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12:09 AM
If I transform a Majorana spinor, does it stay a Majorana spinor
 
now I'm not following you, either :P
 
This maybe a silly question, but why does contravariant and covariant representations pop up for spinors as well?
 
It's alright
 
the Majorana rep is a proper real representation of the Lorentz group
 
I only vaguely know what majorana spinors are
@DIRAC1930 well they are vectors
 
12:11 AM
Do they pop up in non-rel qm?
Pauli spinors
 
sure
 
Why does it pop up for vectors?
I can follow the math but I just don't know why
It just seems to be a definition
 
it's just the generic version of a dual
you have vectors, and you have linear functions on vectors
both of those have similar behaviours
 
But why stop there. Why not consider non-linear functions on vectors?
 
because they don't behave similarly
although you can make algebras on vectors, if you want, but that's a different beast
 
12:15 AM
It it really just a tool to make invariants?
 
what is
 
Contravariant and covariant representations
 
I mean they give you numbers yes
which are coordinate invariant
 
Is that the only reason?
 
I don't know what you want my dude
 
12:21 AM
As in the only simple reason
Well we want the Lagrangian to be invariant under some group $G$
So we have to find invariants of the group
$M_{ab}\phi^a \varphi^b$
where $\phi^a \rightarrow G_{ab}\phi^b$
Which fixes $M$ or something
If given the condition $M$ must be invariant
I dunno
I can't remember
 
 
4 hours later…
3:58 AM
@Slereah, @Semiclassical, @bolbteppa, @ACuriousMind - just eavesdropping on your string discussion...you all seem very broadely read. if i ever manage to get to grad level physics is this kind of general understanding i might expect, or are you reading much more broadely from personal interest?
 
 
4 hours later…
7:43 AM
Hopefully you'll know all the stuff we don't :p
 
haha here's hoping
 
I don't know much about string theory tbh
I mean I know more about string theory than most people on earth, and more than most physicists I guess, but that's a pretty low bar
 
3
Q: What is the risk from radiation on imported food from Japan?

JohnI'm currently resident in Hong Kong a country which appars to import heavily from Japan. Last saturday 7th May I went to a restaurant: http://www.openrice.com/english/restaurant/sr2.htm?shopid=39760 which I later discovered is themed after a popular Japanese coffee brand. I had one of those Fri...

That's an awfully clickbaity title
Any takers for how it can be edited to show the question in a more neutral light?
Particularly to show the timeframe in which the question was asked
 
 
1 hour later…
9:06 AM
Hi all, does anyone have any suggestion on where I can study quantum spin models in 1-d? For now I am mostly interested in XX and XY quantum Heisenberg models. I am looking to understand the concepts of quantum phase transition, spontaneous symmetry breaking in QM with infinite dof ( and why it doesn't arise in the finite dof limit) and the emergence of Dirac fermions in XX model, with using as prototype XX and XY models, the focus is on rigorous result.
 
The Lieb–Liniger model describes a gas of particles moving in one dimension and satisfying Bose–Einstein statistics. == Introduction == A model of a gas of particles moving in one dimension and satisfying Bose–Einstein statistics was introduced in 1963 in order to study whether the available approximate theories of such gases, specifically Bogoliubov's theory, would conform to the actual properties of the model gas. The model is based on a well defined Schrödinger Hamiltonian for particles interacting with each other via a two-body potential, and all the eigenfunctions and eigenvalues of this...
That's often a starting point in these discussions
 
10:00 AM
Is there any source that discusses the limit of relativistic string to point particles in a non-off hand way
Like actually talk about deformation retract or something
 
I have a follow-up question regarding a question that I posted here a few days ago. If I have u=g(x), and some wavefunction \psi(u). Now, I replace all u's in this wavefunction by g(x) and get \psi(u)=\psi(g(x))=\phi(x)
Then \psi(u)=<u|psi>
and we can say |u>=|g(x)>
so, psi(g(x))=<g(x)|psi>=<u|psi>
Can I write <g(x)|psi> as some <x|phi> where |phi> is some other state
 
Barbashov is maybe the only one I have seen that starts from the point particle and uses it to go to the string
The usual way is better, they are basically just doing it backwards anyway, and what happens when you go above strings, the usual way is immediate and it's a direct analog of SR thinking
 
