« first day (4938 days earlier)   

12:31 AM
@SillyGoose all the flags made me come
 
 
2 hours later…
2:47 AM
@naturallyInconsistent Jakobian is commonly in the math stack chat
 
3:33 AM
Shweg
 
 
2 hours later…
5:39 AM
i graduated undergrad today >:D
7
 
6:00 AM
HONK!!!
πŸ‘πŸ»πŸŽ‰πŸ‘πŸ»πŸŽ‰Congratulations πŸ‘πŸ»πŸŽ‰πŸ‘πŸ»
2 hours later...
 
H O N K thanks
does anyone know about "relativity of subsystems"
 
 
1 hour later…
7:13 AM
C O N G R A T S
S C H W E G G ~
 
7:34 AM
@SillyGoose eyy congrats!
 
7:47 AM
@SillyGoose congrats!
hi
 
I don't know much about this system; but graduating undergraduate sounds like a contradiction to me.
 
8:12 AM
anyone want to share their personal philosophy of "what exists" and "how it's related to what we experience?"
 
8:56 AM
thanks all
 
9:09 AM
@SillyGoose Congrats πŸŽ‰πŸŽ‰πŸŽ‰
 
9:19 AM
thanks :D
do ya'll have a mental definition of what a system should be
 
9:43 AM
@SillyGoose i cant define it precisely, when i thought about it
"a subset of spacetime on which one makes measurements" @SillyGoose
i would say we divide the universe into system and environment for convenience
 
10:00 AM
hm yes i feel like the notion of system is inherently amorphous
i am wondering something else in addition
can i define a finite-dimensional quantum state space as a unital algebra with a sort of "tensor product" as the multiplication?
 
@SillyGoose congratulations :)
 
but the output of the tensor product lies in a different vector space. i think one would end up with something similar to a Fock space if one wants the space to be closed under tensor product. But not exactly a Fock space
 
@Mr.Feynman thanks :D
it seems like this would define a chain complex...but not sure if it'd be interesting 0.o
@RyderRude hm i see yeah i was thinking schematically of something like this i suppose
oh the $C^n$ should be an $X$ in the bottom right
i guess it is probably not very interesting. since the cohomology classes will depend on the distinguished $\lambda$
well it could also be interesting for that reason :P
would we ever have in physics a chain complex structure induced by a sort of exotic ladder operator situation?
i.e. our creation operator acts on a given state exactly once before mapping to $0$
schematically something like this situation
also there is another typo in the first image...i meant to put $C^n \otimes ... \otimes C^n$ where there are $k$ tensor products for the $k$th chain in the chain complex
 
10:24 AM
really coool
seems like u r inventing math
so one needs to assign one creation operator at each level, which squares to 0
creation operators in the Fermionic oscillator square to zero, but im not sure if it connects to this idea @SillyGoose
u can ask on the math chat too if this has been studied
i think the Dirac field Fock space is exactly what u r looking for
 
10:47 AM
do you have a reference on hand for dirac field fock space
 
but it's an infinite dimensional hilbert space at each level. one can form the chain using $a^{\dagger} ^r_p$ of a fixed spin and momentum
@SillyGoose it's in Nakahara. lemme check page number
section 1.5 @SillyGoose
 
@SillyGoose What is this? What $\lambda\in\mathbb{C}^n$ except $\lambda= 0 $ has $\lambda\otimes \lambda = 0$?
 
sorry the $a^{\dagger}$ in the Fermionic oscillator is an operator, not a state
ACuriouMind's objection holds
 
oh hmm
then maybe turn the symmetric product into an antisymmetric one?
 
I don't understand what you're even trying to do here - what problem is this construction supposed to solve?
 
