@quid Now that term I am very familiar with!

@amWhy You are likely older than I, but I am quite old by the standards of folk obtaining PhDs.

@amWhy I think that boys are, indeed, prone to communal fawning. But fanboy seems to described a particular type of unshowered, nerdy or geeky fandom. There is a connotation.

@user125142 Hello.

Oh, no.

@quid "Groupie" has sexual connotations.

Like, groupies are people who seek to have sex with the band.

Perhaps "nerded out over" is a good description.

But my research was largely self-directed, and kind of picked up from my masters work.

@user125142 Not precisely, no.

And I think that concrete end goals are a bad idea.

You should have some goals, but they needn't be the end.

You end your thesis when the deadline looms.

I was making substantial additions until the end of last week.

Nope, not really.

Read a paper, then read the references.

Then read another paper.

Since, inactive moderators have been discussed, I have checked whether there is some information on Meta Stack Exchange.

I have seen this post: What is the process regarding moderator inactivity removals?

JNat's answer gives more details, but among other thing it mentions that a mod is removed if they do no moderator activities for 6 months. (With some warning sent before that.)

I think I only saw this in action once (on MO).

If somebody has time to play with it, you can get some stats from SEDE.

However, only some moderator actions are visible in SEDE. (Flag handling isn't shown there.) Or you could check some stats related to activity on meta, or similar things.

For example, recent mod actions, counts by moderator, posts on meta per month, etc.

@MartinSleziak It also happened on this site last year.

Now that you mentioned it, I vaguely recall something. Also I think there wasn't a post on meta about that. (In the case of MO, here is a related meta post: Were there some recent changes to the moderators' team?)

A list of moderators on this site can be seen here: History of Math.StackExchange. There is also a comment on this post related to the above.

launde log... tagde raho!

@abhas_RewCie kahan se h bhai tu?

Nice joke😂

ye sab joke mat kar... marr jaiga...

bhai ghar se...

@abhas_RewCie Please use English in public chatrooms.

I asked you the same yesterday.

okay

@abhas_RewCie which part of India sir

@abhas_RewCie how

I don't know much about set theory. Does anyone have any tips on how I should be thinking about this problem?

@quid Are you around AND available?

@amWhy more or less

@quid Just wondering about chat.stackexchange.com/rooms/109112/hcrajpoots-personal-talk, and whether it is legit to keep as a private room?

Only mods can review the transcript, not "uninvited users"...

Granted it has not been accessed for three days...

Also: $$\Huge \color{blue}\text{T G I F}$$

@ArjunRana Hi! Can you please tell me about your current status of education?

@amWhy it's actually empty.

Generally a "gallery" room, is readable for everybody, only writing is limited.

@quid Okay. Thanks!

@quid Ahhh, yes, thanks. I forgot.

If it continues to be inactive it'll be auto-deleted. I'd just wait for that.

@AfronPie Having trouble reading that.

I assume it's basically a dupe created in error, but it's simplest to just let it fade out.

@Knight high school student, grade 11

@ArjunRana Okayee

@quid Also, the "serial upvotes" I notified you about yesterday were reversed by the script. Not to be mistaken with "cereal upvotes." :-)

@amWhy We say a subset S of Z+ is anti-closed if for any two unique elements in Z+ a,b, if a,b are members of S, then a+b is not a member of S. Can you partition Z+ into a finite number of subsets that are all anti-closed? Here Z+ is the set of positive integers (I'm real bad at using mathjax).

@Knight why the question?

this part of India

@abhas_RewCie ,😭😭😭

this

@amWhy,sorry I undid it, typed it in the flow

@ArjunRana No problem. It's just that we want users to be able to understand conversations here.

@amWhy surely

@amWhy Here is an example. It fails because 13 is the sum of two elements in A,B, and C.

@ArjunRana Wanted to be your friend ?

Hi friend

What about you?

@Knight,?

@ArjunRana About to become a freshman

@Knight at?

I'll see you later, @quid.

@ArjunRana Some state university. Most probably Minnesota

@amWhy see you, and thanks for the info regarding the votes!

@quid Sometimes I say "I'll see you later" after I've posted comments to you to which you do not respond. So yes, we will see each other again, but it would be good when you no longer plan to remain in a room that you state this explicitly, so other users don't waste their time commenting to you, when you're not there.

@amWhy Sorry to bother you but I was wondering if you had any ideas about the question I posted before. I've got no idea where to start.

Happy Friday, btw, @quid, and to all!

@amWhy I more or less understood the intent in that case, but when I said "see you" at least I actually left then. Before that I had not really left. Generally, the way I use chat there is often no particular notion of me being in the room or not. In the current case I was attending to other things on site but I might also do other things in parallel. Since the comment did not seem like one that needed an instant reply, I did not reply right away. But I truly appreciated the info.

@amWhy thank you, same to you!

@quid No problem. Understood.

lol What do we do all day, @quid? math.meta.stackexchange.com/q/31911/9003

@amWhy yes, that's a good one, phrased this way. :-)

Well, the question the OP wants to ask is pretty close to that: What do professional mathematicians do all day?