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2:41 AM
-3
Q: John Rennie help with solar furnace

kirby gainesJohn Rennie or Anyone What is the best way to heat water in a chamber with a magnify glass. To make a solar furnace. Could I use a magnifying glass and a optical fiber I have been trying but have failed. Please send to gaineskirby@gmail.com Pleas help and Thanks Kirby Gaines

Well gee, I know John is highly regarded around here, but...
That seems a wee bit excessive
 
2:53 AM
@Sean saw that. Wtf
Jockin john a bit too hard
despite his mad physics swag
 
@Sean Makes me LOL... :D
@tpg2114 WOW!! O_O
 
3:20 AM
I'm confused about how many basic examples I should be familiar with to "know" quantum mechanics.
What are the basic examples I should know besides particle in a box, free particle, and harmonic oscillator?
 
3:33 AM
@StanShunpike By knowing, if you mean you wanna get a feel about it, there's a list of systems that can be solved analytically :)
 
3:50 AM
@Waffle'sCrazyPeanut sweet. by knowing I mean able to derive off the top of my head.
 
@Waffle'sCrazyPeanut now there's a name I haven't seen in a really long time! How are you buddy?
 
 
1 hour later…
4:52 AM
LOL
5
 
5:12 AM
I'm having trouble understanding Noether's theorem. Can anyone help me? For starters, I don't know what a generator is and when I clicked on the link, it took me to Lie groups. And I'm not sure how that relates. Specifically, this sentence loses me "Consider the generator of time translations Q = ∂/∂t" I have no idea what they mean by generator and ∂/∂t doesn't look like a Lie group.
 
5:27 AM
@DavidZ the difference between SE and other forums is that crap stays on other sites. But that was hilarious :D
 
5:46 AM
@JamalS I was reading this question physics.stackexchange.com/q/106605/66165 and saw your answer. Are you saying that the Dirac Lagrangian is invariant under a $U(1)$ transformation and that there is conserved current by Noether's theorem. What roles does the photon play in this?
 
 
1 hour later…
7:13 AM
@StanShunpike You need to study some group theory before this will really make sense, but in brief, the generator of a family of transformations $U(s)$ (where $s$ is the parameter) is the operator $A$ such that any transformation $U(s)$ can be written $e^{isA}$
The generator is kind of like the normalized derivative of the transformation
So any time translation $T(\Delta t)$ can be written $e^{i\Delta t\ \partial/\partial t}$
It gets a little more complicated when you're transforming in more than one dimension (like rotations in 3D space, they have 3 parameters), but that's the gist
 
7:41 AM
@DavidZ Do standard mathematics books cover group theory in a way that is useful to physicists? I have two books: A Book of Abstract Algebra and Topics in Algebra. I was thinking of getting one on Lie groups, but so far the abstract algebra books haven't really helped my physics, so I want to make sure I choose a book likely to improve my physics.
 
Probably not, though it depends on how you define "standard"
 
Yeah, that hasn't been my experience.
 
Actually I'm told that what physicists call group theory is really "representation theory" in the mathematical terminology
There's a book on Lie groups by Howard Georgi that is pretty popular among physicists. I've read some of it, it's not bad.
I've also heard very good things about a book by Wu-Ki Tung, but I don't have personal experience with that one myself
There must be a question for this ;-)
 
Lol should I just google resource recommendation and group theory? Yeah, representation theory isn't something I know a lot about and I definitely could use more info on.
That book list you put together was nice.
vzn pointed me to a bunch of great ones for CS. So far most book lists I have found have been through word of mouth.
 
Well google doesn't understand SE tags, but yeah, a search of some kind is probably not a bad idea
 
7:49 AM
@DavidZ That's entertaining... :)
 
@DavidZ btw I have increased my flagging and for the most part they have been accepted, so your recommendation to flag more often seems to have been effecfive. I didn't realize they were helpful. I was worried initially about "overloading" but that seems not to have been a problem.
@Waffle'sCrazyPeanut what kind of physics do you like?
 
