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00:01
its primary flaw is its almost total disorganization, but i don't have any idea how to go about usefully organizing it
thanks, it appears to have arrived safely and now we will see if my internet connection can handle it
I had to do a bunch of things to get more Dropbox space as well. Currently used 2.4 GB of which most is the shared folder
yes, it's a good thing I don't have many coauthors using dropbox anymore or I might be running up against space limits soon
I have 15 GB on some other file-sharing thing called 'Copy' but I'm not sure how useful that is.
Out of interest how do you generally handle the co-author thing if not dropbox (or equivalent)?
Do you make people use Git?!
or hg
i can send you a bitbucket referral
they have free hosting for academics
00:10
Geometric Invariant Theory?
works pretty well
It seems like I'd rather just like, send e-mails back and forth. Having one dropbox seems like it could get really messy.
github would be the alternative, though I don't know if I can get private repositories from them
That way you have a record of all changes over time.
dropbox is ugly if anybody wants to edit at the same time
00:11
Right.
I believe I have bitbucket. Don't know how to use it though!
things like git + hg do keep a record of all changes.
Oh that's good.
you have to pay github a small monthly thing to get private repositories
Dropbox has very rudimentary revision control
00:12
they let you roll back, and can automatically do merges if multiple people edit disjoint parts of the same document
But enough so that it's saved me before. But yeah if two people are working at the same time...
I could see that being an issue
it means that when you push out a revision you don't really create any work for anybody in trying to incorporate it, or save it etc
I think my plan was always to use a repository for my hypothetical thesis, and so one day out of procrastination probably I signed up and tried to learn how to use it
Like I tried to learn emacs.
learning emacs + git + bitbucket + etc would probably be very effective procrastination fodder
Is there any known theory of constructing moduli spaces for, say, all possible actions of a given monoid $G$ on an object $X$? That is, all possible group actions $G\times X\to X$ in some category?
00:18
@JonBeardsley: this sounds a bit like stuff that Blanc, Goerss, Turner, Johnson etc might have thought about.
Hm, who are Blanc, Turner and Johnson?
Niles Johnson?
no, mark johnson
look up david blanc on mathscinet
Hm, there appear to be perhaps various pieces of what I'm talking about there in different guises. Maybe.
yeah, they talk about maps between diagrams.
a space with a monoid/group action is a diagram of a particular shape.
Yeah, I'm trying to think about it in that way. I mean, you can probably phrase it as an equalizer.
Like, equalizing the necessary maps, but then how do you compute this thing you get in the end.
00:24
it is a bit easier than that though, right? a monoid or group is a category with one object, a diagram is a functor from a category of a particular shape...
Does anyone know anything about Bousfields notes on simplicial commutative rings from Brandeis?
@TylerLawson hopf is down? Why?
@SeanTilson I don't quite follow. I have a monoid $M$ in a simplicially enriched category $C$ and an object $X$. I can certainly see how I can get the moduli space by looking at a certain subspace of $C(M\times X,X)$, and by looking at it via some equalizers. But how is this related to $M$ being an internal $C$-category with 1-object
Like, how can I realize this as a map of diagrams in $C$?
I guess I wasn't talking about the moduli space yet. I was talking about how to look at objects with M action as a diagram.
The usual way of looking at that moduli space is typically by looking at some pullback.
I might be thinking of something else though.
Hm, I said equalizers, but perhaps I mean coequalizers.
That is, I've got two maps $C(M\times M\times X,X)\to C(M\times X,X)$, one given by $M$ acting on $X$, and one coming from the multiplication on $M$, and I want to coequalize these, etc.
Have you read Johnson-Noel's paper on obstruction theory?
that might help.
Hm. I'll check it out.
Hm, yeah, I think perhaps these are the sorts of thing I want to think about, I just want to, in my particular case, replace their monad $T$ with a comonad. Interesting.
Wow, I don't know when this stuff of Johnson and Noel was done, but it either anticipates or works very nicely with Kathryn Hess' stuff.
