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07:09
@HrishabhNayal here ?
@ronakjain Yes
@HrishabhNayal can you explain me about linear independence and dependence of vectors ? I know the definition but I am not able to understand what that means
@ronakjain you mean you don't understand the definition?
@HrishabhNayal the definition doesn't explain the intuitive behind introducing these terms
@HrishabhNayal i know the definition but what is the use of these ....
@ronakjain what do you mean by use?
07:14
@HrishabhNayal just what is intuitive behind introducing these terms
@ronakjain Are you asking a practical use? I don't know that unfortunately
@HrishabhNayal i am not able to understand why these terms are introduced ? Just memorizing the definition seems quite useless to me
9
A: What exactly does linear dependence and linear independence imply?

Owen SizemoreIntuitively vectors being linearly independent means they represent independent directions in your vector spaces, while linearly dependent vectors means they don't. So for example if you have a set of vector $\{x_1, ..., x_5\}$ and you can walk some distance in the $x_1$ direction, then a differe...

Ok. Let me see ....thanks for it
I dunno how much it will help you tbh..its a shot in a dark actually
 
6 hours later…
13:34
Let $f : \mathbb{R} → \mathbb{R}$ be a function such that $| f(x) − f(y)| ≤ 6|x − y|^2 \forall x, y ∈ R$. If $f(3) = 6$ then $f(6)$ equals?
It seems that the function is constant but I can't prove it.
 
1 hour later…
14:42
@Tapi $$\dfrac{|f(x) - f(y)|}{|x-y|} \leq 6|x-y|$$ now set $x = y+h$ and take $\lim h-> 0$
@Tapi what did you get after differentiating it
F'(x) is coming out be zero
It mean function is constant
So all have same value
@AdvilSell hi
Yaar! Did you got a branch change?
No I didn't tried for it
Why?
14:46
I like biotech
it's fun and interesting
@JackRod I forgot your branch
Noice!
Yaar I am confuse
Like I feel like giving up
why? what happened?
Ghar ke andar pagal ho gaya hun,my whole day went on computer
Some time I feel like koi arts college join kar leta
Mast maze karta
14:49
@JackRod that's the case with everyone lol
don't worry college khul jayenge
@JackRod kyun CS padhne mein maja nai aa raha ?
@AdvilSell nahi yaar during the lockdown I realize what my real love is
Physics it sound stupid but I most of the times read physics book
Even in the lectures
it's not stupid at all dude
if you love physics then go for it
everything kinda mix my as we go
I can't my dad is happy for me
14:52
arey I am not saying to change your "branch"
there are many interdisciplinary things
Haan
Pata hain
toh kisi acche physics professor ko dhund le
Muje pata hain grades ab acche nahi aayenge
ghanta farak padta hai grades se
Bhai idhar sabh teh leke rote hain
14:54
arey koi farak nai padta
maine logon ko dekha hai jinki CG 7.5 se niche thi aur wo MIT mein hain aaj
pursuing PhD
Are you looking for PhD?
Or mtech after graduating
yes most probably
MS+PhD
@JackRod no
It would take more 3-4 years
toh kya hua?
Ghar wale man jayenge?
14:57
it's not like I need to support my family after graduation
my dad is 45 so he have 15 years of job before retirement
@JackRod han kyun nai
Do you know vineeta bal?
Yeah she is Immunologist if I am not wrong
Yes
Aise bol diya lol
.
Muje laga yeh naam kaafi popular log tumhari branch mein
15:02
utna popular nai hai par phir bhi kafi popular hai
@AdvilSell aacha lag raha yaar baat karke
Yaar akle rah kar azib se thought aate hain
@JackRod Nice!
@JackRod han woh hai
@AdvilSell what about Jasmine is she got good rank?
Not that good but still fine
she is more towards adv.
Oh!
Or abhi kya chal raha hain online class mein
15:05
kuch nai yaar
boring chisen chal rahi hai abhi
timepass hai online class
afk
Yes
Kai idea aaye dimag mein
During the lockdown like I and my friend who are like me thinking to create a app a unique app
Which manages your all account in one platform.
$lim_{h \to 0} \frac{|f(y+h)−f(y)|}{|h|}≤lim_{h \to 0} 6|h|$. The LHS is like $f'(y)$ but it's not given that f is differentiable.
@AdvilSell good night my friend
@JackRod Good night bro!
@Tapi huu..that's a point too
@Tapi I think the equations also prove it's differentiable
15:20
@Tapi yes
since the equation effectively says that $\dfrac{f(y+h) - f(y)}{h} = 0 $
*lim of that thing
okay thanks

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