@StanShunpike I like Astrophysics
 
@StanShunpike Yeah, very much not a problem here. On a large site like Stack Overflow they have more of an incentive to limit flags to the most useful ones, but here we get few enough flags that more are better
 
@tpg2114 Heh, apart from my academics, I'm doing great! C'mon, how did you even miss my long rant with Chris?
 
@Waffle'sCrazyPeanuts so are you one of those GR wizards? They use that for astro right?
 
7:54 AM
@StanShunpike What?!!! No, I'm not! Did you have a look at my profile? I'm just an enthusiastic amateur...
 
Lol I've met some pretty amazing amateurs on here :P
@Waffle'sCrazyPeanut why do you like astro?
 
@StanShunpike Well, I honestly dunno "why" I like astro... I've always liked stars & planets just like everyone else. That might be a reason. In fact, I have a strong belief that no one (AFAIK) dislikes astro (given its scale of interesting mysteries!)
 
I suppose that's true. Most of nature is interesting!
 
user54412
8:39 AM
@Waffle'sCrazyPeanut I think there's some truth to that. How could anyone dislike astro?
 
user54412
@StanShunpike Reiterating what David said:
 
user54412
Something useful to keep in mind: when mathematicians say "introductory group theory" they are thinking of stuff like the Sylow theorems. When physicists say "group theory" they really mean representation theory or module theory or linear algebra -- basically most of introductory abstract algebra except group theory proper. — Chris White Jan 16 at 19:21
 
user54412
Don't get a "group theory" math book and expect to find anything like what physicists use
 
user54412
of course, mathematical group theory is a great fundamental topic, and there's a reason many undergrad programs teach it first, before analysis or topology or representation theory
 
9:04 AM
@ChrisWhite yeah, I checked out the book David mentioned and it is a very different feel from a typical math group theory book. Much much better and more appropriate for what I am looking for. Do you have a text you like on this topic? He recommended I look around resource recommendations, which I plan on doing after I read a bit of the one he mentioned.
 
user54412
Alas not only can I not recommend such a book, I've never even looked at one, nor have I taken a course on this. All my physics courses skipped explaining rep theory, and my only math course on it was taught by some emeritus who went so slowly I think we defined "representation" just before the final
 
Ah well, I will keep looking. At least I have clarified these points. I couldn't figure out why the group theory books weren't being useful. Now I know why! Glad I bought cheap ones lol
 
 
2 hours later…
11:46 AM
@user929304 I'd be inclined to award the bounty to yess, if only to acknowlege the amount of effort put in. However I'm not sure yess' post constitutes an answer, as it's more of a general discussion about singularities.
Still, I do think it represents a valuable contribution to the site.
 
 
2 hours later…
1:42 PM
@JohnRennie I guess it just motivates the answer "it's not known"
@StanShunpike To understand what's going on I recommend a differential geometry textbook. The book by Lee covers this material quite well.
This "physics usage", however, doesn't really require understanding at all. The problem is just that Wikipedia pages are typically written at quite a high level.
@Waffle'sCrazyPeanut "just like everyone else" not me, really :P Sorry, @ChrisWhite, not a big astro fan
 
Hahaha, I was debating whether I should burst the astro people's bubble and tell them I don't really like it, and here you come
I don't have an active dislike of it either, though
 
I don't hate it either---it just doesn't do anything for me
I like to think of (contents of) the Universe as an everywhere homogeneous fluid.
 
2:48 PM
@DavidZ I am now alternating between laughing and weeping for humanity, thank you!
 
3:33 PM
@ACuriousMind laughter and crying activate the same area in the brain. There's like some threshold you cross and you change from laughing to crying. I believe they can induce this by electrical stimulation.
 
That's interested. I can imagine a web comic about this
Also, I guess we've all laughed so hard we had to shed a tear
 
@Danu Yep
@StanShunpike Don't come near my brain with your electrodes! ;)
 
@Danu I didn't realize Lee covered representation theory...
@ACuriousMind lmao
 
No representations, but generators
 
Meh. Yet another person who thinks that color is physics. I don't try to close those questions because they get told that by various pop-sci sources and introductory texts, but, bah!
 