I mean... they're totally computing descent spectral sequences... sort of. Or like, well, I should say descent spectral sequences are an example of what they're talking about.
00:47
@SeanTilson no idea
01:13
have you guys ever played QWOP?
ugh. yes.
Ha. 2.2m!
yeah it's verrry hard
you have to do a sort rolling motion with the QWO
er
QWOP
01:28
operads @_@
lol. dude operads are awesome.
like... all that data in one spot.
What does it mean for an object to be compact in the homotopy category again?
There's something called the spiny cactus operad.
@Drew K(n)-locally or not?
(can't remember if there's necessarily a difference)
Not. I'm trying to unwind this statement of AKhil: "(More generally: Given any symmetric monoidal category, if the unit object satisfies some categorical property, then so does any invertible object. This is useful in other contexts. Example: any invertible object in the stable homotopy category has to be a finite spectrum, because finite spectra are the compact objects; from here it's not too hard to conclude that the invertible objects in spectra are the spheres.)"
It'd be nice to figure out the exact argument because the usual proof the Pic(S) = Z is kind of hard.
There is also the "cleavage operad"
I would say that he might mean that finite spectra are the spectra in the thick subcategory generated by the sphere spectrum.
01:36
idk if category theorists have coopted the word to mean something else, but i think compactness should mean that a map to a cofiltered colimit factors through the colimit of a finite stage
Ah, that's a good point.
Oh OK. Maybe I can just avoid it, since compact = finite for spectra anyway apparently
In the triangulated homotopy category of spectra (not localized anywhere) these coincide, I believe.
there is also the word 'small' which means something not dissimilar to this
Yeah. Small, I believe, concerns something about distributing out of homs or something
01:38
Right. Hovey-Strickland like small.
Yeah, all these things are given precise definitions in Axiomatic Stable Homotopy Theory (awesome book!!), but you never really know what people mean when you talk to them.
so for a map of rings R->S, we get a comonad by forgetting S-module structure then tensoring up with S again right?
what's the counit of this comonad?
there's a map M (x)_R S --> M (x)_S S since the tensor over S identifies strictly more stuff
i guess the slightly nicer thing to say is that there's a natural transformation of cospans [M (x) S <-left-act-- M (x) R (x) S --right-act-> M (x) S] ==> [M (x) S <-left-act-- M (x) S (x) S --right-act-> M (x) S] induced by applying f to the middle argument, and so a map of pushouts, which are the tensors over R and over S respectively
i think i am finally coming to terms with the operadic two-sided bar complex
01:54
lol
turns out operadic modules are highly asymmetric, that's been the biggest roadblock
hmmmm. sounds ugly.
idk, it's not, it's just highly misleading if you skip all the introductions to all the papers and keep saying 'ya sure i know what bar complex is, i know what tensors are, come on'
Ohhhh, haha!
Yeah, that sounds like the sort of thing I do all the time.
well here's your warning: it won't work if you're trying to learn about the operadic bar complex
01:59
:-)
speaking of, here's something that's been bugging me....
for a comonad, you get a simplicial object, using the coaction, and the counit.
but.... so then... the resolution of MU, giving us the ANSS, is coming from... a cosimplicial object?
which is coming from the two ways of mapping MU into MU\wedge MU
etc.
so... this is not the standard resolution associated to a comonad??
(in particular, the free forgetful comonad MU-mod-->MU-mod)
it is the standard resolution associated to the monad X |-> X ^ MU, which is the other order of applying those push-pull adjoints you were asking about a bit ago
Hm... okay. So this is being constructed in the category of S-modules.
(rather than in the category of MU-modules, that is)
Okay, I guess that makes sense. Yeah. Great.
