« first day (3489 days earlier)      last day (41 days later) » 

12:49 AM
-2
Q: Have we thought about replacing the negative 'downvoting' of questions with a positive 'requesting clarification'?

DoctorNuuFacebook eliminated the dislike for a reason. My personal experience is just wanting to quit after a question gets to -3 for reasons unknown. Downvoting of a question is an inherently negative process and an even more negative experience for the questioner. Requesting clarification is a natura...

 
 
2 hours later…
2:34 AM
@Slereah This is wrong. You need to cancel the $d$β€˜s.
 
 
6 hours later…
8:41 AM
I'm confused about something is sets. You know how there's: S = {x | x > 5} for example. I'm confused about this: S = {2x | x > 5}. What is the first form thingy
I'm confused about how the first part of the set works
nvm I think I got it somewhat
it's like "the form" of the set. For example, if it's 2x, the condition afterward will be applied to only 2, 4, 6, 8...
so for example, S = {2x | 0 < x < 6} then S = {2, 4, 6, 8, 10}
 
9:16 AM
@JingleBells You got it. Strictly speaking, that notation should mention the domain of x, whether its integers, or reals, etc, but people often don't bother with that if it's obvious from the context.
 
Geoff Dalgas ♦, Corvallis, OR
101 4
 
@JingleBells It's like a list or set comprehension in Python. Your last example could be written in Python as s = {2*x for x in range(1, 6)}
 
He (Geoff) was the second person to create an account on PSE. The first one has probably deleted their account...
 
We should be seeing a lot more presence of SE staff on the network in a couple of weeks:
43
Q: 2020 Community-a-thon: Increasing SE staff engagement with our sites and communities

Yaakov EllisAs was announced in the Q2 roadmap and subsequently discussed on MSE, we will be hosting an internal company Community-a-thon event in June. The exact dates are still to be decided, but it should start in the middle of the month and extend for four weeks. Some of the goals of the event: Impro...

 
Among the top 10 PSE users, Rob Jefferies has the highest upvote to downvote ratio (these are votes on his posts, not the votes by him) of about 1 downvote per 152.7 upvotes. Epic! Mine is 49.7 :D
This probably would be highest among the whole PSE community, excluding the people who got zero downvotes :-)
@PM2Ring I want to see them struggle with doing PHYSICS ;-) (jk, i know they'll not be doing any physics here)
 
9:26 AM
Nobody with any significant amount of rep has zero downvotes (if you include votes on deleted posts).
 
@PM2Ring definitely!
Is it okay to leave bold (metaphorically), strong and a bit (only a bit) snarky comments to questions who just dump their HW on the site?
 
@FakeMod I won't be surprised to see physics questions from SE staff. And they may also write some answers. ACM isn't the only person with a physics degree who works in IT. And not all SE staff are IT people.
 
@PM2Ring I suppose I am also going to have a similar career/future :-)
 
@FakeMod You can have a serious attitude in your comments, abd I think being stern is ok, but we should try to avoid being snarky.
 
@PM2Ring What about:"(We are not here to do your Homework for you.)[Homework policy link]"
 
9:33 AM
Snarkiness was more common in the early days, but the powers that be decided it was too unwelcoming. So snark can be flagged as unkind.
 
@PM2Ring BTW, I just noticed, one of such comment threads which started with the above quote (by me) was deleted by David Z as mildly inappropriate :-b. Seems like I shouldn't post that as a comment.
 
@FakeMod Borderline. You can probably get away with "Physics.SE is not a free homework service".
 
@PM2Ring hmm...
 
Better: "If you want help with this problem you need to ask a specific conceptual question, as explained here [link to homework policy]."
 
@PM2Ring Why is everyone trying to convert the Internet into a fairytale-like "no-one-will-hurt-you" place? It's acceptable to do this for blatant insults, but sometimes people just overdo welcoming by even being feel attacked by trivial stuff...
@PM2Ring that doesn't really convey to the OP that their current question isn't acceptable on the site.
IMO, they always end up trying to explain how their question is very conceptual.
 