3:43 PM
There is a physics approach to color
In fact, Schrödinger was considered an authority on the matter in the early 20th century, and it contributed to him being appointed as full professor in Zürich
 
@dmckee I think the distinction between spectral and non-spectral colors is physics, although rather trivial. At least it's not about optical illusion this time
 
See e.g. this paper
 
Yeah, I did know this
It's a shame, and a complicated matter
 
4:00 PM
@ACuriousMind does solving a QFT problem in the Heisenberg formulation generate an infinite-dimensional representation of the Heisenberg algebra? I believe solving a QM harmonic oscillator generates a 4-dim rep of it books.google.ie/… ?
 
@Danu I'm no expert, but that paper appears to be all about the properties of the function that maps response to perceptions.
In other words, it concerns itself with something happening in the brain.
 
@bolbteppa The representations are always infinite-dimensional, you can't implement the commutation relation $[x,p] = \mathrm{i}$ or $[a,a^\dagger] = 1$ on a finite-dimensional Hilbert space
 
It doesn't surprise me that physicist were the scientists to tackle the problem, any more than physics majors being good people to get for quants, but there is damn little physics in there.
 
The QMHO is also infinite-dimensional, it is spanned by the states with definite occupation number, after all, which are countably many.
 
@ACuriousMind This is a nice exercise, by the way
't was the first one in my MQM course
 
4:04 PM
@Danu Um...it is anything more than to notice that you get a contradiction if both sides are trace-class?
 
@dmckee Hmm, okay. I don't really know anything about it.
@ACuriousMind Yeah, the exercise was (i) show this, then (ii-iv) show that either $x$ or $p$ must be unbounded to get that commutation relation
 
@Danu I see, nice exercise
@bolbteppa What is 4D there is the algebra itself, but the dimension of the representation is the dimension of the representation space.
 
Yeah, you need some other identities for the rest
@ACuriousMind It never ceases to amaze me how "non-linear" the history of mathematics is: "Incidentally, Riemann had no notion of a topological mapping in his work." Whoa!
 
@Danu Heh, I read that and couldn't quite believe it.
It begs the question how weird our current conceptions will look in 100 years
 
:D
I do feel that the exreme period of axiomatization from the 20th century may have changed things a bit---making them more... regular
 
4:13 PM
@Danu Right, the basic notions will probably differ much less than between us and the "old" mathematicians. But, who knows?
 
5:08 PM
@dmckee Before I do this, I wanted to check with the higher powers -- can I copy a figure from a journal paper and put it in an answer (with citations of course)? One could argue it falls under fair use since the answer is to educate others, but since SE is a commercial business and gets the license of the answer and the figure would make up the majority of the content of the answer, fair-use wouldn't apply
I suppose I could like... trace over the lines or digitize some data points on the plot and replot it myself or something, but that's a lot of work and I don't really want to answer this question that badly
 
@Danu can you or somebody please unfreeze that chat room? I forgot to keep it alive and we might still need it.
 
@Dilaton I'm not sure if it's my position to do this---perhaps ask one of the PSE mods.
@ChrisWhite or any other GR whizz (Jerry Schirmer?): Would any of you know anything about the history of the GR energy conditions? There's a question on HSM about it, and it's even received a bounty but it appears to be hard to answer
5
Q: Who created the energy conditions?

RammusThe earliest text I've been able to find that explain the GR energy conditions is "The large scale structure of space-time" (1973) by Hawking and Ellis. However in Barcelo and Visser's paper "Twilight for the energy conditions?" they speak of the trace energy condition which was popular in the ...

 
@Danu I think we even migrated that there
Yep, we did
 
Yeah, that's true, but it appears nobody knows how to answer it
Plus there's a pretty big chance some people missed it :D
 
5:23 PM
What, you mean there are people who don't check every new question? I am shocked!
 
