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00:03
1 1 1 2 2 {fr[x].y}/((1;3);(2;4))
6 hours later…
ngn
05:37
or
fr/[1 1 1 2 2].+((1;3);(2;4))
, i.e.
fr/[1 1 1 2 2;1 2;3 4]
@meyt4r
x='y
is the same as
x=y
1 hour later…
meyt4r
07:02
thank you
1 1 1 2 2 {fr[x],y}\((1;3);(2;4))
(({@[x;&x='y;:;z]}[1 1 1 2 2];1;3)
({@[x;&x='y;:;z]}[({@[x;&x='y;:;z]}[1 1 1 2 2];1;3)];2;4))
seems like there is a duplication of effort
i think i am wrong regarding the previous comment. please ignore.
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