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13:44
Whoa @NatStapleton getting creative with the profile pic. =P
14:05
Nat, what is that? Is it a piece of art somewhere?
Makes me think of like, Mark Rothko, or one of those guys.
it's a stapleton original
Oh really?? So cool!
Upon close inspection it looks like maybe it's a print rather than a painting?
14:30
Blerg.
0
Q: Topological quotient Hopf-algebras and "change-of-rings"

Jon BeardsleyOne way of constructing coalgebra objects in the homotopy theorist's category of spectra is to take the suspension spectrum of a space, with the diagonal providing a cocommutative comultiplication. If, moreover, we assume that the space (call it $X$) of interest has some suitably coherent multipl...

14:55
So - can I think of a Thom spectrum as some sort of twisted tensor product? In other words, $MU$ is something like a twisted version of $\mathbb{S}\wedge BU_+$, twisted by some cochain or something... $\mathbb{S}\wedge_{\phi} BU_+$?
This is of course again inspired by the fact that given a good enough fibration of spaces $F\to E\to B$ we can find a chain equivalence between the singular chains on $E$, and a twisted tensor product of the chains on $F$ with the chains on $B$
And of course the observation that we can think of $MU$ as being some kind of bundle over $BU$ with fiber $\mathbb{S}$.
Hm, maybe this is more or less the content of the ABGHR papers.
@NatStapleton very cool!
it is a graphical representation in terms of explicit homotopies of the maclane pentagon
 
2 hours later…
16:40
@AkhilMathew It depends which spectrum you're working over, but my understanding is that you guys were discussing MU.
(sorry, @JonBeardsley too)
Say you have a "descent diagram": (homotopy) coCartesian section of modules over the cosimplicial diagram {MU --> MU^MU ---> MU^MU^MU ---->...}, call it {M^0 --> M^1 ---> M^2 ----> ...}.
Suppose M^0 is a perfect MU-module, so that it's a candidate for being MU ^ X for some finite complex X.
Let X = Tot {M^0 --> M^1 ---> ...}. I claim that smashing X with {MU --> MU ^ MU ---> ...} recovers our cosimplicial object.
The main components that make this go are the following:
(1) Because MU ^ MU -> MU is 2-connected, the Tot-diagram has a pretty large "vanishing line" in the sense that the fiber of Tot^n -> Tot^{n-1} has connectivity that grows linearly in n.
(2) Next, because MU, M^0, and hence all the M^i are of finite type, so is X.
Together these tell me that smashing with MU moves inside Tot.
Hang on.
Sorry, I have lost the remaining thread of the argument for now -- it is roughly the same as showing essential surjectivity for faithfully flat descent.
I believe that after smashing with MU, it becomes a module over the augmented cosimplicial diagram of rings {MU -> MU^MU --> MU^MU^MU --->}, which is degenerate; this is equivalent data to simply having an MU-module.
Serves me right for trying to do this on the fly. I can try to come back and fix this later tonight if anybody is actually interested.
The last step is observing that, because MU ^ X ~= M^0 is a perfect MU-module, HZ ^ X ~= HZ ^_{MU} M^0 is a perfect HZ-module, which is true iff X is equivalent to a finite complex.
17:42
@TylerLawson I'm extremely interested. So you're proving that S-->MU is of effective descent for finite complexes?
18:30
@NatStapleton haha i like that, "art1.jpg"
so apparently the feynman diagram expansions of certain integrals over spaces of hermitians matrices can be interpreted as a sum over (triangulations of?) compact surfaces. does anyone know a conceptual explanation of this?

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