9:40 AM
@FakeMod They'll learn that shortly, when their question gets closed. :evil grin: Or if they read the homework policy link.
 
@PM2Ring 😈
Lately, I was showing a lot of kindness while closing questions, but it seems, today all of that has evaporated...
Dunno why
 
@FakeMod There's a lot of discussion about this on the various metas, especially MSO & MSE. Basically, online text is more ambiguous than face to face communication. Especially among an international community. So it can be really hard to tell the emotional impact of what you write. You might intend a little playful snarkiness, other people may think you're being nasty & thoughtless. So SE decided we need to present a nice smiling welcoming face, especially to the newbies.
 
@PM2Ring I agree.
 
It's a shame the old XKCD forums disappeared. People were expected to behave in a civilized fashion, but there was room for humour & snarkiness. And mods weren't afraid to retaliate when dealing wirh trolls &/or idiots.
 
10:22 AM
One of the methods I am using for my Master's thesis is working fine, but now I have found a much better way to do it. However, I don't have enough time to implement this new method. I am struggling a bit with how to present this in writing, without sounding like I am not implementing because of laziness.
So the problem is basically presenting my method in a natural way, even though it is not very motivated anymore
 
10:50 AM
Was I being too aggressive here?
Pls don supsend meh :P
 
@FakeMod The page for user no. 1 isn't a deleted user, it's just empty (moderator can usually see some information on deleted users). Looks like it never was an actual account.
 
@ACuriousMind oh, interesting!
@ACuriousMind What do you see when you see this user? :-)
 
@FakeMod Years ago (ugh!), I used to leave somewhat aggressive comments like "Have you read [our homework policy]?". They used to get some more upvotes than my current canned comment (people love snark), but they didn't get any better results, and in my impression more users responded negatively to them. Think about why you're leaving the comment.
@FakeMod The normal amount of information on a deleted user.
 
@ACuriousMind alright.
@ACuriousMind Hmm... I realize...
 
@B.Brekke I think it's perfectly fine to describe why you initially pursued the method you actually implemented and its result, then explaining how you found the better way the (and why you think it's better), then leaving its implementation to a mention in a "Future Work" section.
I think there is value to seeing how ideas and approaches evolve, and we often focus too much on presenting a perfect end result, and not enough on how to get there, leaving many expositions to be a variant of this
 
11:06 AM
@FakeMod I feel your pain. But don't bother wasting time & energy like that. If an edit rollback "war" occurs, an automatic mod flag is raised, and mods can lock the post, if they think it's necessary. They probably wouldn't bother locking a closed (& unanswered) homework post though. The Roomba will delete it, eventually.
 
@ACuriousMind I would actually feel nice to be a bit honest about my initial thoughts. There are some nice lessons to learn from it. I just have to make sure it is formally written and doesn't end up like a diary
 
12:04 PM
@PM2Ring :-) I was thinking of flagging it manually if the OP doesn't stop undo-ing the edits, but fortunately, the OP stopped doing it and probably my stern (IMO) message did the job ;-)
 
Aug 26 '15 at 16:36, by ACuriousMind
@HDE226868 Ah, best Freudian slip I've heard: WIMP - Weakly Interesting Matter Particle
 
(:D)
 
12:31 PM
In a simple electric circuit with wires(ideal) a resistor and A battery
At steady state
The field inside the wires is zero
But it isnt Zero inside the resistor, correct?
 
12:45 PM
@PM2Ring you mean the domain of f(x)? The domain of a function is basically the numbers that go into it (the input), so the domain is 2x, meaning only 2, 4, 6, 8... will be inputs
 
Z/2Z?
No wait that's integers my bad. N/2N.
 
@Thormund that for me?
 
Yeah its an easier way to write {2,4,6,....}
 
oh xD
actually, 2x is easier
sorry I dont' understasnd what you mean
 
So a group $G$ and a subgroup $N$, we say the quotient group of $G/N$ is removing elements in $N$ from $G$.
 