02:29
Should have checked nLab: ncatlab.org/nlab/show/compact+object
Basically what Eric said (not that I doubted you!)
well i doubted me, so
what's an instructive example of a right module for an operad
if you have an algebra for an operad, you can build a left-module by taking the constant symmetric sequence at the algebra, and then the left-module structure maps look like P(j) (x) C^{(x) j}, which has a natural map to C using the algebra map
and i think if C is an operadic algebra, then you can make the sequence M(j) = Maps(C^{(x) j}; C) into both a left- and a right-module for the operad
but that's not very useful i feel for knowing how i should think of a right module
What about like, E_\infty mapping into the endomorphism operad of X? does that make End(X) into an E_\infty-module?
I don't really know anything about these things.
in the sense i just outlined, yeah, but that's not very instructive
it would be excellent if a module M for an algebra A over an operad P could be made into a right P-module to sort of fill up the other slot, but i suspect that's not how this goes
02:41
i may be misremembering, but I feel like the n-sphere is a right module for the little n-cubes operad
Google gives a whole book on modules for operads: math.univ-lille1.fr/~fresse/OperadModuleFunctors.pdf
There is probably something in there for the patient reader
ha, "Part II: The Category of Right Modules"
more precisely, maybe what I mean is that the symmetric sequence which, in degree k, consists of a wedge of k copies of S^n acted on by permutation
02:46
Is there a calculation of K_0 of the K(1)-local stable homotopy category?
Just reading now, there is a map from Pic_1 --> K_0^\times
interesting question
03:28
progress! i've disconvinced myself that i understand the koszul morita equivalence functor in terms of operadic co/bar duality. i think out of chat.stackexchange.com/transcript/message/12220918#12220918 , 1 and 2 are captureable: the bar complex in 1 is the operadic bar complex B(1; P; 1), and the bar complex in 2 is B(1; P; A), where the P-algebra A is considered as a left-P-module. where does an A-module M fit into this? the classical bar complex B(k; A; M) seems a level removed...
03:53
Oh I think I said a lie. The notation K_0 was meant to denote the Grothendieck group ring of isomorphism classes of dualizable objects. Confusing notation.
04:22
Hi @Drew, I think the statement that the Picard group of the stable homotopy category is $\mathbb{Z}$ can be proved as follows: first, you argue that an invertible spectrum is compact, e.g., because the sphere is compact and tensoring with an invertible spectrum (as an autoequivalence) preserves compact objects. Now you need to show that the homology of your spectrum is $\mathbb{Z}$ concentrated in one dimension. So "tensor up" over $S^0 \to H \mathbb{Z}/p$ (i.e., consider mod $p$ homology).
Invertible objects in $H \mathbb{Z}/p$-modules are concentrated in one dimension since you have a K\"unneth theorem; now all that's left is to see that everything fits together at each prime. More generally, this argument can be used to show that the Picard group of modules over a connective $E_\infty$-ring (with $\pi_0 $ noetherian and connected, say) is given by the Picard group of $\pi_0$ times $\mathbb{Z}$ (for suspension).
One way to streamline this argument is to use the theory of flatness for modules over connective structured ring spectra. There's a nice criterion for flatness: if $A$ is an $A_\infty$-ring with $\pi_0 A$ noetherian commutative, then an $A$-module $M$ is flat if for every field $k$ equipped with a map $\pi_0 A \to k$, the relative tensor product $M \otimes_A k$ is discrete.
@AkhilMathew: Thanks! That's really nice. The Hopkins-Mahwoald-Sadosfsky argument by induction over the Postnikov tower always felt too complicated
This lets you argue that, in the connective case, invertible objects are automatically flat (which means that the Picard group is "algebraic"). I think this argument (more or less) is in a paper by Baker-Richter "Invertible modules for commutative S-algebras with residue fields."
I'm not sure I ever understood the HMS argument.
It's slightly expanded on by Strickland in his 'p-adic interpolation' paper
At least I think its meant to be the same argument
Interesting, I'll take a look.
I think in a fit of excitement earlier, I sent Niles Johnson an e-mail that didn't make any sense.
04:29
Ha! Email is so permanent.
Yeah, I just went back and read it and was like "What the hell am I talking about?"
Ugh. And it just makes you seem crazier if you send a follow-up e-mail telling the person to disregard your last e-mail.
