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16:00
and you could throw in an arbitrary (well-behaved) function too: $$\int\mathrm{d}x\,g(x)\delta(f(x,y)) = \int\mathrm{d}x\, g(x)\sum_{i: f(x_i,y)=0} \frac{\delta(x - x_i)}{\lvert\partial_x[f](x_i, y)\lvert}$$ (nb absolute value signs added relative to previous posts)
@DanielSank In my opinion the most explicit formula you could get is mollifying and doing the integral...I am not sure if the result is unique though (it may depend on the choice of the mollifier)
@yuggib It shouldn't depend on the mollifier...
Anyway, the system helpfully informs me that it's chat session time! Though we're already going, it seems :-) Who's here?
lol
yeah I got that too
16:01
@DavidZ What is chat session time?
Aren't we doing that?
@DanielSank of course it shouldn't, but when you do exchange integrals and limits and you have distributions
Yep
I mean, we are chatting
terrible things may happen
@yuggib True.
I have to go though, can't stick around for this one. Have fun, folks!
16:02
aw, too bad, see you @ACuriousMind
@ACuriousMind Thanks for your help.
@DavidZ How did you get that the denominator is $\partial_x f$ and not the full gradient?
@DanielSank you could think of it like this: for each value of $y$, define a function $F_y(x) = f(x, y)$, and then do the normal delta-function thing on $\int\mathrm{d}x\,\delta(F_y(x))$
@DavidZ There should probably be an absolute value around the denominator here.
@DavidZ ::looks for paper/pencil to try::
@DanielSank ah, true, there should.
The $f'(x_i)$ that appears in the normal delta function formula (e.g. that ACM gave) is $\partial_x[F_y](x_i)$
@DavidZ Ok, working through your statements...
16:08
While you do that, in other news, HATS
Pops on December 14, 2015
Another calendar year is ending, which can mean only one thing. It's time once again for the event that brings joy to all (with a slight helping of dismay for our friends in the southern hemisphere1): Winter Bash!
@DavidZ that's where I'd seen "finno-ugric" before
I knew it rang a bell but couldn't place it
They sound really, really alien to me
@DavidZ Ugh, last year they took my hats away after the bash ended. It's hard to be excited again.
Particularly Hungarian
16:09
...I want my hats back...
I had a chameleon hat. A chameleon!
The only animal I might even consider to be as awesome as octopuses. They took it away. Never again.
There should be an app for that
@DanielSank So you wouldn't join, even for an octopus hat?
It would make a hell of an avatar
@EmilioPisanty Ugh, I'm conflicted. That's like offering a single date with the most interesting and beautiful person in the world. Is the fleeting yet deep pleasure worth the ensuing infinity of unfulfillable longing?
2
user54412
This chat got deep and philosophical in a hurry.
@ChrisWhite Word
16:14
@ChrisWhite Well, octopuses came up :D
Hats are a deep topic. They wouldn't be if we could keep them. Since they're temporary all kinds of questions are raised.
Octopuses? Am I in biology chat? Or is this the 8-tentacle-fold way?
@DanielSank Surely you can just mod your avatar afterwards to include the hat?
@EmilioPisanty Well, note that my avatar is already an octopus :-D
You can't get out of the bounding box but there's surely a lot that you can do
That is a really good point though.
16:16
@DanielSank I did, hence the comment.
[Jumping into the silence] So, what if anything is the relationship between spin and charge? Surely none, since e.g. both the neutrino and electron are spin 1/2...
if you want to keep hats
@TerryBollinger sorry :-P I don't think there is any
@DavidZ Fun!
@DavidZ odd things happen with spin and charge in nucleons, though.
Like what?
16:23
@DavidZ Delta baryons, the three 1/3 charges add only if the three 1/2 spins also add.
Ah, well that's because there is a relationship between isospin and charge for quarks. As far as I know, there is no deep reason known for that relationship.
(that's the fun part)
user54412
I knew someone in college who wore a hat like that. Everywhere. All year long.
@DavidZ Huh. All of this "yeah, we mostly understand what's going on" vibe we give off sometimes feels a bit like actually there's so much we don't have a clue about.
That may be a bit much
@ChrisWhite I used to wear one in the summer some times. All year though... that's a real champ.