12:52 PM
I have no idea what you're talking about. The easiest way to write a set of {2, 4, 6, 8...} is $S = \{2x | x \in W\}$
 
Now I confused myself too woops. Does the quotient group yield 2 seperate classes?
 
I have not yet learned about quotient groups, this is sets.
 
@JingleBells The domain of a function y = f(x) is the set of values that x comes from, and the set of corresponding y values is called the codomain (some older books call the codomain the range). See en.wikipedia.org/wiki/Domain_of_a_function
@JingleBells Yeah, don't worry about groups for the moment. Get used to sets first. There's a nice (but old) site that's a good introduction to groups. I think the site was created to help people learn enough group theory to understand & create Rubik's Cube algorithms. dogschool.tripod.com
 
1:20 PM
@Thormund Yes, what you wrote is the finite group with two elements
The set JingleBells describes is just $2\mathbb{N}$.
 
1:40 PM
Ah yes my bad πŸ˜…
 
1:56 PM
I'm learning about the locus in sets, which basically means "all points that" and usually adds up to a continuous shape and I was wondering, how is a line made up of dots? My math source also says that the dots have no size, weird.
I suppose a line would be a set of infinite amounts of dots with infinitely small sizes.
(just a guess tho)
$S = \{x : x \in \R, 5 < x < 10}$ <-- a line?
 
What is your definition of 'size'?
 
damn u latex
@ACuriousMind how big the thing is xDD
jk
@ACuriousMind i'm not sure :p
 
In math you have to be careful not to use concepts that aren't even defined for the objects you're dealing with - a set, without further structure, has no notions of size or how "close" its elements are. For a notion of closeness (the minimum to need to talk about things in at least vaguely geometrical terms), you need topology.
 
Oh, I'm not talking about sets, I was just wondering what a line is
$S = \{x : x \in \R, 5 < x < 10\}$
oh my gooodddd
I think latex is harder than math
Is topology the calculus of graphs?
I never realized how interesting math can be. I'm hooked.
$\R$
why the \R doesn't work :(
$\mathbb{R}$
yay
I meant "Is topology the calculus of geometry" lol
$\frac{1.52}{0.51}$ <-- That's not a rational number?
 
2:11 PM
Usually you need something more than topology to do what we usually think of as geometry (e.g. you need a distance function, a "metric"), but topology endows a set with a notion of "nearness" e.g. it allows you to express what it means for a point to be infinitely close to a given subset ("limit point")
@JingleBells of course it is
 
@ACuriousMind But the definition of rational numbers is when you divide two integers, no?
 
Your number is the same as $\frac{152}{51}$.
 
lol
Got it
 
hi guys
 
hello satan
 
2:16 PM
just tried reading the "hydraulic analogy" for circuits
 
the analogy for a resistor is bothering me
They describe it as a constricted pipe
and it is claimed that a difference in pressure accours
*occurs
however
 
@satan29 That's Bernoulli's principle - changes in diameter affect the speed, which in turn affects the pressure.
 
If you use The bernoulli equation
p + 1/2 (rho)v^2 = constant
at the ends of the constricted pipe, Velocity is the same
so p is the same?
 
Ah, yes, if they claim the pressure is different in parts of the pipe with the same diameter, that's wrong
 
2:22 PM
@satan29 Yes it needs to be the same.
 
v changes only inside the constricted pipe
 
Keep in mind it's just an analogy, it breaks when you stretch it too far
 
The analogy will work perfectly if you tilt the water pipe downwards.
 
But then i am slightly confused regarding a potential "drop"
 
@ACuriousMind In this case, it is misrepresented. If it breaks, here, at the basics, it isn't even an analogy :P
 
2:23 PM
consider normal circuit elements
the velocity of the electrons is the same at the ends of the resistor
 
@satan29 The analogy will work perfectly if you consider a pipe with uniform cross section tilted downwards.
 
so, there is no overall change in KE of electrons as they move from one end to the resistor to the othrer end
 
@satan29 Yes.
 
so no total work is done
since w= delta(ke)
now if we define Voltage as work/unit charge
 
@satan29 Nope. There's a total work done, however it got lost as heat.
 