@AkhilMathew How does one show that the map Pic(R) -> Pic(pi_0 R) is surjective for general connective R?
Hi @TylerLawson; I think you can argue this way: an element in $Pic( \pi_0 R)$ is projective, and any projective $\pi_* R$-module can be realized by an $R$-module (by explicitly writing it as a retract of a free $R$-module).
So in particular, I don't think one needs connectivity for this to happen.
Ah, yes. Thank you.
Hey guys, what's this about the homotopy fixed points spectral sequence being a descent spectral sequence? Is that a thing?
(In other words, can I think of it as a Galois descent spectral sequence for a possibly non-faithfully flat extension?)
04:36
@JonBeardsley, in what setting?
Hm. That's a good question. I guess I'm thinking about this setting of Johnson and Noel's. Where they construct these obstruction spectral sequences for lifting maps up to maps of algebras over a given monad.
In particular, I think one can take the free/forgetful adjunction for having a $G$-action.
But, as I'm typing this, I'm not sure, I think I'm off somehow.
This spectral sequence they get seems like it should be the descent spectral sequence for some kind of generalized monadic descent situation.
Or rather, perhaps codescent. Since they're going from C(A,B) to C_T(TA,TB)
Whereas descent spectral sequences go the other direction.
Okay. I think I'm probably just on a role with saying things that make zero sense tonight. I mean, I frequently babble, but this is getting out of hand.
I need some sleep. And then coffee. And then I need to think hard for a day or two before saying anything else.
@JonBeardsley, I think there is an interpretation: if G is a finite group, the category of G-objects in a category is equivalent to the category of sheaves on the category of finite G-sets (where the topology is based on epimorphisms). The global sections are given by fixed points. If you do this in homotopy theory, I believe that the descent spectral sequence you get is the HFPSS.
04:52
@AkhilMathew Where if we call the category C, you mean C-valued sheaves?
Right, so we can think of global sections in this case as being something like descending along a cover of the terminal object with trivial G-action or something (I guess the point, in this case). But to do more intermediate pieces, we actually get an intermediate descent spectral sequence, something like a Galois correpondence.
Ah yes, where we look at fixed points under some subgroup. Fantastic.
Yes, that is what I should have said.
Thanks! I like that interpretation.
:-)
Now, suppose we have a Galois extension of rings $R\to S$ by $G$. I want to say something like the category of descent data here is equivalent to the category of $S$-modules with $G$-action, but this is entirely by analogy, so I'm not sure that's accurate. The HFPSS for a module $M$ (with some given $G$-action, i.e. a descent datum) gives one the $R$-module that $M$ descends to. But we can think, as you say, of descent data as being something like (for a suitable site based on $G$)
$S$-mod valued sheaves.
And I want to say something like $R$ is the terminal object on this site. Hence what I'm really doing by computing HFPSS if evaluating my sheaf's global sections.
@JonBeardsley: the category of descent data is not quite that, since the G-action won't be in the category of S-modules; it'll, rather, be the homotopy fixed point category for the G-action on the category of S-modules.
Hm. Okay, how does G act on the entire category?
The action of G is by "twisting" the module structure.
05:06
And there is a way to do this uniformly across the entire category?
E.g., in algebra, there's a complex conjugation on $\mathbb{C}$: this induces a $\mathbb{Z}/2$-action on the category of $\mathbb{C}$-vector spaces given by $V \mapsto \overline{V}$.
The homotopy fixed points for that action are given by the category of $\mathbb{R}$-vector spaces (by Galois descent).
Oh, I see what you're saying.
One way to say this: the association $A \to \mathrm{Mod}(A)$ is a functor from rings to categories.
Okay. Yeah, alright. Since Galois descent is faithfully flat, the category of descent data is going to be equivalent to the category of modules over the source of the extension.
Yes (though some of the objects that are called "Galois extensions" in homotopy theory are not faithfully flat in any sense)
05:09
Well, yes exactly.
And that's what I'm getting at. In that case, the category of descent data shouldn't be the fixed point category, right?