16:26
@EmilioPisanty yeah... I dunno, I think I pretend to know what's going on when I'm on SE (for example) to cover up that I actually don't know what's going on anywhere else
@DavidZ There exists a set of simple vector addition rules on the Glashow cube for which that simple charge/spin-orientation link remains invariant across (as best I can tell) all mesons and baryons. Nice mnemonic if nothing else, but actually a bit surprising. Glashow never said anything about it though.
@DavidZ That hit me right in the imposter syndrome.
@DavidZ Naw, it's not so much individually as opposed to as a discipline. From what we tell high-schoolers, you'd think that we've got the standard model pretty much nailed to a t.
@DavidZ Isn't it just anomaly cancellation?
But then "this happens whenever that happens, but we don't know why" happens frighteningly often
for a theory we've got down to a t.
16:27
@EmilioPisanty That may be true, actually. The standard model itself is a nice little package, in some sense. It's just that there's more beyond it, and that's where we're mostly clueless.
@Prahar is it? I haven't heard that anomaly cancellation actually explains the link. At least, not in the standard model.
Anomaly cancellation really fixes the charge of the quarks to be what it is, given their isospin, I think. There are set of algebraic equations that the charge, hypercharge, isospin, etc. should all satisfy in order to cancel all the gauge anomalies. This fixes some, if not all of the quantum numbers of the standard model particles.
@EmilioPisanty In computer science, the reflex would be to assume that the model is too complicated, that is, redundant in some way. Has anyone ever seriously tried to refactor the standard model into some simpler form that predicts exactly the same things?
I would think people have been trying for 40 years
The best closest thing to success anyone's had is supersymmetry
and that's not much of a success at all
@TerryBollinger Well, there is the recent amplituhedron thing going on. Again, its one of those things that works, but we don't exactly know why. But basically, all the details of the complicated standard model can be packaged into simple geometrical shapes whose volume precisely gives the scattering amplitudes.
@DavidZ Again, as a computer type, the search for broader symmetries feels like the opposite of refactoring. Overgeneralization is not the same as reduction of assumptions.
16:33
@TerryBollinger I don't know if this idea has any gusto to it, but it seems to give the same answer in 2 lines as the usual Feynman diagrams would after summing over 8 million diagrams.
@TerryBollinger Hm, we may have to agree to disagree on that. It seems very much like refactoring to me.
Hey y'all, just got this and this room is probably a good space for it
Do you love movies? Do you love science? We have a questionnaire related to both these loves that we would be super grateful if you could fill out. For an upcoming event *we're trying to find out what science films are the favourite of real scientists* (not famous celebrity ones). It's very quick (2 qstns + 3 optional qstns), and can be found here:
3
@Prahar "amplituhedron"? Never heard of that one. But I am very solid that you can produce an amazingly effective mnemonic model of the particles and their properties using nothing more than that silly Glashow cube. Surprising, that.
@TerryBollinger The amplituhedron was all over the news some months back.
Everyone is forgetting the paper that derives the Higgs mass and Weinberg angle from the four color theorem...
@EmilioPisanty Or years? Nima Arkani-Hamed gave a colloquium about it when I was at PSU, probably a couple years ago
@EmilioPisanty For what it's worth, The Martian is a very excellent sci-fi, one of the best I think I've ever seen.
It's an excellent meditation on biology.
@DavidZ Actually, yeah. Late 2013
Man, time flies
user54412
Only 9 papers after all the excitement.
16:38
@ChrisWhite well, the amplituhedrom itself is a grand idea. There are many many papers being written regularly about many little aspects of it, even though there are only 9 papers that discuss the big picture.
@DavidZ I won't disagree... yet argh, to me refactoring means things like finding really unexpected links between "givens". That little question about the unexpectedly solid link (it really is) between spin orientation and charge addition in nucleons is an example. I don't think the "why is that?" for that kind of correlation is addressed by supersymmetry.
@ChrisWhite Wow, that is about as visually UN-intuitive of a paper I've seen in a while, at least for poor moi. No quick scans for that one!
user54412
I've always wondered how much it actually shortens calculations (but not wondered enough to read the papers in detail). I mean, someone could replace $a_{11} (a_{22} a_{33} - a_{23} a_{32}) - a_{12} (a_{21} a_{33} - a_{23} a_{13}) + \ldots$ with the more geometrical $\det a$, but that doesn't actually do anything.
vzn
vzn
@TerryBollinger solitons!