Lol I just played someone on chess.com called "hahnbanach"
 
5:54 PM
@Danu as stated in a comment by Qmechanic here, that chat room is one of the two places officially dedicated for discussions about a certain topic. To serve that purpose, it should be hold in an unfrozen state. I just was too distracted to hold it unfrozen by regularly posting something.
Pointing out a frozen chatroom for discussions to happen would be very zynical, so I am rather sure that unfreezing it is not controversial ...
 
6:07 PM
@Danu BTW I got the suspicion that PSE mods are ignoring me (technically, by choosing this option) in the hbar, so they will probably not see my message.
 
6:29 PM
@Dilaton Unfrozen, as per @Qmechanic's comment I think it is reasonable.
 
7:09 PM
On pages 3-4 in Landau vol 3, he explains why we can't have velocity in QM, but I don't get what he is saying. He says "Let us suppose that, at definite time intervals $\Delta t$, successive measurements of the coordinates of an electron are made. The results will not in general lie on a smooth curve.
On the contrary, the more accurately measurements are made, the more discontinuities and disorderly will be the variation of their results, in accordance with the nonexistence of a path of the electron. A fairly smooth path is obtained only if the coordianfes of the electron are measured with a low degree of accuracy, as for the instance from the condensation of vapour droplets in Wilson chamber.
If now, leaving the accuracy of the measurements unchanged, we diminish the intervals $\Delta t$ between measurements, then adjacent measurements,
of course, give neighboring values of the coordinates.However, the results of a series of successive measurements, though they lie in a small region of space, will be distributed in this region in a wholly irregular manner, lying on no smooth curve. In particular, as $\Delta t$ tends to zero, the results of adjacent measurements by no means rend to lie on one straight line."
Can someone explain this more simply to me?
(^ that's my question)
 
user54412
@tpg2114 That's a sticky issue. My guess is technically it shouldn't be done, but I'll admit to doing it once or twice. In my (moral if not legal) defense, I did it with papers that are freely available online anyway.
 
@tpg2114 @ChrisWhite that's not fair use. My dad is a professor of copyright law. Doesn't mean I'm an authority, but I'm almost postive that's not a legitimate application of fair use.
 
user54412
@StanShunpike Every time you measure position, you force the particle into a position eigenstate, which obliterates any bias toward one or another momentum eigenstate you may have thought it had.
 
What does he mean by a smooth curve? Does he mean like double slit on a wall?
 
user54412
If you sampled a particle's position arbitrarily and found the samples to approach smooth curve as you increased the sampling rate, why then you'd have a hidden variable that's unaffected by your measurement.
 
user54412
7:20 PM
@StanShunpike A path through space
 
Huy
Hey there, is there some application you could recommend to create figures like these?
http://imgur.com/BGZYud9
 
@StanShunpike $\delta p \delta x \sim \hbar$?
 
@Danu @ChrisWhite I get it now. Grazie!
 
@Huy Feynman diagrams? There's a package for it.
 
user54412
@Huy So Feynman diagrams? I don't know any off the top of my head, but I'm sure they exist. Also, you could do that with a number of different general-purpose latex packages or vector image routines.
 
7:23 PM
Feynmp is what I use
it's actually kinda convoluted to use it
(took me ~6 hours to get the hang of it)
(I'm not very good with computers)
 
Huy
@Danu: I'm pretty sure I already tried it but didn't manage to get it to work the way I wanted to. :s
 
@Huy A (slightly crappier) option is the application JaxoDraw
which makes things a lot easier but I didn't get it to fully cooperate with latex, so I had to just import pictures all the time.
(I used this for my BSc. thesis)
but feynmp is a lot better once you get it
 
user54412
@Danu I don't know. Actually, it's hard to look up energy conditions, because many authors don't refer to them as such (I think this is slowly changing). They just state something like "We assume $T_{\mu\nu} \xi^\mu \xi^\nu \geq 0$ for all timelike curves $\xi$" and leave it at that.
 
Huy
I'm fine with importing pictures all the time, too.
I'll check both out again.
 