Or.... is it? But the fixed point category is not equivalent to the category of modules over the source ring?
The "homotopy fixed point" construction on the category is exactly another way of writing down the descent data.
Yes, it's the latter: the fixed point category won't be the category of modules over the source (fixed point) ring.
Okay. I don't suppose this sort of thing is written down somewhere? Your paper maybe?
I don't really know what to think when you say "homotopy fixed point construction."
I'm not sure where this is written down (Lennart and I make a quick reference to it), but it certainly the idea of Galois descent is very old (at least going back to Grothendieck), though algebraists probably don't say the phrase "homotopy fixed point category."
Here's how I'd think of the homotopy fixed points: if you have a set S, with an action of a group G, then the fixed points S^G are those s \in S with gs = s for each g \in G.
In other words, my category of descent data should be something vaguely reminiscent of either "matching families" or "coalgebras over a comonad" or something, so I'm just not seeing where that's coming from.
Now if you're thinking higher categorically, saying gs = s (where s is an object of some category) is not what you're supposed to do: instead you have to say that gs is isomorphic to s, and choose an isomorphism.
You also want to choose the isomorphisms gs \simeq s to satisfy some coherence (cocycle) conditions. The collection of all possible choices (objects s, plus isomorphisms as desired, plus coherence -- and even higher homotopies if you're in a $\infty$-category) is the homotopy fixed point category.
If $R \to S$ is $G$-Galois, then you can identify the descent data along that adjunction with the homotopy fixed points for $G$ acting on $S$-modules.
To see that, you have to identify the cosimplicial (cobar) complex you get and identify that with the cosimplicial construction for computing homotopy fixed points (using the Galois property).
05:20
Okay. Alright. So, in your statement, by analogy, the "set" should be the category of $S$-modules?
Yes, that's right.
(sections! sections over BG!)
Alright, and can you say what you mean by "the action of $G$ is by twisting the module structure"?
I mean, I take a twist of an object $M\otimes_R S$ to be some other $R$-module $M_0$ such that $M_0\otimes_R S\simeq M\otimes_R S$
@TylerLawson: sorry, I didn't follow. Could you clarify?
sorry, just being annoying
05:24
In algebra, it'd mean the following: if G acts on a ring R, and M is an R-module, then for each g \in G, there is a new R-module M^g which has the same underlying abelian group, but such that the multiplication law is now r m = g(r) .m where the second is the old multiplication.
the ring S with its G-action is a functor BG -> (Rings)
Ah, yes.
there's a category (Ring-Module pairs) with a forgetful functor down to rings
descent data is a lift of the functor to a functor BG -> (Ring-Module pairs), or equivalently a section of the pullback category (which is a category over BG whose fiber is the category of S-modules)
[and I believe that something like this is in the DAG chapter on quasicoherent sheaves]
He also says something about this in DAGXI on Galois Descent.
But, I don't understand why elements in $C$ with a $G$-action are functors $BG\to C$
BG is a category with one object x with Hom(x,x) = G
05:27
@JonBeardsley -- to continue along the tack that @SeanTilson was taking: a monoid action of M on X is equivalently a monoid morphism M --> End(X), so you're asking about the space of map between two algebras (in spaces) over the associative operad. if you're willing to be \infty about it, you can use my GHOsT business for this...
@TylerLawson oh. that explains it. I wasn't thinking of the right BG I guess.
right, the categorical BG
@AaronMazel-Gee What's the setup for the infinity-categorical Goerss-Hopkins? E.g. what's the analogue of the Adams-Atiyah portion of the story?