@vzn I love solitons, but eh?
vzn
vzn
@Prahar nice article in quanta mag on amplituhedron
aaronson has been talking about amplituhedron also...
16:45
@vzn yep. I've read this one. It's good, but is slightly misleading to anyone giving it a thorough read
vzn
vzn
@Prahar ah yeah admittedly its "near-pop sci" but whaddya gonna do... this stuff is harder than rocket science :|
@ChrisWhite The simplification is enough to make it a useful thing to study. For instance, 8-gluon scattering has 10525900 (~1 million) Feynman diagram in the traditional way of computing scattering amplitudes. However, the answer can be written down in a single line (for a particular type of scattering) using the Parke-Taylor formula. For other types of scattering, it may be more complicated, but certainly not sum-up-one-million-diagrams level of complicated.
@vzn Local QM? You aren't Randy O'Reilly in real life by any chance, are you?
vzn
vzn
@TerryBollinger havent heard of randy...(?) anyway am still in good company... :D
@vzn He's a pretty famous computer type (he did a great neural model) who also is adamant that QM is purely local. I've had some weird and interesting debates with him on the topic. I am, to say the least, not of the local QM school, quite the opposite in fact.
Thanks for that additional ampliwhazzit ref, BTW, that was a bit easier to quick scan.
vzn
vzn
16:53
@TerryBollinger am quite/ long aware its a very minority pov to say the least, even contrarian... aka "devils advocacy" :| ...
@vzn What's interesting is that I tend to put it the other way around: Non-local is the norm, it's classical physics that is the emergent property, and even then only an approximation that occasionally slips back into the deeper quantum reality.
vzn
vzn
look at list of who espous(ed/es) it: einstein, de broglie, schroedinger, bohm, bell, t'hooft... am proud to be in this small crowd (or motley crew?) :D
@TerryBollinger yes, am very much an advocate/ proponent/ believer of "emergence" & think its still barely understood. the amplituhedron is a good recent example.
@vzn No disagreement, it's an impressive list! Bell is an absolute favorite of mine, and I love the way he used pilot wave logic to think clearly about entanglement. Alas, there is this little issue that you can buy entanglement equipment off the shelf?...
vzn
vzn
locality as an emergent property of quantum physics is still admittedly half-baked. its taken many decades of baking and its still only half-finished at best. and in ("day-to-day") science there is little toleration/ patience for anything "half-finished".
@vzn Heh! I've never even looked it up. It's the emergence of information -- always reversible in principle, but not practical except in very rare cases -- that leads me to view classical as emergent.
Huy
Huy
17:00
"The topics will be roughly about definitions of quantum groups, representations, and two main applications: solutions to Yang--Baxter equations, and constructions of quantum knot invariants (Jones polynomials, HOMFLYPT, etc). "
Can anyone explain what this is about?
vzn
vzn
locality "believers" do have the feel of being embattled and cornered at times. so it can come off as a kind of desperate fanaticism.
like your analogy of refactoring to scientific theory reorganization a lot.
@vzn Well, again that question: What about that off-the-shelf encryption equipment? Even Bell admitted (so very sad he died young!) that the data wasn't looking good for locality. He was rooting for Einstein!
vzn
vzn
"refactoring" is a fairly recent concept in CS, only about ~1½ decade old...
@TerryBollinger yes really like how experimental entanglement is now much more accessible. have bookmarked some of the few "undergraduate lab" experiments. iirc mitchell helped create one & is also behind recent "loophole free" bell tests.
@vzn I'm sure people were doing it for a long time before it had a name
@vzn It's kind of ill-defined, too. However, one difference: Computer types are incredibly disrespectful of past work, and will just play with the data till something fits. Do that in physics and you will get tossed out.
vzn
vzn
17:03
bell was just a little bit ahead of his time. think he will have the last laugh so to speak and same with einstein. its just gonna take a little longer.
Anyway, our chat session time is officially over... see everyone in two weeks! One of these days we'll have an actual topic
vzn
vzn
@DavidZ right exactly meant to add that also. it got a little more credit after it was named refactoring. sort of like in philosophy where something doesnt really exist until it has a name.