2:26 PM
uhh
work energy theorem
 
@satan29 An actual wire is a quantum mechanical system where the drift velocity of the electrons (the speed with which they actually move along the electric field on average) is much lower than the speed of electric signals anyway.
 
Total work done= change in KE
 
Of course, my statement is only true if you exclude the work done by resistive forces.
 
Thinking about little balls moving through the wire is not what happens.
 
although
hows this for an explanation:
 
2:26 PM
Hey, I found a nice analogy...
 
wait @FakeMod
voltage = work done by electric forces/ charge
through the resistor
Electric field does worl
k
on the charges
and elements of the resistor also does work on the charges
total work being zero
on the charge
And, charge does work on the resistor elements: Which appears as heat
 
Imagine a pipe with uniform cross sectional area. Where there's resistance (in the original circuit), there's viscosity in our analogous pipe. This way, there is a pressure gradient accross the viscous part and the speed stays constant everywhere. BOOM! @ACuriousMind any fallacies in my analogy?
@satan29 I couldn't wait more ;-)
 
is this explanation reasonable
 
@FakeMod where does the visocity come from - visocity is a property of the fluid, not of a location
I think the best analogy for a resistor is a water wheel.
 
ah yes, John Rennie said the sam
 
2:30 PM
The current deposits energy at a resistor just like a water flow deposits energy when turning a water wheel
 
e
 
@ACuriousMind I mean, it is an imaginary fluid...
@ACuriousMind ooh, nice!
 
@ACuriousMind (not considering the analogy, rather the circuit elements) is my explanation reasonable?
 
@ACuriousMind Was this user somehow protected from the downvotes they recieved?
Their rep really doesn't reflect the downvotes...
@satan29 IMO, yes.
 
@FakeMod Reputation calculation respects the temporal sequence of events. If you get a downvote while you're at 1 rep and then get an upvote, you end up at 11 rep, not 9.
 
2:33 PM
@ACuriousMind Oh, I see...
 
so the constricted pipe analogy is garbage?
 
I don't find it particularly useful, yeah
 
@satan29 I never really took it seriously.
 
Thank god, i thought i was missing something obvious
circuits arent as intuitive as you'd think , If you try to explain every single nuance
IMO thats electrocstatics in general
btw @fake
 
To be honest, I sometimes think that we should accept physics as it is and not go search for comforting analogies, elegant or simple explanations and intuition.
 
2:36 PM
@FakeMod Hows exam prep going on
 
@satan29 dope
 
Well, I expected some sort of explanation for everything that isnt QM :P
 
I just watched a video and when we talk about electric current, the electrons actually move slow, but the pulse wave between them is what it gives the super fast speed. How does that work?
 
@JingleBells magic!
 
lmao
 
2:38 PM
Jk, idk
 
oh vnm
 
Do you mean "matter waves"?
 
nvm I think I got it
 
1
Q: Relationship between resonance frequency of a cup and amount of water filled

David305For a science project I chose to investigate the relationship between the resonance frequency of cups and the amount of water filled in it. I filled the cup with 10 grams of water each time, and used a pencil to hit the cup. After trying a lot of combinations, I found that there is a linear relat...

 
The electrons don't mechanically move super quickly, but they push each other in a chain-like reaction which reaches the end very quickly
 
2:39 PM
This question looks spooky to me. Mass cubed, I have never seen that :P
 
@JingleBells I don't know what you mean by "pulse wave", but the idea is similar to how sound propagates: When you speak, sound travels pretty fast because the air molecules all move a bit and push on the next one which pushes on the next one etc., but at no point does any volume of air individually travel with the speed of sound.
 