10:57 AM
there's no problem :P just exploring. i was first trying to see if the set of pure states can be said to live naturally in an algebra (rather than textbook complex vector space). then, i was wondering about if there is a natural chain complex structure that you can work with if u consider the algebra of matrices containing density matrices--or something along these lines
 
why would there be an algebra operation on the states, and why would you look for chain complexes randomly?
 
it seemed interesting to consider if the tensor product could be used to make some sort of multiplication operation (in the sense of a multiplication of an algebra)
the chain complex thing also just out of interest
 
The tensor algebra $T(V) = \bigoplus_i V^{\otimes i}$ is trivially an algebra
with the multiplication operator being the tensor product
 
does it need to be a multiplication between states? if u allow for operators, then the Dirac field creation operator squares to zero
 
you don't need to do anything special here
 
11:01 AM
the boundary operator is also an operator in homology
 
@SillyGoose but see: it seems to me you invented the nonexistent $\lambda\otimes\lambda = 0$ because you wanted to find a chain complex somewhere :P
it would make sense to me if you had found such a $\lambda$ first and then wondered about it, but this way it just looks like you recently learned about homological algebra and how you're trying to see it everywhere :P
 
i think the Dirac field Fock space naturally has this structure, with spaces connected by a fixed $a^{\dagger r}_p$
 
@ACuriousMind right. well i wanted to see if there was a "natural" coboundary map. and the available structure is the algebraic structure. so i tried to see if the tensor product could induce such a natural coboundary map
@ACuriousMind this is true, but i was more generally thinking about what can be drawn from the basic structures provided in usual treatments of quantum mechanics. and stuff that is not just written ad nauseam in canonical textbooks
and i don't know of many things so there comes (co)homology :P
but also it is sort of natural to think about i feel like. we have this nice potentially graded vector space-like structure we look at and deal with all the time :P
 
don't you think if there was something else useful there it would already be written in the canonical textbooks? :P
 
that is also true
but it's still a bit of fun nonetheless :)
 
11:06 AM
i think it's great to explore
 
i'll at least learn why it's not useful...
but idk did J.J. sakurai really do cohomology in preparation for his textbook :P
 
what
 
@SillyGoose does cohomology require a multiplication rather than any operator?
 
@RyderRude what do you mean by this?
@ACuriousMind i think i mean that it is conceivably obscure, but my impression could be wrong
 
let's say we hav vector spaces connected forwards by any operator that squares to zero. is this cohomology
i havnt studied cohomology
 
11:10 AM
@SillyGoose cohomology is not an obscure concept, you just haven't done a lot of math :P
it may be obscure to the average physicist, but any mathematician I would expect to know at least the basics of algebraic topology
 
@ACuriousMind i agree with this. i mean to claim that it is conceivable obscure to the average physicist
 
yeah... cohomology seems to be covered in diff geo introductions
 
...and then there's BRST cohomology, a place where we explicitly use it in physics
 
it is also conceivable that if it did have a "use" then perhaps it would be an obscure use. or something more mathematically useful. so then conceivable that physicists writing textbooks on quantum mechanics would not necessary care about it or think about it
@RyderRude i'm not too sure i haven't done much of it. just looked at particular examples in a course i recently took
 
11:13 AM
there might be more technical requirements but the gist is to have a sequence of modules connected by morphisms that square to $0$ indeed--to my understanding
 
the chain complex i gave for the Dirac field seems to be well behaved wrt the operator, and it also squares to 0
@SillyGoose yes..i think the morphism part is satisfied becuz it's a linear operator
 
@SillyGoose but we don't start with "I want to have a cohomology" and then go looking for stuff that might fit into a chain complex, that's not how applying (co)homology theory works. On the contrary, you start with some problem, then you notice that the quantities that interest you can be modeled in terms of quotients of images/kernels of a nilpotent map and then you pull out the (co)homology toolbox
 
i thought the homology operator squared to 0 becuz it made sense for boundaries... weird that the reverse chain also has this property
 
@RyderRude this condition guarantees that the image of the pre-map is a subset of the kernal of the post-map at a given module in the sequence
 
Really, I think fixating on a particular mathematical structure and trying to make random physics fit into it is the completely wrong way to go about either mathematics or physics
 
11:16 AM
which is necessary to even talk about quotients of those substructures
 
@SillyGoose thanks..
yes.this is a requirement for chian complexes in general... i remember
one needs to take the quotient later to talk about the invariant group
 