Since psi(u)=phi(x), they must be representations of different states. However psi(u)=<u|psi>=<g(x)|psi>=psi(g(x))=phi(x). However, is it legal for me to write <g(x)|psi> as <x|phi> where |phi> is some other ket, to show that the normalization has changed by plain substitution, by showing that the state |psi> has changed to |phi>
 
10:18 AM
I kind of want to see like a proper math version
Like "If you do a deformation retract of a brane along a Cauchy foliation of the target manifold, the $p$-brane reduces to a $0$-brane action"
or something like that
Does such a thing exist
maybe mapping the mapping space of $p$-branes to smaller branes
shit like that
 
Does an area integral reduce to a line integral just by taking limits
 
@bolbteppa Maybe it does in some sense!
My best attempt at the idea so far
 
@antimony No, this definitely isn't "general understanding" - I pretty much specialized in QFT and string theory during my studies and read a lot of papers about that beyond the standard syllabus, I know far less about many other subfields (e.g. I know almost nothing about fluid dynamics).
 
But it's all very coordinaty
It doesn't work unless I throw in an additional factor, though
It doesn't change the dynamic, but still
 
@Slereah ...are you talking about compactification?
 
10:22 AM
@ACuriousMind I don't think so?
Just "the limit of a string is a point" sort of thing
 
if you have a p-brane and compactify d of its dimensions, the effective theory has a p-d brane
 
Well that could certainly be part of it, yes
but I meant more leaving the target space intact
And just shrinking the brane
Along a particular foliation
 
I don't understand what sort of limit you're imagining there
 
is that a thing that exists
Well, take your target manifold $M$, a foliation by spacelike hypersurfaces $\Sigma_t$, some $2$-manifold uuuuuh (I'm running out of good letters) $S$ and a string $X : S \to M$
 
@EmilioPisanty maybe just add a "after the Fukushima incident" or something like that to the title?
 
10:25 AM
And now imagine some map that will send $X$ to a... I guess it will be a traintrack 1-manifold, generally, such that for $X$ on $\Sigma_t$, the string is reduced to a point
(Yes I know that the resulting lines will depend on the foliation because there's no localized vertex in strings)
 
but what process does that correspond to?
what's physically happening there?
 
Well physically nothing I guess, just trying to figure out how one can get the limit to a point particle generally
[please note that I'm talking classically here]
 
as I said the idea of "the additional dimension shrinks so much we can effectively ignore it" is already modeled by compactification
 
[just relativistic strings going to relativistic points]
 
oh, you still think classical strings are somehow relevant :P
 
10:28 AM
Well, I don't know about "relevant"
 
If $\mathbf{r}$ is independent of $\sigma$, their derivation of the string from the point particle stops at the first step
 
But I don't need to justify myself in studying topics :p
 
Is it really consistent to do that working backwards I'm not sure, but at least going the other way it seems to make sense
 
String theory is also useless yet I don't see you justify yourself!
 
sorry, when someone is talking about "strings" I always think they're trying to do string theory. If you're just interested in classical strings for reasons unrelated to string theory, sure, go for it
 
10:31 AM
@ACuriousMind If it makes you feel better just pretend I'm talking about domain walls
or just plain old geometry
Although I think cosmic strings are infinite, so idk if those are very good to treat as point particles
Open ones, at least
Or maybe I am tuning my relativistic guitar
 
All you're really doing is looking at Minkowski space and saying a surface is parametrized by two parameters and that the surface has one time-like and one space-like direction, why do you need to do that and then restrict to the case of a curve when you can just do the curve directly
 
Well, the thing is that in some cases, you won't get a curve!
You'll get a graph!
 
why would you get a graph?
 
In the mathematical area of topology, a train track is a family of curves embedded on a surface, meeting the following conditions: The curves meet at a finite set of vertices called switches. Away from the switches, the curves are smooth and do not touch each other. At each switch, three curves meet with the same tangent line, with two curves entering from one direction and one from the other.The main application of train tracks in mathematics is to study laminations of surfaces, that is, partitions of closed subsets of surfaces into unions of smooth curves. Train tracks have also been used in...
You'll get one of these
@ACuriousMind idk, consider the pair of pants worldsheet
 
@Slereah but how are your "classical" strings merging?
 