I need to go too. @vzn, nice meeting you, hope to talk again. I'll read up on hoppy-hedry-amplies, whatever... ( I am just kidding :) )
vzn
vzn
@TerryBollinger nice chatting. would be curious to hear more of your CS bkg sometime. :)
I'm deep deep into artificial intelligence research, day job. I get to meet interesting people and occasionally have robotic snakes crawl up my let, I think there's an opportunity for safe crowd control with that one... :)
vzn
vzn
17:08
@EmilioPisanty have you heard newtons famous quote about pretty shells on the seashore?
@vzn No, I haven't
vzn
vzn
@TerryBollinger cool, what areas of AI? its a huge field. just bought 4 recent/ latest books and am charging thru them, plan to do a review on em in blog.
vzn
vzn
> I was like a boy playing on the sea-shore, and diverting myself now and then finding a smoother pebble or a prettier shell than ordinary, whilst the great ocean of truth lay all undiscovered before me. —Newton
In totally unrelated "news", I think I coined a term today
First step of debugging: internet research to determine whether I'm looking at a Heisenbug or a Schroedingerror
The most surprising thing about this is the fact that there were no Google results for Schroedingerror
17:16
Hey, btw
The "From Review" link in this comment
This does not provide an answer to the question. To critique or request clarification from an author, leave a comment below their post - you can always comment on your own posts, and once you have sufficient reputation you will be able to comment on any post. - From ReviewGert 18 mins ago
It's new, right?
Yeah, fairly new
Like a week or two, I think
Hmmm. I looked for it here
572
Q: Recent feature changes to Stack Exchange

devinbThis is an unofficial list of new features and various changes to Stack Overflow and the Stack Exchange network. It is maintained by the community, but a Stack Exchange developer changes the Accepted Answer to ensure that the latest changes remain on top (given default user settings). To see th...

but I couldn't find it
D'oh
Yes, of course it's there
:-P
I guess it's been more than a couple weeks though
Yeah, more like a month and a bit
There are just too many features, I can't keep up with them
17:36
@yuggib: $\delta(f(x)) = \prod_i \frac{1}{\sqrt{2\pi \sigma_i^2}} \exp \left[ - f(x) / \prod_i 2 \sigma_i^2 \right]$
Here $x$ is an abitrary dimensionful coordinate.
$i$ indexes dimensions.
(I'm trying to do this your way with what you called a mollifier function)
Then I say $f(x) \approx f(p) + \sum_i (\partial_i f)(p) ( x_i - p_i)$ where $p$ is a point such that $f(p)=0$.
OK, I'm off for the night (local time)... see you all later
Therefore we get $\prod_i \frac{1}{\sqrt{2 \pi \sigma_i^2}} \exp \left[ - \sum_i (\partial_i f)(p)(x_i - p_i) / \prod_i 2 \sigma_i^2 \right]$
The exponential factors into $\prod_i \exp \left[ -((\partial_i f)(p) (x_i - p_i))^2 / \prod_i 2 \sigma_i^2 \right]$
(Sorry I missed the square in the exponent in a few lines)
Actually, that changes things quite a bit...
vzn
vzn
17:53
@TerryBollinger thx found it, nice, interesting! Surely You Must All be Joking: An Outsider's Critique of Quantum Physics / O'Reilly
0
Q: Circular motion rotation

SamagraA spherical tank of 1.2 m radius is half filled with oil of relative density 0.8. If the tank is given a horizontal acceleration of 10 m/s2. Calculate the inclination of the oil surface to horizontal and maximum pressure on the tank.

0
Q: Circular motion rotation

SamagraWhich force balance centripetal force . Firstly I thought it is centrifugal force but this force is a psedu force . For example a string is tied to a stone and it is rotating and there is centripetal force towards centre then which force balance it .

What the fuck could be at 750 GeV
18:39
@Danu had some pretty amazing Czech food today
Huy
Huy
@0celo7: "The topics will be roughly about definitions of quantum groups, representations, and two main applications: solutions to Yang--Baxter equations, and constructions of quantum knot invariants (Jones polynomials, HOMFLYPT, etc). " tl;dr?
never heard of any of that
Huy
Huy
wtf
it has the word quantum in it
@Slereah ?