@ACuriousMind is there a name for cohomology generalized to nilpotent (as opposed to square to zero, or 2-nilpotent) maps? is it just cohomology still :P
 
@SillyGoose oh, I meant square-to-zero
 
it would be ideal to have a particular set of problems to put focus towards indeed :P
 
i think it's great to explore but it's more efficient to just read previously discovered stuff
see this thing called Hopf fibration en.m.wikipedia.org/wiki/Homotopy_groups_of_spheres
 
11:28 AM
The wave equation for the electric or magnetic field contains a derivative with respect to time. In the Helmholtz equation the temporal component is omitted. In which cases is one used and in which cases the other?? For example, in my lecture we are talking about optical resonators, and the professor said that we will try to solve the Helmholtz equation for the field inside the resonator.
 
11:48 AM
@SillyGoose congratulations!!
 
there is no paper on fermionic oscillator cohomology.. i think it's not a good theory
 
12:08 PM
For two different resonance frequencies, where one has a smaller linewidth than the other, what can one understand from this? How to interpret that?
Like, what are the consequences when the linewidth is larger?
 
12:30 PM
@SillyGoose LETS GOOOOOOOO
one step closer to becoming a physicist hehe
 
@SillyGoose fermionic creation operators necessarily acts this way
 
acm's drag coefficient is infinite! the drag dont stop!
 
1:08 PM
Why are you dragging ACM? πŸ’€
Is that an Achilles vs Hector reference?
 
1:22 PM
what field in physics do u hate/dislike?
 
1:36 PM
Wigner-Araki-Hanase theorem doesn't seem to be well known. Do you people know any textbook treatment of this?
 
 
1 hour later…
2:48 PM
I don't remember if I've linked this here before.
If you have the time I'd like to hear your thoughts on it
 
 
2 hours later…
5:18 PM
What makes a process irreversible?
Is it like a function without inverses so you can't "go back" to the original space?
 
@Obliv i skimmed thru some of it. it is reasonable i guess
 
I would hope it is :P it's written by a pretty important figure in theoretical physics
 
lemme see
oh
wow he is a nobel winner
 
I want to read this but I want to get more comfortable with stat mech first.
 
@Obliv yeah... i read about it long ago, but there is some four-sided parallelogram graph which is associated to reversibility stuff
 
5:30 PM
Also a pretty important figure in information theory/stat mech
 
idk stat mech though
 
Well it wouldn't be very unfamiliar to you I think.
 
oh
do u mean stat mech
Andrew makes some great points that the principles of emergent sciences are independent of the principles of fundamental sciences
 
@Obliv I think my question was posed in bad faith since I wasn't looking for any answer in a specific framework but kind of fishing for something too big to handle (for my level anyway)
Like I understand reversibility in the thermodynamics framework "X process is reversible, Y process is not" type thing
but was curious about the deeper reasoning but I imagine that requires some complicated stuff
 
oh. sorry :P
i cant answer it exactly....but entropy must increase in an irreversible process... so one loses information
not sure if it's related to some non invertible function
maybe someone else can answer it better :)
 
5:44 PM
Does this principle of increasing entropy apply to all areas of physics though, I wonder
Or is it one of those things that "breaks down" when changing the framework (like GR at the quantum level)
 
i dont know any stat mech but Einstein is quoted as saying "of all the laws of physics, the second law of thermo will never be overthrown"
i think it's because this law is more like a mathematical truth, rather than a physical one. when the system is too large, the chances of reversibility r near zero
but there is also this thing called Poincaire recurrence theorem which says things r guaranteed to reverse back
this discusses Poincaire recurrence and the second law physics.stackexchange.com/questions/405971/…
 
 
1 hour later…
7:01 PM
I recall my mechanics professor last semester saying to me, in reference to that theorem, "It could be that we will have this conversation again at again ad infinitum at other points in time" to which I responded with laughter
I think we sometimes use humor to deflect/deal with troubling realizations :P but yeah I don't really have any reason to believe we live in a dynamical system that obeys such and such axioms or whatever.
It's like, being skeptical must be an automatic process. We do have to believe while doing physics but we also have to not believe so we can explore further. Not sure if that makes sense
 
