
 
@ACuriousMind Fair enough.
 
@vzn Meh, I don't like the new ones. They don't feel like Trek, although they aren't bad movies.
 
vzn
@0celo7 lol that reminds me, did you ever hear that storry about Polly Nomial? might have posted it in here ages ago...
 
2:41 AM
@DanielSank Yeah, I'm not a fan of those "let me just add another thing" answers, either, if that's what you mean
 
vzn
@ACuriousMind yeah abrams changed the formula a lot. hey it cant be wrong if it makes so much $$$ right? actually was kind of shocked at how radical his 1st trek movie was. geez didnt spock/ kirk get into a near fistfight? over uhura-saldana? cant remember exactly... jaw dropping! did you see force awakens? havent seen it yet myself... are youa shatner/ nimoy fan or just a kirk/ spock fan?
 
@vzn I did not
 
@vzn Haven't actually seen much else from them, but I like the old Star Trek, probably because and not in spite of its frequent campiness ;)
 
I need a makeshift straightedge
Anyone have any ideas?
Ah, BBS
 
2:43 AM
Maybe it can be good for at least one thing
@ACuriousMind BBS just let me draw the most perfect right angle
 
vzn
@0celo7 old classic. if she likes math so much she mind find it amusing also. :)
 
@vzn Perhaps.
 
vzn
@0celo7 whats her major? physics?
 
Music.
 
Oh, so many stupid jokes to make in connection with your current profile picture...
 
2:47 AM
@ACuriousMind Not her.
 
vzn
@0celo7 hmmm... did she really understand your proof? uh, actually, maybe that really is a good sign if shes a music major & was willing to read it... :D
 
No, I did not make her read it.
I'm not cruel.
I just wanted to see if she would.
I actually met her in my differential equations class last semester.
 
@0celo7 Still, does she play your oboe? :P
 
https://media.giphy.com/media/WM3HX2cZ3zTry/giphy.gif

Joke:
Warning
We have discovered a case of entanglement among bear like entities
 
@ACuriousMind Oh jeez.
 
2:48 AM
@0celo7 It's a woodwind after all
 
vzn
@ACuriousMind thought you were a lute fan. just pretend its a lute :)
 
Oh no...
 
(Okay, I'll stop now :D )
 
vzn
@0celo7 thats a weird school with a music major in a diffeq class. or does she have math aspirations?
 
No.
 
vzn
2:51 AM
@Secret lol great but just wondering so does that take away or add to the mystery?
 
@vzn Everyone in the school has to take at least one math class and she had calculus in high school.
 
I am not sure, I always interpret entanglement as basically one object.
Perhaps, the 3 barebears are one single entity that for some reason look like 3 dististinct entities?
 
vzn
@0celo7 too bad she couldnt just pass out of calc in college. some schools do have a way to "challenge" the tests or get credit. diffeq is pretty advanced generally, although a lot of engrs tend to have to take it... she probably could have found an easier math class... suggests shes got some major stamina there...
 
She did get out of calc.
By taking diff eq.
Diff eq is a requirement for all engineering and math majors.
Don't know about physics.
Probably there too.
 
PS, this blog is where I got the idea that "entanglement is basically a single object"
http://lesswrong.com/lw/q0/entangled_photons/

At the time I was reading that blog (2012), my physics level is probably not high enough to detect whether this compsci guy of the blog is saying nonsense or valid things
 
vzn
2:55 AM
@0celo7 ok. was talking about college credit for high school classes eg AP
 
@vzn Oh, I think that requirement can't be avoided by an AP score.
She got a 5 on the BC test.
 
The maths of entanglement, being a sum of tensor product of states in subsystems, also kinda suggest an entangled state is one object
 
vzn
@Secret not a bad summary.
@0celo7 did she get college credit for that? that score is enough at many schools to actually get the college credits that apply toward the basic requirements... eg if a school has calculus as a requirement for the major, then passing the AP test can achieve that...
@Secret entanglement is still under active investigation/ research. its arguably not even fully understood by the experts "yet". its a decades-long project stretching to close to century now.
 