Huy
Huy
you're like a physics geek
18:41
literally not
Huy
Huy
literally yes
I'm an uninformed preschool child...
Today I had my first legal beer in public tho
pretty big moment in my life
Huy
Huy
wat
oh right in the US it's $\geq 21$?
yes
Huy
Huy
what's exactly the reasoning behind that
18:43
in Czechia it's $\ge$child
Huy
Huy
over here it's $\geq 16$ and I think that's perfect
@Huy beats me
no one wants to change it ofc
they're talking about legalizing pot and alcohol is still 21+
Huy
Huy
but weed is ok $\geq 18$?
I think so
in some states
Huy
Huy
logic?
18:45
in any case, had my first Hefeweizen...it was pretty good
Huy
Huy
good for you
in America wheat beers are very rare
Huy
Huy
you did illegally have beer in the US already though right?
I also had it legally
Huy
Huy
ok
18:46
it's legal in your parents' house
Huy
Huy
what kind of beers do people usually drink there then?
IPA, Lager, Budwesier/Coors/Corona/horse piss
Dark beers like Guinness or Sam Adams Oktoberfest
not sure how hard that Sam Adams actually is though
Huy
Huy
lager can be great though
dunno about lager in the US
Yuengling is considered by many to be the best American Lager.
Huy
Huy
it's usually the cheapest here but some places have good lager
18:48
::waits for US beer snobs to attack::
Huy
Huy
you drink Guiness in the US
Then there's a lot of craft beer floating around...
Huy
Huy
are you guys allowed to drink non-US drinks
don't you get death sentence for that kinda stuff
@Huy bought a six pack of it two or so months ago
was a good night
@Huy no?
Huy
Huy
good for you
guinness is cool
18:49
Had some Heineken at my brother's
Huy
Huy
oh
@Huy Have you had an IPA before?
Huy
Huy
don't think so, I'm not a fan of ales
Sooooo hoppy.
Huy
Huy
kk
18:51
I don't like a strong hops taste.
hopps? hops?
hohps?
Dunno how to spell that.
@Huy Heard the Spectre theme song on Czech radio.
Huy
Huy
Hobbes
I really disliked it
was one of the worst parts of the movie for me
whereas for Quantum the theme song was the best part
the worst part for me is when Bond raped that chick strong independent womyn
Huy
Huy
yeah that rapist
always raping le women
https://www.youtube.com/watch?v=suXkdsftsVU
that was the shit
best theme song so far
agreed
only good part about that movie
Huy
Huy
pretty much
I don't even think he raped anyone in that movie?
oh wait the ginger
18:55
although the opening chase scene was good
@Huy wow
Huy
Huy
who was supposed to bring him back
REDHEAD
Huy
Huy
hue
@Huy did you like
Huy
Huy
wat
18:58
SKYFAAAAAAALLLLLL
Huy
Huy
movie or song
song
well, both
Huy
Huy
song by itself ok
fit the mood of the movie pretty well imo
I thought skyfalls opening was by far the best
i cry every time
the feelz when she shoots him and M and the others are listening
and moneypenny's like " ......... agent down"
gg no re
the rest of the movie was average imo
all of the Craig movies have me going "wtf??" the whole thing
Huy
Huy
felt like someone had watched TDK too often and tried to copy it james bond style
19:01
he randomly does things
like he randomly found the pale king in the fourth
I feel like he was randomly in Venice in the first one
etc.
why did he randomly go to Skyfall in the third?
Huy
Huy
M said she didn't want any more innocent people to be killed because of her so she wanted to be isolated
also they really make no sense
Huy
Huy
so Bond drove her to Skyfall
which is so unbelievable because M is super selfish
why did the wife of the assassin know where the meeting would be to pick his successor
or when
Huy
Huy
cuz she's Bellucci after all
19:04
maybe she could guess where, but how would she know when
Huy
Huy
did you watch Shoot'em up
what?