10:36 AM
what would be the contraction of that to a point
 
that's not a very classical behaviour
 
@ACuriousMind Hence why it's also a good idea to maybe consider it as more of a geometry problem
Although Wu totally talks about curves like that in GR
I suspect that such a limit would be highly non-unique tho, so idk
but I would still be interested to find out if something on the topic has been done
 
@bolbteppa thanks for the suggestion, I have found some notes looking for Lieb-Liniger model that could help.
 
like your string could contract to any point on that string at a given time, and if the string is closed, it's even worse!
An open string can contract to a point it contains, but a closed string can't get contracted without moving the string itself!
 
@Slereah ...what do you do if the string is wrapped around a hole (it's not null-homotopic) :P
 
10:39 AM
@ACuriousMind Yet another issue!
What if my string is tied through a network of wormholes!
and it's tied into knot
And I don't have my cosmic string scissors
I guess maybe it's doable in some very specific set of circumstances
Like the one Barbashov does
Open string in a topologically simple space
 
@ACuriousMind As a professor told me one time when discussing in which field I could specialize in the master thesis , "either you are Landau or you got to specialize in some subfield".
 
Landau didn't know every field!
Where's Landau's book on vulcanology
or meteorology
Lev Landau
What is that on the board
 
10:57 AM
Is it a gamma matrix
 
11:10 AM
@Slereah In Polyakov it seems more reasonable to just set $X^{\mu}(\tau,\sigma) = X^{\mu}(\tau)$ and $h^{\alpha \beta}$ only having $h^{11}$ non-trivial to do the transition
 
So basically the motion of the endpoint?
but then that's only in a coordinate patch!!!
What if the sheet splits
 
It's the point particle case no
 
11:30 AM
how does one specify that a worldsheet never split in a coordinate invariant way
a worldsheet that splits still has the topology $\mathbb{R}^2$
Convexity would do it, but you could have non-splitting worldsheets that aren't convex
 
@Slereah for an open string? number of connected components of the boundary
 
Well yes, but that's assuming a foliation, no?
 
an open worldsheet that doesn't split has just two - a "right" and a "left" boundary, but one that splits somewhere will have more
 
Although... I guess if you have a worldsheet that doesn't split, the boundary is two copies of R
and if it splits there are three
 
that's what I mean, yes
 
11:38 AM
What is the Hilbert space of string theory anyway
I know that for quantizing a single bosonic string it's like a regular particle Hilbert space $\otimes$ some Fock space for string excitations
what is the full one like?
Or is there no full one that people consider in the perturbative version
 
I don't know what you mean by "full"
 
I mean that's like the Hilbert space for a single string, but the "real" string theory is a sum over however many strings
 
I assume you need a Hilbert space to accomodate arbitrarily many strings
and their excitations
 
that's the part where it gets muddy
 
11:40 AM
Is that one of those string field theory only business
 
string theory is not the theory of "a bunch of strings floating around but quantized "
 
or M theory or whatever
 
string theory is a framework for specific theories just like QFT
asking what the Hilbert space of string theory is is about as meaningful as asking for "the" Hilbert space of QFT
 
Well what is perturbative QFT if not a bunch of little particle collision diagrams :p
@ACuriousMind Well I'd be satisfied with any string theory Hilbert space
You know how cognition works
prototype v. exemplar v. formula
 
and it's also not a quantum theory where we'd have a time evolution operator or anything
it only has "Hilbert spaces" associated to the strings at the outer (infinite past/future) boundaries of a worldsheet
 
11:42 AM
I mean I know that the perturbative one is only for scattering yes
hence why it is BAD
 
there is nothing else
 
what of the M theory
 
string theory is defined by the sum over worldsheets
@Slereah no one knows how the quantum theory of that one is
 
Shouldn't M theory have an actual theory that can do things, at least hopefully
@ACuriousMind Do they not know, or do some people think they know but nobody agrees
 
"M theory" is just the name of a concept that should exist and correspond to 11d SUGRA, just like the five different ways of doing string theory correspond to the five different 10d SUGRAs
 
