Is it really correct to say that the pre-SSB Higgs field does not interact electromagnetically?

after all, the covariant derivative contains a $\sim ie A_\mu(T_3+Y)$ term which is only a symmetry when the Higgs acquires a VEV: $\phi=(0, v+h)^T$

so it should act as an interaction otherwise?

Hi All...

Hello @JohnRennie Sir.

@NiharKarve no, it's not - the "upper component" is clearly electrically charged, see physics.stackexchange.com/q/463026/50583

thanks, that's pretty much what I was thinking

"goldston"

Anyone know what "the BBS-book" is referring to? Used in this answer for context

Becker, Becker, Schwarz

there is a free copy available online if you're interested

aah yeah that sounds familiar

I maintain, however, that it is not a good book to learn string theory from

oh maybe, saves me ahem buying myself a copy

oh, well in that case I was just curious what it meant

Hello. Is it appropriate to ask physics questions here or is this chat mostly for the discussion of how to operate the site?

@Summer You absolutely can ask physics questions here :)

I am working on projectile motion and I was given an equation to find initial velocity given the angle, displacement and heights. The part I am confused on is that the equation uses the constant g, but if I take the value of gravity at 0 seconds the entire equation will ultimately 0 out.

I am trying to find out what value I am supposed to use but I am having trouble finding the answer.

g is just the constant number 9.81, or often approximated to 10, so it isn't clear what you mean by the value of gravity at 0 seconds.

ohh. I thought it was 9.81x^2

No, just 9.81 :-)

wherein at x = 0 the value would be 0

Thanks for clarifying. I am a little embarrassed so I shall retreat now.

😅

Hello there

Why am I getting different COP's for a heatpump when I use Carnot's method, just enthalpies, and lastly both the heat going out from the condenser divided by the compressor power?

I have two sets of values one for each cycle performed in a lab. Of course, when using the Carnot's you acquire the highest COP as possible from the given values. However, between the enthalpies and the when heat is absorbed by the heatsink, enthalpy always has a higher value.

For the COP, that is.

I can clarify one of the methods, the "heat going out from the condenser divided by the compressor power". This is where you can make use of the water loop around the condenser, where both the cold water goes in and the warm water at the outlet. For its heat rejection we make use of the specific heat capacity of water and even the mass flow rate of the water.

And the temperature difference of the warm and cold water.

I wonder whether the author of this recent cartoon was inspired by this slightly-less-recent question.

“Move the Earth” was totally my answer to that question, but I was pretty sure it wasn’t what the asker wanted.