@ChrisWhite Aye
Then by all means go for JaxoDraw @Huy
it's a lot easier
 
7:33 PM
@StanShunpike I was also leaning towards it not being fair use also which is why I didn't include it...
 
@tpg2114 sounds like you have the mind of a copyright lawyer ;)
He also says, "Since all quantities calculated by means of the wave function, and having a direct physical meaning, are of the form $\int \int \Psi(q) \Psi^*(q') \phi(q,q') dq dq'$, in which $\Psi$ appears multiplied by $\Psi^*$, it is clear that the normalized wave function is determined only to within a constant phase factor of the form $e^{i\alpha}$ (where $\alpha$ is any real number), whose modulus is unity.
@Danu why is this?
I don't get where the idea of a phase factor comes from...
 
user54412
@StanShunpike Forget about integrating over space. Just look at one point. The wavefunction there is a complex number $\psi$. Physically, all that matters is $\lvert \psi^* \psi \rvert$. This is left invariant under transformations of the form $\psi \mapsto \mathrm{e}^{\mathrm{i}\alpha} \psi$ for real $\alpha$.
 
@ChrisWhite Why is it invariant? I get the idea that the wave function at a point is a complex number. Also, $\Psi^* \Psi$ is a real number. But how can $(a + ib) = e^{i\alpha}(a+ib)$? That only makes sense if $\alpha = 0$...
 
user54412
@StanShunpike $\psi \neq \mathrm{e}^{\mathrm{i}\alpha} \psi$, but $\psi^* \psi = (\mathrm{e}^{\mathrm{i}\alpha} \psi)^* \mathrm{e}^{\mathrm{i}\alpha} \psi$.
 
Oh, duh!
Nice! I never got that. That's awesome!
 
7:55 PM
Woah, a single toy may have ruined lots of brains finance.yahoo.com/news/…
Okay -- obviously overly dramatic just because it's a news article, but it's still kind of crazy
 
@tpg2114 have you heard of spatial sequence synesthesia? synesthesiatest.org/blog/spatial-sequence-synesthesia pretty crazy too
My Landau book is so old I can't tell what is a $\bar{f}$ and what is a $\hat{f}$
@0celo7 you watchin march madness or nah?
 
8:24 PM
@bolbteppa Landau is awesome :D
 
@tpg2114 I don't feel able to advise you on IP issues. Generally you can take 1 figure under fair-use (this was the rule of thumb they gave me for my dissertation). However, if the figure is the main part of the work fair use may not apply.
 
8:37 PM
Hey guys i have been watching vlogs about people's experience of Phds and all people describe it as really bad process. Any thoughts? Any of you having or perusing a phd that thinks otherwise?
 
@GeorgeSmyridis A PhD is hard. Don't kid yourself.
But I had the support of not only my advisor and the other professors in the nuclear and particle physics group at my school, but also of the department secretaries (don't underestimate the value of that!) and the department head.
So the pain and difficulty was only what was inherent in the process.
Even so, you will despair at some point.
It is your peers who will get you through that.
 
9:20 PM
How many different models do I need to be familiar with to have a decent basic knowledge of QM? are particle in a box, free particle, and quantum harmonic oscillator the primary ones? Those look like the main ones Griffiths covers and, when I was at Caltech, those were the ones we discussed. But I don't really get why these specific ones are preferred.
@ChrisWhite going back to the phase factor point, is this why ACuriousMind mentioned that the probability amplitude has a DOF the probability density doesn't?
 
user54412
9:32 PM
@StanShunpike Probably
 
user54412
There's also another degree of freedom in that we can scale all our wavefunctions by the same number (not necessarily with unit modulus) and get the same physics, but we often just deal with normalized wavefunctions to get rid of that degree of freedom
 
@Danu thanks! I will try to be more careful to not let it freeze again.
 
@StanShunpike This stuff is exactly what I mean when I say you may be getting ahead of yourself doing QFT---no offense intended!
@GeorgeSmyridis What can I say... everybody loves to complain ;)
 
!! interesting
 
10:32 PM
@StanShunpike he's trying to explain why 'the concept of the path of a particle' does not exist in QM. He says that if you make a sequence of exact successive measurements the resulting points will not lie on a curve but will be scattered about randomly, however if you measure with less and less accuracy it will start to look like a path is forming
 
Is it obvious that the squares of numbers modulo $p$ where $p$ is prime take on only $\frac{p+1}{2}$ distinct values?
 
