@DanielFischer I just want to make sure I understand things correctly. If an old question has been answered in the comments but has no answers at all (as opposed to a 0-vote answer), the thing to do is answer it as community wiki and then tell this chat?
One of the options. You can also ask the comment author to convert it to an answer. Or if you add enough content to the comment, you need not feel obliged to CW the answer. And if there is a (bad) $0$-score answer, but a good comment, IMO, you can act as if the answer wasn't there; if the answer is good enough, you can upvote it and get the question off the list that way. But that's not official, I'm just lurking here.
Thanks for the input. While the comment answers are probably good enough to be a sole answer, I'm going to try expanding on them a bit. In the case I was looking at, the asker is active, so I probably won't have a reason to post a link here.
Our lecturer gave us a hard exercice to go further in group theory (we stopped at group actions) :
Let G be a group, V and W complex vector spaces and $\rho_1 : G \mapsto GL(V) $ be a group homomorphism where GL(V) is the general linear group of V
(i.e. the invertible linear maps V $\mapsto$ V,...
Problem
Let $\text{ABC}$ be a triangle, and $\text{M}$ and $\text{N}$ are points where: $\vec{\text{AM}}=\frac{1}{3}\vec{\text{AB}}$ and $\vec{\text{AN}}=\frac{1}{2}\vec{\text{AB}}$ and $\text{M'}$ and $\text{N'}$ are points in $\text{(AC)}$ such that both $\text{(NN')}$ and $\text{(MM')}...
Our lecturer gave us a hard exercice to go further in group theory (we stopped at group actions) :
Let G be a group, V and W complex vector spaces and $\rho_1 : G \mapsto GL(V) $ be a group homomorphism where GL(V) is the general linear group of V
(i.e. the invertible linear maps V $\mapsto$ V,...
Problem
Let $\text{ABC}$ be a triangle, and $\text{M}$ and $\text{N}$ are points where: $\vec{\text{AM}}=\frac{1}{3}\vec{\text{AB}}$ and $\vec{\text{AN}}=\frac{1}{2}\vec{\text{AB}}$ and $\text{M'}$ and $\text{N'}$ are points in $\text{(AC)}$ such that both $\text{(NN')}$ and $\text{(MM')}...
