Apparently this artist (Salvatore Garau) sold an invisible sculpture for $18,000 a few years ago
His description of it was that it asserts "confirmation of its own nothingness"
> The vacuum is nothing more than a space full of energy, and even if we empty it and there is nothing left, according to the Heisenberg uncertainty principle, that nothing has a weight... Therefore, it has energy that is condensed and transformed into particles, that is, into us.
This is a list of invisible artworks; that is, works of art that cannot be seen and, in many cases, touched.
== Invisible artworks ==
== See also ==
Conceptual art
Anti-art
No Show Museum
== References ==
Apparently other people have done it too. I guess you can make money by just spouting some quantum gibberish
physics.stackexchange.com/questions/129978 Can somebody confirm that if I have a $\delta(x-x_0)$ instead of $\delta(x)$ here, I just get an extra factor of $e^{i k x_0}$ in the final wavefunction?
@naturallyInconsistent that message you sent yesterday got me thinking harder about the relation between the band index, the next BZs (2BZ, 3BZ) and the reciprocal vectors. As elemantary as it'a supposed to be I don't seem to be satisfied with any reference that I know, so do you know any be it notes, books or SE that breaks it down?
For example, in the case of the empty lattice, the free particle energy is $$\vec{p}=\vec{k}+\vec{G}\qquad \vec{k}\in\mathrm{1BZ}$$ and $\vec{G}$ is a reciprocal vector
So $\vec{k}$ selects the point of $\mathrm{1BZ}$, while $G$ selects the band (?)
@SirCumference I mean ofc people can do whatever they want with their money,but 18k would've fed a poor kid in somalia 3 meals a day for atleast half of his life lol
@Mr.Feynman Yes, the correct thing to study is the empty lattice. But I'm not sure why you say that textbooks don't cover it---those that do things slowly and draw out all the Fermi surface games from empty lattice upwards, should also cover this. It is just that professors usually aren't that patient. My NUS prof Sow Chorng Haur was a great prof who really cared about education and so he had some good notes about this. And magnetic breakdowns of the empty lattice. Very nice stuff.
@Mr.Feynman effectively, but it gets complicated when you are outside 1BZ
@naturallyInconsistent books do cover but I haven't been satisfied with the ones I've checked so far, so if you know any standard about (except Ashcroft&Mermin, which I've checked), I'll gladly check
@NairitSahoo remember that the translation operator defined as $$ T_bf(x) = f(x-b)$$ transforms, under Fourier Transform, in the folllowing way: $$ [\mathcal{F} T_b \mathcal{F}^{-1})](k) = e^{-i\mathcal{Q}b}, \text{ where } \mathcal{Q}f(x) := xf(x) $$
@SirCumference oh no he's Italian, thats some bad PR
@Mr.Feynman I havent seen anybody else put in that much effort. But surely there are some online resources for empty lattice? Even Kittel covered the empty lattice.
Do note that there are quite a lot of bad ideas out there. For example, the shape of the bandstructure seems to look like the quadratic bands are folded inwards. There is actually no folding whatsoever. It is entirely about rigid translations; goes to the other side of the BZ. But that kind of misleading is unavoidable.
so then to talk about cotangent vectors, I can, by definition of the differential say that if $f: M \to \mathbb{R}$, then $Df_p: T_pM \to T_{f(p)}\mathbb{R}$. Then, perhaps we can just say that $T_{f(p)}\mathbb{R} \cong \mathbb{R}$. Then, we have that $Df_p$ is precisely a linear functional over $T_pM$. This is just what a covector is.
However, how do I show that all linear functionals over $T_pM$ can be written in the form $Df_p$?
Would it just be to (1) observe that the dimension of $T_p^*M$ is the same as $T_pM$ (2) find a basis?
yeah you're more of a mathematical physicist, we know that much at this point hahaha
You must be having fun :P I'm here stuck studying for my optics oral exam
the only good part was the one about density matrices (the two hours we spent on the topic), but that part is optional so they don't even ask about it :)
Tbh you seem to me more knowledgeable than most professors I've ever met..these profs have gotten their phds from top schools in the world nd work in top 1% institutes in India : )
@naturallyInconsistent both you n @ACuriousMind : )
@NairitSahoo no; yes, signs are where you are most allowed to be uncertain about, but you should be able to get it with just one simple substitution. And yes, the conventions would impact this; but at the same time, you should be extremely familiar with the standard physics conventions---those are so important, that there exists no physics deviation from that convention!
