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1:50 AM
Does Neil Turok have any Physics Text books out there? I watched one of his lectures on PI video archive and loved it
 
@dmckee I know you @'d me
What should I know about Maker's Mark
 
2:23 AM
Copying 3800 songs to my phone. This will take a while.
@StanShunpike Wrestling with iTunes ^
Somehow I have >4000 songs on my phone
I only have 3800 in my library
And to sync these I need another 30 gigs
Sigh...
Lol
I "removed all songs" but there are still 500
And now it only wants to copy 3600 songs
This will take all night.
 
Holy crap
dude u weren't kidding
Wowowow
 
I'm trying to clear out the dupes
It's just making iTunes even madder
 
i hate duplicates
 
Well there are some dupes that I like
I have songs that are on albums and also on festival mixes
So I can get the song when I want stuff from just that artist or when I want "similar" songs
uhhhhhhhhgggggggggg
I wonder if wifi syncing is faster than USB
@StanShunpike a good review of hardstyle this year pro.beatport.com/release/hardstyle-the-annual-2016/1669326
(pretty happy hardstyle)
@StanShunpike don't you hate when you know you've heard a melody somewhere before but can't remember where
 
 
2 hours later…
4:18 AM
@0celo7 I HATE THAT SO MUCH
@0celo7 happens all the time. One time took 6 months before I figured it out
@ACuriousMind What is a representation?
 
hmm why aren't upvoted comments yieding points?
 
@ACuriousMind like specifically, what does it mean to represent a group like the Lorentz group with a bispinor?
@no_choice99 they never have
The incentives are designed to promote answering not commenting.
Commenting is merely a supplement to answers but not considered the primary product of SE
 
ok that makes sense
are answers with tons of negative votes eventually deleted or they just whiteout? (i.e. appears in grey, almost white)
 
The latter
 
thanks a lot
another question. in the profile page of anyone, sometimes I see a "top 5% overall" for the reputation. what does this mean
nevermind I got the answer
 
 
1 hour later…
5:46 AM
Anybody around?
 
 
3 hours later…
8:51 AM
-6
Q: Nobel Prize for Gravitation?

Adrian FerentWho is the smartest to explain Gravitation? 900 Nobel Laureates and they were not able to explain Gravitation, the most important force in nature. In my view the graviton must have a speed higher then the speed of light; the gravitons with the speed of light will not escape a black hole. General ...

 
9:04 AM
@dmckee Thanks for the info on Maker's Mark ;D
 
 
1 hour later…
10:22 AM
@Danu please tell me
 
@0celo7 @ACuriousMind @Danu @Slereah @all_the_others (tricky) Question to begin the year:

Let $Q$, $P$ be self-adjoint operators and $D\subset \mathscr{H}$ a domain such that
(a) $Q$, $P$ are essentially self-adjoint on $D$;
(b) $Q:D\to D$, $P:D\to D$;
 
Screw you
 
(c) $QP\varphi -PQ\varphi=i\varphi$ for all $\varphi\in D$.
what are $Q$ and $P$?
@0celo7 shut up and think :P
 
Position and momentum
 
are you sure?
are the only ones?
 
10:26 AM
Something something Stone Von Neumann
I'm not a quantum mathematician
 
so the answer of @0celo7 is: the operators are (unitarily equivalent to) position and momentum because of Stone-von Neumann
 
Sure. Why not.
 
I would like to collect other answers ;-)
 
Ok. I'm going to take a shower.
 
very good, cleanliness is important
 
10:29 AM
I had a very strange dream and a shower was involved.
@yuggib btw I have no clue what this sentence means
 
@0celo7 it is a careful rewording of "something something Stone Von Neumann"
 
10:48 AM
@yuggib well I don't know what that means, either
Wow Headhunterz has a collab with Aoki :o
Dude has gone mainstreeeeeeeeeaaaam
 
 
2 hours later…
12:33 PM
@0celo7 I'm not sure why @dmckee deleted his messages.
 
1:33 PM
@yuggib Anything more about this "domain" $D$? Is it dense? Also, what are the domains of definition of $Q,P$?
 