[it might be that I've mixed up my DAG chapters]
i was hoping to dispense with it, but it ends up being totally crucial. i just ask for an "adams's condition" on the object E that's playing the role of "homology"
i think the weakest i can get away with is saying that my category has a monoidal structure which commutes with colimits in the first variable, defining E_*X = \pi_*(E \otimes X), and then saying that E satisfies a "left" Adams's condition
Okay, but @TylerLawson you're telling me then that a descent datum is an $S$-module with a $G$-action.
it is totally crucial. it took me years to understand how important it was
@jon: you gotta be careful
05:30
markus spitzweck and i worked out that MGL, and indeed any landweber-exact motivic homology theory, satisfies adams's condition
so that's nice, at least
a ring-module pair is (R,M), and maps to (S,N) are ring maps R -> S plus a module map M -> N of R-modules (where R acts on N through R -> S)
so a functor BG -> (ring-module pairs) is:
a choice (S,M) of a ring and a module it acts on
and, for any g in G, a ring map g: S -> S
AND a module map g: M -> M
but the condition then says, effectively, that g (s.m) = gs . gm
for g in G, s in S, and m in M.
so yes, it is an S-module
Okay. Yes. Agreed. My mistake, the $G$-action on the ring part of the pair has to be the same as the downstairs action of $G$ on $S$
and it has a G-action
Yes, exactly.
Hm. Okay. I believe I have all the necessary pieces at this point to build the picture.
At least in the Galois descent case.
for more complicated descent, the algebraic geometers have you covered
05:35
How so?
I mean, frankly, more general descent makes a lot more sense to me than this.
depends on if you're trying to calculate anything with it
Fair enough. The (Hopf-)Galois object probably helps here.
it would be nice if you could figure that out
You mean in the Hopf case? I understand that you've more or less worked it out in the Galois case?
well, I think David Gepner deserves a lot more credit than I do
05:38
Okay. Fine. :-)
So you and David Gepner have essentially written down the aforementioned story in the case of Galois extensions of ring spectra?
Do you have any kind of statement for specific objects like "this computes twisted forms of this spectrum"?
For instance... a spectrum level realization of Jack's "Forms of K-theory" for higher K(n)'s?
=P
how do I say
we're still writing (he is stuck with a very slow coauthor)
Haha! I see. Well, alright. Looking forward to it. :-)
Maybe it's good that I don't see it. That way I can't just say "just dualize everything."
the statements about twisted forms are relative (for R -> S a finite G-Galois extension you can classify R-(xxx)'s that become equivalent to a fixed object after extending to S)
yeah. fantastic.
that sounds lovely.
and do the associated sseq's to compute moduli of forms have any hope of being computed?
where (xxx)'s at this point can be modules or algebras, I think.
05:44
"virtual representation spheres" are a thing, right? equivariantly/
?
those are the guys with respect to which you take homotopy groups, i'd expect
yes! so e.g. for KO -> KU you can compute lots of goodies
Oh boy.
"Forms of Real K-Theory"
@AaronMazel-Gee I'm not 100% sure I follow, but you can use some kind of Pic-graded model structure if you need things where homotopy groups won't get it right sometimes
oh, i'm just wondering what "cellular equivariant spectra" ought to be
anyway, so for computing forms of K(n) I'm not sure. the Hopkins-Miller theorem already produces all the "forms of E_n"
05:46
This seems like it might be a way of obtaining new elements of picard groups, if one were able to do this for more general... I dunno, profinite groups?
right. there are differing perspectives on what the basic cells in equivariant theory should be. virtual representation spheres are a very common one
(Sorry, you've already said all of this. I just process things very very slowly.)
Yes, if you could do this profinitely then you could calculate Pic.
@TylerLawson the cellular motivic spectra are the ones that are generated under hocolims by the S^{i,j}. this is the colocalization of mspectra for which equivalences are detected by homotopy groups, rather than homotopy-sheaves-of-groups or whatever
right, ok
Hmmmmm. Sweet.
05:47
There'd be this Dwyer-Greenlees-Iyengar spectral sequence H^s(G; pi_t(Pic(S)) => pi_{t-s} Pic(R)
@TylerLawson well, so i want to make sure i'm recovering the same colocalization, is really what i meant to say
Cool! Right, and so Pic(K(n)) is basically just K(n) right? So at least, the left hand side appears to be computable.
Or rather... contains just K(n)
Hm. Sweet.
Okay. My brain is full now.