@ACuriousMind Yes exactly, thanks for the analogy.
By the way, current loses energy as the "push wave" travels more distance, right? Just like sound?
Just like Minecraft Redstone
 
In ordinary conductors, yes, because ordinary wires have non-zero resistance. This is not analogous to sound, however, because sound loses power mostly because it expands in all directions.
 
5 mins ago, by FakeMod
This question looks spooky to me. Mass cubed, I have never seen that :P
Even dimensional analysis yields only mass, not mass cubed...
 
@ACuriousMind Got it, thanks
 
2:46 PM
Curious...
 
 
3 hours later…
5:26 PM
-2
Q: Gauss law symmetry

Ojas AgarwalCreating symmetry is always difficult for me. For example cube related gaussian surface is tough to imagine. Flux through conducting and non conducting spheres are way tougher to understand

 
@JingleBells "how is a line made up of dots?" Mathematicians have been pondering how a line is "made of" points for about 2500 years. For most of that time, people just hand-waved the tricky issues, or talked about the paradoxes that arise in building a line from points.
We started to make real progress in the 1800s, especially after Cantor invented set theory. Other notable names from that time period include Dedekind and Weierstrass. The theory of infinite sets has made a lot of progress since then, but it's still a field of active research.
 
5:41 PM
Cardinals and ordinals
my favourite infinities
 
 
1 hour later…
7:04 PM
Hello
anybody ?
 
hi?
 
i am confused about the constants appearing in the lagrangian
 
I'm not an expert but can you be more specific?
 
say i would like to derive the Klein gordon equation
or dirac equation
we have hbar the planck's constant in those equations
 
I do not know QFT sorry, I'm sure someone else here can help you though if they see this
 
7:11 PM
yeah no problem
maybe some other time or I post
 
7:28 PM
Does anyone know what algorithm AI uses to recognize and count for example cars on the road? I know we can use a CNN (Convolutional Neural Network) and train it on a dataset of cars, but how would we go about recognizing and counting a few cars on a road? One crappy way I can think of is to make a scanner (let's say 5x5 pixels) that will go through the big image of the road and spot cars.
And I've seen algorithms such as YOLO which does real-time object detection, and sure, you can train a CNN to recognize and label different objects (by having a huge dataset), but how is the other part done? - Recognizing multiple objects on a single image? And I suppose that the way it's made real-time is by basically taking an image of the live feed every x seconds and doing a recognition scan on it.
I think I found what I was looking for - Region Proposal Network (RPN)
 
7:50 PM
Yo! Just crossed 500 first posts reviews :-)
 
8:49 PM
It's almost dawn. I am going to sleep.
 
9:01 PM
Guys I feel like an absolute idiot
I can't seem to get that relation
Any suggestions on method?
 
just substitute the expression for $p$, then try to pull everything in front of the second $\partial_t$ inside it.
 
$\rho$ is a function of time right?
 
Probably? It's your exercise, you should know what $\rho$ is :P
2
 
Sorry, it definitely is.
I'm unsure as to how to pull it in that right derivative though
 
You'll probably have to use the product rule. You can then also take the time derivative of the term you want to show is constant, use the product rule, and start staring really hard at both expressions until you figure out why they're equal
 
9:12 PM
Mhm I tried that
Lemme try again
Must be making some silly mistake
 
@JakeRose I mean pulling in like $f \partial_t(g) = \partial_t(fg) - \partial_t(f) g$.
 
Yeah that was what I did
I must have just made a mistake
will try gain
 
9:57 PM
@ACuriousMind I'm still getting stuck
Not seeming to spot the link
I get $\partial_t (\rho R^3)(1+w) - \partial_t (R^3) \rho w = 0$
From the fluid equation
But I can't get constant equation in a form that matches this
 
10:18 PM
FINALLY
I got it in quite a round about way
Not sure if it was the most direct
Took the second and differentiated it wrt $R^3$ to get the $(1+w)$ term
Then used chain rule to swap for a time derivative
 

« first day (3489 days earlier)      last day (41 days later) »