11:44 AM
^this is how cognition works
it involves a lot of dogs
in this case, replace the dogs on the left by examples of Hilbert spaces in a string theory, and on the right it's a "canonical" Hilbert space for a string theory
 
@Slereah I'm sure some people think they know
but I'm also sure no one really has anything that really works
as much as string theory dresses itself in "this is just a classical theory quantized", it is not a QFT
 
Well I'm sure we would have heard of it otherwise
 
there's no interaction picture or anything, you just have the in/out Hilbert spaces associated to the Fock spaces of the strings at the edges of the worldsheets and a prescription for how to compute scattering amplitudes
 
I know, but I also know that plenty of people are not satisfied with that state of affair :p
 
that's fine
 
11:47 AM
I'm sure there's a bunch of proposals
 
the problem is a bit that proposals for that are even less "testable" than the string theory we already have
the scattering prescription suffices to take the "low-energy" limit and get an effective QFT
and the effective QFT is what we are comfortable to work with to see beta function, particle content and whatnot
 
$$\mathcal{H} = L^2(\text{sheaves of differential cohomology on the $\infty$-topos BV-BRST of smooth $p$-branes with orbifold twist})$$
Something like that
@ACuriousMind Psh who cares about testability
What are we, engineers?
 
so I don't think it's clear how one would even tell what the "correct" non-perturbative formulation of string theory is because it is unclear what sort of effect that would even have
@Slereah I put that into quotes because I'm not thinking about experiments here, really
I'm saying I wouldn't even know how to assess the theoretical physical significance of the non-scattering part
 
Well, you know what I always say
When in doubt, do the hydrogen atom
 
easy, just take the low-energy effective QFT and do whatever you do in QFT for the hydrogen atom
 
11:52 AM
if your theory can't do the hydrogen atom without going back to QFT, is it really good for anything!
 
the problem is that the "low-energy" threshold here is so high that it's unclear what sort of situations one should think about in order to see truly "stringy" effects
@Slereah my point is more that any deviations from the QFT hydrogen atom in prediction has to be so miniscule that it's not a practical way of assessing a "true" string theory
 
Well I'm not saying it should be, but I'm saying you should be able to compute it from the theory
 
if the person who designed the theory isn't a complete idiot it will be such a tiny correction (if any) that that's not a criterion you can usefully apply
 
Not a lot of difference between the Pauli equation hydrogen atom and the Dirac equation hydrogen atom, but it's good that we can do both
It's the completeness requirement for a theory thing
The theory should be able to predict everything within its domain of discourse
and since string theory is a theory of everything that's a pretty large domain
 
@Slereah but that's the thing - via the effective QFT, it already "predicts everything"
 
11:57 AM
well yeah but that's like saying "GR can predict orbits by going to the Newtonian limit!"
 
we do not know any actual phenomenon that you would need string theory (or any other beyond-QFT) to explain
 
True, but lame
 
so there's no starting point for the theory
 
if your theory of everything only works in its already known limits, then it's not a very impressive one!
 
I'm not saying you're wrong philosophically, I'm explaining why I think we don't have a good angle on how to get the "full" string theory/M-theory whatever
@Slereah well, yes...that's kinda what the opponents of string theory say!
 
11:58 AM
Maybe I am a string hater
Boo string theory
Do better you hacks
 
but it's a very general problem for the QG theories, I think
 
I'd try to read more string field theory but then when they start talking about the superorthosympletic group my soul starts leaving my body
Well some of them are very easy for that
covariant QG and canonical QG and euclidian gravity do it very easily, it's just that they otherwise don't work
 
they're all just motivated by us being aesthetically displeased with QFT and GR not playing nice, not by actual phenomena we obviously need a new theory to explain
and so you don't know what sort of "fundamental mechanics" to look for because all you want to do is get a theory that has both QFT and GR as its limits, but we don't really have data on what else it should be
 
Like you can do the hydrogen atom in covariant QG, it is super easy
just too bad that it's not renormalizable!
 
If all we knew about QFT was that it should reduce to both classical EM and quantum mechanics in some limits, how would we ever have arrived at QED?
 