Pic(K(n)) is ... roughly, Z/{2p^n-2} x BGL_1(K(n))
05:50
Oh. Alright.
but "just K(n)" is basically right, the only invertible K(n)-modules are suspensions of it
the rest just tracks what the spaces of self-equivalences are
That would have been my guess. Ah I see.
@TylerLawson, what do you mean by invertible K(n)-modules?
Jesus, this stuff is wild.
(since K(n) is only an $E_1$-algebra).
05:52
Right. Good point, Akhil -- I'm not being careful.
hey akhil! just invited you to gchat
I guess I'd need to work in bimodules, and then I think Pic would be much more complicated.
Hi @AaronMazel-Gee; I'm not sure I got it, so let me invite you.
Sorry, Jon.
Darn.
Haha. No worries.
Okay. Well. Man, thanks everyone for telling me awesome stuff.
Homotopy theorists are very generous with their knowledge.
A friend of mine in number theory has said that he experiences quite the opposite in his field.
I think I probably need to go to sleep though. Good night.
05:57
@JonBeardsley that's really unfortunate
see you!
that is really unfortunate
have a good night
@JonBeardsley: good night.
so, motivically, usually to test if a map X --> Y is an equivalence, one needs to have an equivalence of all [[S^{i,j},X]] --> [[S^{i,j},Y]] -- i'm just randomly using [[-,-]] to denote the discrete-motivic-space of homotopy classes of maps. (i.e., the sectionwise \pi_0 of the hom-mspace)
fwiw, "jack's forms" refers to something arithmetic, rather than something structured: counting (incoherent) ring maps MU --> E_n which become conjugate in whatever relevant sense when passing to E_n (x)^ W(k bar)
so, probably not something hopkins--miller has something to say about, but also not something that requires much technology to answer
but then, if my mspectra are cellular, then i can just check on [S^{i,j},X] --> [S^{i,j},Y]
so: what is the analogous thing i get to forget if my equivariant spectra are cellular? i'd guess i can forget the maps involved in my mackey functors and just remember the values?
06:03
I'm afraid I don't understand the thing underlying [[,]]
anyway, are you asking about the difference between knowing Mackey pi_* and knowing just the RO(G)-graded homotopy groups?
yes, i think those are the words i want to be saying
let me try again with the "power series" ;o)
OK
(I think that S^n ^ (G/H)_+ and S^V generate the same thick subcategories of the genuine-equivariant category, and so you get the same notions of weak equivalence)
so, mspectra are enriched in mspaces. in particular, we have a mspace map(S^{i,j},X). this has a 0-truncation, which is the discrete mspace [[S^{i,j},X]] -- one might call this the (i,j)th "homotopy motivic-group". these determine the equivalences of mspectra...whereas the usual [S^{i,j},X] (which are the global sections of [[-,-]]) are too weak
(but I may need to restrict to abelian groups to be sure about that)
well, definitely i'd believe you can decompose S^V as a G-CW complex, at least
06:10
what's the relationship between 0-truncated mspaces and sheaves?
so officially, the catetegory MSpaces is the A^1-localization of the category of nisnevich presheaves of spaces
and i guess i just mean a 0-truncated object therein
so it's an A^1-invariant object in nisnevich presheaves of (homotopically discrete) spaces?
(the A^1-localization is a left localization, so you're basically shrinking the fibrant objects. so i'd guess that they are in particular fibrant as nisnevich presheaves-of-spaces -- i.e., they are sheaves)
yes, i think we're saying the same thing
so, does my question make sense then?
