« first day (1065 days earlier)      last day (470 days later) » 

00:03
1 1 1 2 2 {fr[x].y}/((1;3);(2;4))
 
6 hours later…
ngn
ngn
05:37
or fr/[1 1 1 2 2].+((1;3);(2;4)), i.e. fr/[1 1 1 2 2;1 2;3 4]
@meyt4r x='y is the same as x=y
 
1 hour later…
07:02
thank you
1 1 1 2 2 {fr[x],y}\((1;3);(2;4))
(({@[x;&x='y;:;z]}[1 1 1 2 2];1;3)
({@[x;&x='y;:;z]}[({@[x;&x='y;:;z]}[1 1 1 2 2];1;3)];2;4))
seems like there is a duplication of effort
i think i am wrong regarding the previous comment. please ignore.

« first day (1065 days earlier)      last day (470 days later) »