No
 
Hmm, my book states it without justification in a proof of a lemma
 
It's probably mentioned somewhere earlier, that is definitely a theorem somewhere
 
Hmm, I don't think so.
There was only one section focusing on $\mathbb{Z}_p$ thusfar
 
10:39 PM
If it's a group theory book they may have assumed it as a number theory theorem you should know, but it's not obvious to me (though nothing in n.t. is)
 
It's an algebra book---not group theory specifically.
A Course in Algebra by Vinberg
(proof of lemma 5.57)
 
He was probably born knowing that theorem man
 
Or wait, I am probably reading it wrong.
...yup
You know, asking things "out loud" is really the best way to force yourself to really pay attention... lol
Embarrassment is the only way!
Wait... I don't know anymore...
...I guess it really isn't all that important right now either, so I'll just leave it for now and try to look at it again later... or hope for someone here to solve it ;D
 
That's not obvious to me man
 
Damn modular arithmetic
Robbin' me of my intuition
 
10:52 PM
Ask in the math chat
I'm quite sure that this is extremely obvious to those guys lol
 
Idk, I have some not-amazing experiences over there plus I'm not sure if it's worth spending a lot of time on right now :P
 
Man Vinberg's derivation of the commutator is what I've been looking for forever
 
I'm not there yet ^^ Where is it?
 
and the adjoint!
Lie groups section, page 482
 
Well glad you found something you like in there! A very enjoyable book in general
The derivation my diff geo prof gave this semester was nicer IMO
much more general, IIRC
Oh yeah, it was introduced to make the space of derivations of an algebra into an algebra
 
11:01 PM
That's not nicer!
 
In Arnold books.google.com/… he mentions that time is a map from $t:\Bbb{R}^4 \rightarrow \Bbb{R}$. I am used to thinking about time as just $\Bbb{R}$ and space as $\Bbb{R}^3$. Can anybody explain how my notion of time relates to his?
 
That is random and out of the blue
 
@bolbteppa Heh
 
It's a shame he didn't give a similar derivation of the Jacobi identity
 
The Jacobi identity seems... just meh
Never seen a beautiful derivation of it
 
11:03 PM
There is the nicest derivation of that fucker I've ever seen in Schwinger's particles, sources and fields
 
Although Arnold is famous for saying it's related to a theorem from Euclidean geometry
@bolbteppa Lol. He does that in there? Where? Also, why'd you read that book
(or series rather)
 
You know the way $U^{-1}TU$ is the change of basis of $T$ to find something equivalent to it?
 
Sure
 
If you replace $U$ with $U = U_{[1,2]}$, where $U_{[1,2]}$ is the group commutator $U_2U_1U_2^{-1}U_1^{-1}$, and then expand $U^{-1}TU$ to first order you get the Jacobi identity
But I'm sure you could give a Vinberg (12.16) style derivation of it too now!
 
@Danu Re the QFT thing....Most of my time has been spent learning the basics of differential geo and QM. Those are the areas I think I need the most work.
 
11:10 PM
@StanShunpike it's just a way of defining spacetime, obviously he is defining Newtonian mechanics that way so he can make it as similar to special relativity as possible
 
Yeah @StanShunpike and it's just a more formal way of defining what time really is. Your problem is that you're still thinking in coordinates
(as pretty much all physicists)
But the spacetime manifold exists independent of your coordinates and so something like "time" must be defined as a map from the manifold
not as something in the definition of the manifold itself
 
Ah, that makes sense.
:)
 
If the group commutator $U_{[12]}$ is the group element that converts $U_1U_2$ into $U_2U_1$ then what is $U_{[12]}TU_{[12]}^{-1}$ intuitively?
Whatever it is, it's first order expansion gives you the Jacobi identity
 
