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12:42 AM
Coleman's Lecture Notes on QFT is about $140 USD. that's damn costly... especially considering Coleman already passed away ...
but I really want and need the problem-set with detailed solution.... damn
 
 
4 hours later…
4:24 AM
@JohnRennie hello
 
@user8718165 morning :-)
Yes, I'm free.
 
 
1 hour later…
5:28 AM
@JohnRennie can we cool photons to zero energy?
 
@Akash.B it depends what you mean.
Normally photons don't have a temperature so it doesn't make sense to try and cool them.
Strictly speaking you can't change an individual photon. You can just destroy it and create a new photon to replace it.
 
6:13 AM
@EmilioPisanty Well, you're right, now that I look at it again it's a male symbol
 
6:58 AM
@ACuriousMind ;-)
 
 
2 hours later…
9:15 AM
hi
 
@Akash.B morning :-)
 
@JohnRennie its noon here!
 
@Akash.B Hi. In some situations, we can assign a sensible temperature to a collection of photons. See en.wikipedia.org/wiki/Photon_gas
 
@Akash.B oh well. I'm using a regional greeting :-)
 
It's 7:20PM here.
 
9:21 AM
@JohnRennie can we bring photons to rest using laser beams?
 
@PM2Ring I think I'd argue that what you're doing is assigning a temperature to whatever the photons are in equilibrium with. I know it comes down to the same thing in the end, but you need to be careful about assigning statistical properties to photons.
@Akash.B light doesn't interact with itself, so you cannot affect photons by shining laser beams at them.
 
@JohnRennie okay
 
It is possible to bring photon to rest by making them interact with certain types of matter.
Though strictly speaking when a photon interacts with matter it is no longer just a photon. The photon wavefunction becomes entangled with the matter wavefunction.
 
@JohnRennie I totally agree. But pretending that the photons in an oven are in thermal equilibrium with oven walls does lead to interesting & useful results.
 
That's why the photons slow down. The photon/matter entangled system behaves as a quasiparticle that has a non-zero mass. This particle is called a polariton.
 
9:24 AM
@JohnRennie I have an interesting idea about dark energy
 
When we bring light to a halt, e.g. using a Bose-Einstein condensate, what we are really doing is bringing polaritons to rest.
@Akash.B yes?
 
first let me check on internet
 
9:35 AM
Cripes, you miss a days reviewing and the Close queue explodes in your face!
 
 
1 hour later…
10:52 AM
What is the way to develop calculus in theoretical physics articles?
Most of the time, we find in our way when reading articles expressions that had been put by the author(s) without expansion and I wonder how to prove such expressions?!
 
 
1 hour later…
12:12 PM
@Student404Mus The author assumes that if you're reading their article then you have the necessary physics & mathematics pre-requisite knowledge to follow their text & their equations. But it's frustrating when you stumble on an article with an interesting sounding title and you don't know what those pre-requisites are. Or you kind of follow what they're saying, but their notation is unfamiliar, so you're unsure how to interpret their equations.
 
 
2 hours later…
2:06 PM
@EmilioPisanty r/softwaregore
 
3:04 PM
Hello @JohnRennie
 
@user8718165 hi
 
For how long are you around?
I had a doubt
 
Not sure ...
If you have a question it would be best to ask now.
 
@JohnRennie if we apply a force to an object of mass m off the centre of mass, how would the predicted motion be?
It will turn but will radius become bigger and bigger with each turn?
 
@user8718165 that's actually quite straightforward.
 
3:08 PM
@JohnRennie I'm not getting it still...
 
Suppose you apply a small impulse at a distance $r$ from the centre of mass of the body. (Impulse is force times time, and it's equal to change in momentum).
 
@JohnRennie yes, got this much
 
The linear momentum must increase. Since momentum is equal to $mv$ and the mass is constant the linear velocity must increase my an amount $dv$ given by $Fdt = mdv$.
 
@JohnRennie got it
 
Here I'm writing the small impulse as $Fdt$ i.e. a constant force times a small time $dt$.
This is actually just the same as if you applied the force at the centre of mass. For the linear part of the motion it makes no difference.
 
3:12 PM
@JohnRennie so will it spiral?
 
Now for angular motion we have an angular impulse that is torque times time. And this is equal to the change in angular momentum. Since we apply the force at a distance $r$ from the centre of mass the torque is $Fr$, so we get an increase in the angular velocity given by: $Frdt = I d\omega$.
So the force both accelerates the object and increases its rotation rate.
 
@JohnRennie got it
 
This is a very common type of exam question. You'll see lots of questions like this :-)
 
I couldn't find any on the internet even on the site...
 
in Problem Solving Strategies, 8 hours ago, by kyle campbell
Hi, I have a question I cannot figure out: You wind a string around the outer rim of a solid disc with a radius of 10 cm and a mass of 2.8 kg. The disc sits at on a frictionless horizontal surface. You pull on the string with a force of 10 N for 3 s. What is the final kinetic energy of the disc? This includes both translational and rotational kinetic
energy.