Huy
Huy
a movie
I figured that
Huy
Huy
action movie
worst plot ever but with Monica Bellucci
19:04
the name suggested that
Huy
Huy
and she's really hot in there
I suggest you watch it with your SJW lady friend
I don't have an SJW lady friend
Huy
Huy
in one scene the main character is in the middle of Bellucci when enemies come and try kill him and he just keeps banging making love to her whilst shooting enemies
very realistic
oh man I could have included so many more puns in that sentence
uh...
Huy
Huy
I swear that movie is worth watching
when you want your brain to completely shut down
19:08
was it rape
Huy
Huy
I recall her orally consenting
so no written contract
speaking of brainless action movies
I hope you have seen Taken
did she say "yes" enthusiatically and at multiple points
did he ask her repeatedly if he had consent
@Huy is it on Netflix
Huy
Huy
most definitely
but don't ever touch Taken 2 or Taken 3
almost as terrible as Matrix 2 and 3
Taken 2 the Zoo
smh
@ACuriousMind Oh, yes.
@Huy ^
@Qmechanic Yes, my bad. Dunno how I did that...the only think I know about M-theory is that it reproduces 11D SUGRA.
19:19
Hm, sugar
@Huy who was the bond girl in Skyfall
hello guys . I'm tempted to create a bounty to a question I posted 2 days ago (only 28 views and no accepted answer so far) but I'd lose points that I find extremely hard to get and I'd like to have the downvote priviledge so I'd rather not spend points for now. In any case, is there something wrong with my post? physics.stackexchange.com/questions/223838/… it has no vote so far
Huy
Huy
@0celo7: marlohe
not in any other famous movies, french chick
don't remember her
what did she do
Huy
Huy
she was in that casino
Bond killed the guy who stole the HDD
after the guy killed some other guy
in the room of that other guy was she
Bond's and her eyes met after Bond killed the thief
then she met Bond in the casino
where Bond went to because of the jeton he found in the thief's suitcase
19:34
@Huy ooooooh
pretty sure that was rape
he just walked in the shower
like wtf??
Huy
Huy
Bond realized her bodyguards weren't protecting her but that she was an escort or so
exactly
that was rape par excellence
and after that he just let her die
and only proceeded to kill everyone and capture silva after she had died
such rapist
yup
@DanielSank Take the function $\varphi(x)=N(2d)e^{-1/(1-\lvert x\rvert^2-\lvert y\rvert^2)}$ when $\sqrt{\lvert x\rvert^2+\lvert y\rvert^2}< 1$ and zero otherwise
where $x,y\in\mathbb{R}^d$, and $N(2d)$ is a normalization factor
then $\varphi_h(x,y)=h^{-2d}\varphi(x/h,y/h)$ is such that $\lim_{h\to 0}\varphi_h(x,y)=\delta(x,y)$
then if you define $\varphi_h(f_h(x,y))=h^{-2d}\varphi(h^{-2d}f(x/h,y/h))$ (I am not sure about the $h$ dependence in this case, to be checked...)
what I suppose is that then $\lim_{h\to 0}\int dx \varphi_h(f_h(x,y))$ could define your $\int dx \delta(f(x,y))$
19:50
does that have to be a Lebesgue integral
however that is supposing that nothing terrible happens when I exchange the limit with the integral, and that indeed $\lim_{h\to 0}\varphi_h(f_h(x,y))=\delta(f(x,y))$.
Riemann, Lebesgue, they are the same in this case
you are integrating a well-behaved function
($\varphi_h(f_h(x,y))$)
@yuggib how useful is it to shove category theory into diff geo
@0celo7 don't know...but I guy that I know who works on algebraic geometry uses categories
quite often
not algebraic
sadly AMS does not put ebooks online
or even samples
@yuggib are you an AMS member
does one have to have a PhD in math to be a member?
the same told me that the "only" results in category theory that may yield some result that is not proved by other means are the adjoint functor theorems
but I don't know anything about that
but if that is true, then category theory is necessary for diff geo only if using the adjoint functor theorem you get something unproved by other means
@0celo7 yes I am a member
but also members do not have free access to books
and to be a member it is sufficient to pay
19:58
@yuggib but you have a discount
young ones like you (and me to some extent) have a discounted price on membership
@0celo7 yes that's true
I want to know why this book needs an appendix on categories
I have no idea
anyways, in view of the discount
I think that if you are to buy 2/3 AMS books per year it is convenient to become member

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