But anyway...... I have a new question: is there a way to derive the boundary conditions $n \cdot E_1-E_2= \sigma/ \varepsilon$ and $n \cdot B_1 - n \cdot B_2=0$, etc. in a Lorentz covariant way?
@naturallyInconsistent (and @ACuriousMind ...) I suppose since we're on the topic if you'd feel comfortable sharing what motivated you to leave academia?
@naturallyInconsistent Idk. Let's consider this to be an academic exercise? I know EM is a Lorentz covariant theory, I just need a Lorentz covariant way to derive something which I derived in a non-covariant way!
@qwerty I'm not in academia. But my temperament is suitable for academia. I'm interested in the esoteric details that goes into making sure the physics we work with, will make modern society tick smoothly.
@NairitSahoo Then I'm going to have to ask you to go bother someone else. Nobody gets to waste my time on clearly useless pursuits without my own approval. That is, I'm perfectly fine wasting my time on useless pursuits in my own leisure, but that is the key: my own leisure.
Hi all. Im currently reading about the Pauli exclusion principle in my PChem textbook and im curious, is it necessarily the case that a multi electron wave function can be written as the product of single electron wave functions?
In the section on Hartree-Fock it makes that assumption but I’m not sure if thats part of that approximation or if its generally true
@Allie necessarily impossible. And in Hartree-Fock it is not a product, it is a Slater determinant; even one single Slater determinant is necessarily going to fail to capture some physics. There is no hope of using that to get the exact answer. However, it can get you results that are soooooo gooodd despite being wrong.
@Arjun how mathematically rigorous? Actually, quite a lot of those rigour came from fistfights. i.e. those were real careers at stake and plenty of money behind making sure that things are done correctly. But of course, you can find rigorous nonsense too
@Allie what limit? You can improve upon Hartree-Fock results by doing even more computation...
@qwerty yay, om nom nom
but it is sad; today at work miao miao went to ask a wise advisor for directions, and he said that the direction miao miao wanted to pursue is unlikely to be fruitful.
@naturallyInconsistent More HF computations or other methods? From my understanding the book says that theres a limit to how good your approximation can get with HF, and after that people use perturbation or other methods
@Allie post-Hartree-Fock. The issue is precisely as the book states: HF has a limit to goodness, so if you want to go better than that limit, you have to go beyond HF.
@qwerty There is a tremendous chasm between theoretical physics and mathematical physics. Theoretical physics is busy finding new physics, using old maths to fit new phenomena, things of that vein, whereas mathematical physics often tries to rewrite the known physics theories in terms of rigorous maths. Sadly, even though we do get great insights into what known physics is really trying to say when they succeed, those rigorous formulations seem to never be applied.
@qwerty I ditched myow phd track to pursue this company
@Arjun all of those are heavily applied stuff. Boltzmann's equations, transport or not, are extremely annoying to solve. You can definitely feed your family on it, but always hungrily.
@naturallyInconsistent Who do I bother? How to get your approval? When will you like to waste your time: I mean, when is your leisure time? I will come back when you have some leisure period to enjoy
thanks for sharing, @naturallyInconsistent. it's nice to hear about different life paths. tho idk if working for a research start up is less stressful than trying to make it through various postdocs / there are any vaguely in my field lol
@Arjun and it would be time to go and partyyyyyyy soon miehehe
@qwerty each position comes with its own ups and downs. but it grinds against conscience when the entire research direction is purely scammy. If one cares a lot about morals, it may prove too much if one cannot at least prove to themselves that their work is trustworthy.
I mean, people may well not trust our research startup's output, but at least we arent in the business of lying to ourselves.
I certainly do hope that the recent papers about taming quantum noise is actually good. That was the shitshow that miao miao is lucky to have exited very early on.
At least their direction isn't anywhere as doomed as mine
somehow I'm not completely jaded about science. I just don't know if I have it in me to go through the job insecurity and come up with research proposals and all that. and Im a little slow, it takes months to years for me to figure out things that it takes other people a few hours or days at most.
@qwerty I realized I didn't enjoy doing research. I like learning and I like teaching, but the research work you do as a theorist didn't appeal to me all that much. Also the precariousness of the non-tenure academic job market wasn't particularly inviting, either. And finally I had gotten a bit disillusionized with my specialty - QFT and string theory - but I could've switched topics, I guess.