i think you already gave the answer, which is what i expected: the analog of the motivic difference between[[S^{i,j},-]] and [S^{i,j},-] is equivariantly given by the difference between mackey functors and RO(G)-graded homotopy groups
06:18
yeah. I worry, now, about groups where the number of subgroups is very different from the number of irreducible representations
I am not clear on what happens
well, so (as i mention at the very end of those notes!) i'm thinking about this via elmendorf's theorem
certainly
so the representation spheres each give you a list of integers, one per subgroup, according to the dimension of the fixed sphere
so [[S^V,-]] should be a 0-truncated presheaf on the orbit category, and [S^V,-] is its evaluation on G/G, i.e. its G-fixedpoints
and so a necessary condition -- at least on G-spectra for a trivial universe -- seems to be that these generate a full-rank submodule of Z^{# subgroups}
that sounds reasonable, but also wacky
i mean, i wouldn't expect it to have much to do with the group theoretic properties o G
*of
06:24
that leads to a dumb question: are there any groups for which the number of conjugacy classes is strictly less than the number of subgroups?
so the difference between universes is really just a question of which vrep-spheres i've decided to smash-invert, right?
haha i guess just "rep-spheres"
yes, that's right.
so we only get homotopy groups graded on all of RO(G) when we're in a complete universe?
correct.
what is the motivic analog of these different G-universes?
06:27
sorry. that was a dumb question, because I don't want # of subgroups: I want # of conjugacy classes of subgroups.
motivic analogue? let's say you do A^1 homotopy theory and you never invert the Lefschetz motive
haha i have no idea what that is
I'm not sure anybody does
it's not some particular mspace?
oh, perhaps your sentence has multiple interpretations
you have the pointed G_m, which you're supposed to invert
06:32
but you could decide not to
that's all i know: smash-invert your spheres
so the trivial G-universe must correspond to only "categorically" stabilizing, you're saying
right
so something like sheaves of spectra on something or other
haha kyle ormsby and i have been on-and-off mucking with this, trying to equate mspectra with presheaves-of-spectra-with-certain-transfers
presheaves on a certain correspondence category
torus correspondences, maybe?
what's that? actually our most recent attempt was with correspondences where your backwards map needs to have a trivialization of its normal bundle
which, tantalizingly, suggests a more general statement for modules over various thom spectra (inasmuch as S = MFramed)
clark suggested that actually the difference between such spectral presheaves and actual motivic spectra might somehow be analogous to the difference between the sphere spectrum and its A-theory, but i can't remember anything more concrete than that
06:40
I guess transfers for principal G_M torsors (and iterates) was what I meant
aha, that's not a bad idea. although it seems on the face of it like it might be stronger, like you're building in some thom iso's or something. a related guess would be only for trivialized principal G_m-torsors
it took me a minute to see why that was your guess
maybe i'm lying, G_m isn't the one-point compactification of anything that might deserve to be called the fiber of a vector bundle
ok. sorry to end abruptly, but it is much later than I expected
cheers
yeah, i gotta go to sleep too
thanks for the chat
you too
 
6 hours later…
12:59
@AaronMazel-Gee would you mind spelling out what this adams-atiyah/adams condition actually is? I don't necessarily need all of the details, but something more than "an Adams-Atiyah condition" would be really helpful.
 
2 hours later…
14:48
@SeanTilson it's the thing that's necessary for a homotopy ring spectrum E to have a kunneth spectral sequence. i think the name is because it was first written down in adams's blue book, but he credits it to atiyah
namely: you need to be able to write E = colim E_\alpha for dualizable E_\alpha, such that:
(a) the E_* DE_\alpha are projective E_*-modules, and
(b) for any E-module spectrum M, the Kunneth map
[DE_\alpha , M ] --> hom_{E_*-modules} ( E_*DE_\alpha, M_*)
given by taking a map DE_\alpha --f--> M to the composite
E ^ DE_\alpha --> E ^ M --> M
is an isomorphism
so i guess the key point, functionally speaking, is that E becomes "procorepresented" or something (probably that's the wrong word): for any X
E_* X = [ S , E ^ X ] = colim [ S , E_\alpha ^ X ] = colim [ DE_\alpha , X ]
so somehow you're turning E-homology into something that smells like homotoyp
*homotopy
and this is essentially how goerss--hopkins reduce the E-homology obstruction theory to follow the story of Pi-algebra obstruction theory
Wow, I went to bed too early last night
00:00 - 15:0015:00 - 23:00

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