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yuvraj singh
yuvraj singh
2:00 PM
4^16.4 mod 17
Oh wait.
(4^2)^4.4 mod 17
Now 16^4. 4 mod 17.
 
user21820
user21820
Sorry I'm going off. Take your time and make sure you post the right answer. I will check tomorrow. Don't assume what you wrote so far is correct.
 
yuvraj singh
yuvraj singh
(17-1)^4.4 mod 17=(-1)^4.4 mod 17=4
 
user21820
user21820
@yuvrajsingh This one is correct, but your earlier working is not.
 
yuvraj singh
yuvraj singh
@user21820
 
user21820
user21820
Tomorrow.
Another one for you to do before next time.
 
yuvraj singh
yuvraj singh
2:04 PM
Is that correct.
 
user21820
user21820
6^(5^4) mod 7 = ...?
 
yuvraj singh
yuvraj singh
Are you OK with my effort?
@user21820
 
user21820
user21820
@yuvrajsingh Yes. But write out your working carefully on paper.
 
yuvraj singh
yuvraj singh
Yes.
I can answer last one too
If you wait a minute m
 
user21820
user21820
Don't be so hasty; you already got the first one wrong.
Treat this as a challenge. You only get one try to get it right.
Don't waste it.
See you next time.
 
yuvraj singh
yuvraj singh
2:07 PM
First one wrong?
(17-1)^4.4 mod 17=(-1)^4.4 mod 17=4
(7-1)^(5^4) mod 7= (7-1)^625 mod 7 =(-1)^625 mod 7=-1
@user21820
@user21820 @user21820 @user21820 I know you are here only, you haven, t leave. Yet.
Oh, sorry there is an error in the last answer.
Is 6 not - 1
Please reply.
 
Abhas Kumar Sinha
Abhas Kumar Sinha
2:54 PM
@yuvrajsingh this is wrong too, $$ a^x \equiv b^x \mod{m} \not \Rightarrow c^x \equiv d^x \mod{m} $$
 
yuvraj singh
yuvraj singh
@AbhasKumarSinha Alesha here hi
 
Abhas Kumar Sinha
Abhas Kumar Sinha
@yuvrajsingh let's talk in other chat room, not here.
 
yuvraj singh
yuvraj singh
@AbhasKumarSinha it is right.
 
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