The fact that you can reduce your classical mechanics to some parametrized system by time is essentially that process, you select a preferred class of observer and then you quotient it out of the spacetime
so they usually just guess, and not only they are able to guess a time-like foliation, they r also able to get the parameter to equal proper time in advance
i will have to read about it, so i can ask better questions
@ACuriousMind I need to link an SE answer in a (personal) document. Is there a possibility that the link or id of the answer will change in the future and my link will be dead?
@Mr.Feynman again, since SE is under a creative commons license, there are several data dumps (e.g. on the Internet Archive) that contain all posts up to a certain date and these are regularly updated; even the site going offline would not mean you can't find the post again from the id in the link
@ACuriousMind We can copyright strike them right?cuz I feel like they're making money off someone else's hardwork and scamming people for content that is freely available!
You can read all about it in this last link I pasted here
It's not a scam, nonetheless just from a moral standpoint I think it's indecent. Making money off of content that people voluntarily created and is free to read on the internet
@naturallyInconsistent why do you say the entire research direction is scammy? Are they fudging results or something? Please elaborate cuz who knows might be useful in the future
@Slereah But wouldn't it be a real problem to make it more restrictive? I mean if I'm working on some commercial project and I get some specific help in SE... I would need to think twice about whether I'm allowed to use it with a more restrictive license, won't I?
and in many cases that would defeat the whole purpose of SE
I guess one distinction the license can make, is between using the contents of an answer in some way vs. quoting an answer. Arguably, the latter can be made more restrictive
But I'm not a lawyer and I don't even know that license really very well
@Mr.Feynman What's special about IT that relates to physicists?.. Some startups and tech companies need physicists (theoreticians or experimentalists). It's just that the numbers aren't very big compared to other positions I guess
@Mr.Feynman One good reason can be, it is a position that has to do with a lot of numerical simulation. Many physicist can happen to have more experience with that than most programmers. Even when lacking the technical know how, they have the theoretical background to understand how to simulate a physical system
A software career is not bad per se, but do companies usually provide formation? For example, the only programming language that I know is basic C. Not that I couldn't learn others but why would they choose someone who doesn't already know their languages 💀
@Amit there are approximately zero jobs in "simulating physical systems" compared to everything else in the tech sector; they really don't hire STEM people for their STEM expertise, they hire STEM people because they have general problem solving skills and often come with programming knowledge
I'm using 0% of my physics knowledge in my job, and this is the norm among people who studied physics but now work in tech
@Mr.Feynman I see but like, are you in the middle of a PhD or something like that , that you're considering to give up on?
@ACuriousMind 100% agree that a Physics major that can also program in language X is way more attractive to any reasonable tech firm than someone who can just program in the same language X. Those companies know that a Physics degree is a stamp that indeed says "problem solver"
I guess my answer to Mr.Feynman's question was assuming that he also wants to apply his actual physics skills & knowledge in some manner in said job
@Mr.Feynman If you have a strong grasp of C that's an amazing starting point to learn OOP languages like C++, Java, C# and probably several others languages that basically expand on the C syntax albeit with varying degrees of (at times, crucial) alterations of syntax. Anyway the major alteration is conceptual in understanding the "Object oriented" business, but since that was invented to make programming ultimately easier, it shouldn't be difficult
ofc. Question is also, whether you like this stuff or not. Liking in this context means probably sitting every day for at least a good 5-6 hours and writing code with this stuff ;)
Yeah C++ is kind of the dinosaur of OOP. C# & Java are a bit more modern in that genre. Then there's Python, which is just too "cool" to be "just OOP" -- it is very multi-paradigm
Anyway, if you're at the end of MSc it definitely makes sense to weigh the options
i would say other parameters are fine even in QM, as long as u know how to convert between them and time
but in quantum gravity, a strange problem arises, as the actual time becomes quantum mechanical, while the parameter time stays a parameter
so the theory becomes non predictive, as the parameter time can't be measured in experiments
in Wheeler Dewitt equation, this problem doesn't arise. But this theory does not have parameter time (i think), and the actual time is quantum mechanical
@RyderRude there's this new interesting (in my mind) question, when I read it I thought the linked article is the type of thing that's exactly up your street ;)
> In other words, in an "interaction-free" measurement, there is an interaction, and it triggers the collapse process, which then impertinently deletes it from existence.
In MWI, the deletion part isn't there
cuz the other branch still exists
@Amit I'm not sure, but yes, weak measurements are just usual measurements
I think the notion is not really defined too well either. For example sometimes the EV bomb tester experiment is considered a type of weak measurement, too. But other people talk of weak measurement only in relation to something you do on an ensemble of states that are identically prepared... so it seems a bit of a loose term