12:02 PM
@ACuriousMind Whatever people were doing in the 20's with it!
 
I'm pretty sure they already knew about phenomena you can't explain with ordinary QM
 
I'm not a picky man
I'm not asking that it works in experiments, that it predicts anything new, or even that you can physically calculate anything
Just try something idk
go wild
 
What's wrong with Barbashov's version of the limit from strings to particles in (2.23)
 
It's one of those things where people get super partisan for some weird reason
I don't care that much about who wins the quantum gravity race
@bolbteppa Well it only works in a very limited number of cases and also you kind of have to add weird terms to the action to make sense?
 
I think it's a general derivation in (2.23) and they don't add anything
 
12:11 PM
Well yeah but then obviously they're cheating because they're using specific coordinates
 
They're not using specific coordinates, and why they write the overall constant as energy per unit length is also something you can show by looking at the non-relativistic limit
 
The sheet is already $\mathbb{R} \times \mathbb{R}$ and $\sigma$ is purely timelike and everything has the appropriate number of boundaries
This wouldn't work if you considered an arbitrary worldsheet in an arbitrary spacetime
Also I think it wouldn't work for a closed string?
 
I don't know what that means :p But for $S = - T \int \sqrt{(\dot{x} \cdot x')^2 - \dot{x}^2 x'^2} d \tau d \sigma$ it works
 
It certainly does!
There is actually a better demonstration of it in one of Nambu's papers
 
You mean the Goto paper where he basically does this backwards
 
Yeah it's the same idea
They even reference it for this
 
I know
It's how I found it :p
 
I know you know I just seen your question :p
 
Well, the question says I don't know!
 
I think this is the best one can expect
 
12:15 PM
Or at least I don't know everything
I'm pretty sure you can't consider every string as a point particle in some limit, but there is probably a class of them that you can
I'm just not sure how wide that class would be
like if you had a string that tied all the way around the two mouths of a wormhole, it would be a stretch to consider it as a point particle
 
Well the big thing is appreciating that $\gamma = m_0 c/l_0$ is actually the string tension and it's given as energy per unit length. You can see this has to be the case from the non-relativistic limit where you get the non-relativistic action for a string letting one interpret the coefficient in that way. The Becker book does it explicitly
 
It would be a literal stretch
 
This means we can take this $l_0 \to 0$ limit and the $L \to 0$ limit simultaneously. That the integral thing in (2.23) is actually the length we can just give the Goto argument if we need to justify it's interpretation
 
yeah that part is fine, mostly
Since if you add the length of the string in the action like that, it doesn't change the EoM
So it's probably fine on a formal level
 
@Slereah Well you can be sure only that these books weren't published, but yet Landau could have wrote it
 
12:20 PM
So I mean I don't know what the issue is except vague arguments that we can't even write $\sqrt{(\dot{x} \cdot x')^2 - \dot{x}^2 x'^2} d \tau d \sigma$ because it's sullied by using coordinates even though it's covariant
 
@Ratman I'm not sure I trust someone who looks so much like Kramer
@bolbteppa Well as I said, it's a very specific case
 
It's not a specific case it's everything the free bosonic string claims to describe
How do you argue $S = - \alpha \int ds$ reduces to the free non-relativistic action without using $ds = \sqrt{1-(v/c)^2} c dt$
 
there's something going on there
 
We'd never get anywhere if we didn't just accept arguments on this level and move on, there's nothing wrong with it
 
I didn't say I had the solution in mind!
 
12:26 PM
Is pulling $\sqrt{\dot{x}^{2}(\tau,\sigma^*)}$ past the integral without using some $...$ terms okay
 
@bolbteppa Also really if you're gonna use coordinates for the NG action, why use such a vulgar one
No that's fine
I'm just not sure what's gonna happen for like
a closed string
 
The whole thing is covariant so it doesn't matter that we use them in this form
 
or anything else with a weirder shape
 
It works for a closed string too
It's just shrinking down to a dot
 
Yeah but then that's not the same process, is it?
If you do it by shrinking the $\sigma$ parameter, a closed string isn't gonna contract
 
12:28 PM
All boundary conditions are built into the action as it's written in (2.23)
 