I have tried to simply do K = 1/2mv^2 + 1/2I(\omega)^2 but numerically I'm getting half of the correct answer. The moment of inertia for a solid disc, as far as I know, is 1/2mr^2 about the z-axis. Is this not correct?
@user8718165 there, I answered just this type of question this morning
 
3:19 PM
@JohnRennie this question asks about the $K.E$
 
@user8718165 yes, but the way to solve it is to calculate the linear velocity $v$ and angular velocity $\omega$, then the KE is $\tfrac{1}{2}mv^2 + \tfrac{1}{2}I\omega^2$.
 
I understood parts of the solution of the question. I think the object will move in a straight line and at the same time rotate...
 
@user8718165 correct
 
that's why we have to account for the $M.I$ (for rotation)
 
@user8718165 yes
In angular motion you generally replace $m$ by $I$ and $v$ by $\omega$. So for example the linear momentum $mv$ becomes angular momentum $I\omega$.
And linear kinetic energy $\tfrac{1}{2}mv^2$ becomes rotational kinetic energy $\tfrac{1}{2}I\omega^2$
And you replace force $F$ by torque $\tau$, so for example Newton's second law for rotation becomes $\tau = I d^2\theta/dt^2$
 
3:28 PM
@JohnRennie Thank you got it fully:-)
 
 
2 hours later…
5:17 PM
What exactly expands when we say the universe is expanding? Spacetime? The magical fabric that makes space? Why aren't we expanding as well? (our bodies, eyes...)
 
@ACuriousMind dammit, I was about to post the exact same link, I'm blaming you for letting me waste those 20 seconds searching (and an additional 40 seconds making a rant)
 
@JMac I accept the blame and as penance will spend one minute in a superposition of feeling guilty and being unreasonably pleased with myself.
 
@ACuriousMind I grudgingly accept these conditions.
 
@ACuriousMind So basically atoms and mass should expand but it doesnt due to the attractive forces between the atoms?
 
5:29 PM
@ACuriousMind $\frac{1}{\sqrt{2}}(|\text{upper}\rangle+|\text{downer}\rangle)$
 
@Semiclassical That sounds more like Schrödinger's drug
@NovaliumCompany yup
 
I wonder how weak an attractive force you need for that
 
I'm reading A Brief History of Time and there is one more thing I dont understand called light cone. I understand it describes the delay of the light reaching and so on but how?
 
@NovaliumCompany I'm not sure I understand the question. What's your definition of a light cone?
 
5:44 PM
@ACuriousMind Its a type of diagram used to describe the delay between when slmething hapoens and then someone far sees it happening.
 
@NovaliumCompany That's not a definition, and probably the root of your confusion.
Maybe read the Wikipedia article and see if it becomes clearer to you
 
5:59 PM
@ACuriousMind I understand it now thanks :) But the past cone is a bit confusing.
 
hmmmmmm.
Who's going through my old questions and upvoting them?
it looks like it's fishing for a voting reversal, that
 
@EmilioPisanty I actually upvoted your question and answer for this one > physics.stackexchange.com/questions/100864/… because a different answer came into a queue, so you can take a bit off the upvote chain as legitimate upvotes. I got hit with what looked like some serial votes last week too
 
@EmilioPisanty Not me, although I do tend to upvote your answers when I bump into them. If I understand the topic well enough to know that you're right. ;)
 
yeah, I'm not too fussed by any of that
it's the long-tail there that doesn't happen very often
 
6:19 PM
Yeah that one's a lot worse than last week for me. I got hit with 3 in a row on all my top rated answers though. Two of them within 6 seconds of each other. Seems like whoever did mine isn't the same as yours though; since they clearly don't care about having the votes reversed
 
eh
if they get reversed, they get reversed
if it gets me a rep-cap day and then takes it away then that's definitely more cruel
but I'm not going to get worked up over 100 rep
 
@Blue Hello !
 
huh
btw
congratulations to our new fourth-place rep holder, @Qmechanic
and I guess @Floris gets a you-snooze-you-lose?
 
@EmilioPisanty Yeah, definitely nothing to worry about directly. Still pretty annoying to have the numbers jump around all willy nilly
 
Anonymous
@Jasmine Hi. What's up?
 
6:34 PM
still, it's pretty striking that Floris has a Legendary badge, as do John Rennie and Lubos Motl, while Qmechanic has eight rep-cap days
(anna has 69 currently)
 
@Blue I need to know about WBJEE
 
Anonymous
Okay?
 
