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07:55
@Jasmine @samjoe According to me it should be 0 because denominator has higher power, what do you say?
 
3 hours later…
10:58
@abcd i think limit is on $n$, and no highest power on both numerator and denominator is like $3/2$
 
2 hours later…
Anonymous
12:36
So it'll be 1
@IceInkberry why
Anonymous
@Abcd Both the highest powers are $\dfrac{3}{2}$ and their coefficients are also the same that is $1$
Anonymous
Ignore everything execpt the terms with highest powers
14:57
@IceInkberry how did you get their coefficients
@Abcd just divide by $n^{3/2}$ on both numerator and denominator.
 
1 hour later…
16:10
@Abcd 1 should be the answer. Same logic as by @IceInkberry and @samjoe
Did anyone see they put x instead of n
16:37
@Abcd I just solved it and you may check in case you need solution.
Can anyone help me understanding some symbols I am very poor in getting symbols in functions. Is there any chart or any thing like that I really get scared when I see symbols
@Jasmine Which symbols are you talking about?
16:52
Too many symbols and norations
Do you have any examples of intimidating notation?
@ParthKohli nope actually whenever it's symbol I fail to understand.
@ParthKohli I have tried to learn a few lik f :x arrow y means x is the domain and y the codomain
Hm, they are very fundamental to functions. Koi standard textbook pakad le, and then try solving problems.
@ParthKohli I have solved problems without understanding symbols
I think you just answered your own question here. First build an understanding of the underlying notation.
16:58
@ParthKohli kisi bhi book me aise symbol ka kya matlab hota ha nahi dia hua hai
The books use the symbols themselves
Hmm
Sad
Then just use Google, maybe
Okay, which part of this is troublesome to you?
The 2nd sentence what does it mean?
The only point of this problem is to make you work through cumbersome notation. lol
The set of all x in the interval [-2,2] such that x <= 0 and f(|x|) = x
17:02
@ParthKohli perfect got itm
This means that we're looking at x in the interval [-2, 0] (since we have the condition x <= 0). Now in this interval, |x| = -x since x <= 0. So it wants to know for what x is f(x) = -x in [-2, 2].
Actually I have not learned set theory yet that's why
@ParthKohli I got it thanks! But there are more symbols to go
Shoot 'em.
Which class/grade/standard are you in?
I think I should first study set theory then it would get easier for me
Am in 12th
Just in 12
@ParthKohli I don't know why they didn't directly use[ -2,0] as interval
Because they want you to work through the problem.
17:34
$$\lim_{n \to \infty}n^2 (x^{\frac 1n}- x^{\frac 1{n+1}})$$
@ParthKohli @Jasmine Please see^
 
1 hour later…
19:02
@Abcd is it 1?
@Jasmine No
It's ln x
Oh no yeah it's I got ln 2
And I thought ln2 is so close to 1 so I said
I don't want to confuse you but I use shortcuts like put x=2
Coming back shortly with a proper solution.
 
1 hour later…
20:33
@Abcd tried enough can't properly prove it

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