@vzn I don't know, why does it matter?
It's not a calculus requirement, it's just a math requirement.
 
vzn
@0celo7 if she enjoys diffeq then no big deal, but if shes tired of taking math classes, she might have avoided it... at least at some schools, dont know details of yours...
 
2:59 AM
So if entanglement is one object, then I won't be suprised why measuring one (and giving a random result) will determine the other (a result that correlates to the random result obtained form the first)

The only question is, why does it look separate to us
 
@vzn No, she wanted to take it
And she's not taking any more math classes
 
vzn
@0celo7 awww geek luv :D
 
@vzn She didn't know I would be in it...
Last semester, not this semester
 
and then, the partial trace operation mentioned by Acuriousmind yesterday which gives the link between esembles and entagled states makes me ponder that entanglement might not really that simple, but I still yet to digest the maths completely
 
vzn
@Secret of course its not simple (much at all). theres a lot of good refs to study other than blog pages if you so choose :)
@0celo7 (ACMs query notwithstanding) does she play any instruments?
 
3:06 AM
@vzn yes, flute and piccolo
@ACuriousMind So yes, she does play woodwind instruments :P
 
vzn
@Secret my opinion, the complex/ unintuitive math is obscuring some of the reality, but this is at best a small )( minority view these days (more accurately, contrarian). this is not an outlandish/ unique idea, its basically Bohmian ... "philosophy"...
 
Drums are complicated.
I wish Knife Party made more music :(
 
Well, even for bohmian trajectories, there's still nonlocality in it. Is the nonlocality a fundamental thing, or is just a manifestation/projection of something that is basically just a connected whole.

If it is the latter, what is the mechanism of this connection, how does it form and why our detectors only see them as separate?
 
vzn
@0celo7 drums have some signficant fluid dynamics analogies... :)
 
@ACuriousMind How does the divergence theorem work when integrating over a $2$-surface
Do you get a line integral along the boundary?
 
3:11 AM
These are the questions I am always wondering. We know how to produce entangled states (with some chance c.f. Spontaneous parametric down conversion)
 
Dotted with the outward normal on the boundary?
 
but we are still nto clear the mechanisms on how it happened
 
vzn
@Secret these questions are all under active research. did you hear about the recent "loophole free bell test(s)"? historic. anyway think that "weak measurement" will eventually/ finally resolve the theoretical conflict. leading to some big new theory.
@Secret trying to remember, are you in college? what major?
 
one year ago: Bachelor: Chemsitry and physics double major, currently: Honours chemistry
I am studying in UNSW
 
I'd like to let a message to @ACuriousMind . I once asked here whether "the number of photons of a system" is a lorentz invariant quantity and you (and fenderlespaul) answered me that no. After talking to a friend the question arose again so I posted it physics.stackexchange.com/questions/241522/… and the answer seems to be that it's invariant. I'd appreciate if you could comment on that or even reply.
 
3:14 AM
Those questions are infinite rabbit holes. If you know the mechanism how something happens, you can always ask what the mechanism how the mechanism works is. At some point, physical theories *always* cut off this chain of questioning and postulate some mechanism as "fundamental", as note being composed of smaller units of understanding.
The preliminary nature of human knowledge means that we can never be sure whether that point is really "the end of the line" or whether there is something to it we have not yet discovered. The chain of reasons is either infinite or terminates at something wh
 
vzn
@Secret australia?
 
@vzn yes
@ACuriousMind Perhaps among this chain, the really key thing I am interested in is "why does an entangled state look like a separate thing to us and our detectors"
 
vzn
@Secret cool, oz has a big qm computing govt initiative. bearing fruit. dont recall if some of it is at UNSW but presumably it is...
 
@vzn I have a couple of honours friends working in that facility and yes, that facility is rapidly expanding. Right now it has consumed 1/4 of the physics building
 
vzn
@Secret way cool. ok wrt entanglement feel free to drop by my chat room anytime for ideas/ info. have a few intermittent cohorts into that stuff also. chat.stackexchange.com/rooms/9446/theory-salon (gotta go nice chatting all)
 
3:20 AM
@no_choice99 I left a comment at the answer
 
thanks a lot @ACuriousMind
 
@Secret It doesn't really look like a "separate" thing. The point is the detectors are only sensitive to a subsystem, they cannot measure the whole system (because the state is inherently non-local (but this isn't really because of entanglement!), but every measurement is local).
 