Anonymous
I'm a bit busy today...so perhaps make it quick. :)
 
Is it possible to get CS in JU ?
 
Anonymous
@Jasmine You mean there's a CS stream or not? Yes, there is. You'd need a state rank of <150.
 
6:36 PM
Without being from West Bengal ?
 
Anonymous
Yes, anyone from India can appear for the test.
 
I guess Floris earned the bulk of his rep over ~four years, while Qmechanic's is spread over twice as long, and that tips it over into a vastly reduced number of days at the cap
 
What are the ranks v/s marks
What marks can fetch me CS or Electronics and Communication Engineering if I am not from WB
@Blue if you are busy then it's fine I will contact you later when you are available as you say me :)
 
Anonymous
@Jasmine That isn't really fixed; changes every year. You can check this.
 
Anonymous
@Jasmine I don't think it matters whether you're from WB or not (there's no state quota).
 
6:40 PM
@Blue How did you prepare I need tips
Anything other then Advanced and Mains prep ?
@Blue oh !
 
Anonymous
Just go through the past 10 years' papers and you're done. It's more of a test for speed; difficult questions are rarely asked.
 
@Blue only that nothing else
Then it's good !
Thank you @Blue :-)
 
Anonymous
@Jasmine I just revised the syllabus from Physics Galaxy and Mathongo in the week before WBJEE. For Chemistry you have NCERT...memorize it. :P
 
Anonymous
@Jasmine Good luck!
 
@Blue Thank you !
 
6:46 PM
@EmilioPisanty Qmechanic only has 8 max rep days!? That's pretty wild, it would take a very careful balance of consistent quality contributions, while somehow not having many answers hit like HNQ and stuff. I have less than 10% of his rep, and 11 full rep days, but that's because I pretty much only answer classical physics questions, which are usually easier to reach a broad audience quickly
 
@JMac indeed, it would take a substantial amount of extremely high-quality contributions spread out over a very long period, making sure that you're answering every day so that they're evenly spread and they don't bunch up
so yeah, it sounds like Qmechanic
 
Well what gets me is he somehow managed to do that while still avoiding getting into HNQ one way or another enough times to just start piling up rep caps. Gotta be a strange mix of the types of questions he answers and some pure chance sprinkled in.
 
@JMac you've just got to keep answering all the hard questions instead of the easy ones, 'cause it's the easy ones that get all the votes
 
7:04 PM
Plus he doesn't seem to give answers as easily digestible by the broader audience; I think that's a big part of it. Like all the people with the most rep cap days seem to be the ones who answers questions in a more qualitative way (while still trying to be accurate). Qmech seems to take a more technical approach, which is a lot harder for drive by users to read and go "yeah that makes sense I'm going to upvote".
 
Makes it sound like more max rep days means your aren't as thorough in your answers haha
 
7:29 PM
@EmilioPisanty : Thx, Floris collected all his rep in just 3.5 years. If he becomes active again he could presumably easily get back in front :) Anyway, we're not really here for the rep. We're here for the physics!
 
Why is the time mean value (mean value over a period $T$) just the real part of the expression?
Is there not a factor $1/2$ missing?
Since $\langle f(\mathbf{r},t)g((\mathbf{r},t) \rangle = \frac{1}{2} \mathrm{Re}\{f(\mathbf{r})\bar{g}(\mathbf{r})\}$
 
@Qmechanic I learned physics just so I could get reputation points on this site
3
 
7:56 PM
@AaronStevens : A honorable goal. Somehow I doubt that ;-)
 
@Qmechanic dunno about you, but I'm only here for the fake internet points =P
In that spirit, so long as I'm ahead at total earned rep (current rep + offered bounties), you and Floris duke it out =P
Seriously though, much respect for the consistently awesome content you post
 
Is there a general name for forces that are proportional to mass, and therefore accelerate objects of different masses equally?
 
8:22 PM
@SirCumference Gravities. ;)
@OliverWatkins: In this community, you gotta make the rep first. Then when you get the rep, you get the power. Then when you get the power, then you get the women. — PM 2Ring Oct 27 '14 at 10:16
In case it's not obvious, that comment is a parody of a quote from a movie (and a rap song, which samples the movie). If ROs or mods think it's in poor taste, please remove it.
 
 
2 hours later…
10:36 PM
oooboy...so much research paper reading...brain cramping...
 
11:19 PM
@enumaris better than spec reading!
 
You're doing spec reading?
 
Yeah I get the joy of doing that from time to time. It's fairly mind-numbing
 
I got no specs
not at the software dev level anyways
 
Well mine are less software specs and more compliance specs, which have the fun of being written and approved by some committee
 
11:44 PM
^ The only thing I know to be more painful than reading those things is writing them. Uhg.
 
that sounds...unpleasant
 
lol
 

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