 
1 hour later…
8:10 PM
I wonder what negative temperature objects would feel like
I guess just as hot as the absolute value
since they're more inclined to give energy like normal high temperature objects
 
8:22 PM
anyone know some cool experiments with entropy, showcasing the 2nd law?
For some reason it feels like the 2nd law is emergent from something deeper about the fundamental forces
Gotta study QFT/ST D:
 
look, you are making remarks like these because you didn't understand stat therm from the book you are using. If you truly understood stat therm, you will realise that there is no way you can get a deeper understanding from studying fundamental theories.
 
8:41 PM
yes, it is emergent, but the emergence is not illuminated by fundamental considerations.
 
ill look into callen later then
 
fqq
@Obliv arguably the 2nd law is deeper than whatever field theory happens to fit scattering experiments
 
It is more of a mathematical derivation that is self-contained in stat therm. There would need to be a lot more in-depth understanding of quantum theory if we want to improve upon the current understanding. We do need it, because quantum stat therm is still a rudimentarily developed field.
 
@naturallyInconsistent The second law isn't a self containted truth of the universe though. It's not like a solid will sublime into a gas spontaneously because that would increase its entropy? I think there are some underying reasons for why systems evolve in the way they do, no?
I guess that example is poor because if you analyze the system properly, the system still evolves to largest number of microstate probably
Plus I don't know what the "true" system is. All the examples we did so far are only approximations/ideals anyway
Einstein solid, bose-einstein condensate, 2 state paramagnet, ideal gas, van der waal gas, fermion gases, etc are all approximate models to describe certain systems
miao miao doesn't seem to sleep. How do I see u on at 5am your time lol
 
9:04 PM
@Obliv ... it does... At least in the current conception, with the mathematical, probabilistic version, it will automatically do that.
@Obliv insomnia crycry
nothing a little whiskey wont fix miehehe
 
9:29 PM
Why can't any arbitrary tensor be written as tensor product of vectors?
This seems to be a very well known fact which I have missed all these days...Can somebody give an easy counterexample or a proof of some kind?
 
;(
 
Does it make sense to consider a paraboloidal wave / gaussian wave, in free space ?
 
10:17 PM
@Relativisticcucumber omg one day
@Sanjana What do you mean by this?
@naturallyInconsistent do u know of a textbook or other resource in quantum stat mech
 
@SillyGoose I am asking for a proof of the fact that a generic tensor can't be written as a tensor product of some vectors
E.g. The claim for a 2-index tensor $T$ is that $\nexists~ u,v$ such that $T= u \otimes v$
Actually, I read a statement that the above can be done for a symmetric traceless tensor always and I thought: "why not for an arbit tensor?"
Sounds like this might be related to entanglement, etc.
 
is this related to what you are asking perhaps? math.stackexchange.com/questions/1486541/… @Sanjana
 
10:32 PM
@SillyGoose Exactly, what I was looking for: Thanks!
It is quite surprising that proving that such a decomposition into tensor product of vectors can be done for symmetric traceless tensors is a difficult task involving two component spinors, etc.
 
@Sanjana indeed; i think a more physical example is the dual of an entangled ket
like $\langle \psi_1 \lvert \otimes \langle \psi_2 \lvert + \langle \psi_2 \lvert \otimes \langle \psi_1 \lvert$
thought of as a linear functional over $\mathcal{H}_1 \otimes \mathcal{H}_2$
@Sanjana i wonder if Schmidt or singular value decomposition could be used to make a proof for this result?
would want to prove that all but one term in the sum of the Schmidt decomposition of an arbitrary covector in a tensor product space vanishes if...corresponding matrix to this functional is symmetric and traceless...or something
 
 
1 hour later…
11:43 PM
has anyone worked through these notes "Fundamentals of Quantum Information Theory" by Keyl? arxiv.org/pdf/quant-ph/0202122
 

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