@ACuriousMind It is dense, and it is a domain of essential self-adjointness of both $Q$ and $P$
invariant for both $Q$ and $P$
(domain of essential self-adjointness as you probably know well means that the closure of the operator defined on that domain is self-adjoint)
 
@StanShunpike You are not "representing the Lorentz group with a bispinor". There is the space of bispinors, and there is a map from the Lorentz group into the matrices on that space (the representation map) so that we can speak of the Lorentz group "acting" on the bispinors (by applying the corresponding matrix)
@yuggib: Hm, unless you give me that $Q,P$ also fulfill the Weyl relations and act irreducibly, I think Stone-von Neumann doesn't apply.
 
@ACuriousMind irreducibility is not so important...the question boils down to: Is it necessary for two operators with those properties to satisfy the Weyl relations
?
 
1:49 PM
Hmmmmm
You might have forced that by fixing the invariant domain of definition to be the same for $P$ and $Q$ and forcing $[P,Q]$ to be also defined on the whole of $D$. The "counterexamples" I would think of (e.g. the pair of the angle/angular momentum operators for a particle confined to a circle) seem to run into trouble mainly due to the mismatched domains of the operators
 
2:08 PM
maybe there are trickier counterexamples :-P
that would show that there are a priori pretty reasonable candidates to be QM canonical couples that in fact do not satisfy the Weyl relations
 
 
2 hours later…
4:26 PM
0
Q: Why does electromagnetism have torsion, whereas gravity does not?

DavidWhy don't we use torsion-free covariant derivatives for QM, even though we already do so in the case of GR? In general relativity, we use the Levi-civita connection, a torsion-free connection compatible with some Lorentz fibre metric on the tangent bundle. (represents a structure-group reductio...

@ACuriousMind 1) Does the torsion of a connection on a principal bundle make sense as an object? 2) If yes, what significance does the torsion of the EM cov. deriv. have?
 
@0celo7 1. No. To have torsion you need to have a solder form. Since soldering identifies a particular assoc. bundle with the tangent bundle, I don't think such a think should be done in a general gauge theory - the whole point is that that gauge structure is wholly unrelated to the tangent structure of the manifold. One might even say that it's is the distinguishing feature of GR that we have such a natural solder form.
 
What is the solder form of GR?
The vielbein perhaps?
 
@0celo7 The example list on the Wiki page gives the answer :P
 
@ACuriousMind Does the vielbein also work
 
4:42 PM
Yes.
 
@ACuriousMind I'm stuck proving that if map on a top. vector space V is continuous at 0, then it is continuous on all of V.
Stuck as in don't know how to start.
I'm using the definition: $f:X\to Y$ is continuous at $x\in X$ if for every nbd. $N$ of $f(x)$ there is an nbd $M$ of $x$ s.t. $f(M)\subset N$.
I've already proven that if this holds at every $x$, then the usual "preimage of open set is open" definition holds.
 
@0celo7 Surely you mean linear map?
 
@ACuriousMind Yes.
 
Huy
lol
$\mathfrak{troll}^2$
 
Blocked. I've had enough of your shit.
 
Huy
4:49 PM
haha mad
 
what's the definition of a topological vector space, @0celo7?
 
@MikeMiller A vector space which is Hausdorff and vector addition and scalar multiplication are jointly continuous.
 
Huy
@0celo7: you can try to show it's bounded and then that it's even Lipschitz
 
OK, so in particular, the map $f(v)=v+x$ is continuous.
 
Translation is continuous, yes.
So can I turn "T is continuous around 0" into "T is continuous around x" by translation by x?
 
4:55 PM
@Huy Bounded doesn't even make sense on a mere topological vector space :P
@0celo7 Yes, that is the idea
 
Huy
truth
-_-
 
@FenderLesPaul I thought you were gonna write an answer on my light waves question...
 
 
3 hours later…
7:57 PM
0
Q: Can not remember the name of an effect --- where should I ask?

Gyro GearlooseI have a phenomenon in mind but can't remember the name. Without name or other keywords, I can google for the rest of my life. Where, in general, should I ask in such a case? The concrete thing I can't remember the name of right now is the relativistic effect that alters classical gravitational ...

 
 
1 hour later…
9:10 PM
sup venka
 
10:06 PM
I'm so bored.
Life is boring.
 
10:40 PM
is the interaction between the photon and charged particle in a compton scattering interaction instantaneous?
in other words, is the scattered photon the same as the incoming one but only with another momentum/energy? or it's a different one and the original one has been absorbed and then a new photon has been emitted after some time
 
11:08 PM
Apple Store playing that U2 album no one likes
 

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