"but this isn't really because of entanglement!" omg, now I am more confused. I must have mixed up nonlocality with entanglement, I should read more before get back to it
 
Why should the number operator be proportional to the Hamiltonian @ACuriousMind? That implies that all photons have the same energy. Under Lorentz transformation the occupation of photons at different frequencies changes but the total photon number is fixed. I would have commented on the original post but I am new to the community.
 
But your explanation makes sense
 
3:33 AM
@JamesRowland The Hamiltonian is schematically $a^\dagger a + \text{zero point energy}$. In the single, non-relativistic harmonic oscillator, it's $H = N + \frac{1}{2}$. The difference between the number operator in that answer and the Hamiltonian is essentially just the choice of measure - spatial vs. Lorentz invariant one. I want to know why it is physically correct to choose the Lorentz invariant number operator.
I realize now that, physically, the photons get red/blueshifted through a boost, and it is probably really correct to choose the Lorentz invariant one. But how does one see this in the formalism?
 
@ACuriousMind I mostly mean that if you don't know who else wrote an answer you're more likely to try to write a good one. I know I definitely am way less likely to try to answer if there's even a moderately good one already there.
@ACuriousMind Regarding those "one more thing" answers... some times they really do add value, so I'm not sure what to think.
 
The number operator needs to satisfy $[a^\dagger(k),a(k)]=1$. If you make this choice than the Hamiltonian is $H=\sum_k E(k)(a^\dagger(k)a(k)+1/2)$ which is only proportional to $N$ is $E(k)$ is constant.
 
@JamesRowland That makes perfect sense!
@no_choice99, see above for why Fender and I were most probably wrong.
 
I just thought of an intuitive picture as well. The Lorentz transformation is a continuous transformation. Going from one to two particles in not a continuous transformation. If the Lorentz transformation could do this then there would be some special boost at which you jump discontinuously from one to two particles, etc.
 
@ Acuriousmind Sometimes I do wonder why I tend to ask a lot of infintie rabbit hole type questions...
 
3:39 AM
@Secret There's an easy non-entangled "non-local" state: Consider a photon incident on a half-transmitting, half-reflecting mirror. Its wavefunction gets split up into two separate packets, whose separation gets larger with time. If you measure the photon on one side of the mirror, you won't measure it on the other. Ta-da, non-local correlation without entanglement.
@JamesRowland It can't be that easy because the Unruh effect in curved spacetime does transform the zero-particle state of the vacuum for one observer into a populated state for another, and the transform into an accelerated state seems to be continuous to me.
 
@ACuriousMind @ChrisWhite Is there a way to make fractions where the numerator and denominator are not forced into the "inline" size?
 
Also, nothing forbids the number operator to have continuous expectation on a state that's not an eigenstate
 
user54412
@0celo7 \dfrac?
 
Doesn't do anything.
Standard \frac.
 
@DanielSank I don't know, if you couldn't see the other answers, you could end up with multiple answers that say pretty much the same, which would be a waste of everyone's time
 
3:46 AM
So you mean when I start e.g. measuring the transmitted photon, the wavefunction get evolved by the measurement hamiltonian into a new one such that there is probability of 1 for the transmitted photon to be measured and zero for the reflected photon

That is, even though the wave packets became more separate over time, the interaction caused by the measurement will still be able to affect the whole wavefunction of the photon, hence the nonlocality?
 
Yeah, "collapse", however you actually model it, seems non-local to me even in the absence of entanglement
 
But I don't quite get it, isn't that entanglement requires the states in the subsystems to be correlated somehow?

Here in the photon hitting the half mirror case above, there's clearly some kind of correlation because whenever you can detect a transmitted photon, you won't detect a reflected photon, and vise versa. Thus it seems that the transmitted photon and reflected photon can be considered as two correlated subsystem, thus leading the conclusion these two cases are entangled. What am I missing here in my deduction?
 
