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Suppose $\sigma = (yz + x^2z^2 + 3xy^2z)dx dy dz$ then how do we find a 2 - form $w$ such that $dw = \sigma$?.
As I know that if it would have been $\sigma = \sum_{i} \alpha_{i} dx_{i}$ then as a Pffafian form an integrating factor would exist iff $(X).\nabla \times X = 0$ where $X = (\alpha_{1}...