I'm not 100% sure there
 
They even have a paragraph on string fields later on
 
I think in $2.23$, no matter what shrinking you do to the parameters, the string is never gonna go to places it wasn't before, so to speak
Which works for shrinking an open string, but not so much for a closed one
 
The action just describes the surface generated by a string moving through space-time, it makes no different what type of string it is, you're just looking at the surface it generates as it evolves for any type of string
 
I think you need to contract the brane itself and not play around with the parameters here
I mean I guess maybe mathematically you'll end up with the same action, but it feels a little weird you know?
Like if I shrink the parameter a little bit on a closed string, then it will cease to be a closed string
since you no longer have $X(\sigma_1) = X(\sigma_2)$
 
12:32 PM
Yeah but the weirdness is in that limit, what limit isn't weird when you think about it
 
idk I think the process should be continuous at least
 
$\lim_{x \to 2}\frac{x^2 - 4}{x-2} = 4$ is weird
 
I want to see little retracts of the string
Like what Barbashov is doing here is essentially taking an open set of the sheet and shrinking its domain
It's not the string itself shrinking, so to speak
Doesn't matter that much I suppose, but I wonder if you could do it that way
 
Right it's shrinking the area that the string spans in space-time down to a curve
 
the same way you shrink a loop in homotopy theory
 
12:36 PM
I'm sure you could do it with a retract but you'd probably end up doing what they do here at some intermediate step in some form
 
Well yes, but I'd like to see it!
many things are equivalent, that doesn't mean we shouldn't do it!
I think it is of the utmost importance that someone do it bc I think it would be cool
 
fqq
@Slereah the problem is that apparently some other attempts at quantum gravity don't even have that
 
Well I never said it was easy
but I think just saying "That's not the goal here!" is a bit of a cop out
If it doesn't exist yet that is fine, but pretending that the question itself is irrelevant is a bit weird
 
fqq
@Ratman I don't know what the best source would be, there are many books, e.g. Sachdev - Quantum phase transitions
 
In topology, a branch of mathematics, a retraction is a continuous mapping from a topological space into a subspace that preserves the position of all points in that subspace. The subspace is then called a retract of the original space. A deformation retraction is a mapping that captures the idea of continuously shrinking a space into a subspace. An absolute neighborhood retract (ANR) is a particularly well-behaved type of topological space. For example, every topological manifold is an ANR. Every ANR has the homotopy type of a very simple topological space, a CW complex. == Definitions == ��3...
The action written as (2.23) is probably the $F$ in the definition of a retract
 
12:43 PM
I know what a retraction is, yes, that is the word I employed :p
I think it works as a retraction in the open case but not in the closed case
In the closed case I guess maybe you'd need to retract in some notion of "the middle", but that seems hard to define properly
 
Where is the distinction of open vs closed written in the action?
 
it works for both, but in the closed case that limit isn't a retraction
Since it doesn't preserve the loop
 
fqq
@Ratman Mussardo - Statistical field theory, Tsvelik - ¨ QFT in condensed matter" or something like that, Giamarchi - Quantum physics in one dimension
 
the string just snaps open and goes down to a point like a dying Pacman
 
fqq
then there is more specifically all the Bethe Ansatz stuff, again I'm very rusty so I don't know the best resources, maybe these notes arxiv.org/abs/1609.02100
 
12:50 PM
also if the topology goes slightly more complex than open or closed, then I think it all goes out the window
 
The closed string doesn't need to snap open it's like a ring getting smaller until it collapses to a point!
 
Is that what happens in Barbashov?
I think not
He only changes the parameters, the mapping $X$ doesn't change at all
 
Because the length shrinks down to zero in the limit, what else can happen
 
So it can't "shrink" in that sense
it can only be "less" of what it already is
which works for a line, but not for a circle
you can only have a subset of that circle, not a smaller circle
 
The length literally shrinks to zero so that the line/circle collapses down to a literal point, it has to
 
12:54 PM
well its length shrinks, yes, but only because you consider a receeding arc of the circle!
 
The tension goes to infinity in the same limit, which is equivalent to $l_0 \to 0$
 
Hm
 
You'd be contradicting the meaning of a limit to say otherwise!
 