@Secret What are the "two subsystems" here? It's just a single photon, you can't partition that into two distinct subsystems in any way I can see.
 
vzn
@ACuriousMind that reminds me. have always wondered if bell type experiments are the "simplest" entangled states possible. because theyre not so "simple" to produce experimentally. if they are, seems like it would be possible to prove it, and it would likely be an interesting proof. if not, it would be interesting also.
 
@ACuriousMind I just read the wiki page for Unruh effect. This is for accelerating observers. The Lorentz transformation connects observers at different velocities but not accelerating. Looking into this I found a post about the Unruh effect which made me remember that particles can be in a superposition of unoccupied and occupied, e.g., you can go continuously from zero to one particle.
 
3:59 AM
@vzn They are the "simplest" in the sense that they work with two two-dimensional subsystems (spin up/down). You don't get smaller spaces than that, so the math is the simplest. I don't know whether you can measure experimental simplicity in the formalism
 
@vzn @Secret @ACuriousMind I have not been following the entaglement discussion. Has anyone brought up the fact that all Fermions are entangled by definition?
The Fermion anti-commutation relations enforce this.
 
thanks @ACuriousMind , James please post an answer (since you can't comment yet).
 
> Polly rotated and saw Curly approaching her with his power series expanding.
Lol
 
@JamesRowland Yes, I know the Unruh effect is different and I now don't doubt that indeed the photon number is Lorentz invariant, I'm just saying the continuity argument alone is not enough.
 
@vzn p. good...
@ACuriousMind You're up late even for ACM.
 
4:02 AM
@JamesRowland I've not heard that, what do you mean, i.e. what are the subsystems that are entangled?
 
Any one know a toy system that is (a) easy to analyze in Lagrangian mechanics if you use some generalized coordinates but (b) very difficult to do simply writing down the positions of the masses?
 
@dmckee Yes.
Motion of a particle in polar coordinates.
 
Care to enlighten me?I can't think of one just now. Though I must have seen one at some point in the past.
 
Will get back to that later, I am slow at typiing laTex (STILL TYPING)
and yes you are right about the fermions, the electrons in a molecule is commonly regarded as entangled such that to compute the correct energy you have to consider all electron correlations in the molecule
 
@dmckee Atwood machines? I seem to remember those get pretty horrible in Newtonian mechanics, but the right choice of generalized coordinates makes them rather tractable in Lagrangian mechanics
 
4:04 AM
@dmckee Well it's easy if you know the metric tensor of flat space in polar coordinates.
 
@ACuriousMind Yeah. That's not a bad one, alas it's done in the text we're using and I was trying to prepare some separate examples.
 
Suppose you have a system of just two electrons. One in state a and one in state b. The state of the system has to be anti-symmetry under exchange of a and b so $\psi=a\ctimes b-b\ctimes a$.
 
@JamesRowland Ah, yes. But isn't that also true for bosons, who have to symmetrize the state, or am I missing something?
 
waaaaay easier than doing the coordinate transformation in $m\mathbf{a}=-\nabla V$.
 
user54412
4:07 AM
@dmckee iirc there's the mass sliding on a circular hoop, maybe with the hoop oriented vertically and spinning in a gravitational field
 
For Bosons you can have the state $a\ctimes a$ that is not entangled
 
@ChrisWhite lol
 
@JamesRowland Ah, right! (it's \otimes for the tensor product, by the way)
 
@dmckee my vote is for the polar coordinate thing, unless you're already doing that
I say that as a student, not a graduate like the others
that example blew my mind the first time I saw it
 
@ChrisWhite Ah, yes. I think I used that on a test a couple of years ago. Good problem.
 
4:09 AM
In some sense it is not an interesting form of entanglement though.
 
@0celo7 It's a good problem but my students will find it opaque both ways, and I'm trying to write a clarifying document.
 