How do you get an equality sign in there?
What do you set it equal to
 
idk but I know it can be done lol
 
11:19 PM
hahaha
 
That is Schwinger for you
 
Physics ftw
 
He gives it in crazy notation
Conceptually it's the best thing ever, computationally fuck...
I believe his approach to QFT is no different lol
 
I still cant sync this with Arnold's trianglles
 
11:21 PM
I think if you get it it's awesome
I just don't get it
 
haha
perfect
 
I also never really tried, but ok
 
me neither and that proof is not nice
Woah...
I think I just got it
Using Schwinger + Vinberg"
!!!
fukkk... it's so obvious
 
It sounds like the shrooms just kicked in
 
I can't even put it into math though haha
But it's like, if you look at Vinberg, $\frac{\partial }{\partial t}$ is moving along one side of the triangle, then applying the $\frac{\partial }{\partial s}$ is like the other side of the triangle, and then the thing on the other side of the equality (Schwinger's thing) gives you the third side of the triangle
I'll write that up better someday and beat that guy's little note! :D
 
11:28 PM
The note is bad, huh? :P
 
@Danu What up, D?
 
Not too much; reading my algebra book
will probably go to sleep soon, D
 
Algebra, eh? Sounds like a good way to get yourself to sleep.
 
I really really love some parts of it
The chapter on polynomial algebra---not so much
I ended up skipping the later sections in it because it just got way too boring
the chapter on (finite) groups was fun, and now the one vector spaces is mmm not too bad
 
I didn't finish my math minor because of how horrible the algebra course was.
 
11:32 PM
@StanShunpike Print quality is a common issue with the Landau books. I suppose nobody bothered to TeXify them and they're just basically printing scanned copies. The worst print quality I've had in a book was in one by Gibbs. I suppose it's out of copyright and anyone can print it; The one I bought, online, was probably scanned and then resized, so it's a mess. I can't imagine trying to read more than a page at a time. At least it was almost free.
 
@Danu: It was the Sylow theorems that killed me.
 
This is quite elementary---Sylow theorems not covered in the chapters I've read thusfar
 
@alarge The scanned and resized books are awful. I realized a lot of sketchy companies do it instead of high quality printers.
@alarge Speaking of shady printing, my uncle gave me John Lee's Introduction to Smooth Manifolds hardcover by springer. The back fell off after 2 weeks of barely using it.
 
@Danu: Ah. I suspected that was one of the problems with my course: we covered too much too fast. We had gone through rings, Sylow theorems, and a bunch of other stuff and still had linear groups and modules on the list in a single semester. Too much.
 
Yeah, sounds like crap
@StanShunpike Wow, that sucks
 
11:38 PM
@Danu I know! I was like...really? cmon man
 
@StanShunpike I rather regularly use the "sketchy" companies, as they offer stuff at a much cheaper rate. The reason being that the books are meant for the third world markets, like India etc. The printing itself is rarely an issue, but they do use thin, recycled paper which might bother some (but then again, this makes the books lighter and thinner usually, so my bookshelf can hold more information per kilogram).
 
Bookshelf information density lol
Such a 20th century concept ;)
 
True true. Apparently, for some law books, some companies have had the idea of only loaning you a paper copy and "giving" you the digital version with the requirement you mail the paper copy back.
That's one problem I have with the digital books. How do you ensure control over ownership? Obviously not a problem if you are given a PDF but for ones that require a portal so to speak, it doesn't seem nearly as good as the paper, at least to me.
 
Whoa, what a rip off
 
@Danu I don't really like reading stuff on tablets. Unfortunately, because this makes my bookshelf rather large.
 
11:43 PM
@Danu Right? So I think some of the schools then boycotted using those books, which makes sense because it's obviously a gyp.
wow, I didn't know gyp was spelled that way
I thought it was jip...and jipped
weird
 
Could it be from the (racist) "gypsy"?
 
yeah, that's what i'm thinking too. huh never knew that
 
yeah, google-fu tells me that's the case. Kinda sad
 

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