I guess maybe I need to work it out explicitely to check
Like maybe consider a closed string with two circles on the boundaries and see what happens
 
If anything stays finite then you still just have the string action
So the way they wrote it with that $\sigma^*$, I mean is there not some approximation there with $...$'s
 
12:56 PM
The $\sigma^*$ I am fine with, that's just the mean value theorem :p
I'm trying to think of a way to write this proof in a coordinate invariant way :p
I guess you could use a length function $l(X)$
and then perform a retract on $X$
But then you need to define a foliation first I guess
But I guess that definition would work for any foliation
 
So because $\sigma^* \in [\sigma_1(\tau),\sigma_2(\tau)]$ it's different for every $\tau$ so really there is no approximation
 
so it is independent of the foliation in that sense
but I guess there is kind of a choice there
To which point do you contract it to
but I think you need to decide that by hand
maybe by considering the midpoint on the boundary condition idk
 
1:14 PM
Hi everyone
 
Hello
 
I have a quick question
I created a riddle inspired by physics.stackexchange.com/questions/126919/…
41
A: Does time move slower at the equator?

Luboš MotlThe difference would indeed be measurable with state-of-the-art atomic clocks but it's not there: it cancels. The reasons actually boil down to the very first thought experiments that Einstein went through when he realized the importance of the equivalence principle for general relativity – it wa...

I'm trying to understand the answer (I'm only an first-year undergrad in Physics)
We expect time to tick slower at the equator because the earth spins fastest at the equator, and slowest at the poles (in fact, the poles technically don't rotate at all)
Thus, we expect time to dilate by an amount given by the gamma factor
Apparently this effect of time dilation cancels out because the equator is farther from the earth's center (due to the equatorial bulge), and so time ticks slightly faster than the poles, which are closer to the core?
Would that be correct? @Slereah
 
I don't know if it cancels but yes, there are several effects at work
 
David Hammen states "Yes. The flaw is that you are ignoring general relativity. The poles are closer to the center of the Earth and are thus deeper in the Earth's gravity well than is the equator. The combined effects of gravitational and special relativistic time mean that clocks at sea level tick at the same rate. More precisely, clocks at the surface of the geoid tick at the same rate."
13
A: Does time move slower at the equator?

David Hammen Is there a flaw in my reasoning or have I simply not been reading the right journals? Yes. The flaw is that you are ignoring general relativity. The poles are closer to the center of the Earth and are thus deeper in the Earth's gravity well than is the equator. The combined effects of gravit...

 
1:30 PM
Also check out this interesting tidbit from xkcd :
"It's common knowledge that Mt. Everest is the tallest mountain on Earth, measured from sea level. A somewhat more obscure piece of trivia is that the point on the Earth's surface farthest from its center is the summit of Mt. Chimborazo in Ecuador, due to the fact that the planet bulges out at the equator.
Even more obscure is the question of which point on the Earth's surface moves the fastest as the Earth spins, which is the same as asking which point is farthest from the Earth's axis. The answer isn't Chimborazo or Everest. The fastest point turns out to be the peak of Mt. Cayambe, a vol
With these you could try to figure out which point of earth has the largest time dilation!
 
 
2 hours later…
3:59 PM
hey
so i was thinking a projectile motion
i think at maximum height potential energy is 0
since when ball is going up gravity does negative work
and when ball goes down gravity does positive work
must be 0
at top
 
@fqq thanks a lot, those are exactly the notes I found after bolbteppa suggestion. Giamarchi index seems to suite more what I should do. Thanks for the help again
 
fqq
4:25 PM
@Ratman I've never read Giamarchi's book, keep in mind that it's relatively old and there's been a lot of activity in the field in the past 15 years
 
What is the purpose of pain?
why I was born with a badluck!? Since the very beginning, nothing seemed to be going right.
 
4:39 PM
@fqq I think it shouldn't be a problem, I intend to use it just for few parts, but thanks a lot for the warning. My problem is that the path followed in my course is quite particular (just in the sense that I am having hard time finding the literature that use the methods presented) so I am trying to fill some gaps for specific topics.
 
 
1 hour later…
5:48 PM
@antimony not sure why you pinged me on that. i don't know bubkis about strings :P
 
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