:/
I would struggle with the spinning thing in the thing
I don't see how that's clearer
 
user54412
I once had a mass attached to a spring anchored to a rod swinging around a joint off-center on a turntable -- not sure it was easy in any formalism though
 
@0celo7 People who haven't read GR texts in high school struggle a lot with coordinate changes ;)
 
I think because you cannot tell which electron you measured. Both a\otimes b and b\otimes a have the same specturm for any operator
 
4:12 AM
@ACuriousMind if my PDE prof does not give me the Laplacian in polar coordinates on our midterm I'll just give up
@ACuriousMind (and that's precisely the idea)
(people struggle with coordinate changes so let's show them how easy it is in the Lagrangian formalism)
 
@JamesRowland Yes, the antisymmetrization may be seen as just quotienting out the unphysical symmetry of interchanging two indistinguishable particles. (If you want to see TeX in chat, go to this page )
 
Very helpful thanks!
 
@ChrisWhite Do you mean you had that in an exam or do you mean you had that on your desk to stump other physicists by asking them to calculate it? ;)
 
4:30 AM
I am only clear that the hamiltonian cannot evolve the wavefunction into one that involve both D_1 and D_2 terms as otherwise both detectors will get a nonzero probability of detection

I need to figure out what form the final state has to take in order to ensure whenever D_1 detects something D_2 must be zero and vise versa
 
 
1 hour later…
5:35 AM
hi
 
 
3 hours later…
8:13 AM
Hi
 
 
1 hour later…
9:23 AM
Cor, two upvotes within seconds of posting my latest fartwork, err, artwork ...
2
Q: What is time dilation really?

John RenniePlease will someone explain what time dilation really is and how it occurs. There are lots of questions and answers going into how to calculate time dilation, but none that give an intuitive feel for how it happens.

The answer isn't completely finished. I'll be tweaking it and adding more detail over the next day or two.
 
-1
Q: Which gives the most realistic pictures, Mirror, camera or their combination?

TimBy googling, I have found several different opinions about how to take one's own facial images more realistically: Some said photos taken by cameras (smartphone's cameras, if specific) are more objective than images from flat mirrors, because it is close to what others see myself. some said the...

Off-topic?
 
9:56 AM
@JohnRennie Okay.
You're already in the "hot questions" list of PSE---let's see if it makes the HNQ list.
@Qmechanic I want to say yes, but I don't know how to phrase why :P
 
10:14 AM
@Danu Thanks for the tweaks. This was sort of a first draft - I rushed it out when I saw there was yet another question about time dilation. I think it could do with considerable polishing.
I'd be interested in opinions from the panel on whether it hits the right tone i.e. does it actually give a useful explanation of why time dilation happens?
 
10:31 AM
I think it's pretty decent.
I think it might be interesting to write a mathematician-oriented answer as well.
 
10:58 AM
@ACuriousMind: I am one of the close votes. The example in the book is bad physics and I don't think we really need an analysis of all the possible mistakes the author made/the possible attempts one could make on his behalf to rescue this nonsense. — CuriousOne 2 mins ago
...that's not what "primarily opinion-based" is for...
 
Classic CuriousOne :P
 
-2
Q: Car Collision with Deer

D MaciasHow fast would a 1500kg, 1.4 m tall car have to be going to lodge a deer with a mass of 160 kg into the radiator or the bumper of that same car? I know that at most speeds, the deer will hit the windshield once it has been hit by the car but isn't there a velocity where the deer would get stuck i...

I don't know what that question is, but it surely is not "homework-like" as the close votes suggest :P
 
11:26 AM
Help
I am stuck at a family week end
 
Lol
 
Why can't I be an orphan
 
user116211
12:06 PM
@ACuriousMind This is inhumane! Tht's why I hate HW ;/
 
user116211
@Danu primarily opinion based. His query points at that. His question starts like some said.... some said.... IMO, it's primarily opinion-based.
 
user116211
CuriousOne has a habit of posting answers in comments ;D
 
user116211
@Slereah other side of the grass is always greener ;)
 
3:19 PM
@JohnRennie "Maths" is such a bothersome word to me
 
3:55 PM
@0celo7 Why bother when you are interested in physics. Maths is after all made to understand physics. :P
 
@0celo7 ???
 
@JohnRennie I think he means that he prefers the more American "math"
Don't ask me why he felt the need to tell you that, though :D
 
@ACuriousMind gosh i changed my username yesterday(accidentally) and now i can't change it back.
 

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